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f(x) = x²-25/(x-5) = (x+5)(x-5)/(x-5) = (x+5)

so, f(5) = 5+5 = 10.

25 ( x + y)² - 36 ( x - 2y)²

(5(x+y))² - ( 6 ( x-2y))²

(5x + 5y)² - (6x - 12y)²

(5x + 5y - 6x + 12y) ( 5x + 5y + 6x - 12y)

(-x + 17y) ( 11x -7y)

-28/5 is the correct answer of the given question

Given division is ( 5 ) ÷ ( -3 / 5 ) = -25 / 3.

-4/5 is the right answer

2x^2+4x-9 is the right answer

2x^2+4x-9 is the right answer.

3/26 is right answer of this question.please like my answer

3/26 is the correct answer of the following question

thanks

I think so it is wrong

oh sorry

my mistake it is correct

it is totally wrong

in my book its answer is -113÷9

Sorry, there was an error in the last part of the solution. It has been corrected and updated.

1st

2nd

=35 * (9-4-3) =35 * 2= 70

5.39845638 is the answer of this question

(7+2)4 = 36(6+8)3 = 42hence

(9+4)x = 2613x = 26x = 2

(1/4)×12√(35×(35-(2×12)))=58.864250611

answer is 30(3 multiply by 10)

5×6=30+5=354×20=80+4=843×9=27+3=30

(1.5x-4y)(1.5x+4y+3)-4.5x+12y

a)12.3cmb)10.3cmc)5.8cmd)1.05cm

the correct answer is 12.510.35.81.05

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Proof:

I. Prove that the equation holds for n = 1

If n = 1, then [n(n+1)(2n+1)]/6 = [(1)(2)(3)]/6 = 1.

So,12= [(1)(1+1)(2(1)+1)]/6

II. Assume that the equation holds for n and prove that the equation holds for n+1.

Assume: 12+22+ ... + n2= [n(n+1)(2n+1)]/6

Prove: 12+ 22+ ... + n2+(n+1)2=

[(n+1)(n+2)(2n+3)]/6

By assumption, 12+ 22+... + n2+ (n+1)2=

[n(n+1)(2n+1)]/6 + (n+1)2

= [n(n+1)(2n+1) +6(n+1)2]/6

= [(n+1){n(2n+1) + 6(n+1)}]/6

=[(n+1){2n2+ 7n +6}]/6

= [(n+1)(n+2)(2n+3)]/6

Therefore, by induction on n, the equation is valid for all positive integers, n.

Let a , d are first term and common

difference of an A.Pnth term = Last term = a + ( n - 1 )d

an = a + ( n - 1 )d

Now ,

It is given that ,

Third term = 12

a + 2d = 12 ------( 1 )

Last term = 106

a + 49d = 106 ---( 2 )

Subtract ( 1 ) from ( 2 ) , we get

47d = 94

d = 2

Substitute d value in equation ( 1 ) ,

We get

a + 2 × 2 = 12

a = 12 - 4

a = 8

29th term = a + 28d

a29 = 8 + 28 × 2

= 8 + 56

= 64

speed. time|. |12. 20minutes x. 15 minutes

x/12=20/1515x=12×20

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it's average speed is 4.4444444 m/s

36°c = 96.8 96.8°F-36°F= 60.8° Fthe object having 36°C is hotter than 36°F

Formula

(36°C× 9/5) + 32 = 96.8°F

First object,by= 96.8°F – 36°F=60.8°Fthe object having 36°C is hotter than 36°F

the object having 36°c is hotter

The right answer is 36 degrees Celsius

15÷24/5=15×5/2425/83 intiger 1 upon 8 times

please like my answer if you find it useful

thnku

Let the cost of one kg of sugar be Rs. xand that of tea be Rs. y.

x+y=300-----------(i)5x+2y=720---------(ii)On solving equation (i) and (ii),we get:-x=40:. Value of one kg of sugar=x=Rs. 40

Thanks

Selling Price = Cost Price + Profit (SP = CP + P)

Profit on sale of 45 kg sugar = Selling Price of 5 kg sugar : 45P = 5(C + P)

⇒ 45P = 5C + 5P

⇒ 45P - 5P = 5C

⇒ 40P = 5C

⇒ P/C = (5*100)/40

⇒ P/C = 500/40

⇒ 12.5 %

So, profit margin on Cost Price is 12.5 %

Find first cost price of sugar= 22×120=2640.then 30% of sugar=30×120/100=36.so he sell 36 kg of sugar at Rs 13 = 36×13= Rs 468.then he sells the remaining sugar i.e(120-36)kg sugar at the rate of Rs 25=84×25=Rs 2100.Now both the selling price =Rs2100+Rs468=Rs2568.now selling price is less than cost price.So, it will be a loss.So loss percentage=(2640-2568×100/2640)=2.727%

total weight 3 1/4 kg = 13/4 kg weight of 1 packet = 1/16 kg number of packets can be made = (13/4)/(1/16) = (16×13)/4 = 4×13 = 52