InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 80301. |
The sum of the age of a man his son is 45 years. Fiveyears ago, the product of their ages was four timesthe man's age at that time. Find their present ages.2. |
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Answer» can't see full . |
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| 80302. |
Find the equation of a straight line passing through origin and making an angle of120° with the positive direction of x-axis. |
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Answer» m=tan120°y=mxy=tan120xy=tan(90+30)Xy=-1/√3x |
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| 80303. |
229. Five years ago, a woman's age (in year) was the square of her son's age. Ten years later from now, her agevill be twice that of her son's age. find.(a) The age of the son five years ago.(b) The present age of the woman.anaf work If both A and B together can finish it in 4 days, fv |
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Answer» a) the age of the son is 15 years old b) the present age of women is 45% |
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| 80304. |
\left. \begin{array} { l } { ( 12 x y + 3 x ) - ( 14 x - 4 x y ) } \\ { ( 9 x ^ { 2 } - 7 x ^ { 2 } z + 8 x z ^ { 2 } ) - ( 11 x ^ { 2 } z - 12 x ^ { 2 } + 2 x z ^ { 2 } ) } \\ { ( 23 x ^ { 2 } - 34 y ^ { 2 } ) - ( 34 x y - 29 x ^ { 2 } ) } \\ { ( 5 x ^ { 2 } + 3 y ^ { 2 } - x y ) - ( 4 x y - 5 x ^ { 2 } - 3 y ^ { 2 } ) } \end{array} \right. |
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Answer» 1.12xy+3x-14x+4xy=16xy-11x2.9x^2+12x^2+8xz^2-2xz^2-7x^2z-11x^2z=21x^2+6x^2-18x^2z3.52x^2-34xy-34y^24.10x^2+6y^2-5xy |
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| 80305. |
11. The value ofa machine depreciates 10% annually. Ifts present value is18,000. What was its value 1 year ago ?(n) What will be its value after Iyear? |
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Answer» suppose previous year value is xso present value is 0.9x (10% depreciation)so 0.9x=18000so x=20000 and next year it will be 18000*0.9=16200 Ty |
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| 80306. |
Find and correct the errors in the following\begin{array}{l}{4(x-5)=4 x-5} \\ {x+2 x+3 x=5 x} \\ {(2 x)^{2}+4(2 x)+7=2 x^{2}+8 x+} \\ {(3 x+2)^{2}=3 x^{2}+6 x+4}\end{array} |
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| 80307. |
\left. \begin{array} { l } { a b ( x ^ { 2 } + y ^ { 2 } ) + x y ( a ^ { 2 } + b ^ { 2 } ) } \\ { x ^ { 5 } + x ^ { 4 } - 2 x ^ { 2 } - 2 x } \\ { a b ( c ^ { 2 } + 1 ) + c ( a ^ { 2 } + b ^ { 2 } ) } \\ { x ^ { 2 } + \frac { 1 } { x ^ { 2 } } + 2 - 3 x - \frac { 3 } { x } } \end{array} \right. |
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| 80308. |
VISUALISING SOLID SHAPES159For each given solid, identify the top view. Tront view and side view.Topd -SideFront |
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| 80309. |
Raman a painter, always donated one-fifth of his income to an orphanage.Once he got a contract of painting a house having three rooms of dimensions10m x 12m x 3.5m, 8m x 6m x 3.5m and 7m x 5m x 3.5m. He charged 30 per mfor his work.(a) How much money did Raman earn? |
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Answer» D so well Yanni to be able to do number of This is a answer of that sum 8,643,870. answer: 8643870the answer is give above (a) 1670 (b)3234 is answer your question b is the best answer 8643870 :answer a)16170b)3234 Rs 22260 is the answer rs 22260 is the answer to your question These is a answer of that sum is 8,643,860.is the correct answer This is a answer of that sum is8,643,870.please like my answer a)16170b)3234is the best answer a) 16170 and b)3234 is the best answer 8643870 is the right answer 16170 is the answer of this question 161703234is the right answer a) 16170b) 3234is the right answer the correct answer is 16170 This is a answer of that Sum 8,643,870. 3234 is the best answer , gcjucyckcgxhvhxjnn, bxi, gzjcgXkc😅🥰 3234. is a 16170 b 3234 is the answer this is the answer II of that sum 8643870 answer . 8643870 the answer is give above answer: 8643870 the right answer is give above sum is of that answer is 8643870 |
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| 80310. |
11.Draw the top view, front view and side view of the figure given below.3 f3.0Section D |
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| 80311. |
The area of a square whose side is a diameter of a circle of area 4sa) 2s2b) 4sc) 1682is |
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Answer» the area of square whose side is a dimeter of a circle of area 4s^π is answer is 16s^2 right answer is 16s^2 of the following question 16s^2 is right answer of this question |
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| 80312. |
POLYNOMIALSEXERCISE 2.2Find the zeroes of the following quadratic polynomials and verify the relationship betweenthe zeroes and the coefficients.1.(ii)4s -4s +1(ii) 6x2 -3-7x(vi) 3x2-x-4 |
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| 80313. |
EXERCISE 2.2I. Find the zeroes of the following quadratie polynomials and verify the relationship betweenthe zeroes and the coefficients.(i) 4s-4s +1(v) -15(ii) 6x2-3-7x(vi) 3x2-x-4(iv) 4u2+ 8uIV |
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| 80314. |
. In the given figure, a circle with centre 0 isgiven in which a diameter AB bisects the chordCD at a point E such that CE-ED 8 cm andEB 4 cm. Find the radius of the circle. |
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| 80315. |
Sum of the present ages of two friends are 23 years, five years ago productof their ages was 42. Find their ages 5 years hence. |
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Answer» Let the ages of friends 5 years ago be X , Y ATQ: 5 years ago, X * Y = 42 ...(i) Now, X +5 + Y+5 = 23 X + Y = 13 .... (ii) X = 13-Y ...(iii) (iii) in (i) (13-Y)*Y = 42 13Y - Y² = 42 Y² - 13Y + 42 = 0 Sum = -13 && product = 42 Numbers are -6,-7 Y² - 6Y - 7Y +42 = 0 Y(Y-6) -7(Y-6) = 0 [Y-6][Y-7] = 0 Y = 6 or Y =7 When Y = 6, X = 7 Y = 7, then, X = 6 Ages 5 years ago = 6,7 tq |
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| 80316. |
b) Sum of the present ages of two friends are 23 years, five years ago productof their ages was 42. Find their ages 5 years hence. |
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Answer» Let present of first friend be xThen, present age of second friend = 23 - x Five years ago:First friend age = x - 5Second friend age= 23 - x - 5= 18 - x As per given condition (x - 5)(18 - x) = 4218x - x^2 - 90 + 5x = 42x^2 - 23x + 132 = 0x^2 - 12x - 11x + 132 = 0x(x - 12) - 11(x - 12) = 0(x - 11)(x - 12) = 0x = 11, 12 After 5 years there ages are16 years and 17 years |
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| 80317. |
Fi nd the value ofCRO ROX? |
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Answer» Any non zero number raised to the power of zero is equal to 1. Therefore the answer is 0. |
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| 80318. |
dratic Equations4.19EXA1IPLE (7) Solve the quadratic equation 2x2 +ax-a2 =0, for x |
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| 80319. |
3. If-1 is one root of quadratic equation 2x2 + kx= 0, find k.2 |
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| 80320. |
15. Find the equation of the straight line passing through the point (2, 1) and bisectingthe portion of the straight line 3x-5y15 lying between the axes. |
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| 80321. |
\operatorname { tan } 2 x = \frac { 2 \operatorname { tan } x } { 1 - \operatorname { tan } ^ { 2 } x } |
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Answer» tan(x+x) = tan(x) + tan(x) ---------------------- 1- tan(x) × tan(x) tan(2x) = 2tan(x) ---------------------- 1- tan²(x) |
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| 80322. |
\left( 1 \frac { 1 } { 2 } + 11 \frac { 1 } { 2 } + 111 \frac { 1 } { 2 } + 1111 \frac { 1 } { 2 } \right) = ? |
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| 80323. |
ementaryhe given c and BD when produced meet at P. Prove that APB istantre, AB is a diameter of a circle (o, r) and chord CDfigure, AB is aOC IFAC and BD whe |
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| 80324. |
23. From the window (9 m above the ground) ofhouse in a street, the angles of elevation ardepression of the top and foot of another house cthe opposite side of the street are 30° and 6C10ηrespectively. Find the height of the opposite housand width of the street. (Use 3 1.732) |
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| 80325. |
Two years ago, Ritu was three times as old as her daughter and two years hence, twice her age will be equal to five times that of her daughter. What is the sum of the present ages of Ritu and her daughter? |
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Answer» suppose Ritu's age is R and her daughter's age is D R - 2 = 3(D - 2) R - 2 = 3D - 6 R = 3D - 4 2(R + 2) = 5(D + 2) 2R + 4 = 5D + 10 2R = 5D + 6 2(3D - 4) = 5D + 6 6D - 8 = 5D + 6 D = 14 R = 3*14-4 = 42-4 = 38 R + D = 38 + 14 = 52 |
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| 80326. |
2. Find the discriminant of the fiequation and hence find the(1) 2x2 - 16x + 30 = 0 (ii) |
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| 80327. |
98. \left(1 \frac{1}{2}+11 \frac{1}{2}+111 \frac{1}{2}+1111 \frac{1}{2}\right) बराबर |
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| 80328. |
Example 16: Find the discriminant of the quadratic equation 2x2 - 4x + 3 = 0, andhence find the nature of its roots. |
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| 80329. |
3. In the adjoining figure, AOB is a straight line.Find the value of x. Hence, find ZAOC, ZCODand ZBOD(x+A0 |
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Answer» AOB is straight lineso 3x+7+2x-19+x=1806x=192so x=32so AOC=3x+7=103COD=2x-19=45BOD=x=32 |
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| 80330. |
and y-1 111+81+12-1Showthat -tan2x=cos |
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| 80331. |
II. Answer ANY TEN of thefllowinequestiS.11. If A and B are two disjoints sets and n(A)-15 and n(B)-10 find n(AUB),n(AnB)t y is primel and R-lxe N. x is evenI write AnB |
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Answer» A and B are disjoint setsso n(A intersection B)=0so n(A U B)=n(A)+n(B)=15+10=25 |
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| 80332. |
ITT L0l 0It 1 46, ind x10. An alloy contains 36% zinc, 40% copper and remaining is nickel. Find the amount of each metalin a sample of alloy of mass 1 kg. |
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Answer» 360g zinc ,400g copper and 240g nickel muntz metal is an alloy of |
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| 80333. |
44. 1 ie Stin of the two Opposite enb23. Diviand , by the difference of 3 and 29ide the sum of5 |
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Answer» thank you so much |
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| 80334. |
(i)3召すに1 m341 에aiA sheet measuring 44 mx 11 mis folded along its length 44 m to form a cylinder. Find the radius of this2.cylinder |
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Answer» Let the radius be r we know that the length of the sheet = circumference of the circle and height of the cylinder = 18cm 44 = 2 r 2 * 22/7 r = 44 r = (44*7) / (22*2) r = 7cm |
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| 80335. |
2. It takes ShwetĂ 45 minutes to walk 5 km. How long would it take her to walk 4 kmathe same speed? How far would she go in 90 minutes? |
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Answer» Time taken to cover 5km = 45 mins Time taken to cover 1km = 455 = 9mins Time taken to cover 4km = 9 x 4 = 36mins Distance covered in 45mins = 5km As 90mins = 45 x 2 Therefore, Distance covered in 90 mins = 5 x 2 ( As 90mins = 45 x 2 ) = 10 km ANSWER - Time taken to cover 4km = 36mins and distance covered in 90mins = 10km |
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| 80336. |
2x+y) 23x -y) 8Formulate the following problems as a pair of equations, and hence find thai0 Ritu can row downstream 20 km in 2 hours, and upstream 4 km in 2 hours. Find herspeed of rowing in still water and the speed of the current.(iu) 2 w |
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| 80337. |
Formulate the following problems as a pair of equations, and hence find their solutions:(i) Ritu can row downstream 20 km in 2 hours, and upstream 4 kin in 2 hours. Find her2.speed of rowing in still water and the speed of the current. |
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| 80338. |
(1+2+3+4+5+4+3+2+1)+(3+3+4+6+7+0+01)*(0)+(1+2+7)÷0 |
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Answer» 0 is correct answer of this question 100 is the correct answer for this problem It's answer is infiniti .Because any number divided by o is infinity. ans is infinity(25+24)*0+(10)÷00+10÷0 10÷0=infinityany no divided by 0 is infinity 0 is correct ans....... it's ans is infinity is the correct ans 0 answer is infinite 0. is correct answer (25)+(24)×(0)+(10)÷(0)49×0+10÷00+10÷010÷00 is the right answer 25 is the correct answer because in first itis 25 and then it will be 0 and third itwill be 0 or undefined so answer is 25 infinity is the right answer because it's divided by 0 (25)+(24)×(0)+(10)÷(0)49×0+10÷00+10÷010÷00 25+ 24 × 0 +10 ÷0 49×0+10÷025 (25)+(6+4+13+0)*(0)+(10)÷0=0 25+23×0+10 ÷ 0=48 × 0 +10 ÷ 0=0 + 10 ÷ 0=10÷0=0 answer 0 is correct answer of this question 0 is correct answer of this question |
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| 80339. |
By observing the following patterns, generate the next three lines of num( 5 x 5 = 1 + 2 + 3 + 4 + 5 + 4 + 3 + 2 + 16 x 6 = 1 + 2 + 3 + 4 + 5 + 6 + 5 + 4 + 3 + 2 + 1XT-11111 1T1IIITIF1!111111TI1111 11(11)------------ - - -- --81 + 19 = 100100 + 21 = 121121 + 23 = 144 |
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Answer» i)1)7×7=1+2+3+4+5+6+7+6+5+4+3+2+12)8×8=1+2+3+4+5+6+7+8+7+6+5+4+3+2+13)9×91+2+3+4+5+6+7+8+9+8+7+6+5+4+3+2+1ii)1)144+25=1692)169+27=1963)196+29=225 7×7=1+2+3+4+5+6+7+6+5+4+3+2+18×8=1+2+3+4+5+6+7+8+7+6+5+4+3+2+19×9=1+2+3+4+5+6+7+8+9+8+7+6+5+4+3+2+1 144+25=169169+27=196196+29=225are answers of following questions |
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| 80340. |
2.v) ABUIf A = {1, 2, 3, 4), B = {3, 4, 5, 6} and C = {2, 4, 6}, then show that1) AN(BUC)=(ANB)U(ANC)ii) AU(BNC)=(AUB)n(AUC) |
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Answer» (i) (ii) |
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| 80341. |
Section AQuestion Nos 1 to 10 are 2;ween 3 and Amarks eachFiod the value ofe Evaluate (ng suitable identity8 Eveluate: (102) using suitable identity9- In a cricket batset match, a bats woman hits a boundary 6 times out of 30 bals she plays. Find the probabilitydid not hit a boundary(10)xpross 04? in the form where p and g are integers and qre oSection BQuestion Nos 11 to 20 are 3 marks each1 Rationalise the denominator12. Find the remainder when x) + 3x; + 38 + 1 is divided by x + 1.aanationaliso the denominator i) İRG6Wp.iilia maths test stores of sudents are 41.39.48.52.460 62.54 40,30,52.98,40,42,52.60, Find its Mes, Threg coins were tossed 30 timefollows0112 2 231,3,0331.1,2.2,0,1,2,1,3.0,0,1,1,2,3,220Prepare a frequency distribution able for the dts ve o16. Find the total surface area of a cone, ifits slant height 21 m and diameter of its base is 24 m.17. The curved surface area of a right circular cylinder of height 14 cm is 88 cm find the diametcylinder18. Expand using suitable identities (x +2y + 42)19 Expand using suitable identities:(2s-y+20. The length, breadth and height of a room are 5m, 4m and 3m respectively. Find the cost owals of the room and the celing at the rate of Rs 750 per mSection C |
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Answer» crop 1 questions please |
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| 80342. |
19.in a certa ni Ahリtile 24 til territ20. Prove that the sum of (m + n)th and (m - n)th terms of an A.P. is equal to twice the mth term. |
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| 80343. |
Write the place value and face value of the underlined digit3 ones(a) 313(b) 569(c) 712(d) 232856708g) 844(h) 473(1) 955(1) 569IIIIIIIIIIIIhundred........6..7. hundre....7.Love.............Fahl....5...hls...5 hundedWrite the place value of 5 in the given numbers |
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Answer» plz anybody answer ones is right .... |
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| 80344. |
11. There are S red, 2 yellow and 3 white roses in a flowerpot. Select one rose from it at randornWhat is the probability that the selected rose is of () red (ii) yellow (ili) not white colour |
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Answer» Total number of roses=10i)Probability that the rose is red=5/10=1/2ii)Probability that the rose is yellow=2/10=1/5iii)Probability that the rose is white=3/10∴Probability that the rose is not white=1-3/10=7/10 |
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| 80345. |
161In the given figure, find the values of x and yocitt angles are eqnnos |
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| 80346. |
5ijke-4th-tesnaf AP is..zero: Rove that the 25th tenan 4 APis thee timer itt nth texn |
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| 80347. |
The sum of the 4th and 8th terms of an AP is 24 and the sum of the 6th and 10th terms is44. Find the first three terms of the AP. |
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Answer» A4+a8=24a+3d+a+7d=242a+10d=24. .........1 a6+a10=34a+5d+a+9d=342a+14d=34. .,.......2Subtracting 2 from 12a+14d=342a+10d=24- - -4d=10d=4/10or 2/5Put d= 2/5 in 12a+10×2/5=242a+4=242a=24-42a=20a=10 4th+8th=24; a+3d+a+7th=24; 2a+3d+7d=24; 2a+10d=24,; a+5d+a+9d=34; 2a+14d=34; 2a+10d=24; 2a+14d=34/4d=10; d=10/4=5/2; 2a+10d=24; 2a+10(5/2)=24; 2a+50/2=24; 2a+25=24; 2a=-1; a=-1/2 A4+a8=24a+3d+a+7d=242a+10d=24. .........1 a6+a10=34a+5d+a+9d=342a+14d=34. .,.......2Subtracting 2 from 12a+14d=342a+10d=24- - -4d=10d=4/10or 2/5Put d= 2/5 in 12a+10×2/5=242a+4=242a=24-42a=20a=10 |
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| 80348. |
The sum of the 4'h and g'h terms of an AP is 24 and thesum of its 6h and 10h terms is 44. Find the first threeterms of the A.P |
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| 80349. |
(i) Ritu can row downstream 20 km in 2 hours, and upstream 4 km in 2 hours. Find her speed of rowing in still water and the speed of the current. |
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Answer» please do this question in hindi format💐 |
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| 80350. |
8. A train travels at a certain average speed for a distance 63 km and then travels adistance of 72 km at an average speed of 6 km/hr more than the original speed. If ittakes 3 hours to complete total journey, what is its original asverage speed? |
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Answer» Let original speed of the train be x km/h. Time taken to travel 63 km = 63/x hours New speed = (x + 6) km/hr Time taken to travel 72 km = 72/(x + 6) hours According to the question, 63/x +72/(x + 6) = 3 x2- 39x - 126 = 0 (x - 42)(x + 3) = 0 x = -3 or x = 42 As the speed cannot be negative, x = 42 Thus, the average speed of the train is 42 km/hr. |
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