Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Identify the quantifier in the statement and write the negation of the statement.There exists a number which is equal to its square.

Answer»

SOLUTION :Each NUMBER is not EQUAL to its SQUARE.
Discussion
2.

If x=a+b, y=a omega+b omega^2,z=a omega^2+bomega show thatxyz =a^3+b^3

Answer»

SOLUTION :`L.H.S.=xyz=(a+b)(aomega+bomega^2)(a OMEGA^2+b omega)`
`=(a+b)(a^2omega^3+abomega^2+abomega^4+b^2omega^3)`
`=(a+b){a^2+b^2+ab(omega^2+omega)}`
`=(a+b){a^2-b^2+ab(omega^2=omega)}`
`=(a+b)(a^2-ab+b^2)=a^3+b^3="R.H.S.(PROVED)"`
Discussion
3.

Find (dy)/(dx) if 2x+3y=sinx

Answer»

SOLUTION :DIFFERENTIATING throughout w.r.t.x, we GET `d/DX(2x)+d/dx(3y)=d/dx(sinx)2+3(DY)/(dx)=cosx3(dy)/(dx)=cosx-2,(dy)/(dx)=(cosx-2)/3`
Discussion
4.

Evaluation of definite integrals by subsitiution and properties of its : int_(0)^(pi/2)(2^(sinx))/(2^(sinx)+2^(cosx))dx=.........

Answer»

`(PI)/(4)`
`(pi)/(2)`
`pi`
`2PI`

ANSWER :A
Discussion
5.

Differentiate w.r.t.x the function in Exercises 1 to 11. (x)^(log x), x gt 1.

Answer»
Discussion
6.

If |x| is so small that x^(2) and higher powers of x may beneglected then the approximate value of (sqrt(4+x)+root(3)(8-x))/((1-(2x)/(3))^(3/2)) when x = (6)/(25) is

Answer»

6
5
`(2)/(5)`
`(5)/(6)`

ANSWER :B
Discussion
7.

If (omega ne1) is a cube root of unity , then {:(1 , 1 + i+ omega^(2) , omega^(2)) , (1-i, -1 , omega^(2) -1) , (-i , -1 + omega - i, -1):}|

Answer»

ZERO
1
`i`
`OMEGA`

ANSWER :A
Discussion
8.

Evaluate the following integrals. int(3x-2)sqrt(2x^(2)-x+1)dx

Answer»


Answer :`(1)/(2)(2X^(2)-X+1)^(3//2)-(5)/(4sqrt(2))(x-(1)/(4))sqrt((x-(1)/(4))^(2)+(7)/(16)) - (35)/(64sqrt(2)))sinh^(-1)((4x-1)/(sqrt(7))+C`
Discussion
9.

One of the value of [cos(pi//6)-isin(pi//6)]^(11//2)/[cos(pi//6)+isin(pi//6)]^(1//2) is

Answer»

1
0
-1
`1//2`

ANSWER :C
Discussion
10.

If A=[a" "b],B=[-b" "-a]andC=[{:(a),(-a):}]then out of the following ……… statement is true.

Answer»

A=-B
A+B=A-B
AC =BC
CA =CB

Answer :C
Discussion
11.

Which set of magnitude of vectors can give null vector ?

Answer»

2,2,4,9
4,8,12,16
3,6,9,19
1,1,5,2
Discussion
12.

A point M divides A and B in the ratio 1:2 where A and B diametrically opposite ends of a circle x^(2)+y^(2)-5x-9y+22=0 square AMCD and BMEF on the length AM and MB are constructed on the same side of line AB if co-ordinates of A is (1,3) then find the orthocentre of DeltaABE

Answer»

`(1,6)`
`(1,5)`
`(3,3)`
`(4,6)`

Solution :SHOWN in the figure SINCE `C(1,5)` is the orthocentre of triangle `DeltaAEB`, similarly for the other SIDE COORDINATES of `C(3,3)`.
Discussion
13.

If for n gt 1, P_(n)=int_(1)^(e ) ( logx)^(n)dx, then P_(10)-90P_(8)is equal to:

Answer»

A) `-9`
B) 10E
C) `-9e`
D) 10

Answer :3
Discussion
14.

Let overset(-)a be a unit vector overset(-)b=2hati+hatj-hatk and overset(-)c=hati+3hatk. Then maximum value of [overset(-)a overset(-)b overset(-)c] is

Answer»

`-1`
`SQRT10 +SQRT6`
`SQRT(10)-sqrt6`
`sqrt(59)`

Answer :D
Discussion
15.

sin47^(@)+sin61^(@)-sin11^(@)-sin25^(@)=

Answer»

`SIN7^(@)`
`COS7^(@)`
`TAN7^(@)`
`sin14^(@)`

ANSWER :B
Discussion
16.

The locus of the poles of the line 2x+3y-4=0 w.r.t. the circle x^(2)+y^(2)+2lambdax-16=0 is

Answer»

`13X^(2)-22xy-14y+48=0`
`X^(2)-32xy-14y+88=0`
`3x^(2)-2xy-4y+48=0`
`3x^(2)-2xy-4y-48=0`

ANSWER :C
Discussion
17.

Let f(x) denotes the number of zeroes in f'(x). If f(m)-f(n)=3, the value of ((m-n)_(max)-(m-n)_(min))/(2) is ........... .

Answer»


ANSWER :9
Discussion
18.

An ellipse and a hyperbola have the same centre as origin, the same foci and the minor-axis of the one is the same as the conhugate axis of the other . If e_1,e_2 betheir eccentricities respectively, then e_1^(-2)+e_2^(-2) equals

Answer»

1
2
3
4

Answer :B
Discussion
19.

Latus rectum of the parabola whose axis is parallel to the y-axis and which passes through the points (0,4), (1,9) and (-2,6) is equal to

Answer»

2
1
`1//2`
`1//4`

ANSWER :C
Discussion
20.

If A = [(2,52,152),(4 , 106,358),(6,162,620)] then det (adj ((1)/(2) A)) is equal to _______ .

Answer»


ANSWER :1
Discussion
21.

(1^2.2)/(1!) +(2^2.3)/(2!) + (3^2.4)/(3!)+......oo =

Answer»

2e
3e
7e
9e

Answer :C
Discussion
22.

Statement 1 : Lines vecr=hati+hatj-hatk+lamda(3hati-hatj) and vecr=4hati-hatk+ mu (2hati+ 3hatk) intersect. Statement 2 : If vecbxxvecd=vec0, then lines vecr=veca+lamdavecb and vecr= vecc+lamdavecd do not intersect.

Answer»

Both the statements are true, andStatement 2 is the CORRECT explanation for Statement 1.
Both the Statements are true, but Statement 2 is not the correct explanation for Statement 1.
Statement 1 is true and Statement 2 is false.
Statement 1 is false and Statement 2 is true.

Solution :For the GIVEN lines, LET `vec(a_1) =hati+hatj-hatk, vec(a_2)= 4hati-hatk, vec(b_1) = 3hati-hatj and vec(b_2) = 2hati+3hatk`. Therefore,
`""[vec(a_(2))-vec(a_(1))vec(b_1)vec(b_2)]=|{:(4-1,,0-1,,-1+1),(3,,-1,,0),(2,,0,,3):}|`
`""= |{:(3,,-1,,0),(3,,-1,,0),(2,,0,,3):}|=0`
Hence, the lines are COPLANAR. Also VECTOR `vec(b_1) adn vec(b_2)`along which the lines are directed are not collinear.
Hence, the lines intersect. When `vecbxxvecd=vec0` , vectors and `vecr=vecc+lamdavecd` are parallel and do not intersect. But this statement is not the correct explanation for Statement 1.
Discussion
23.

Evaluate the following integrals inte^(x)sin^(2)x dx

Answer»


ANSWER :`(E^(x))/(2)[1-(cos2x+2sin2x)/(5)]+C`
Discussion
24.

An urn contains 25 balls of which I0 balls bear a mark 'X' and remaining 15 bear a mark 'Y'. A ball is drawn at random from the urn, its mark is noted down and it is replaced. If 6 balls are drawn in this way, find the probability that i. all will bear 'X'mark ii. not more than 2 will bear 'Y' mark iii. atlest one ball will bear 'Y' mark iv. the number of balls with 'X' marks and 'Y' mark will be equal

Answer»


Answer :i. `((2)/(5))^(6)`, ii. `7((2)/(5))^(4)` , III. `1-((2)/(5))^(6)` and IV. `(864)/(3125)`
Discussion
25.

If s and p are respectively the sum and the product of the slopes of the lines 3x^(2) - 2 xy - 15 y^(2) = 0then s : p is equal to

Answer»

`4 : 3`
`2 : 3`
`3 : 5`
`3 :4`

ANSWER :B
Discussion
26.

Match the following .

Answer»
Discussion
27.

If 3,-2 are the Eigen values of a non-singular matrix A and |A|=4,then the Eigen values ofare :

Answer»

`3/4,(-1)/2`
`4/3,-2`
`12,-6`
`-12,8`

ANSWER :B
Discussion
28.

The point ofinersection of the line vec(r)=(hat(i)-hat(k))+t(3hat(i)+2hat(j)+7hat(k))" and the plane "vec(r)=(hat(i)+hat(j)-hat(k))=8 is

Answer»

`(8,6,22)`
`(3t+1,2t,7t-1)` for some value of t
`(-8,-6,-22)`
`(x-1)/(3)=(y-0)/(2)=(z+1)/(7)=" for some value of t "`

ANSWER :B
Discussion
29.

If one root of the equation lx^(2)+mx+n=0" is "(9)/(2) (l,m and n are positive integers) and (m)/(4n)=(l)/(m), then l+n is equal to

Answer»

`80`
`85`
`90`
`95`

ANSWER :B
Discussion
30.

Match the following .

Answer»

<P>`{:(P,Q,R,S),(2,1,4,3):}`
`{:(P,Q,R,S),(4,3,1,2):}`
`{:(P,Q,R,S),(3,1,2,4):}`
`{:(P,Q,R,S),(2,4,1,3):}`

ANSWER :D
Discussion
31.

If x+1/x=2cos alpha,y+1/y=2cos beta, then xy+(1)/(xy)=

Answer»

`cos(pm alpha pm beta)`
`2COS(pm alpha pm beta)`
`2sin(pm alpha pm beta)`
`SIN(pm alpha pm beta)`

ANSWER :B
Discussion
32.

If a, b, c, d are in G.P., then (a + b + c + d)^(2) is equal to

Answer»

`(a + B)^(2) + (C + d)^(2) + 2(b + c)^(2)`
`(a + b)^(2) + (c + d)^(2) + 2(a + c)^(2)`
`(a + b)^(2) + (c + d)^(2) + 2(b + d)^(2)`
`(a + b)^(2) + (c + d)^(2) + (b + c)^(2)`

ANSWER :A
Discussion
33.

Show that four points with position vectors 6 hat i - 7 hat j, 16 hat i - 19 hat j - 4 hat k, 3 hat i - 6 hat k and 2 hat i + 5 hat j + 10 hat k are not coplanar.

Answer»


ANSWER :The POINTS A, B, C and D are not COPLANAR.
Discussion
34.

For the curve x= 2a sin t+ a sin t cos^(2) t, y=-a cos^(3) t

Answer»

NORMAL is inclined at an ANGLE `(pi)/(2)+1` with x-axis.
nomal is inclined at an angle t with r-axis.
portion of normal contained between the co-ordinate AXES has the maximum value. co-ordinate axes is EQUAL to 2a
portion of normal contained between theco-ordinate axes is equal to 4a.

Answer :A::C
Discussion
35.

Incircle of Delta ABC touches AB, BC, CA at R, P, Q, respectively. If (2)/(AR)+(5)/(BP)+(5)/(CQ)=(6)/(r ) and the perimeter of the triangle is the smallest integer, then answer the following questions : The area of Delta ABC is

Answer»

15 sq. units
21 sq. units
24 sq. units
27 sq. units

Solution :
LET `tan.(A)/(2)= x, tan.(B)/(2)=y, tan.(C )/(2)=z`
`therefore x=(r )/(AR), y = (r )/(BP), z=(r )/(CQ)`
Put the values of AR, BP and CQ in given RELATION, we GET
`(2x)/(r )+(5y)/(r )+(5Z)/(r )=(6)/(r )`
`rarr 2x+5y+5z=6` .....(1)
Also in the triangle, `xy + yz + zx = 1`.....(2)
It we interchange y and z, then both equations (1) and (2) remain unchanged
`rArr ABC` is isoceles with `angle B = angle C rArr y =z`
So form (1) and (2), we get
x = 3 - 5 y.......(3)
and `2xy + y^(2)=1` ....(4)
Solving we get, `x = (4)/(3), y = z = (1)/(3)`
`therefore AR = (3r)/(4), BP= 3r, C = 3r`
Now perimeter `2s=2.AR+2.BP+2.CQ=(27r)/(2)`
Given perimeter is smallest integer `rarr r =2`
`therefore s=(27)/(2)`
`therefore Delta = rs = 2xx(27)/(2)=27` sq. unit.
Discussion
36.

If s = t^(3) - 4t^(2) + 7 the velocity when the acceleration is zero is

Answer»

`(32)/(3)` m/sec
`(-16)/(3)` m/sec
`(16)/(3)` m/sec
`(-32)/(3)` m/sec

Answer :B
Discussion
37.

Incircle of Delta ABC touches AB, BC, CA at R, P, Q, respectively. If (2)/(AR)+(5)/(BP)+(5)/(CQ)=(6)/(r ) and the perimeter of the triangle is the smallest integer, then answer the following questions : The inradius of incircle of Delta ABC is

Answer»

4
3
2
1

Solution :
LET `tan.(A)/(2)= x, tan.(B)/(2)=y, tan.(C )/(2)=z`
`THEREFORE x=(r )/(AR), y = (r )/(BP), z=(r )/(CQ)`
Put the VALUES of AR, BP and CQ in given relation, we get
`(2x)/(r )+(5y)/(r )+(5z)/(r )=(6)/(r )`
`rarr 2x+5y+5z=6` .....(1)
Also in the triangle, `xy + yz + zx = 1`.....(2)
It we interchange y and z, then both equations (1) and (2) remain unchanged
`rArr ABC` is isoceles with `angle B = angle C rArr y =z`
So form (1) and (2), we get
x = 3 - 5 y.......(3)
and `2xy + y^(2)=1` ....(4)
Solving we get, `x = (4)/(3), y = z = (1)/(3)`
`therefore AR = (3r)/(4), BP= 3r, C = 3r`
Now perimeter `2s=2.AR+2.BP+2.CQ=(27r)/(2)`
Given perimeter is smallest integer `rarr r =2`
`therefore s=(27)/(2)`
`therefore Delta = rs = 2xx(27)/(2)=27` sq. unit.
Discussion
38.

Incircle of Delta ABC touches AB, BC, CA at R, P, Q, respectively. If (2)/(AR)+(5)/(BP)+(5)/(CQ)=(6)/(r ) and the perimeter of the triangle is the smallest integer, then answer the following questions : Delta ABC is

Answer»

scalene
isosceles
equilateral
right angled

Solution :
Let `tan.(A)/(2)= x, tan.(B)/(2)=y, tan.(C )/(2)=z`
`therefore x=(r )/(AR), y = (r )/(BP), z=(r )/(CQ)`
Put the values of AR, BP and CQ in given relation, we get
`(2x)/(r )+(5y)/(r )+(5z)/(r )=(6)/(r )`
`rarr 2x+5y+5z=6` .....(1)
Also in the triangle, `xy + yz + zx = 1`.....(2)
It we interchange y and z, then both equations (1) and (2) remain unchanged
`rArr ABC` is isoceles with `angle B = angle C rArr y =z`
So FORM (1) and (2), we get
x = 3 - 5 y.......(3)
and `2xy + y^(2)=1` ....(4)
Solving we get, `x = (4)/(3), y = z = (1)/(3)`
`therefore AR = (3r)/(4), BP= 3r, C = 3r`
Now perimeter `2s=2.AR+2.BP+2.CQ=(27r)/(2)`
Given perimeter is smallest integer `rarr r =2`
`therefore s=(27)/(2)`
`therefore Delta = RS = 2xx(27)/(2)=27` SQ. unit.
Discussion
39.

If f(x) = [4-(x-7)^(3) ] , then f^(-1)(x) = .........

Answer»


SOLUTION :N/A
Discussion
40.

If ath term is independent of x in (sqrtx//7- sqrt5 //x^2 )^10, bth term is independent of x in (7x^(-1//3) - 3x^(1//2))^25 and cth term is independent of x in (3x^2//7+21 //4x)^9 then , the ascending order of a, b, c is

Answer»

a, B, C
b, c, a
c, a, b
a, c, b

Answer :D
Discussion
41.

Iron filling and water were placed in a 5 litre tank and sealed. The tank was heated to 1273 K. Upon analysis the tank was found to contain 1.10 gram of hydrogen and 42.5 gm of water vapour. If the reaction in the tank is represented by 3Fe(s)+4H_(2)O(g)hArrFe_(3)O_(4)(s)+4H_(2)(g) the equilibrium constant will be-

Answer»

`2.949xx10^(-3)`
`6.490xx10^(3)`
`4.940xx10^(3)`
`3.200xx10^(3)`

ANSWER :a
Discussion
42.

Find the equation of the circle for which the point given below are the end points of a diameter.(7,-3) ,(3,5)

Answer»


ANSWER :` X^(2) + y^(2) -10 x - 2Y + 6=0 `
Discussion
43.

Letz_(1),z_(2),z_(3) be complex numbers, not all real, such that |z_(1)|= |z_(2)| =|z_(3)| = 1 and 2(z_(1) +z_(2)+z_(3)) -3z_(1)z_(2)z_(3) in Rprove that ma (arg z_(1)arg z_(2), argz_(3)) ge pi/6

Answer»
Discussion
44.

If p_(1),p_(2),p_(3) are the principal values of following trigonometric equations I) Sintheta=-1//2 II) Costheta=-sqrt(3)/(2) III) Tantheta=sqrt(3)-2

Answer»

<P>`p_(1)lt p_(2)lt p_(3)`
`p_(1)lt p_(3)lt p_(2)`
`p_(3)lt p_(1)lt p_(2)`
`p_(2)lt p_(3)lt p_(1)`

Answer :B
Discussion
45.

Evaluate the following integrals. int(1)/(x^(3)+1)dx

Answer»


Answer :`(1)/(3)log|x+1|-(1)/(6)log|x^(2)-x+1|+(1)/(sqrt(3))tan^(-1)((2x-1)/(sqrt(3)))+C`
Discussion
46.

The x intercept of the tangent to a curve f(x,y) = 0 is equal to the ordinate of the point of contact. Then the value of (d^(2)x)/(dy^(2)) at the point (1,1) on the curve is "_____".

Answer»


ANSWER :`-1`
Discussion
47.

Solve the following differential equations.dy/dt=sqrt(1-y^2)

Answer»

SOLUTION :`dy/DT=sqrt(1-y^2)rArrdy/sqrt(1-y^2)=dt`
`SIN^(-1)y=t+C`
Discussion
48.

z, if A='[{:(0,2y,z),(x,y,-z),(x,-y,z):}] satisfy A'=A^(-1)

Answer»

SOLUTION :We have `A=[{:(0,2y,z),(X,-y,z):}]` and `A=[{:(0,x,x),(2y,y,-y),(z,-z,z):}]`
By using elementary row transformation, we get
`rArr [{:(0,2y,z),(x,y,-z),(x,-y,z):}]=[{:(1,0,0),(0,1,0),(0,0,1):}]A`
`rArr [{:(0,2y,z),(x,y,-z),(0,2y,2z):}]=[{:(1,0,0),(0,1,0),(0,-1,1):}]A [because R_(3)rArrR_(3)-R_(2)]`
`rArr [{:(0,2y,z),(x,3Y,0),(0,0,3z):}]=[{:(1,0,0),(1,1,0),(1,-1,1):}]A [{:(becauseR_(3)rArrR_(3),+R_(1)),("and"R_(2)rArrR_(2),+R_(1)):}]`
`rArr [{:(-x,-y-z),(x,3y,0),(0,0,z):}]=[{:(0,-1,0),(1,1,0),((1)/(3),(-1)/(3),(1)/(3)):}]A[because R_(1)rArrR_(1)-R_(2)` and `R_(3)rArr(1)/(3)R_(3)`]
`rArr[{:(-x,-y,0),(x,3y,0),(0,0,z):}]=[{:((-1)/(3),(-2)/(3),(-1)/(3)),(1,1,0),((1)/(3),(-1)/(3),(1)/(3)):}]A [because R_(10rArrR_(1)-R_(3)]`
`rArr [{:(-x,-y,0),(0,2y,0),(0,0,z):}]=[{:((-1)/(3),(-2)/(3),(-1)/(3)),((2)/(3),(1)/(3),(-1)/(3)),((1)/(3),(-1)/(3),(1)/(3)):}]A[because R_(2)rArrR_(2)+R_(1)]`
`rArr[{:(-x,0,0),(0,2y,0),(0,0z):}]=[{:(0,(-1)/(2),(-1)/(2)),((2)/(3),(1)/(3),(-1)/(3)),((1)/(3),(-1)/(3),(1)/(3)):}]A[because R_(1)rArrR_(1)+(1)/(2)R_(2)]`
`rArr [{:(1,0,0),(0,1,0),(0,0,1):}]=[{:(0,(1)/(2x),(1)/(2x)),((1)/(3y),(1)/(6y),(-1)/(6y)),((1)/(3z),(-1)/(3z),(1)/(3z)):}]A[because R_(1)rArr(-1)/(x)R_(1)R_(2)rArr(1)/(2y)R_(2) "and" R_(3)rArr(1)/(2)R_(3)]`
`[{:(0,(1)/(2x),(1)/(2x)),((1)/(3y),(1)/(6 y)),(-1)/(6y)),((1)/(3z),(-1)/(3z),(1)/(3z)):}]=[{:(0,x,x),(2y,y,-y),(z,-z,z):}]`
`rArr (1)/(2x)=xrArr=+-(1)/sqrt(2)`
`rArr (1)/(6y)=yrArry=+-(1)/sqrt(6)`
and `(1)/(3z)=zrArrz=+-(1)/sqrt(3)`
Alternate method
We have, `A=[{:(0,2y,z),(x,y,-z),(x,-y,-z),(x,-y,z):}]` and `A=[{:(0,x,x),(2y,y, -y),(z,-z,z):}]`
ALSO, `A'=A^(-1)`'
`rArr A A'=A A^(-1) [because A A^(-1)=I]`
`rArr A A=I`
`rArr[{:(0,2y,z),(x,y,-2),(x,y,-z),(x,-y,z):}][{:(0,x,x),(2y,y,-y),(z,-z,z):}]=[{:(1,0,0),(0,1,0),(0,0,1):}]`
`rArr[{:(4y^(2)+z^(2),2y^(2)-z^(2),-2y^(2)+z^(2)),(2y^(2)-z^(2),x^(2)+y^(2)+z^(2),x^(2)-y^(2)-z^(2)),(-2y^(2)+z^(2),x^(2)-y^(2)-z^(2),x^(2)+y^(2)+z^(3)):}]=[{:(1,0,0),(0,1,0),(0,0,1):}]`
`rArr 2y^(2)-z^(2)=0rArr2y^(2)=z^(2)`
`rArr 4y^(2)+z^(2)=1`
`rArr 2.z^(2)+z^(2)=1`
`z=+-(1)/sqrt(3)`
`therefore y^(2)=(z^(2))/(2)rArry=+-(1)/sqrt(6)`
Also, `x^(2)+y^(2)+z^(2)=1`
`rArr x^(2)=1-y^(2)-z^(2)=1-(1)/(6)-(1)/(3)`
`=1-(3)/(6)=(1)/(2)`
`rArr x=+-(1)/sqrt(2)`
`therefore x=+-(1)/sqrt(2).y=+-(1)/sqrt(6)`
and `z=+-(1)/sqrt(3)`
Discussion
49.

Find the roots ofz^n = (z + 1)^nand show that the points which represent them are collinear. Hence show that these roots are also the roots of the equation, (2sin.(mpi)/(n))^2bar(z)^2+(2sin.(mpi)/n)^2bar(z)+1=0 where m = 1 , 2, 3, ..... (n-1)& |z| is finite.

Answer»


Answer :`ICOS.(mpi)/N; square and GET the RESULT
Discussion
50.

Let f (x) =1+ int _(0) ^(1) (xe ^(y) + ye ^(x)) f (y) dy where x and y are independent vartiables. If complete solution set of 'x' for which function h (x) = f(x) +3x is strictly increasing is (-oo, k) then [(4)/(4) e ^(k) ] equals to: (where [.] denotes greatest integer function):

Answer»

1
2
3
4

Answer :C
Discussion