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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 78701. |
12. The uieuu13. The area of an equilateral triangle is 36/3 cm2. Find the perimeter of the triangle. |
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Answer» Area of equilateral triangle of side a = a²√3/4a²√3/4= 36√3a² = 36*4a= 12perimeter of equilateral triangle = 3a = 3*12 = 36 cm. |
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| 78702. |
13. The area of an equilateral triangle is 36/3 cm2. Its perimeter is(a) 36 cm (b) 12/3 cm (c) 24 cm (d) 30 cm |
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| 78703. |
3 x + 12 + 2 x = 6 x + 4 - x |
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| 78704. |
4 x ^ { 2 } - 12 x y + 9 y ^ { 2 } - 4 x ^ { 2 } y ^ { 2 } |
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| 78705. |
Show that the diagonals of a parallelogram divideit into four triangles of equal area.RDare two triangles on |
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| 78706. |
If two triangles have their corresponding angles equal, are they always congruent? If not,two triangles which are not congruent but which have their corresponding angles equal.draw |
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| 78707. |
15. A wire is in the shape of a square of side 10 cm. If the wire is rebent into a rectangle of lenge encloses more area and by how much?12 cm, find its breadth. Which figur6. A godown is 50 m lonơ 40 m broad and |
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| 78708. |
15. Prove that a median divides a triangle into two triangles of equal area.16. Show that a diagonal divides a parallelogram into two triangles ofequal area. |
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| 78709. |
. Theorem 6.3: lf in two triangles, corresponding angles are equal, then theirs corresponding sides are in the same ratio (or proportion) and hence the, triangles are similartwo |
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Answer» In ∆ ABC and ∆ DEF,∠ A = ∠ D∠ B = ∠ E∠ C = ∠ FLet us draw a line PQ so that DP = AB and DQ = ACSo, ∆ ABC ≅ ∆ DPQSo, ∠ B = ∠ P = ∠ E and PQ ll EF, because by making a similar triangle like ABC theline PQ bisects lines DE and DF in the same ratio. Hence,AB/DE=BC/DFSo, ∆ ABC ≈ ∆ DEF proved |
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| 78710. |
Mathematics for Class 820. A cylinder is open at both ends and is made of 1.5-cm-thick metal. Its external diameter is12 cm and height is 84 cm. What is the volume of metal used in making the cylinder? Alsofind the weight of the cylinder if 1 cm of the metal weighs 7.5 gHint. External radtus 6 cm, Internal radtus 45 rm |
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| 78711. |
50. A coin is tossed 300 times and we get head 136 times and tail 164 times. When a coin is tossedat random, what is the probability of getting (i) a head, (ii) a tail? |
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| 78712. |
A coin is tossed 100 times and tail is obtained 60 times. Now if a coin is tossed at ranis the probability of getting 'head'?4. |
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| 78713. |
Two dice are throwr simultaneously. Find the probability that the sum of the numbersappearing on the top of two dice is less than 10.Q10. |
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| 78714. |
wo different dice are tossed together. the probability(i) of getting prime number on each dice(ii) of getting a sum 9, of the numbers on the two diceQ10. TFindrom to 100 Find the probabil |
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Answer» On one dice prime numbers are 2,5 hence 4 possibilitiesAnd total numbers are 36probability=4/36=1/9Sum of 9(6,3),(3,6)(5,4)(4,5)Hence total 4 possibilities =4/36=1/9 is 3 not a prime number? |
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| 78715. |
(4.8)* + (3.2)* eเคฌเคน 5 18) (32)4+(3.2)2 |
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Answer» hit like if you find it useful |
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| 78716. |
20. Two dice are rolled together, what is theprobability that the total score on the two diceis a prime number?(A)5/121/313/361/2 |
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Answer» nice answer |
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| 78717. |
S6xample 31 Two dice are thrown simultaneously. Find the probability that the sum of thenumbers appearing on the top of two dice is less than or equal to 10. |
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Answer» Total number of outcomes when two dices = 6*6 = 36 Possible outcomes that sum is greater than 10= (5,6) (6,5) (6,6) Probability that sum is greater than 10 = 3/36 = 1/12 Then, probability that sum is less than or equal to 10 = 1 - 1/12= 11/12 |
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| 78718. |
9.Loot at the number pattern1x3-2x1 = 122 x 4 2 x 2 = 223 x 5 - 2 x 3 = 324 x 6 - 2 x 4 = 42Using this pattern.i) Write the next two lines.Find the relationship you observed.iii) Prove this relationship using algebra. |
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Answer» this is write answer (i) 5×7-2×5=5² 6×8-2×6=6²(ii)Relationship observed is 1² ,2²,3²,4²,5²,6² |
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| 78719. |
cm. Construct a right triangle having hypotenuse of length 5.6 em and one of whoseacute angles measures 30°p450 Ts this a right angled triangle? |
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| 78720. |
If the hypotenuse and a side of a right-angled triangle are equal to the hypotenuse :another right-angled triangle, then by which congruency criteria the two triangles are(a)ASA Property(b)SSS Property(c) SAS Property(d) RHS Pro |
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Answer» rhs is the name of the property According to Right-angle Hypotenuse Side (RHS) symmetry If the ratio of the hypotenuse and one side of a right-angled triangle is equal to the ratio of the hypotenuse and one side of another right-angled triangle, then the two triangles are similar. (d) is correct option side angle side property |
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| 78721. |
A convex lens of focal length 20 cm is placed incontact with a concave lens of focal leng 10 cmWhat is the focal length of this combins tion?5. |
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| 78722. |
15. What is the perimeter of the quadrilateral, if length of its four sides measure 5 em, 24 cm,310 cm and 1 cm?12 and 1152 |
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Answer» To find the perimeter add the length of all sides=16/3+9/4+12/10+17/15=16*4+9*3/12+6/5+17/15=64+27/12+6*15+17*5/16*6=91/12+90+85/9691/12+175/96=91*96+175*12/11*96=8736+2100/1056=10836/1056=903/88cm |
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| 78723. |
woodvolume of a soap cake is 160 cm. Its length and width are 10 em and 5 cm. Find its heightf 60 cm ofa metal weighs 1 kg, find the weight of a block of the same metal of the size 20 em by 1211. Thecm by 5 cmshower, 5 cm of rain falls. Find the volume of water that falls on 2 hectares of land. |
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Answer» Volume=160cm^3length=10cmwidth=5cmlength×width×height=volume10×5×height=16050×height=160height=160/50height=3.2cm Thank One question please 60cm cube=1kgthen metalof 240×5=1200cm=1200/60=20×1=20kgso weight=20kg Can you explain please |
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| 78724. |
(4) A coin is tossed 300 times and it is found that head comes up 225 times and tail 75times.If a coin is tossed at random, what is the probability of getting a tail? |
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Answer» The probability of getting a tail = 75/300as favourable event = 75and total event = 300then probability = 75/300= 0.25 Thank you |
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| 78725. |
5. A coin is tossed thrice. Find the probability that comes(1) three head (2) two heads. |
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| 78726. |
5.In the given figure, find the value of xкバー/v0 声ㄧㄧㄧㄧX.130° |
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Answer» In given fig.x + 90 = 130 As these are alternate angles due to parallel line property Therefore,x = 130 - 90x = 40° |
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| 78727. |
027) Two dice are thrown simultaneously. What is the probability that the total score is aprime number? |
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| 78728. |
Q.27) Two dice are thrown simultaneously. What is the probability that the total score is aprime number? |
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Answer» number of favorable events=15total number of possible outcomes= 6*6=36probability of getting a total score as a prime number= 15/36= 5/12 |
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| 78729. |
2-672actreure - a) 92 + y + 27-6212-132-320+20 1022.522 de= V0 312 4030ationaliseu - 4253 +5-4-2 & 2-I are factors of pe +50 +7shows that b r !4 7+3 Is – 7-355 4+ 556 find a li1 3+1sSimplify :-2-P+4 |
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Answer» V6/V2 +V3 + 3V2/V6- V3 - 4V3/V6+V2; V6/V2 + V3 × V2 -V3/V2 - V3=V6( V2-V3)/(V2)^2-(V3)^2=V6( V2+V3)/2-3=V6(V2 + V3)/-1; 3V2/V6+V3 × V6-V3/V6-V3= 3V2(V6-V3)/ (V6)^2-(V3)^2=3V2( V6-V3)/3; 4V3/ V6 + V2 x V6- V2/ V6- V2=4V3(V6-V2)/4; (V12-V18)/-1 + 3V12-3V6/3-V3(V4) =-V6+V12-V6-V12=0 7+3V5/3 + V5 x 3-V5/3- V5= 7+3V5(3-V5)/(3)^2-(V5)^2= 21+9V5-7V5-3(V3)^2/9-5 = 21+3V5-3(3)/4=21-9+3V5/4=12+3V5/4_(1) 7-3V5/3-V5 x 3+V5/3+V5= (7-3V5)(3+V5)/(3)^2-(V5)^2= 21+7V5--9V5-3(V5)^2/9-5 = 21-2V5-3(5)/4=21-2V5-15/4= 6-2V5/4___/___________(2); 12+3V5/4 - (6-2V5)/4= 12+3V5-6+2V5/4=6+V5/4 4/2+V3+V7; 4/2+V3+V7 x 2- V3+V7/2-V3+V7= 4(2-V3+V7)/(2)^2-( V3 + V7)^2 =8-4V3+4V7/4-3+7 = 8-4V3+4V7/1+7= =4(2-V3+V7)/8= 2-V3+V7/2 |
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| 78730. |
If the probability P(E)0.3, then findprobability not P(E). |
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| 78731. |
(b) 10 = 22) 10 |
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Answer» quotation is 5remainder is 0 |
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| 78732. |
a) 10b) 20c) 402. Volumes of a Cylinder and a Cone with same radii are in the ratioa) 1:2b) 2:1c) 3:1d) 1:3 |
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Answer» c) 3:1 Volume of cylinder = πr²h Volume of cone = (1/3) πr²h Volume of cylinder/Volume of cone = πr²h/(1/3)πr²h = 3/1 Ratio = 3:1 |
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| 78733. |
Construct a right-angled triangle whose hypotenuse is 6 cm long and one of the legsis 4 cm long. |
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Answer» excuse me sir I will ask now another question please tell that solution plsssssssssssssss plssssssssssssssssssssssssssssssssssssssssssss sir answer to the question |
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| 78734. |
Example 7:A rectangular block of ice measures 40 cm by 25 cm by 15 cm. Calculate its weightinif ice weighsof the weight of the same volume of water and 1 cm' of water weighs10g. |
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Answer» Solution : Dimensions of the rectangular ice block : Length ( L ) = 40cm Breadth ( B ) = 25 cm , Height ( H ) = 15 cm Volume of the ice block ( V ) = LBH = 40cm × 25 cm × 15 cm = 15000cm³ It is given that, 1 cm³ ice block volume = ( 9/10 ) cm³ water volume 15000 cm³ ice block volume = [15000cm³ × ( 9/10 ) cm³ ]/1cm³ [ Unitary method ] = 15000 × 0.9 cm³ = 13.5 × 1000 cm³ = 13.5 × 1000 g [ 1 cm³ = 1 g ] = 13.5 kg hit like if you find it useful |
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| 78735. |
6. A hemisphericaltank is made up of an iron sheet l cm thick. lf the inner radius istheĹ find the volume of the iron used to make the tank. |
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| 78736. |
Ans. (B)(ii) The focal length of a lens of power + 2D is :(B)50 cm(D) -2 cm(A) +50 em(C) +2m |
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| 78737. |
53. CP and CQ are tangents to a circle with centre O. ARB is another tarncircle at R. If CP 11 em, BC-7 em, then the length BR is:f ((A) 11 cnm(B) 7 cm(C) 3 cm(D) 4 cm |
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| 78738. |
:5 cm6 cmIV1.5 cm6.5 emi1 cm1 em Il2 cm |
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| 78739. |
9. Write the prime factorisation of 15470. |
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Answer» The number15470is a composite number so, it is possible to factorize it. The prime factorization of15470= 2•5•7•13•17. The prime factors of15470are 2, 5, 7, 13 and 17.Like if you find it useful |
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| 78740. |
, Ifİis the probability ofan event, what is the probability of the event "notAprobability of the event 'not A |
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Answer» The probability of even not A is 1-A=1-2/11=9/11 |
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| 78741. |
2On tossing a coin 1000 times, head comes 425 times. Find the probability of getting a tail in this event. |
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Answer» Coin is tossed 1000times and head comes 425 times, then tail comes 575 times. Probability of getting tail in this event is, 575/1000=23/40 Like my answer if you find it useful! |
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| 78742. |
A) Do the following activities.(Anytwo)(4)One coin and one die are thrownsimultaneously. Complete the activityfor the probability of following events.Sample space, S1)n(S)Event A: To get a head and an odd number.PA n(A)lotn the following activity to find |
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Answer» Sample space, S = (H, T, 1, 2, 3, 4, 5, 6)n(s) = 8 Event A : To get Head and Odd numberA = (H, 1, 3, 5)n(A) = 4 P(A) = n(A)/n(S) = 4/8 = 1/2 thanks |
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| 78743. |
If the probability of an event is \root 0.25, then the probability of the event is |
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Answer» probability of the even = √0.25= 0.5 |
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| 78744. |
If the probability of an event to happen isfind the probabilityfor the event not to happen. |
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Answer» Probability of an event to happen = 3/5Probability for event not to happen= 1-3/5(5-3) /52/5 |
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| 78745. |
25XX 13-(A) 4(B) 3t on Y83 Produal camera(C) 99(D) 03 |
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Answer» 2/5 × 13 × 3/5 × 13 - 10 = 1014/25 - 10 = (1014-250)/25 = 764/25 |
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| 78746. |
which is the required ratio.Example 5. Prove that the area of the equilateraltriangle described on the side of an isosceles rightangled triangle is half the area of the equilateraltriangle described on its hypotenuseCBSE 20 |
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| 78747. |
how that the points A(7, 10), B(-2,5) and C(3,-4) are the vertices of anisosceles right-angled triangle. |
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Answer» thank you |
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| 78748. |
Find the length of the hypotenuse of an isosceles right-angled triangle whose area is 200 m2.nd its perimeter. [Take-d2 = 1.414] |
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Answer» since the triangle is isoscelesthen the base and the altitude will be samelet the base and the altitude be xarea=1/2x^2=200x=20mhypotenuse=√20^2 +20^2 =20√2=28.28m |
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| 78749. |
• Marks Questions12. If A and B are two independent events such that. PLACINSPAB) =then find P(A) andPBDelhi 2015 |
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| 78750. |
State whether the following quadrilaterals are similar or not3 cm3.(CyS 1.5 cm R3 cmem1.5 c1.5 cmP1.5 cm3 em |
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