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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 2751. |
enSolved Examples:Ex.1. Differentiate the following fun |
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Answer» differentiate the following w.r.t.x.y=under root x²+5 |
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| 2752. |
ND SOLVED EXAMPLES OeEx. 1. Find the sum of 7, 11, 15, 19,... , up to 60 terms. |
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Answer» Tq |
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| 2753. |
Solved Examples:Ex.1. Find , if y is equal to :(i) x. log x(iv) tan-1xSolutions: (1) |
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Answer» it is equal to=x.logc it is equal to x.log x x.log x is the correct answer x.logx is the correct answer it is equal to=x.logc |
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| 2754. |
umerent types, thfirst which appears first in the word ILATE, where I stafunction, L stands for logarithmic function, A stands for algfor trigonometric function arnd E stands for exponential funSOLVED EXAMPLESExample 1. Ecaluate the following integralsz da(i) x log (1+ x) dxiiu) |
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| 2755. |
4 . 3sind +2c0s0 oडी IR tand =, ¥ St A ज्ञात करें।3sin® — 2cos0 |
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Answer» Given 3tanA=43sinA/cosA=43sinA/2cosA=2/1applying componendo dividendo3sinA+2cosA/3sinA-2cosA=2+1/2-1=3/1=3 |
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| 2756. |
cotCOcotdditional Solved Examples: |
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Answer» Abe saale |
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| 2757. |
SOLVED EXAMPLESShow that the system of equationshas a unique solution. Find the solution. |
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Answer» 2x+5y=17.....5-----10x+25y=85 5x+3y=14.....2-----10x+6y=28subtract both the equations19y=57y=32x+5*3=172x=17-15=2X=1 |
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| 2758. |
sinx âsiny _COSXx+Ccosy |
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| 2759. |
निखित फलनों से ज्ञात कीजिए0/2x+3y-siny |
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Answer» d 2x/dx + d 3y / dx = d sinydx ; 2 + 3 dy/dx = cosy ( dy/dx); cos y ( dy/dx) = 2 + 3 ( dy/dx); cos y ( dy/ dx)-3 dy/ dx =2; dy/ dx ( cos y -3) = 2; dy/ dx = 2 / cosy -3; dy/dx =2/cosy-3; answer dy/dx=2/cos y-3 is the right answer |
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| 2760. |
SOLVED EXAMPLESlei. | Trace the conic 9x^2 + 24xy + 16y^2-2x + 14y + 1 = 0 . |
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| 2761. |
Solved Examples1-Write the equation of ellipse 20x^2 +9y^2 = 180 in standard form |
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| 2762. |
cos(x+y)=cosx cosy-sinx siny |
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Answer» Let x+y= c, a constant Let A(x)=cos(x)cos(c-x)-sin(x)sin(c-x)=cos(x)cos(y)-sin(x)sin(y) If we know the differentiations of sin(x) and of cos(x), then it can be shown that A’(x)=0 Let if x=0, Then A(0)= 1*cos(c)= 0*sin(c)=cos(c)= cos(x+y)= constant, so, A(x)=cos(x+y)=cos*x)cos(y)=sin(x)sin(y) |
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| 2763. |
c)Solve the differential equationdy1 + x2y + siny |
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| 2764. |
Prove that geometrically cos (x + y)cosx cosy-sinx siny |
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| 2765. |
¢hle Bk dh Mnle Bl bl g UiC |
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| 2766. |
i. i? = con"(/cosi-tan-loss), then prove that : siny = un- |
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Answer» Y= cot-¹( √cosx ) - tan-¹( √cosx) Let cot-¹(√cosx) =PcotP = √cosx sinP = 1/√(1 + cosx) P = sin-¹{1/√(1 + cosx)} Let tan-¹( √cosx) = Q tanQ = √cosx sinQ = √cosx/√(1 + cosx) Q = sin-¹( √cosx/√(1 + cosx ) y = P - Q siny = sin(P - Q ) = sinP.cosQ - cosP.sinQ = 1/√(1 + cosx).1/√(1 + cosx) - √cosx/√(1 + cosx) .√cosx/√(1 + cosx) = (1 - cosx)/(1 + cosx)= 2sin²x/2/2cos²x/2 = tan²x/2 Hence, siny = tan²x/2 |
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| 2767. |
ââ Al | Jant Cobt+ Q= St - (et |
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Answer» tan²A + cot²A + 2 = tan²A + cot²A + 2 tan A × cot A = ( tan A + cot A)² = (sinA/cosA + cosA /sinA)² = ( sin²A + cos² A)²/ cos²A sin²A = sec²A cosec²A |
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| 2768. |
। ८८ णब ) [ o£9509 2छब०० | व.AL ST |
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Answer» (sin27 /cos63)² + (cos63/sin27)² (sin(90°-63°)/cos63°)²+ (cos(90°-27°)/sin27)² (cos63/cos63)² + (sin27/sin27)² 1² + 1² 2 Please hit like and BeScholr |
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| 2769. |
show that 250 is ivationalnumber |
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| 2770. |
(n 35 Cx,Pind the radius of a circle whose circumference is 57.2 cn |
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| 2771. |
दि +) नव; 235 2. कि |
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Answer» x + y = 4 .....(1) 2x - 5y = 1 ......(2) eq(1) × 5 + eq(2) 5x + 5y = 20 2x - 5y = 1 solving we get 7x = 21 So, x = 3 Therefore y = 4 - x = 4 - 3 = 1 |
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| 2772. |
7. What is the ratio of 3.525 Ă 108 and 235 x 105 ? |
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| 2773. |
235/5 |
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Answer» 235/5 = 47 |
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| 2774. |
Find the cost of fencing a square park of side 250 m al the rate of Rs 20 per metre. |
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| 2775. |
or a circle is (14+6,6) Ď untis, Pind its radius.2. Show that 4 and 1 are the zeroes of quadratie polynormiai p(-xA. Aisverify the relation between the zeroes and the coefficients of the polynomial3. Sol Ive the pair of equations for at t |
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| 2776. |
8)Pind the area of triangle whose sides are 14 em. 15 cn & 17 m |
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Answer» ask to your math teacher |
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| 2777. |
In fig. 11.49, in ÎABC, a lineparallel to BC intersects AB and AC at D and Erespectively and divides ABin the ratio 1:2, findthe ratio of the areas of trapezium BDEC andÎ ADE formed. |
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Answer» nice |
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| 2778. |
LeM Pind42.1105 |
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| 2779. |
Pind n and Y |
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| 2780. |
Pind the two ivational no Land |
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Answer» Two find two rational numbers between 1/7 and 2/7 Multiply and divide each rational number by 3 Now,1/7 = 3/212/7 = 6/21 Therefore,Two rational numbers between 3/21 and 6/21 are 4/21, 5/21 |
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| 2781. |
aide 2a pind each or ihs alttude |
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| 2782. |
Pind Rive Gational numbes between 5 and 5 |
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Answer» 3.1/5,3.2/5,3.3/5,3.4/5,3.5/5 |
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| 2783. |
3. Pind Rive Gational numbers between 5 and |
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Answer» Five rational numbers3.1/5,3.2/5,3.3/5,3.4/5,3.5/5 |
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| 2784. |
[{-15/13}]×139/8÷4 |
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Answer» can be solved using BODMAS :-=>{-15/13}×139/2=>(-15×139)÷(13×2)=>-77/13 |
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| 2785. |
139 + 235 = |
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| 2786. |
TIL1000 amount to1331 at 10% per annum comMPLE 9.In what time willannually? |
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| 2787. |
If √3-1 divided by √3+1 = a+b√3 , then find a and b ? |
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| 2788. |
( g ) ( a ^ { 3 } b ^ { 3 } - \frac { 1 } { a ^ { 3 } b ^ { 3 } } ) ( a ^ { 3 } b ^ { 3 } + \frac { 1 } { a ^ { 3 } b ^ { 3 } } ) ( a ^ { 6 } b ^ { 6 } + \frac { 1 } { a ^ { 6 } b ^ { 6 } } ) |
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| 2789. |
18. If 2a + b = 37, then A divides BC in the ratio:(a) 3:1 externally (b) 3:1 internally(c) 1:3 externally d) 1:3 internally |
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Answer» b)3:1 internally ...... |
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| 2790. |
5.af2x-y=1332-1 4-43-3 이 and 2y + x =1-1 4-4「 4 1Sten find x and y.if 2x-y=13322 -1 1Ans. x=1-1 20 |
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| 2791. |
26. Show that the following points are the vertices of a square:(i) A(3, 2), B(0, 5), C(-3, 2) and D(0,-1)ti A(6, 2), B(2, 1), C(1, 5) and D(5, 6)(iii) A(0, -2), B(3, 1), C(0, 4) and D(-3, 1)[Cr cn 3 and D(4 |
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Answer» pura Nhi aarha hsi sorry pura Nhi aarha hai |
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| 2792. |
12-1-a+bV2 20. 52+1(a) a = 3, b = -2(c) a = 2, b = -3(b) a = 3, b = 2(d) a = -2, b = 3 |
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Answer» a=3b=-2 is the rigth answer |
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| 2793. |
factorise.|1 1 1 ||a^2 b^2 c^2 ||a^3 b^3 c^3 | |
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Answer» Please post an appropriate question |
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| 2794. |
Solve : \{ ( \frac { 1 } { 4 } ) ^ { - 1 } - ( \frac { 1 } { 4 } ) ^ { - 1 } \} ^ { - 1 } |
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Answer» The answer is zero. 4/1 - 4/1 = 0 |
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| 2795. |
\left. \begin{array} { l } { \text { The square root of } \frac { ( 3 \frac { 1 } { 4 } ) ^ { 4 } - ( 4 \frac { 1 } { 3 } ) ^ { 4 } } { ( 3 \frac { 1 } { 4 } ) ^ { 2 } } - ( 4 \frac { 1 } { 3 } ) ^ { 4 } } \\ { ( a ) 7 \frac { 1 } { 12 } } \\ { ( c ) 1 \frac { 1 } { 12 } } \end{array} \right. |
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Answer» Option B is correct. |
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| 2796. |
1 4+ ] 4 1 is139 42 1 )G 1 ) 4 % |
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| 2797. |
side.jacent sides of a parallelogram are 20cm and 12cm. If the distance between the longer sides t6cm. find the distance between the shorter sides.Pr |
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| 2798. |
If length,breadth and total surface area of a Cuboid are 15cm,10cm and 1300cmsquare,then it's height is |
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Answer» Surface area = 2(lb+bh+hl)1300 = 2(15×10+10h+15h)1300÷2 =(150+25h)650=150+25h25h=650–15025h = 500h=500/25h = 20cm |
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| 2799. |
If length,breadth and total surface area of a Cuboid are 15cm,10cm and 1300cmsquare ,then it's height is |
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Answer» Surface area = 2(lb+bh+hl)1300 = 2(15×10+10h+15h)1300÷2 =(150+25h)650=150+25h25h=650–15025h = 500h=500/25h = 20cm |
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| 2800. |
The adjacent sides of a parallelogram are 32 cm and 24 cm. If thedistance between the longer sides is 17.4 cm, find the distance betweenthe shorter sides. |
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Answer» thanks bhai |
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