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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 80951. |
integers2. Use number line and add the following hegI(d) (-5)+ 103. Add without using number line:(d) ( 250) + + 150)(e) (-380)+(-270)() (217) + (- 100) |
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Answer» 2 a) 3b)-6c)-8d)5e)-6f)2 3 a)4b)5c)9d)-100e)-650f)-317 Thanks 😊😊😊😊😊 |
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| 80952. |
(5) By using variable x and y form any equation in two variables. |
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Answer» Consider this Equation 9x + 5y = 0 |
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| 80953. |
word problems grade 5 students visited a big farm there they saw 1056 horses how many legs did these horses have in all |
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Answer» 10000000000000000000000000000000000 1056×4 +5×24,224+104,234 is the right answer...... Your correct answer is horses have legs 4224 Number of horses = 1056Number of legs each horse have = 4Total number of legs = 1056*4 = 4224 legs ( ANS ) 1056*4=4224 horses have legs=4224 1054*4=4224 total no. of legs 4224 is the correct one this question answer is 1056×4=4224horses have legs 4224 4234 is the correct answer |
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| 80954. |
are 4 elephants. Each elephant has 4 legs. How many leg |
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Answer» Each element have 4 legs So, 4 elephants have 4 × 4 = 16 legs |
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| 80955. |
Tu U VUCU SU at the quolient is a pertte cubes of five natural numbers which are multiples of 3 and verify the following:The cube of a natural number which is a multiple of 3 is a multiple of 27'. |
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| 80956. |
9арVelocity-time graph foruniform velocityA train is moving with auniform velocity of 60 km/hourfor 5 hours. The velocity-timegraph for this uniform motion isshown in figure 1.7.1. With the help of the graph, howkm/hr) |
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| 80957. |
5 A solid cylinder has total surface area of 42 sq, cm. Its curved area is one-third of is totalsurface area. |
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Answer» thanku |
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| 80958. |
2 NS |
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Answer» thanks |
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| 80959. |
3.Co-ordinates of some pairs of points are given below. Hence find the distanceeach pair(iv) x, -2(v) x+3, x3(vi) 25,-47 (v) 80,-85V1111 C |
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Answer» Crop only the question that you want a solution for. We will not be able to provide solutions to multiple questions. HTC guy |
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| 80960. |
Add the followingi) 5/8 = 10/16 |
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Answer» 10/16 = (5*2)/(8*2) = 5/8 , its true.. |
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| 80961. |
2. Add :(a) -16, 12 |
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Answer» Adding -16 and 12hence-16+12=-4 Adding -16 and 12 hence -16+12 = -4 adding -16+and12hence,-16+12=4 let -16 be equation 1and 12 be equation 2 now we know that (- +)= -so adding equations 1 and 2 .(-16)+(12)=-4 adding -16 and 12 hence -16 +12=-4 add -16+12 =-4 it is answer |
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| 80962. |
i(use t 3.14).15. The circumference of the front wheel of a car is 10 dm and that of the hind wheel in 16 dm. Howmay revolutions more will the first wheel make than the second in covering a distance of 96 km?d ond font nath runs alone its boundary. A man walks around it, exactly once, |
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| 80963. |
EXERCISE 12.11. Get the algebraic expressions in the following cases using variables, constants andarithmetic operations0) Subtraction of: from y(n)1 IdenOne-half of the sum of numbers x and yThe number z multipliod by itself.iv) One-fourth of the product of numbers p and qv) Numbers x and y both squared and added.(vi) Number 5 added to three times the product of numbers m and n(vn) Product of numbers y and : subtracted from 10.vn) Sum of numbers a and b subtracted from their product12.6 |
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Answer» 3. z × z5. x2 × y26. 5 + 3mn |
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| 80964. |
Which term of the AP 121, 117, 113,... is its first negative term? |
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| 80965. |
A rectangular solid metallic cuboid 18 cm Ă 15 cm Ă 4.5 cm is melted and recast into solid unit cubes. Howmany solid unit cubes can be made? |
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| 80966. |
81 77(iv) Which term of the sequence 17,is first negative term? |
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| 80967. |
2.The edges of three cubes are 8 cm, 6 cm and 1 cmrespectively. After melting these cubes a newcube is formed. Find the total surface area ofnew cube. |
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Answer» Volume of first cube = 1 *1 *1 = 1 cubic cm.Volume of second cube = 6 * 6 *6 = 216 cu cm.Volume of third cube = 8 * 8 * 8 = 512 cub cm.Then Volume of bigger cube = 512 + 1 + 216 = 729.So, side of bigger cube = Cube root of 729 = 9 cm.Surface area of cube = 6 * a^2 = 6 * 9 *9 = 486 sq. cm. |
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| 80968. |
13. Three metallic solid cubes whose edges are 3cm,4cm, and 5cm are melted and converted into a singlecube Find the edge of the cube so formed? |
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| 80969. |
Find the prime factor of the following number.(i) 12-8, (ii) 15-(v) 54 %, (vi) 48(iii) 28 =(vii) 42V1V11 |
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| 80970. |
| निम्नांकित संख्याओं का ल0स0 ज्ञात कीजिए।(क) 5, 10, 15 (ख) 16, 44, 64 (ग) 10, 65, 91(घ) 22, 121,418 (ङ) 14, 28, 35, 563 |
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| 80971. |
12. Let A = (12, 13, 14, 15, 16, 17) and f: A → Z be a function given byf(x) = highest prime factor of x.Find range of f. |
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| 80972. |
To find sum of three numbers 16, 28 and 12, we can have two(a) We may first add 16 and 28 to get 44 and then add 12 to it to(b) We may add 28 and 12 to get 40 and then add 16 to get the sum 56.Thus, (16+ 28) +12 16+ (28+12)ways:get the total sum 56 ortetiuity of addition of |
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| 80973. |
5. To find som of three nmumbers 16. 28 and 12, we can have teo ways(a) We may first add 16 and 28 to get 44 and then add 12 to it to get the total sum 56 or0) We may add 28 and 12 to get 40 and then udd 1s to get the sum 56Thus, (164 28)4 12 16 (28 12) |
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| 80974. |
By using the principle of mathematical induction, prove that2.7 +3.55 is divisible by 24, Vn N |
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Answer» Letp(n) be the statement given by p(1)= 2.7+3.5-524 which is divisible by 12 ∴p(1) is true Letp(m) : 2.7m+ 3.5m– 5 is divisible by 24 be true ⇒ 2.7m+ 3.5m– 5 = 24λ ;λ∈N ⇒ 3.5m= 24λ + 5 – 2.7m... (1) p(m+ 1) : 2.7m+ 1+ 3.5m+ 1– 5 = 2.7m+ 1+ (3.5m) 5 – 5 = 2.7m+ 1+ (24λ + 5 – 2.7m) 5 – 5 (from (1)) = 2.7m+ 1+ 120λ + 25 – 10.7m– 5 = (2.7m+ 1– 10.7m) + 120λ+ 20 = (2 × 7λ7m– 10 × 7m) + 120λ+ 24 – 4 = (14 – 10)7m– 4 + 24 (5λ+ 1) = 4 (7m– 1) + 24 (5λ+ 1) = 4 × 6µ + 24(5λ+ 1) (∵ 7m– 1 is a multiple of 6 for allm∈N∴ 7m– 1 = 6µ, µ∈N) = 24 (µ +5λ+ 1) which is divisible by 24 ∴p(m+ 1) is true. Hence by principle of mathematical inductionp(n) is true for alln∈N |
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| 80975. |
Ans, 486 c 2Example1: Three cubes of metal with edges 6 cm, 8 cm and 10 cm respectiveltoform a singte cube. Find the total surface area of the new cube formed.Solution: Fdeesofthe three cubes are a 6 cm, a2 8 cm and a3 10 cm. |
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Answer» Volume of new cube = 6³+8³+10³= 216+512+1000=1728 (side)³= 1728 => side= 12 cm Total surface area of new cube=6side²=6(12)²=6*144= 864 cm² |
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| 80976. |
Which term of the A.P. 171, 167, 163,is its first negative term ? |
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| 80977. |
Three cubes of side 3 cm each are joint to form a cuboid then find the surface area of cuboid |
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Answer» length will become 3(2)=6cmbreadth will be 2 and height 2soso surface area will be 2(lb+bh+HL)=2(6*2+2*2+2*6)=2(12+4+12)^2(28)=56cm Thank you |
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| 80978. |
D. Examine whether the two triangles are congruent by ASA congruencecriterion.1. APQS with ZP- 50°, S 70°, PS 6 cm,ΔΧΥΖ with <X= 50°,ΔΡQS with <P = 30°, <Q= 50°, PQ = 3 cm,ABC with <AZ = 35°, XY = 6 cm2.WI30°, <C25°, АВ--3 cmΔGHI with LH-50°, ZI-700, HI3 cm |
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Answer» 1) in first case only one angle and one side il is same hence , it's not following ASA test 2) Here also only one side and angle are same which is not sufficient condition for ASA tes.3) But here Though only two angles are equal but due to this one of the unknown side will also have equal length hence this follows ASA test.. |
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| 80979. |
Examine whether the two triangles are congruent by ASA congruencecriterion.D.1. Δ1'QS with ZP-50°,2S = 70°, PS = 6 cm,XYZ with ZX-50°, <Z 35°, XY = 6 cm2. APQS with P-30°, ZQ-50°, PQ 3 cm,AABC with ZA-30, C-25°, AB 3 cm |
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Answer» 1) since angle S and Z are not equal, thus the ∆PQS and ∆XYZ are not congruent. 2) since angle Q and C are not equal, thus the ∆PQS and ∆ABC are not congruent. |
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| 80980. |
Three solid cubes otsides 1 cm, ocm and 8cm are14 melted to form a new cube. Find the surface area ofnew cube |
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Answer» thank u |
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| 80981. |
N 1.30 s5. निम्नलिखित सर्व्समिकाएँ सिद्ध कीजिए, जहाँ वे कोण, जिनके लिए व्यंजक परिभाषित # (i) (cosech — cotf)? = स्का1+ 00590) ही. +2डए 4 “22.1+sind4 cosA4tan cotf (iif) न 17 8609 ०0528. = [संकेत व्यंजक FI sin1-cot® 1-tan® |
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| 80982. |
nd the area of the following cincles, given tdhat) radius .: 14 mrn (Take Ď-T )radius 5 cme circumference of a circular sheet is 154 m, find its radius. Also fithat:(b diameter n 49 md the a |
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Answer» Area of circle = pi*r*r 1) For radius r = 14 mm by Area = 22/7*14*14 = 22*2*14 = 616 mm^2 2) For radius r = 5 cm Area = 22/7*5*5 = 22*25/7 = 78.57 mm^2 |
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| 80983. |
11./1A ABC and Δ DEF, AB n DE. ABIDE, BC-Eliand BC II EF. Vertices A, B and Ç are joined tovertices D. E and F respectively (see Pig. 8.22).Show that6) quadrilateral ABED is a parallelogramGi) quadrilateral BEFC is a parallelogram(Iİİ) ADIICF and AD CF(iv) quadrilateral ACFD is a parallelogram(v) AC DF |
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| 80984. |
3/28 â 7/10 + 15/6 â 36/12 |
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Answer» 3/28 - 7/10 + 15/6 - 36/12= 3/28 - 7/10 + 5/2 - 3Take LCM= (3*5 - 7*14 + 5*70 - 3*140)/140= (15 - 98 + 350 - 520)/140= - 253/140.= - 1.8 |
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| 80985. |
12 13 14 15 16 17 1819 20 21 22 23 24 2526 27 28 29 3016DAYS 230-13619 20 21 22 23 24 25 ó simply fy:-Qii) -2 – 3V3 TV2r5-V3 12-15 |
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| 80986. |
Write all the factors of the following numbers.NumberFactor1215162844 |
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Answer» 2*2*33*52*2*2*22*2*77*511*2*2 2 2 23 52 2 2 27 511 2 2 12=2×2×315=3×516=2×2×2×228=2×2×735=5×744=2×2×11 , answer |
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| 80987. |
(1) 42.65.93.240write the compact numeral.Interintenns, b5 * 100000 + 7 * 1000 + 8 * 100 + 1 * 10 + 6 * 19.7 * 1000000 + 9 * 100000 + 0 10000 + 6 * 100 + 2* 10-8.. The p20,00,00,000 + 4,00,00,000 + 70,000 + 600 + 5osT! |
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| 80988. |
if m term is n andterm is m, where m vn, find the |
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| 80989. |
5. Factorise:(1) 4x* +9y2 + 167² + 12xy - 24yz - 16xZ |
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Answer» I want to talk with teachers (a+b-c)^2=a^2+b^2+c^2+2ab-2bc-2cahence put a=2x b=3y and c=-4zthen(2x+3y-4z)^2=4x^2+3y^2+4z^2+12xy-24yz-16xzhence(2x+3y-4z)(2x+3y-4z) |
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| 80990. |
23 x-25 y=-169,25 x-23 y=-167 |
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| 80991. |
24. 122209 = ?(A) 167(C) 257(B) 244(D) 297 |
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Answer» Answer:D)297297×297=88209 |
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| 80992. |
, A metal cube is melted to form three smaller cubes of edges 3 cm, 4 cm and 5,cm. Find the edgeof the original metal cube. |
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Answer» Vol. of larger metal cube = vol. of three smaller cubes=(3)³ + 4³ + 5³= 27 + 64 + 125= 216 cm³vol.of larger metal cube = 216 cm³(a)³ = 216 cm³a³ = 6³a = 6 cmtherefore edge of larger metal cube is 6 cm |
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| 80993. |
find the hiberpeisots at cai bea. A metal cube is melted to form three smaller cubes of edges 3 em,4 em and 5 am. Find the edgsof the original metal cube. |
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Answer» Given:- a metal cube is melted to form three smaller cubes of edges 3 cm, 4 cm and 5 cm Total volume of the three cubes=(3³ +4³+5³) cm³=216 cm³ Now, volume of the original cube=216 cm³ =>a³=216 =>a=6 ∴Edge of the original cube=6 cm |
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| 80994. |
two smaller cubes are 6cmadelll,theeug5melted and recast17. The dimensions of a metallic cuboid are 100 cm x 80 cm x 64 cm. It isinto a cube. |
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Answer» Volume should remain same. Volume of cuboid= Volume of cube 100×80×64 = (a×a×a) a= 80 cm. |
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| 80995. |
How many litres of water wouldthe tank below hold when full ofwater?20.70 cm50 cmA. 385 litresB. 76.25 litresC. 3 500 litresD. 770 litres |
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Answer» Volume of cylinder= πr^2h= 22/7*50*70*70= 22*500*7077000 cm^3= 770 litreas 1000cm^3= 1 litreplease like the solution 👍 ✔️👍 |
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| 80996. |
paits.22. A bucket, made of metal sheet, is in the form of a cone whose height is 35 cm andradii of circular ends are 30 cm and 12 cm. How many litres of milk it contains if it isfull to the brim? If the milk is sold at 40 per litre, find the amount received by theICBSE 2017person |
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| 80997. |
#.. की 63% | + 28 yJ» EB3dos1F T 2 1 3j¢f=tid |
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Answer» 2sin^2 63+2sin^2 27+1 / 3cos^2 17+3cos^2 73-2 2(sin^2 63+sin^2 27)+1 / 3(cos^2 17 +cos^2 73 -22(sin^2 63+cos^2 63)+1 / 3(cos^2 17+sin^2 17-22(1)+1 / 3(1)-22+1 / 3-23/1=3 |
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| 80998. |
. o,25, diagonals AC and BD of quadrilateraln Fi.ABCD intersect at O such that OB = ODIEAB- CD, then show that:ar(DOC) ar (AOB)(ii) ar (DCB) = ar (ACB)ii) DAI CB or ABCD is a parallelogram.Hlint: From D and B, draw perpendiculars to AC.]Fig. 9.25 |
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| 80999. |
2 sec Atan + cot θ1+sinAI-sin A10. Determine missing frequency x,from the following data, when Mode is 67Class40-5050-6060-7070-8080-90Frequency51512 |
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| 81000. |
Find the mode for the following frequency distribution.Class 4-8 816 16- 20 20-24 24-28Freqyency961215 |
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