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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 76351. |
1. Find the volume,cuirverdSirfaceareaandtotalsurfaceareaofcachofthecyfinderswhose1.Find the volume, curved surface area and total surface area of each of the cylinddimensions are(o radius 7 cm, height -50 cm(i) radius 5.6 cm, height 1.25 rmcylinder2. The circumference of the base of a cylinder is 12 m and its height is 77 m. Find the volurme of the |
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Answer» the circumference of a circle is 15m and height is 84m.find the volume of the cylinder? |
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| 76352. |
요Lei 효83(a) 6tan-1J3-cot-ih/3) "rm t (equals)(a) O7,(c)π(b) 2 |
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Answer» ⇒tan¯¹ √3 - cot-1(-√3)⇒π/3 - (π-π/3)⇒π/3 - 5π/6⇒ -3π/6⇒ -π/2 option b. |
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| 76353. |
x+1 r 1 413. If, then write the value of x.3|x-3x+2||1rm |
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| 76354. |
५. 525-मान ज्ञात कीजिए। |
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Answer» √25= 5now5*5÷5+55+5= 10thanks |
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| 76355. |
4. Find the values of 'a and 'b' in each of thefollowing:2+132-v3 |
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Answer» Rationalising2+√3/2-√3*2+√3/2+√3=(2+√3)^2/4-3=4+3+4√3/1=7+4√3hence a=7 and b=4 |
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| 76356. |
Q5. Solve the following:-3 2a 2-38 |
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Answer» a) 2 - 3/5 = 10-3/5 = 7/5 b) 4 + 7/8 = 32+7/8 = 39/8 c) 3/5 + 2/7 = 21+10/25 = 31/35 |
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| 76357. |
1.The density of room temperature water is equal to...a. 0.0 g/mLb. 1.0 g/mLc 100 g/cm3d.) 0.0 g/cm3AU |
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Answer» In general, we say that the density of water is1000 kg/m^3(or1 g/cm^3). But you're right that it does vary a little bit with temperature. It is exactly1000 kg/m^3at 4 degrees Celsius. At 20 degrees Celsius it is998.23 kg/m^3 ( or 0.99823 g/cm^3 |
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| 76358. |
25) In a rain-water harvesting system, the rain-water from a roof of 22 m Ă 20 m drains into a cylindricaltank having diameter of base 2 m and height 3.5 m. If the tank is full, find the rainfall in cm. Write yourviews on water conservation. |
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| 76359. |
For rain water harvesting a tank of length 10 m, breadth 6 m and depth 3m isbuilt. What is the capacity of the tank ? How many litre of water can it hold? |
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Answer» Solution:A.T.Q length = 10m breadth = 6 m depth = 3m so,we can do analysis that tank is rectangular. Volume of rectangular tank= length x breadth x depth = 10 x 6 x 3 = 180 meter cube. Capacity: Normally capacity of tank is calculated in lites. as we know 1 meter cube = 1000 ltr so 180 meter cube = 180* 1000 liters Capacity= 180000 ltr hope it helps you. l=10mB=6mH=3mvolume of cuboidal tank=l*b*hhere,10m*6m*3m=180 cu.mwe know that1cu.m=1000ltherefore:180 cu.m =180*1000l180000L solution>lenth=10m, breadth=6m, depth=3m, therefore, volume=10×6×3 metre cube=180 metre cube 1metre cube=1000L180 metre cube=180000L volume of tank=10×6×3 =180m³ capacity1m³=1000 litre 180m³=180×1000 =180000 litres 1,80000 liters can hold the capacity of the tank is 18000litre Capacity of the tank = length x breadth x height = 10 x 6 x 3 = 180 cu. m in 1 cu. m = 1000 l. in 180 cu. m = 180 x 1000 = 180000 litre. (ANS) lenght of tank ,l= 10mbreathe of tank,b=6mdepth of tank ,h =3m capacity of tank meansVolume of tank or amountOf space occupied by tanksSuch volume of tank = lenght x breathing x depth = 10m x 6m x 3m = 180m³हम 1L = 1000cmqu = 10 ^ -3m 1000 जानते हैंया, 1 वर्ग मीटर = 1000 एलso ,180m³ =180,000L= 1,80,000LHance ,water can hold 1,80,000L |
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| 76360. |
In a rain-water harvesting system the rain-water from a roof of22 m x 20 m drains into a cylindrical tank having diameter of base 2 rmand height 3.5 m. If the tank is full, ind the rainfall in cm. Write yourviews on water conservation. |
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| 76361. |
T & AIMf the27 Al nucleus is taken to be R13If radius of the 27adius of 525 Te nucleus is nearlythethen[AIPMT-2015] |
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| 76362. |
4. The diameter of a tyre is 77 cm. Find the distancecovered by it in 10 rounds. |
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Answer» so radius of tyre is 77/2For round distance covered is perimeter so 2×pi× 77/2= 2×22/7×77/2= 242 in 10 round it will go 10× 242 cm = 2420cm |
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| 76363. |
Q5.Solve the following:-2-5 |
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Answer» PLEASE LIKE AND SHARE THIS APP |
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| 76364. |
Q5.Solvethe following:-3imi) |
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Answer» please like my answer if you find it useful |
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| 76365. |
Q.26. A metallic sphere of radius 10.5 cm is meltedand then recast into smaller cones, each of radius 3.5 cmand height 3 cm. How many cones are obtained ? |
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| 76366. |
Find the perimeter of(a) Rectangle whose length = 30 cm, breadth = 15 cm.(b) Square whose each side is 15 cm.nhan to unlle around its houndary thrice find the dist |
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Answer» Perimeter1) 2(length+breadth)= 2(45)= 90cm2) 4* side= 4*15= 60cm |
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| 76367. |
- (2)A zinc sheet is of length 3.3 m and breadth 3 m. How many pipes of length30 cm and radius 3.5 cm can be made from this sheet? |
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| 76368. |
The inner radius of a metallic tube of density 10 gper cm3 is 7 cm. The thickness of the tube is0.35 cm. Find the weight of the tube if it is of length30 cm |
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Answer» Inner radius,r=7cmthickness=0.35 cmso,outer radius,R = 7+0.35=7.35 cmheight,h= 30 cmvolume=pi×(R^2-r^2)×h=22/7×(7.35^2-7^2)×100=22/7×(54.0225-49)×100=22/7×5.0225×100=11049.5/7 since,density=10 gm/cm^3also,weight=volume×densityweight=11049.5/7×10 =15785 g |
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| 76369. |
3. A chord of length 30 cm is drawn at a distance of 8 cm from the centre ofa circle. Find out the radius of the circle. |
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| 76370. |
Find the vatuc(s) of k for which the equation x2+5kx16mation a2 + 5kx + 16 0 has real and cqual roots. |
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| 76371. |
4. Find the zero of the polynomial in each of the following cases:(i) p(x)=x+5(iv) p(x) 3x -2(yil)p(x) = cr + d, cヂ0, c, d are real numbers.(ii) p(x)x-5(v) p(x)=3x(iii) p(x)-2x+5(vi) p(x) = ax, a # 0 |
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Answer» (1)x+5=0x=-5(2)x-5=0x=5(3)2x+5=0x=-5/2(4)3x-2=0x=2/3(5)3x=0x=0(6)ax=0, a is not equal to 0x=0(7)cx+d=0, c is not equal to 0,d is real numbercx=-dx=-d/c |
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| 76372. |
If the heignteQ5. A solid sphere of radius 10.5cm is melted and then recast into smallercones of radius 3.5cm and height 3cm. Find the numbers of cone so formed.d dinmeter 1 4cm, a |
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| 76373. |
9. A metallic sphere of radius 10.5 cm is melted and then recast intosmaller cones, each of radius 3.5 cm and height 3 cm. How many conesare obtained? |
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Answer» Volume of sphere = 4/3πr³= 4/3*22/7*10.5*10.5*10.5Volume of metallic sphere = 4851 cm³Now,Volume of one cone = 1/3πr²h= 1/3*22/7*3.5*3.5*3Volume of one cone = 38.5 cm³Total number of cones = Volume of metallic sphere/volume of one cone= 4851/38.5= 126 conesTotal number of cones can be formed is 126 |
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| 76374. |
4.If the points A(4, 3) and B(x, 5) are on the circle with cente 0(2, 3), find the value of x. |
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Answer» not full answer |
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| 76375. |
Solvex−3x+3+x+3x−3=212,x≠−3,x≠3 |
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Answer» x-3x+3+x+3x-3=2122x=212X=106Value of x is 106 |
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| 76376. |
hord of length 30 cm is drawn at a distance of 8 cm from the centea circle. Find out the radius of the circle. |
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| 76377. |
9. AOB is a straight line. Find .x and also determine the measure of each angle:(b) C(5x + 3°)6xr-9ă)2 |
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Answer» clear hai puestion |
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| 76378. |
\begin{array}{l}{\text { If } \frac{1}{a}+\frac{1}{b}+\frac{1}{c}=0, \text { where } a, b \text { and } c \text { are non-zero real }} \\ {\text { numbers, then } \frac{a^{2}+b^{2}+c^{2}-a b-b c-c a}{(a+b+c)^{2}} \text { is equal }} \\ {\text { to }}\end{array} |
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Answer» a square + b square + c square minus b square minus C square batha ghost a + b + c Quest square |
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| 76379. |
In the given figure, AOB is a straight line. IfZAOC 4x and LBOC-5x, thenZAOC?(a) 40°(c) 80°(b) 60°(d) 100°A |
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| 76380. |
If the tangent at the point P on the circlex^{2}+y^{2}+6 x+6 y=21at a point Q on the y-axis, then length of PQ is(A)42 mects the straight line 5x -2y +6 0(B) 215(C) 5(D) 345 |
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| 76381. |
Write the equation of a line which is parallel to x-axis and isat a distance of 2 units above x-3axis. Aiso draw the graph |
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| 76382. |
and aiso ina the value or p sueh that yp-2A metallic solid sphere of radius 10.5 cm is melted and recasted into3.5 cm and height 3 cm. IHow many cones will be made?9.smaller solid cones, each of radius |
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Answer» Given:- a metallic solid sphere of radius 10. 5 cm is melted and recasted into smaller solid cones each of radius 3. 5 cm and height 3 cm. Let the number of small solid cones be n. ∴Volume of the sphere=n× Volume of each small solid cone=>n=Volume of the sphere/Volume of each small solid cone=>n=(4πr³/3)/(πr'²h/3)=(4×3.14×10.5³/3)/(3.14×3.5²×3/3)=126 ∴n=126 |
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| 76383. |
Draw the graphs of the lines Noy-1 and20th=8 . Shade the are a commed bythese two lines and the H-avis.AISO, sind this area . |
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| 76384. |
Show that the function f: R, R, defined by f(x)1Swhere R is the set of all non-zero real numbers. Is the result true, 1R, is replaced by N with co-domain being same as R,?is one-one and ontf the domai |
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| 76385. |
I. The relation fis defined by Cr)The relation g is defined by g(x)-3x .2s xS10Show that is a function and g is not a function |
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| 76386. |
smallest prime number |
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Answer» 2is the smallest prime number. 1 is considered to be neither prime nor composite. Negative numbers are not counted as prime numbers. Hence, the smallest number is2(just leave out 0). 2 is the smallest prime number who is the smallest prime number 2 is the smallest prime |
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| 76387. |
show that the following line are parallel2x-3y+7 and 12y=8x-5 |
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Answer» The following is the condition for the two lines to be parallel. |
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| 76388. |
5. Find the equation of the circle which has its centre at the point (3, 4) and touches the straight line5x +12y-1 0 |
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| 76389. |
100°In figure 3.9, measures of some anglesare given, Using the measures find thevalues of x, y, z5.40Fig. 3.9 |
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| 76390. |
100°In figure 3.9, measures of some anglesare given. Using the measures find the0y2140°values of t, y, z.Fig. 3.9 |
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| 76391. |
n ^ { 2 } + 19 n - 180 |
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Answer» please factorise it and give accurate answer |
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| 76392. |
How many paying stones, each measuring 2 1/2 m * 2 m are required to pave a rectangular court yard 30 m long and 16 1/2 m board? |
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| 76393. |
ofdeciial.Write the HCF of smallest composite number and smallest prime number.312nd |
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| 76394. |
1, What is the HCF of the smallest composite number and the smallest prime number ? |
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| 76395. |
1. Iff is a real function defined by f(x) = x2 + 7, findfind (t)-f(5) where t# 52. Write the domain1-5jer |
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Answer» f(t) = t² + 7and f(5) = (5)² + 7 = 25 + 7 = 32hencef(t) - f(5)/t - 5 = t² + 7 - 32/t - 5 = t² - 25/t - 5 = (t + 5)(t - 5)/t - 5 = t + 5 |
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| 76396. |
Find the equations of the lines which pass through (4, 5) and make equal angles withthe lines 5 12y 60 and 3x 4y+7.5.6. Find the erunti |
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| 76397. |
4. In figure 2.24, measures of some angles1 300are shown. Using the measures find themeasures of x and Zy and henceshow that line ㅙ line m50°Fig. |
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| 76398. |
\sqrt{7+\sqrt{7+\sqrt{7+\sqrt{7}}}} |
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Answer» suppose x=root(7+root(7+root(7)+.....))so x=root(7+x)so x^2=7+xso x^2-x-7=0so x=(1+root(1+28))/2 or (1-root(1+28))/2so x=(1+root(29))/2 or (1-root(29))/2 |
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| 76399. |
us) Gre, go, 300ROOd-250-200d -OSOn 2-Son = n/29+ (2-).ďSko109/20X200 + (203=0ESvexelGtoonS301400 tluso) |
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Answer» i need help with homework 1725 is the right answer s= 1725is the right answer |
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| 76400. |
Find the degree measures corresponding to the following radian measures(Use π-16(ii) 4iv) |
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