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2801.

The adjacent sides of a parallelogram are 10 m and 8 m. If the distance between the longer sides is4 m, find the distance between the shorter sides

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2802.

he adjacent sides of a parallelogram are 15 cm and 8 cm. If the distance between thelonger sides is 4 cm, find the distance between the shorter sides.

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2803.

29. The variation of acceleration (a) and displacement() of the particle executing SHM is indicated bythe following curveAax (2)153

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Correct option: 1Reason: In SHM, acceleration is directly proportional to negative of displacement.

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2804.

19. The radi of the circular ends of a bucket of height 15cm are 14cm and r cm (rIf the volume of bucket is 5390 cms then find value of r. (Use π-)7

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2805.

a train covers 120 km in 1hr ?how much distance will it cover in 45 minutes

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90 km in 45 min is correct answer

train will cover 90 km in 45 min

90 km in 45 min is right ans

I think it's 90 km ....

2806.

Q10. The radii of the circular ends of a bucket of height 15em are 14cm andrem. If the volume of the bucket is 5390 cm", then find the value of r.

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2807.

Q10. The radii of the circular ends of a bucket of height 15cm are 14cm andr em. If the volume of the bucket is 5390 cm, then find the value of r.

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2808.

21. The radii of the circular ends of a bucket of height 15 cm are 14 cm and r em (r <14), If thevolume of bucket is 5390 cm3, then find the value of r

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2809.

Find the distance covered by the wheel of a car in 500 revolutións the dwheel is 77 cm.imake toThe diameter of the wheel of a car is 70 cm. How many revolutions will it.65 km?ARFA

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8 revolutions per km...............

2810.

AE of the jet from a point A on the ground is 60°.after flight of 15 second. AE changes to 30° . if the jet speed is 720 km\h.find the height

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2811.

khil covered a distance of 15 km in 60 minutes. He covered first part of the journey by walking at5 km/h and the rest of the journey by a car at 30 km/h. Find the distance covered by the car.

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Average speed = 15/1= 15km/h

Let Akhil covered distance by walk be xthen distance by car be 15-x

x/4.5 + 15-x/30= 110x/45+ 15-x/30= 1{20x+3(15-x)}/90= 120x+45-3x=9017x=45

x= 45/17=2.6km (approximately)

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2812.

Akhil covered a distance of 15 km in 60 minutes. He covered first part of the journey by walking at 4.5km/h and the rest of the journey by a car at 30 km/h. Find the distance covered by the car

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Average speed = 15/1= 15km/hLet Akhil covered distance by walk be xthen distance by car be 15-xx/4.5 + 15-x/30= 110x/45+ 15-x/30= 1{20x+3(15-x)}/90= 120x+45-3x=9017x=45x= 45/17=2.6km (approximately)

2813.

19. A car covers the first 30 km of its journey in 45 minutesand the remaining 25 km in 35 minutes. What is theaverage speed of the car?

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total distance=30+25=55total time taken=45+35=80minaverage=55/80=11/16average=11:16

2814.

A car covers 72 km in 2 hours and a train covers 120 km in 3 hours. Find the ratio of their speeds.

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2815.

3 n^{2}-2 n-2640=0

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2+145.3/4 and 2-145.3/4 roots will be there for this equation

2816.

८; 2080 45+ ०08 30* |— sin® 60°,

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Tan45=1cos30=√3/2sin60=√3/2hence2(1)^2+(√3/2)^2-(√3/2)^2hence2(1)+0=2

2817.

A car travelled 60 Km to the north of patna and then 90 km to the South from there. how far from panta was the car finally?

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2818.

Mohit travelled 2/3 of his journey by train, 1/4 of the journey by bus andremaining journey by car. If the distance he travelled by train is 60 KM more thanthe distance he travelled by bus, what was the total distance he had travelled?

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2819.

Ramesh covered r of his entire trip by air, two-thirds of his trip by bus and the remaining bycar. If Ramesh travelled 720 Km. by air, thenfind the distance travelled by him by car.A) 460 Km. /frfi.B) 480 Km

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2820.

A car travelled 90 km in 2 1/2 hours . How much time is required to cover 30 km in same speed.

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2821.

यिं 2005 (90%- 8) -1 न 0 कब, जाएव (718 (T sin3A = 3sinA — 4sin’A

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2822.

1/2,2/3,3/4,3/4 set decreasing order

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1/2=.52/3=.66663/4=.753/4 =.75 it's ans hope u like this

2823.

नई eD फिमििक न 85956

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9sec²θ-9tan²θ9(sec²θ-tan²θ)sec²x-tan²x=19*19

2824.

Take flowers. How many flowers will he take?A book contains 64 pages. Radha readspages of the book in one day. How manypages does she read on that day?Rahul invited 20 friends on his birthday party.Only 17 friends came to attend the party. Whatfraction of the friends did not attend the party?A shopkeeper has 18 diamonds. He used 1How many diamonds did he use?106

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2825.

33. Show that r - sinr has neither marima nor minima.

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for maxima or minima , f'(x) should change its sign from +ve to -ve , or vice versa..

but here f'(x) = 1-cosx that is always ≥ 0 so since f'(x) ≥ 0 so it will not have any maximum or minimum value

2826.

1)Discuss the continuity of the function f given by f(x) = x at x = 032 if y

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2827.

1.Apark, in the shape ofaquadrilateral ABCD, hasLC#90°.AB-9m,BC-nnCD5 m and AD8rn. How much area does it occupy?

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2828.

17. (A) The mode of the below table is 97.5. Find'xHeight lin am) 81-85 8690 91-95 96-100 101-105 106-110 111-115No. of persons 2718 36(or)

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2829.

( 1 + \operatorname { cos } \frac { \pi } { 8 } ) ( 1 + \operatorname { cos } \frac { 3 \pi } { 8 } ) ( 1 + \operatorname { cos } \frac { 5 \pi } { 8 } ) ( 1 + \operatorname { cos } \frac { 7 \pi } { 8 } ) = \frac { 1 } { 8 }

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2830.

: ( 1 + \operatorname { cos } \frac { \pi } { 8 } ) ( 1 + \operatorname { cos } \frac { 3 \pi } { 8 } ) ( 1 + \operatorname { cos } \frac { 5 \pi } { 8 } ) ( 1 + \operatorname { cos } \frac { 7 \pi } { 8 } ) = \frac { 1 } { 8 }

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2831.

(2 1/2 × 8/10)÷(1 1/2+ 5/8)

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(5/2*4/5)/(3/2+5/8)(2)/34/1616*2/3416/17

16/17 is the correct answer.

2832.

1/(1/3 %2B 1/2) %2B 1/(1/8 %2B 1/6)

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(6^-1 + 8^-1)^-1 + (3^-1 + 2^-1)^-1

= (1/6 + 1/8)^-1 + (1/3 + 1/2)^-1

= [(4 + 3)/24]^-1 + [(2 + 3)/6]^-1

= 24/7 + 6/5

= (24*5 + 6*7)/35

= (120 + 42)/35

= 162/35

2833.

X-1し5.(a) Prove that the function log sin x is decreasing inIT,T2

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2834.

The function f(x) = x + 1/x is decreasing in the interval

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f(x) is decreasing then f'(x) <0

So, f'(x) = 1 - 1/x² < 0

x² < 1

So, x belongs to (-1,0) union (0,1)

2835.

INCREASINGAND DECREASINGFUNCTIONSf(x)=x^{3}-3 x^{2}+5 x+7 is

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2836.

[ 2 - \frac { 1 } { 3 } ] [ 2 - \frac { 3 } { 5 } ] [ 2 - \frac { 5 } { 7 } ] \dots [ 2 \cdot \frac { 997 } { 999 } ]

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5/3*7/5*9/7.......1001/999=1001/3

2837.

6.For what value of m, the function f (x) = mx + c is decreasing for x E R.

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2838.

(MATHEMATICS-IB) MAXIMA &amp; MINIMA32.f(x) = x2 -4 is decreasing in

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2839.

1५५७४ A SIS Ml Ber. Oice,y T VR, R sen3 nae. AL whial s o aion A,Q) 2 15 VE. z\m\eflw A wY AV लक MM_%%‘MJ

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Let a be any positive integer and b = 3a = 3q + r, where q ≥ 0 and 0 ≤ r < 3Therefore, every number can be represented as these three forms. There are three cases.Case 1: When a = 3q,Where m is an integer such that m = Case 2: When a = 3q + 1,a^3= (3q +1)^3a^3= 27q^3+ 27q^2+ 9q + 1a^3= 9(3q^3+ 3q^2+ q) + 1a^3= 9m + 1Where m is an integer such that m = (3q^3+ 3q^2+ q)Case 3: When a = 3q + 2,a^3= (3q +2)^3a^3= 27q^3+ 54q^2+ 36q + 8a^3= 9(3q^3+ 6q^2+ 4q) + 8a3= 9m + 8Where m is an integer such that m = (3q^3+ 6q^2+ 4q)Therefore, the cube of any positive integer is of the form 9m, 9m + 1, or 9m+8

2840.

Find the intervals in which the function f given by4 sin x-2x-xcos xf(x) =2 + cos xis (i) increasing (ii) decreasing.

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2841.

Find the circumference and area of a circle whose diameter is 35 cm.

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circumference is πd=22/7*35=22*5=110cmarea is πd^2/4=22/7*35*35/4=962.5cm^2

2842.

4om,CDs2, Pind thearea ofaquadrilateral ABCD in which AB #3 cm. BCDA#5cm andACSens.

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2843.

ace area of a sphere is 3850 cm?, then the diameter of the sphere is4 35 cm

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2844.

2. Find the circumference of a circle whose diameter is(i) 14 cm(ii) 35 cm(ii) 10.5 m

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2845.

chordofcircleofradius 15 cm subtends an angle of 60° at the centre. Find theAareas of the corresponding minor and major segments of the circle. (Use Tt 3.14and v31.73)a

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2846.

The factors of 11x2 - 7x - 44x + 28 are1) (x 4)(11x - 7)3l (x- 4)(11x + 7)2) (x + 4)(11x -7)4) (11x + 4)x -7)

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Factor of this will be (x-4) (11x-7)

2847.

Find the median of the following dat6, 7, 9, 3, 2, 4, 7, 11, 19, 216, 7, 9, 3, 2, 4, 7, 11, 19, 21

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2,3,4,6,7,7,9,11,19,21

Median = 10+1/2 = 5th + 6th term/2

= 7+7/2

= 7

2848.

\frac { 1 } { 7 } , \frac { 2 } { 7 } , \frac { 3 } { 7 } , \frac { 4 } { 7 }

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2849.

999*(6/7) %2B 999*(5/7) %2B 999*(4/7) %2B 999*(3/7) %2B 999/7 %2B 999*(2/7)

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answer is 2997 because take 999/7 as common in all terms then it add them we get 21 by dividing it with 7 we get 3.. so 999*3= 2997

2850.

-Abs(4/((-7))) %2B 3/7 - Abs(-2/7) %2B Abs(9/7)

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=(9/7)-(2/7)+(3/7)-(4/7)=(9-2+3-4)/7=6/7. ans.

(9/7)+2/7+3/7-4/7=9+2+3-4/7=10/7

(9/7)+(2/7)+3/7-4/7=11/7-1/7=10/7.