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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 80351. |
7. Answer any one question :ଯେକୌଣସି ଗୋଟିଏ ପ୍ରଶ୍ନର ଉତ୍ତର ଦିଅ :(a) Find the inverse of the following matrixusing elementary transformation:112 371214110 21201 Continuad |
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Answer» 1(2)-2(2×4)+3(1)2-2(8)+32-16+3-14+3-11 |
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| 80352. |
Q.3 A suitcase with measure 1 m x 60 cm x 30 cm is to be coveredwith tarpaulin. How many metrequired to cover 100 such suitcases?res of tarpaulin of width 96 cm are |
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| 80353. |
Ir the th term of an AP is g and is th ter19, Tmof an AP is q and its qth term is p then show that its(p+q)th term is zero. |
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| 80354. |
Underline the given placevalue:a. 54.128 (tenths)b. 9,841.2 (ones)c. 51.9274 (hundredths)d. 830.1596 (thousandths) |
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Answer» a) 5"4".128b) 9,84"1".2c)"0"51.9274d)"0"830.1596so, its 4, 1, 0 and 0 |
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| 80355. |
4) Select one solution of theequation 2 x - y = 4*(x,y) = (1,-2)O (x) 1,)(x,y) =(-2,1)O x)(x,y) = (1,1)Ο Ο(x,y) = (1,0) |
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Answer» (x,y) ===(1,2) yahi answer hai equal. 2x-y=4put (x, y) =(1,-2) L. H. S. = 2*1-(-2) =2+2 =4 R. H. S. =4 L. H. S.= R. H. S. equal. 2x-y=4put ( x and y) = (1 and -2) L.H.S. =2×1-(-2) =2+2 = 4R.H.S.= 4L.H.S. = R.H.S. hope this will help you 😊😊😊 1st option is the right answer. x=1. y=-22*1-(-2)=2+2=4so (x,y)=(1,-2) (x, y) =(1,-2) is the solution first option is the right answer some printing mistake in that question correct ans is x=2 and y=0 2x−y=6 2x=6+y (A)(3,0) LHS=2x−y =2(3)−06=6RHS (3,0)is a solution (B)(0.6) LHS=2xy⇒2(0)−6⇒−6=RHS (o,6)is not a solution (C)(2,−2) LHS2(2)−(−2)⇒6⇒RHS (2,−2)is asolution (D)(3,0) LHS:2(3)−(0)=23=RHS (3,0)is not a solution (E)(21,−5) LHS:2(21)−(−5)⇒1+5⇒6=RHS (21,−5)is a solution. correct ans is 1,-2 put the value of x and y in equation 1 st option is the ans 1st questions is right |
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| 80356. |
construct a triangle PQR in which QR=6cm angle QR= 60° and PR-PQ=2 |
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| 80357. |
.An aeroplane flying horizontally at a height of 2500 m above the ground is observed at anelevation of 60°. If after 15 seconds, the angle of elevation is observed to be 30°, find thespeed of the aeroplane in km per hour. |
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| 80358. |
2x + 1), 3x and (4x + 2) are first three terms of anAP, then find its 5th termFind the first negative term of the sequence 2000,1995, 1990, 1985,6. If (7.2 |
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| 80359. |
e first and thrice5. Find two numbers such that the sum of twice the firstsecond is 92, and four times the first exceeds seven times the secondtheby 2. |
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| 80360. |
A bus travels at y km per hour It is going from Daspur to Beespur. After thebus has travelled 5 hours, Beespur is still 20 km away. What is the distancefrom Daspur to Beespur ? Express it using y |
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Answer» Distance travelled by the bus in 1 hour = y km Distance travelled in 5 hours = 5y km So, total distance from Daspur to Beespur = Distance travelled in 5 hours + 20 = 5y +20 km |
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| 80361. |
IDIRODLCISA train takes 8 hours to cover a distance of 1808 km. How much distancedcover in 1 hour? |
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Answer» 226 km is the answer of the following 226 is the answer of the question Distance covered in 8 hrs = 1808 kmSo, distance covered in 1 hr = 1808/8 = 226 km 226 km is right answer 226 km is the correct answer of the given question 226 km in one hour, this is right answer it cover 226 km in one hour 226km in one hour, this is right answer a train cover 226 km distance in 1 hour 226 k.m in one hour is the right answer. it cover 226 km in one hour |
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| 80362. |
to travel some distance. WhatA car with speed 60 km/hr takes 8 hours to travel some distanashould be the increase in the speed if the same distance is to be covered in7 hours?biel |
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Answer» it should be increased 4km/h car speed -60 km/hrtime taken-8hrdistance = speed× time d = 60 × 8 = 480 time 15/2same distance = time × speed480 = 15/2 × speed 480×2 =15 ×speed 960 /15 = speed64 km/hr speed |
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| 80363. |
7h mahed Price of a booh乏225. Tu publisher okus15dsountoret . Find te sellprice on it. |
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Answer» Price of the book = 225Discount = 10%i.e. , 225 / 10= 22.5 rs.Selling price = ( 225 - 22.5) The selling price is = rupees 202.5 |
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| 80364. |
5. The dimensions of an almirah are 1 m x 60 cm x 2 m. It has been dividedin 4 compartments partitioned by three shelves made of 4 cm thick wood.What is the volume of each compartment?HOTS |
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Answer» Length and breadth of each compartment is same.Let height of one compartment is x.So, x+x+x+4+4=2003x+8=2003x=192x=64So volume of each compartment=100*60*64=384000cm^3=3.84m^3 |
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| 80365. |
Findtheareaofanisoscelestrianglewith two equal angles of 45 eachand two equalsides of length 20 cm. |
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| 80366. |
Using elementary transformin Exercises 1 to 17.\left[ \begin{array}{rr}{1} & {-1} \\ {2} & {3}\end{array}\right] |
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Answer» right answer is 5 thank you what we have to in this given question. please post full question. |
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| 80367. |
term of an A.P. is q and its qth term is p, show that its rth termis ptq-r. What is its (p + q)th term? |
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Answer» So ar = p+q-r Hence proved. |
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| 80368. |
n fig. (2) AB is a chord of length 8 cmcirle ofsect at P. Find thof a cirele of radius 5 cm. The tangents to the5 emciTO 8 cmFig.(2)QRnl noint to a circle are equal. |
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Answer» Step-by-step explanation: Given radius, OP = OQ = 5 cm Length of chord, PQ = 4 cm OT ⊥ PQ, ∴ PM = MQ = 4 cm [Perpendicular draw from the centre of the circle to a chord bisect the chord] In right ΔOPM, OP2 = PM2 + OM2 ⇒ 52 = 42 + OM2 ⇒ OM2 = 25 – 16 = 9 Hence OM = 3cm In right ΔPTM, PT2 = TM2 + PM2 → (1) ∠OPT = 90º [Radius is perpendicular to tangent at point of contact] In right ΔOPT, OT2 = PT2 + OP2 → (2) From equations (1) and (2), we get OT2 = (TM2 + PM2) + OP2 ⇒ (TM + OM)2 = (TM2 + PM2) + OP2 ⇒ TM2 + OM2 + 2 × TM × OM = TM2 + PM2 + OP2 ⇒ OM2 + 2 × TM × OM = PM2 + OP2 ⇒ 32 + 2 × TM × 3 = 42 + 52 ⇒ 9 + 6TM = 16 + 25 ⇒ 6TM = 32 ⇒ TM = 32/6 = 16/3 Equation (1) becomes, PT2 = TM2 + PM2 = (16/3)2 + 42 = (256/9) + 16 = (256 + 144)/9 = (400/9) = (20/3)2 Hence PT = 20/3 Thus, the length of tangent PT is (20/3) cm |
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| 80369. |
/5 marks each]The diagonals PR and QS of OPQRS intersect inpoint O.Prove: (1) PQQR+RS+ PS> PR+QS(2) PQ QR + RS+ PS <2 (PR +QS) |
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Answer» Where is the figure? |
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| 80370. |
ss the following speeds in metres per second:(a)36 km per hour(b)60 km per hour |
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| 80371. |
at 12 kin per hour using a tonga. What is the man's avelaA car can travel the distance between the home and the othceare 1.2 km apart, inKomlhHow much faster must it travel to do the distance in 1.5 minutes? |
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Answer» Speed of car in 1.8min traveling =1.2/1.8 = 0.67km per min.speed required if it travels distance in 1.5 min =1.2/1.5 = 0.8km per min. now how faster it should travel to do distance in 1.5 minutes = speed in 1.5min traveling -speed in 1.8min traveling = 0.2km per minute It should travel 0.2km per minute faster |
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| 80372. |
Speed of a cycle 15 km per hour to the speed of scooter 30 km per hour |
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| 80373. |
7. Pratik takes 8 hours to travel 36 km downstream and return to the same spot. The, speed of boat in still water is 12 km. per hour. Find the speed of water current. |
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Answer» Speed downstream = 12 +xSpeed upstream = 12-xNow36 + 36------ ------ = 812+ x 12- xSolving this we get x = 6 = speed of water current |
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| 80374. |
in an A. P. the 10h term is 46, sum of the Sth and 7h term is 52. Find the A.P. |
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| 80375. |
mnle21 If p", qth, rth and sth terms of an A.P. are in G.P, thenIf pg). (q-n.-s) are also in G.P |
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| 80376. |
24, lf sect. tan θsec θ+tan θthen find sin 04 |
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| 80377. |
ame the oldest and the most traditional form of public sectonterprise,Q.1. N |
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Answer» Departmental undertakings are theoldest and most traditional formof organisingpublic sector enterpriseswhich are established as departments of the ministry and are considered part or an extension of the ministry itself. Please hit the like button if this helped you |
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| 80378. |
5. In adjacent figure, PR >PQ and PS bisetsect5.ZQPR. Prove that PSR> LPSQ |
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| 80379. |
A man walks from his home to a town 6 km away at 4 km per hour and returns again to his homeat 12 km per hour using a tonga. What is the man's average speed for the double journey? b KA car can travel the ist |
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Answer» D=6kms1=4kmphs2=12kmpht1=6/4=1.5st2=6/12=0.5saverage speed=6×2/1.5+0.5=12/2=6kmph hit like if you find it useful |
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| 80380. |
. IV. Solve. (any two)2x3=61. An aeroplane leaves an airport and flies due north at aspeed of 1000 km per hour. At the same time, anotheraeroplane leaves the same airport and flies due westspeed of 1200 km per hour How far apart will be the twolanes after 1 /2 hoursat a |
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| 80381. |
6. If you can cycle at an average speed of 12 km per hour, how many km can you cycle45 minutes? |
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Answer» 45 minutes=45×1/60 he=3/4hrdistance covered =speed ×time. =12×3/4 km =9km |
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| 80382. |
3. Obtain ll thet zeroes of36x2-10s-5,if two of its zeroes areand-On dividing3r+ 2 by a polynomial gtx), the quotiept and remainder were x-2d-2x4, respectively. Find g(r). |
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| 80383. |
Bills PTotalClosinPartice(III) FLAL= 2,77,500Nilustration 13:The Balance sheet of Waridhi Ltd. as on 31st March, 2014 was as underBalance Sheet as on 31-03-2014LiabilitiesAssets10,000 -8% Preference Share ofFreehold Premises3,00,00010 each fully paid1,00,000 Plant3,00,00025,000 Equity Shares ofFurniture2,00,00010 each fully paid2,50,000 Motor Car50,000Securities Premium3,00,000 Stock2,50,000General Reserves4,00,000 Debtors3,50,00010% Debentures2,00,000 Cash50,000Accounts Payable2,50,00015,00,00015,00,000The Company earned profits (after tax) for the past five years as follows:Year ended Profit after tax (3) Income tax rate31-03-2010 1,80,00040%31-03-2011 3,38,00035%31-03-2012 3,64,00035%31-03-2013 2,60,00035%31-03-2014 4,20,00030%he Profit of 31-03-2010 included loss due to fire 30,000 and profit of 31-03-2013 included abnonarofit of 40,000.(lv) S.(V) G7.7.1NormSomecomp1. Sa12 saa) As on 31-03-2014 Fixed Assets were worth 10% above book value.5) Income tax rate for the future may be taken at 30% |
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Answer» what is your question which question I can solve I solve this question all please like my answer then I like your answer |
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| 80384. |
The string of a kite is 100 m long and it makes an angle of60° with the horizontal. Find the height of the kite, assumingthat there is no slack in the string. |
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| 80385. |
5.first number is 9 times the second(Ans. 63. 746. The product of the first and second terms of u G. P. is 256 andthat of second and third terms is 16. Find its Sth tenn.(Ans. |
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Answer» what is your question 1/8 is the right answer |
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| 80386. |
If three numbers are added, their sum is2'. If 2 times the second number issubtracted from the sum of first and thirdnumber we get '8' and if three times thefirst number is added to the sum of secondand third number we get 4'. Find the14 Marksnumbers using matrices. |
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Answer» no it is not like that |
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| 80387. |
15. ARB represents a semicircular plate where AB14 cm. A semicircle ASO is cut away. (O is the :mid-point of AB). What is the area of the remaining portion? (Take 7Fig. Q. 15 |
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| 80388. |
(xi)2. Chetk whetler the valte given in the brsekets is a solation to the given equntiotor ot3. Solve the following equations hy trial and error method0 Sp + 2-17Wřite equations for the following statements(i) The sum of numbers tand 4i5% (ii)(ii) Ten times a is 70(v) Three-fourth of s is 15() 3- 14 44.2 subtracted from v is 8.,(iv) The numbet b divided by 5 gives 6(vi) Seven times m plus 7 gets you 77(vi) One-fourth of a number x minus 4 gives 4(vii If you take away 6 from6 times y, you get 60.(ix) If you add 3 to one-third of. you get 305. Write the following equations in statement forms:3m |
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Answer» again show the answers.please sir |
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| 80389. |
. Mary cycles at 6 km per hour. Howlong will she take to reach her Aunt'shouse which is 12 km away? If shecycles at a speed of 4 km/hr, how longwould she take ? |
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Answer» Given:Speed= 6 km/hrDistance= 12 kmFormula: distance= speed* time Solution:Time=12/6=2 hr.Thus she takes 2 hrs to reach at the speed of 6km/hrIf she cycles at the speed of 4 km /hrTime= 12/4= 3 hrsThus at the sped of 6km/hr time = 2 hrsand at the speed of 4km/hr time = 3 hrs |
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| 80390. |
Set 383. Mary cycles at 6 km per hour. Howlong will she take to reach her Aunt'shouse which is 12 km away? If shecycles at a speed of 4 km/hr, how longwould she take? |
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Answer» thank you |
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| 80391. |
Mary cycles at 6 km per hour. Howlong will she take to reach her Auntshouse which is 12 km away? If shecycles at a speed of 4 km/hr, how longwould she take ? hou ea / 3 hour |
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Answer» Mary's speed, S = 6km/hDistance, D = 12 kmD = S×TT = D/S = 12 km/(6km/h)= 2kmShe takes 2 hours to reach her Aunt's housewith speed 6 km/h |
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| 80392. |
5. Draw a double bar graph for the given data.Year/Number of students School A School B d200920102011201220131,0001,150 1,2001,2001,2501,300 1,3001,500 1,45090012. |
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| 80393. |
find the three consecutive number whose sum is 72 |
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Answer» thank thank friend |
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| 80394. |
. A number is 4times the another number. By sulbtracting 3 from each number, the first number becom5 times the second. What are the two numbers? |
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| 80395. |
The string of a kite is 100m long and it makes an angle of 60' with the horizontalFind the height of the kite, assuming that there is no slack in the string5. |
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Answer» String of kite is 100 m longAngle between horizontal and string is 60° Let height of kite be hThen,sin 60° = h/100sqrt(3)/2 = h/100h = 50*sqrt(3) Therefore height of kite= 50.sqrt(3) m |
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| 80396. |
one-third 01 a number10. A number istimes another number. If their sum is 104, find thenumbersA |
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Answer» thanks 💐👍☺️ didi please answer my new question |
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| 80397. |
1 Three times a number increased lafee times another number in 49 butSlunce the second number exceedsfive times the first number by oneO, what are the numbers ? |
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Answer» Let x = "a number"Let y = "another number":Write an equation for each statement::"three times a number increased 5 times another number is 49"3x + 5y = 49:"twice the second number exceeds 5 times the first number by 1."2y = 5x + 1In standard form-5x + 2y = 1:what are the numbers?:Multiply the 1st equation by 5, and the 2nd equation by 315x + 25y = 245-15x + 6y = 3-----------------Adding eliminates, x; find y:0x + 31y = 248:y =248/31y = 8:Find x using the 1st equation3x + 5(8) = 493x = 49 - 40x =9/3x = 3 |
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| 80398. |
Take a number ab. Double it and add 18 to the result. Take away 10 and divide it by 2. Take away 4Now, what do you get and why?5. |
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Answer» number=abAccording to condition;double it and add 18equation becomes:2ab+18now,take away 10 and divide by 2equation:(2ab+18-10)/2 =(2ab+8)/2 =ab+4 now take away 4equation: ab+4-4 =abso,at the end we are left off with ab because all the other terms got nullified. Thank you |
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| 80399. |
take away 599 from 6000 |
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Answer» 6000 - 599 = 5401 |
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| 80400. |
2. (a) Take away 15 from 45.................... |
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Answer» That means you have to subtract 15 from 45so 45-15= 30 |
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