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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 78501. |
eiiven that.Sa-3b |
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Answer» A or b ka maan kase aaya equation 1 and 2 ko solve kro by substitution method |
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| 78502. |
Find three irrationalsa benveen |
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| 78503. |
ne lull marks in an examination is 600. If a student secures 78% markes he score?nan hafa TT |
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| 78504. |
Ashish lepw his howe at 20 nin toas mnls naninishthhis breatlast in auuotaerustich takesleave Kunal's howe to eac the |
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Answer» 7:20/ |
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| 78505. |
200+400+600+800+1000+200+400+600+800+1000 |
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Answer» 6000 is the most correct answer |
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| 78506. |
1o. A wall 15 m long, 30 cm wide and 4 m high is made of bricks. each measuringof the total volume of the wall consists of mortar, how many22 cm x 12.5 cm x 7.5 cm. Ifcm × 7.5 cm12bricks are there in the wall? |
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| 78507. |
UIIC TLI SI, 2O, 25,xample 33. The taxi fare after each km, when the fare is 15 for thend 8 for each additional km does not form an A.P. as the total fareeach km is 15, 8, 8, 8, . Is the statement true? Give reason.NCERT Erem |
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Answer» No, the statement is not ture as the total fare (in Rs.) after each km is given as: 15, (15 + 8), (15 + 2 × 8), (15 + 3 × 8),… . = 15, 23, 31, 39,… Let t1= 15, t2= 23, t3= 31 and t4= 39 Now, d1= t2– t1= 23 – 5 = 8 d2= t3– t2= 33 – 23 = 8 And d3= t4– t3= 39 – 31 = 8 As d1= d2= d3, therefore given list of numbers formed by taking total fares after each Km forms an AP. |
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| 78508. |
(v) The mean of first four natural numbers is(a) 2(b) 2.5(vi) The median of first eight natural numbers is(a) 4(b) 5 |
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Answer» The mean of first four natural numbers=1+2+3+4/4=10/4=2.5Option b is correct The median of first eight natural numbers (1,2,3,4,5,6,7,8)=4+5/2=9/2=4.5 |
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| 78509. |
If three distinct natural numbers are chosenrandomly from the first natural numbers, then theprobability that all three of them are divisible byboth 2 and 3, is |
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Answer» First 100 natural numbers? |
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| 78510. |
0 14: A man goes 150 m due cust and then 200 m due north. How far is he from the starting point'? |
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| 78511. |
nan goes 80 m due east and then 150 m due north.m the starting point? |
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| 78512. |
sound of 30 ticks with a frequency of 800 hertz. |
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Answer» iffguchh djxbdi Hicks issue ICU icy ICU Ori icy info occurs kid |
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| 78513. |
(42/105)*(20/49) |
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Answer» 42÷7=6 × 20÷5=4105÷5=21 49÷7=7 6÷3=2 × 421÷3=7 7 849 42/105* 20/496/105*20/72/35*20/70.16 |
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| 78514. |
A cuboid is 50 cm x 22 cm x 27 cm. What would be the sideof a cube having the same volume? |
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Answer» Given : Volume of cubiod = Volume of cube 50×22×27 = (side)³ (side) = cube root ( 50 × 22 × 27) side = 3 × cube root ( 1100) side = 3 × 10.32 side = 30.92 cm |
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| 78515. |
. How many wooden cubical blocks of side 25 cm can be cut from a log of wood of size 3 m x 75 cmx 50 cm. Assuming that there is no wastage? |
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| 78516. |
A train Covers a distance of 51 km in 45 min.how long will it take to run 221 km? |
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Answer» Time taken by train to cover 51 km is 45 min Time taken to cover 1 km = 45 / 51 km Time taken to cover 221 km = ( 45 / 51) * 221 = 195 min Therefore the train takes 3 hours and 15 min to cover 221km. Solution 2: Time taken by train to cover 51km = 45min So, 17km = 15min Then, 221/17 = 13 13 * 15 = 195min |
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| 78517. |
0Find the sum of all natural numbers from 1 to 200Dwhich are divisible by 5 Awhich are divisible by 3.P |
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| 78518. |
Q.27) Find the sum of all two -digit numbers which whendivided by 7 yield I as remainder.Q.28) Find the sum of all natural numbers between 100 and 200which are divisible by 4. |
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| 78519. |
A man goes 5 m in east and then 12 m in north direction. Find the distance from thestarting point. |
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| 78520. |
| 400 - 400 ग्राम की 15 डबल रोटियों का मूल्य 45 रु० है। 500 - 500 ग्राम की 18 डबल| रोटियों का मन्य ज्ञात करें। |
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Answer» 67.5 Rupees is the correct answer of your question |
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| 78521. |
A man goes 35m due to west and then 12m due to north. how far is he from the starting point? |
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| 78522. |
2. A man goes 80 m due east and then 150 m due north. How far is hefrom the starting point? |
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| 78523. |
A mangoes 20 m due west and then 15 m due North. How far is it from the starting point? |
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| 78524. |
The median of the following data is 525. Find x and y if the sum of all frequencies is 100.Classes 200-300 300-400 400-500 500-600 600-700 700-800Frequency 1622.172015 |
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| 78525. |
12.8 +500(vi) 18.08 + 4007. Divide:(i) 3.28 by 0.8(iv) 2.0484 by 0.18(vii) 21.976 by 1.64(x) 0.076 by 0.19(xiii) 28 by 0.56(ii) 0.288 by 0.9(v) 0.228 by 0.38(viii) 11.04 by 1.6(xi) 148 by 0.074(xiv) 204 by 0.17(ii) 25.395 by 1.5(vi) 0.8085 by 0.35(ix) 6.612 by 11.6(xii) 16.578 by 5.4(xv) 3 by 80 |
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| 78526. |
C335 3Sбзь:68 68 |
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| 78527. |
A playground is 38m 50 cm long and61 m 50 cm wide. Find:(a) the cost of levelling it at ? 40 per(b) the number of rounds along the boundary one should take to run 2 km |
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| 78528. |
A school auditorium is 50 m long and 30 m wide. This auditorium is surrounded by averandah 5 m wide on the outside of it. Find the area of the verandah. If tiles of 50x 50 cm are fixed on the verandah, how many tiles will be required?cm1i mr1 m lfacarnet is to he put in the middle |
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| 78529. |
7. A playground is 38 m 50 cm long and 61 m 50 cm wide. Find:(a) the cost of levelling it at 40 per m(b) the number of rounds along the boundary one should take to run 2 km |
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| 78530. |
ORIn an election contested between A and B, A obtained votes equal to twice the no. of persons on theelectoral roll who did not cast their votes and this later number was equal to twice his majority over B.If there were 18,000 persons on the electoral roll. How many voted for B. |
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Answer» Please like the solution 👍 ✔️ Let the number of people who did'nt voted be x. Now the number of people who voted = 18000-x Number of votes given to A = 2× x = 2x .......As per the queston Number of votes given to B = Total no. of voters -Total number of votes given to A.i.e. No. of votes given to B = [18000-x]-2xNow As given in the que., x is equal to the twice of majority got by A.Majority got by A = Total no. votes given to A-Total votes given to B.i.e. 2x-[18000-x-2x]So,x = 2{2x-[18000-x-2x]}x = 2{2x - 18000 + 3x}x = 2{5x - 18000}x = 10x - 360009x = 36000x = 4000So, No. of votes given to B = 18000-x-2x = 18000-4000-2×4000 = 18000-12000 = 6000 votes. |
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| 78531. |
(3)(d) 8,730of natural numbers upto 200 excluding those divisible by 5 is- --b)The sum(b) 41000td) ione(c) 16,000(a) 20,100(d) |
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Answer» The sum of the numbers from 1 to N is N(N+1)/2. The sum of the numbers from 1 to 200 is (200)(201)/2 = 100(201) = 20100 The sum of the numbers from 1 to 200 divisible by 5 is the sum of 5, 10, 15, ..., 200. This sum is 5 times the sum of the numbers from 1 to 40: 5(40)(41)/2 = 5(20)(41) = 4100. Since we want the sum of the numbers to 200 exclusive of those divisible by 5, we want 20100 - 4100 = 16000. |
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| 78532. |
18 The radius of a circular field is 15 m. Inside the field a path of 1 m widthfuns round it. Find the area of the field excluding the path |
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Answer» thank u so much dear |
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| 78533. |
A man goes 24 m West, again he goes 10 m North. Now at what distance is the man from his initialpoint?(A 34 m(C 26 m(B)17 m(D) 28 m |
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Answer» As man goes 24 West then 10 m North. This route forms right angled triangle with base b = 24 m, perpendicular p = 10 m and hypotenuse h =? Using pythagoras theoramh^2 = p^2 + b^2h^2 = 10*10 + 24*24h^2 = 100 + 576h^2 = 676h = 26 Therefore distance of man from starting point = 26 m (C) is correct option |
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| 78534. |
A man goes 10 m due east and then 24 m due north .find his distance from the starting point. |
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Answer» distance is 24m to west |
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| 78535. |
A man goes 10 m due east and then 24 m due north. How far is he from the starting point? |
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| 78536. |
CBSE 2012]O. A tent is in the shape of a right circular cylinder up to a height of 3 mand conical above it. The total height of the tent is 13.5 m and the radiusof its base is 14 m. Find the cost of cloth required to make the tent at theCBSE 200511rate of80 per square metre. Take π = 226.1 |
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| 78537. |
a) 3The angles of a triangle are in the ratio 2:3:4,b) 0c) 1then the angles in degrees (respectively) arec) 4060 80d) 26.h1 400 500 80ed) of these |
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| 78538. |
12. Using suitable identity evaluate:78 Ă 82 |
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Answer» 78 × 82 = (80 - 2)(80 + 2) = (80 - 2) = 6400 - 4 = 6396 |
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| 78539. |
evaluate the following by using suitable identity 799^2 |
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Answer» (799)^2 = (800-1)^2 Using identity (a-b)^2 = a^2 + b^2 - 2ab (800-1)^2 = (800)^2 +(1)^2 - 2*800*1 = 640000 + 1 - 1600 = 638400 + 1 = 638401 |
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| 78540. |
Ans.number of boys : number of girls = 4 : 5.e mean marks of 150 students in an examination was 60. The mean marks of boysrls was 55. Find the number of boys and number of girls inènce,15. Thfound to be 70 and that of the githe class.ils heno then |
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Answer» please do it in paper and then send ...I am not able to understand |
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| 78541. |
square mo8. The side of a square garden is 125 m long. A path 2 m 50 cm wide is Bulll listaeall around it. Find the area of the path. |
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| 78542. |
6. Whaeach piece?metres, what is its length. The area of a room is 65 m2. If its breadth is 516 |
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Answer» the length of the room I'd 12m |
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| 78543. |
7. Evaluate:(i) (-16) 12+(-16) 8(iii) (-19) (-25)+(-19) (-15)(v) (-105) = 21(vii) 0 =(-34)(ii) 25 % (-33) + 25 (-17(iv) (-47)*68 - (-47)3(vi) (-168) = (-14)(viii) 370 |
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| 78544. |
The mean weight of 60 students of a class is 52-75 kg. If the mean weight of 25 of51 kg, find the mean weight of the remaining students.them isThe mean of five numbers is 18. On excluding one number, the mean becomes 16. Findexcluded number. |
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| 78545. |
412 x 83 x 2²=(a) 2(b) 1(c) 4 |
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Answer» the correct answer is 14 =2×2×(1/4)=1 answer b) 1 is the correct answer 4^1/2 × 8^1/3 ×2^-2=(2)^2×1/2 × (2)^3×1/3 ×(2)^-2=2^1 ×2^1 ×2^-2=2^1+1-2=2^0=1 1 is correct answer hence option b is correct 1 correct answer for this question b is the right answer option (b) 1 is the correct answer to this question . 1 is the correct answer me 1 is correct answer of this question 1 is correct answer of this question 1 is correct answer of this question the correct answer is 4 2×2×1/4=1 is the correct answer 1 is the correct answer b is the correct answer.... option b is correct answer 1 correct answer for this question b aayega.............. the correct answer is 1 option b is the correct answer the correct answer is option number (b) 1 correct answer is option number (b) 1 (b) is a correct anwer two answer hoga........... B)1. is the right answer the correct answer is 1 1 is the correct answer 1 is the correct answer 1 is a correct answer 1 is the correct answer option number 1 is the right answer |
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| 78546. |
Solve the equations and find the value of x.\frac{3 x-2}{10}-\frac{x+3}{15}+\frac{4 x-7}{3}=x-1 |
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| 78547. |
right circular conical tent 11 persons can stay. For each person 4 sq meter space in these and 20 cu meter air are necessary. Determine the height of the tent put up exactly forl persons.a |
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Answer» As each person needs 4 sq.m space on groundSo 11 person will need 44 sq.m space on the ground.Therefore,Area of ground = 44sq.mπr = 44sq.mr = 44/π .......(1)and each person needs 20cu.m of airSo 11 persons will need 220 cu .m of airTherefore volume of tent = 220 cu.m1/3πr h = 220cu.m(1/3*π)*(44/π)*h = 220 ( from 1 )1/3*44*h = 220h = 220*3 / 44h = 5*3h = 15 cm Like my answer if you find it useful! |
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| 78548. |
student pass in Maths= 77%student pass in Hindi = 66%total student pass = 280total failed student = 13%how many total students are there =? |
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Answer» Let Total number of students = S Passed in Maths = 0.77 S Failed in Maths = S - 0.77S = 0.23S Passed in Hindi = 0.66 S Failed in Hindi = S - 0.66S = 0.34S Failed in Both = 0.13S Total Failed in Any subject = 0.23S + 0.34S - 0.13S = 0.44S Passed in both subject = S -044S = 0.56S 0.56S = 280 S = 280/0.56 S = 500 Therefore, total number of students are 500 |
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| 78549. |
12,4 412(i) Factorise: ay - ay(i) Evaluate using suitable identity (104) |
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Answer» If you like the solution, Please give it a 👍 |
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| 78550. |
vers for cans are stamped out of sheets of metal. How many square centimetreswhen the covers are cut from a square 5 cm wide? (Use 3.14 for rt)there, wheny square centimetres of waste material isf the shaded part. |
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