InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 80801. |
8. In the adjoining figure, AD is a median ofΔABC and DEIBA. Show that BE is also amedian of AABC. |
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| 80802. |
10. A motor boat heads upstream a distance of 24 km in a river whose current is running at 3km per hour. The trip up and back takes 6 hours. (Assuming that the motor boat maintaineda constant speed) what was its speed in still water? |
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| 80803. |
25. A group consists of 4 girls and 7 boys. In how many ways can a team of 5members be selected if the team has() no girls(a) at least one boy and one girl(m) at least three girls. |
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Answer» (iii) |
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| 80804. |
20. A bag contains 12 items of which 4 are defective. From this 2 items are drown atrandom. Find the probability of getting(i) no item defective(ii)one item defective Ga) both items defectiverds are drawn at random from a pack of 52 cards. Find the probability ofgetting all the four cards of the same number. |
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Answer» There are 4 suits in a standard deck 52 cards.Number of ways of selecting 4 cards out of 13 cards( i.e. a suit) are 13!/(4!9!)Note that we can choose 4 cards out of any 4 possible suits.So total ways become: P = 4 * ( 13!/9!4! ) Also, no of ways to select 4 cards out of 52 cards are: Q = 52!/(4!48!) Hence The probability is: P/Q = (4*13!/4!9!)/(52!/4!48!) |
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| 80805. |
A fort has food items for 500 people for 20 days .How many days will the food items last if there are 250 people? . |
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Answer» Total food = Number of people * number of daysThis total food amount remains constant throughout. Therefore, 500 * 20 = 250 * number of days=> number of days = (500*20)/250=> number of days = 40 |
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| 80806. |
Q14. A group consists of 4 girls and 7 boys. In how many way can a team of 5 members be selected if theteam has:(1) No gilrs?(ii) At least one boy and one girl?(iii) At least three girls? |
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| 80807. |
Diameter of the base of a cone is 105 cm and its slant height is 10 cm Find its curvedsurface area |
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| 80808. |
utiple fck () the correct option.square tiles of equal size were needed to cover a floor area of 135 square metres. What is thelength of each tile?(a) 105 cm(b) 150 cm(c) 70 cm(d) 210 cm |
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Answer» No answer is (B) but how 1.5m=1.5×100=150cm (b) is tye answer.Not (a) yes I got the answer 150cmnot 105c.kindly check the solution |
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| 80809. |
Find the area of a rhombus having each side equal to13 cm and one whose diagonals is 24 cm. |
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| 80810. |
7. Each of the equal sides of an isosceles triangle is 13 cm and its base is24 cm. The area of the triangle is(a) 30 cm(b) 45 cm2(c) 60 cm(d) 78 cm2 |
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| 80811. |
Find the area of a rhombus having each side equal to13 cm and one whose diagonals is 24 cm.4. |
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| 80812. |
Mr Narayan saves 20%of his salary and receives14500rs per month as his salary.find his monthly expenditure |
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Answer» Total salary = 14500savings = 20%expenditure = 80%80/100×14500=11600 |
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| 80813. |
3) Simplify (-13-1-28) +{-25-1-40) |
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| 80814. |
6. Simplify:W -8) 9+(-8) 7*** 20 x(-16) +20 x 14(v) (-11) (-15) + (-11) (-25)(vil) (-16) (-8)+(-4) (-8)7. Fill in the blanks:(1) (-6) (......) = 6(ul) (-8)(-9) =(-9)x(.....)(v) [(-5)x3)(-6)=(...... )x{3x(-6)}(ii) 9X(-13)+9x(-7)(iv) (-16)X(-15) +(-16)X(-5)*** TO X(-12)+5x(-12)(viii) (-26) x 72+(-26) 28(11) (-18)x(.....) =(-18)(iv) 7x(-3)=(-3) (.....)(vi) (-5)(.....) = 0 |
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Answer» Simplify the follwing a generator rated at 10kw delivers 10 kw receive 15 HP find the efficiency Fill in the blank sudtracted |
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| 80815. |
A boat takes 2 hours to go 50 km from A to B down the stream. But for return journey from B toA, it takes 3 hours. Find the uniform speed of the boat in still water and the uniform speed ofthe stream. |
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Answer» Boat speed=xkm/hcurrent speed=ykm/hagainst current x-y3.00hourswith current x+y2.00hours Distance = same=50kmt=d/r50/(x-y)=3.003(x-y)=50.003x-3y=50....................150/(x+y)=2.002.00(x+y)=502.00x+2.00y=50...............2Multiply (1) by 2.00Multiply (2) by3.00we get6x-6y=1006x+6y=15012x=250/12x =125/6km/h plug value of x in (1)3x-3y=50125/2-3y=50-3y=50-125/2-3y=-25/2y=25/6km/hThe speed of Boat =125/6km/hThe speed of current =25/6km/h |
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| 80816. |
6. Two pipes can fill a tank in 10 hours and 12 hoursrespectively while a third pipe empties the fulltank in 20 hours. If all the three pipes are openedsimultaneously, in how much time the tank willbe filled?(a) 7 hours(c) 7 hours 30 minutes (d) 8 hours 30 minutes(b) 8 hours |
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| 80817. |
. 10 different letters of English alphabet aregiven. Out of these letters, words of 5 lettersare formed. How many words are formed whenat least one letter is repeated?(A) 69760(C) 96747(B) 98748(D) 97147 |
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| 80818. |
8. In ALFABETA + GAMA DELTA, each letter stands for a unique number. Find thevalue of each letterHOTS |
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Answer» There are lots of solutions for this problem. The only thing that is fixed is that E=4, A=5 F+M must equal to nine so (F,M) can be from the set (0,9)(1,8)(2,7)(3,6)(4,5)(5,4)(6,3)(9,0) T can be any digit from 0-9 L can be any digit from 0-9 D can be either 1 or 2 if D=2 then B=G=9 if D=1 then (B,G) can be any combination from the set (0,8)(2,6)(3,5)(4,4)(5,3)(6,2)(8,0) By following these rules you can simply select random pieces and they are solutions to ALFA+BETA+GAMA=DELTA 5795 + 6435 + 2505 = 14735or 5305 + 2475 + 6595 = 14375 these are some combinations. |
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| 80819. |
3) An iron block is of volume 105 cm. If its lengthand breadth are 7 cm and 5 cm respectively, findthe height of the block. |
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Answer» Let height =x7*5*x=10535x=105X=105/35=3cm 3 cm is the best answer yes 3cm is the right answer in this question length= 7 CM, breadth=5 cm, volume=105 cm^3; lxbxv=105, 35V/105; ; 35V=105; V=105/35=3cm हिरणों के एक झुंड का आधा भाग मैदान में चर रहा है और शेष का तीन चौथाई पड़ोस में ही खेलकूद रहा है। शेष बचे 9 हिरण एक तालाब में पानी पी रहे हैं। झुंड में हिरणों की संख्या ज्ञात कीजिए। x = 3 cm is the right answer this question answer is 3cm x=105/35=3cm is the answer.... height of block = volume /( length ✖ breadth) = 105/(7 ✖ 5) = 105/35 = 3 cm ( ANS ).. 3cm is the best answer volume=l*b*h =105 cm^3. 7*5*h = 105 35h = 105. h= 105/35 = 3 is height the height of the block is 3cm the height of the block is 3 cm please like my answer please Height of the iron block is 3 cm volume= length× breadth×height105=7×5×heightheight=105/35 =3height =3cm volume =lengthxbreadthxheight 105=7x5x5xheightheight =105/35 =35height =3cm |
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| 80820. |
2. Arectangular ground is 90 m long and 32 m broad. In the middle ofFind the14thecost ound there is a circular tank of radius 14 metrest 50 pera rof turfing the remaining portion at the rate ofsquare metre.e 5o p90 |
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| 80821. |
the lenght and breadth of a rectangle is 12cm and 5 cm respectively . find the lenght of diagnols |
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Answer» in the rectangle diagonal*diagonal = length*length + breadth*breadth = 12*12 + 5*5 = 144+25 = 169 so diagonal = root(169) = 13cm |
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| 80822. |
10, If one ange of a parallelogram is 24 less thantwice the smallest angle then the largest angleof the parallelogram Is(a)68。lb) 102(c) 112(d) 176 |
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| 80823. |
and slant height of a cone are 5 cm and 13 cm respectivelyThe basethen its height isc) 18 cmd) 24 cm13 cm |
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Answer» R=5 L=13 given Find H? Volume of cone is 1/3pi r^2h H = √13^2-5^2 H =12 Put in formula 1/3×π×25×12 =100πcm |
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| 80824. |
lts. 11, A village path was 130 metres long. Its lengthisincreased by 20%. How long is the village pathnow?s.13/Due to a leak in the water tank, 36% of the watersdrained out. Now, there is only 1024 litres of waterleft in the tank. How much water was in the tankbefore the leak?13. If the chance of finding a natural pearl in an oyster is0.08%, then how many oysters will have to be crackedopen to find 10 pearls?14, Mr Dubey saves 11,550, which is 55% of his |
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| 80825. |
U11 U104..htract -134 from the sum of 38 and -87.S. Subtract _19Fill in the blanks:(1) {(-13)+27} +(-41) = (-13) + {27 +(.....)}(ii) (-26)+{(-49)+(-83)} = {(-26)+(-49)}+(..(iii) 53 +(-37) = (-37)+(.....)list 681+1-76) = (.....)+(-68)to (-72) + (.....) = -72(vi) -583) =......vii) -60) - (.....) = -59viii -31)+(.....) = -40Simplify: {-13-(-27)}+{-25 -(-40)}.ind 36 -(-64) and (-64) - 36. Are they equal?that lahtra |
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Answer» ans1 41ans2 -83ans3 53ans4 -76ans5 0ans6 -83 ans7 -1 ans8 -9 |
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| 80826. |
A plane takes 2 hours and 45 minutes to cover the distance between two airports.travels 20 km/h slower then it takes 3 hours. Find the speed of the plane. Also, find thedistance between the two airports |
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Answer» D=rtDistance is samelet x be the speedD=2 3/4 *x==11/4 xspeed x-20d= (x-20)*3equate both11/4 x = (x-20)*311x= 12(x-20)11x=12x-24012x=11x=240x= 240speed = 240 kphd=rtd= 11/4 * 240d=11*60=660 km Like my answer if you find it useful! |
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| 80827. |
5. There are 3 pipes in a tank. First two pipes can fill.the tank in 3 hours and 3 hours 45 minutesrespectively while the third can empty the tank in1 hours. If the pipes are opened at 1, 2 and 3respectively then the tank will be empty on. |
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Answer» because 3pipe can empty the tank in 1housr bcz these 3 pipes can empty tank in 1 hour because these 3 pipes can empty tanks in 1hour because these 3 pipes can empty tanks in 1hour |
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| 80828. |
. Write formulas for mean (all), median, mode.1. Solve the following:-(2M)1.If the mean of the following distribution is 6, find the value of P.6F:3(Ans: P = 7)P + 51022.Find the mean of the following distribution:10308(Ans: 55 )89507010151003. Find the missing frequencies, if mean of the distribution is 1.46.x:012F:46(Ans : f1 = 76, f2 = 385Total5 52002510(Ans: 5)04. Obtain median for the following frequency distribution:1 2 3 4 5F:106871511162025 |
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Answer» 7 is value of pcorrect answer |
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| 80829. |
Find the number of different 8 letterarrangements that can be made from the letterof the word EQUATION. Also find the number ofarrangements in which vowels are together. |
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Answer» total no. of words=8vowels= e,u, a, i ,oassume vowels as a single objectso our word becomes euaio,q,t,nnumber of permutation of vowels=5p5!5!/(5-5)!=5*4*3*2*1=120 waysnow arranging 4 letters120*4=480 |
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| 80830. |
nce,8. How many words, with or without meaningscan be formed using all the letters of the wordEQUATION', using each letter exactly once? |
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| 80831. |
3.Add the following.ab -bc, be - ca, ca- ab |
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Answer» ab-bc+bc-ca+ca-aball gets cancelled 0 It very nice |
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| 80832. |
1: wy R का Y T कि 35 3y 7 AN en o v o e/ =27 ८ Qe Lfizu P ENn AN an पति | - M = /\ : 1 0[ he 2t sP £ aro Y he h P aly at id M(227८. 0 £ U \(7’ e ans, |
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Answer» Simple interest=PRT=3600*15*4/100=2160Amount to be paid=3600+2160=5760Rs |
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| 80833. |
5.If the difference between the circumference and radius of a circle is 37 cm, then the area of the circle is(use π = 227)α) 111 cm2b) 148 cm2c) 259 cm2d) 154 cm |
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| 80834. |
The difference between the semi-perimeterand the sides of a ∆ABC are 8 cm, 7 cmand 5 cm respectively. The area of thetriangle is(A) 20√7 cm2 B) 10√ 14 cm^2(c) 20√14 cm2 (D) 140 cm2 |
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Answer» Let the semi-perimeter of the triangle be s. Let the sides of the triangle be a, b and c. Given:s – a = 8,s – b = 7 ands – c = 5 Adding all the above equations, we get(s – a) + (s – b) + (s – c) = 8 + 7 + 5 ⇒ 3s – (a + b + c) = 20 ⇒ 3s – 2s = 20⇒ s = 20 cm Thus the semi-perimeter is 20 cm a = √s(s-a)(s-b)(s-c) = √20*8*7*5 = √5600 Area = 74.83 cm² |
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| 80835. |
The percentages of marks obtained by a student inthe monthly unit tests are given below.Unit testPercentage of marks 60 75 5572 85obtainednd the probability that the student gets,(i)At least 60% marks.Marks between 80% and 90%.75% or above.(iii)A. 3/5 2/5B. 3/5 1/5C. 4/515D. 45 2/5(iii)2/51/52/51/5 |
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Answer» Total number of test=5p(Atleast 60% marks)=4/5 Marks between 80% and 90%=1/575% or above=2/5 Ans is C |
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| 80836. |
7668114102e |
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Answer» thanks |
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| 80837. |
16. Twe coins are tossed simultaneously 500 times and we getResult2 Head1 HeadNo HeadFroqueney10527512Tiad the probability of occurrence of each of these events |
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Answer» from this way you solve remaining question |
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| 80838. |
& Find the difference between:(i) 25 hours 12 minutes and 45 hours 13 minutes.(i) 30 minutes 45 seconds and 25 minutes 55 seconds.(ii) 19 minutes 25 seconds and 15 minutes 45 seconds.umbai at 2350 |
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Answer» i) 45 hrs 13 min - 25 hrs 12 min = 20 hrs 1 min ii) 30 min 45 s - 25 min 55 s = 4 min 50 s iii) 19 min 25 s - 15 min 45 s = 3 min 40 s |
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| 80839. |
ina) 35 (20)(b) 72-90)(e) 23-(-12)Fill in the blanks with >, < or - sign2(c) 45-11) 57 + (-4)Fill in the blanks.(a) (-8)+80(b) 13+-0(c) 12+-12)-(d) (-4) +Eb=-12(e) 9-15 =-10Find(b) (-13) +32-8-1What have we dis |
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Answer» 35-(20)=1572-(90)=-18(-15)-(-18)=323-(-12)=23+12=35(-32)-(-40)=(-32)+40=8 a) <b) >c) >d)> How this question was solved 35 -(20) = 1572 - (90) =-18( -15) -( -18) = 323 - ( -12) = 23 +12 =35( -32) - (-40) = (-32) +40 =8 |
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| 80840. |
のb , ab , ab ‘ー-(γ)の26)ab ( 1 ) |
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| 80841. |
4. If 2^a=3^b=6^c then c cannot be equal toa)a+b/abb)ab/a+b(C)a-b/ab(D)ab/a-b |
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| 80842. |
1010triangular plot. Explain how this pnd h e of his land adjoining his plot soroposal will be implementedABCD is a trapezium with AB |IDC. A line parallel to AC intersects AB at X and BCat Y. Prove that ar (ADX) = ar (ACY).13.[Hint : Join CX.] |
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Answer» Given, ABCD is atrapezium with AB || DC & XY || AC Construction, Join CX . To Prove, ar(ADX) =ar(ACY) Proof:ar(△ADX) =ar(△AXC) —(i) (On the same base AX and between the same parallels AB and CD) also, ar(△ AXC)=ar(△ ACY) — (ii) (On the same base AC and between the sameparallels XY and AC.) From (i) and (ii), ar(△ADX)=ar(△ACY) hit like if you find it useful |
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| 80843. |
25.In the given figure ,ABC is a triangle and GHED is a rectangle. BC=12 cm, HE =6cm, FC-BF andaltitude AF 24 cm. Find the area of the rectangle. |
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| 80844. |
10. The length of a rectangle is 12 cm. This is 1 of itsperimeter. Find the perimeter of the rectangle. |
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Answer» please answer my other questions on community |
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| 80845. |
A wire is bent in the form of a rectangle having length twice the breadth. The samewire is bent in the form of a circle. It was found that the area of the circle is greaterthan that of the rectangle by 104.5 cm2. Find the length of the wire. |
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Answer» Define x: Let the breadth be x The length = 2x Find the area of the rectangle: Area = Length x Breadth Area = 2x² Find the perimeter of the rectangle: Perimeter = 2(Length + breadth) Perimeter = 2(2x + x) Perimeter = 6x Find the radius of the circle in term of x Circumference = 2πr 2πr = 6x r = 6x ÷2π r = 3x/π Find the area of the circle in term of x: Area = πr² Area = π(3x/π)² = 9x²/π Solve x: The area of the circle is greater than the rectangle by 104.5 cm² 9x²/π - 2x² = 104.5 x² (9/π - 2) = 104.5 19/22 x² = 104.5 x² = 104.5 ÷19/22 x² = 121 x = √121 x = 11 cm Find the length: Length = 2x = 2(11) = 22 cm Answer: The length is 22 cm |
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| 80846. |
12. A rectangle has length which is 5 cm less than twice its breadthIf the length is decreased by 5 cm and breadth is increased b2cm, the perimeter of the resulting rectangle will be 74cmFind the length and breadth of the original rectangle. |
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| 80847. |
(İİİ) What is the degree of the 0 polynomial ?(A) 0(B)I(C) undefined(D) any real number |
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Answer» option C Thedegreeof the zeropolynomialis either left undefined, or is defined to be negative (usually −1 or ). Like any constant value, the value0 can be considered as a (constant)polynomial, called the zeropolynomial. As such, itsdegreeis undefined. |
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| 80848. |
21. The percentage of marks obtained by a student in monthly unit tests are given belowUnit test736876Percentage of marks obtained6971Find the probability that the student gets:(i) more than 70% marks(ii) less than 70% marks(iii) a distinction |
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| 80849. |
5. Two coins are tossed simultaneously 500 times, and we getTwo heads: 105 timesFind the probability of getting 0 head.One head: 275 times |
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| 80850. |
L Find the mode of the following frequency distribution:Marks10-20 20-30 304040-50 50-601235452513ICaSE 2014 |
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