This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Solve in R and represent the solution on the number line. abs(x-5) lt 1 |
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Answer» Solution :`abs(x-5) lt 1` `rArr -1 lt x-5 lt 1` `rArr 4 lt x lt 6` If x `in` R then the solution set is S = (4,6) We can REPRESENTTHE solution on number LINE as
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| 2. |
At Lincoln High School, approximately 7 percent of enrolled juniors and 5 percent of enrolled seniors were inducted into the National Honor Society last year. If there were 562 juniors and 602 seniors enrolled at Lincoln High School last year, which of the following is closest to the total number of juniors and seniors at Lincoln High School last year who were inducted into the National Honor Society? |
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Answer» 140 |
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| 3. |
A setcontains (12) elements . Thenumberofsubsetsof thesetwhichcontainatmost2 elements is |
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Answer» 6 |
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| 4. |
No. of distinct terms in (a+b+c+d)^n , n in N is |
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Answer» `""^((n+3))C_2` |
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| 5. |
int(1)/(e^(x)+1)dx=.... |
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Answer» `LOG((E^(x))/(e^(x)+1))+c` |
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| 6. |
Find the slope of the normal to the curve y^(2)=4 axat ((a)/(m^(2)),(2a)/(m)) |
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| 7. |
If I = int(sinx(cosx)^(-5//2)dx)/(sqrt(sinx+3cosx)+sqrt(sinx+4cosx)) =(A)/(4)((tanx+4)^(5//2)-(tanx+3)^(3//2)) -(2)/(4) [4(tanx+4)^(3//2)-3(tanx+3)^(3//2)1+C |
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| 8. |
Find the scalar triple product vecb.(veccxxveca) where veca, vecb and vecc are respectively hati+hatj,hati-hatj, 5hati+2hatj+3hatk. |
Answer» SOLUTION :
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| 9. |
Given that F(x)=[{:(,cos x,-sin x,0),(,sin x,cos x,0),(,0,0,1):}]."If"in R Then for what values of y, F(x+y)=F(x)F(y) |
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| 10. |
The vectors a + 2b + 3c, 2a + b - 2c, 3a - 7c are |
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Answer» coplanar |
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| 11. |
squareABCD is a parallelogram. (A_(1)) and B_(1) are midpoints of the sides bar(BC) and bar(AD) respectively. If vec("AA")_(1)+vec(AB)_(1)=lambda vec(AC) then lambda = ………… |
| Answer» Answer :C | |
| 12. |
int (logx)/((1+logx)^(2))dx=.... |
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Answer» `(1)/(1+logx)+C` |
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| 14. |
If f(x)=(x^(5))/(5)+(x^(4))/(4)+x^(3)+(kx^(2))/(2)+x be an increasing function AA x in R, then k^(2) is |
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Answer» 11 |
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| 15. |
Binomial coefficients which are in decreasing order are |
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Answer» `""^15C_5, ""^15C_6,""^15C_7` |
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| 16. |
Let= [1, inftY). Define f :S to S by f(x) = 5^(x(x+1)) Then f^(-1)(x) is equal to |
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Answer» `(1/5)^(x(x-1))` |
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| 17. |
If S_(r)= sum_(r=1)^(n)T_(1)=n(n+1)(n+2)(n+3) then sum_(r=1)^(10) 1/(T_(r)) is equal to |
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Answer» `55/527` |
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| 18. |
Two numbers x and y are chosen at random from {1, 2, 3,…,5n} where n ge 2, show that the probability x^(4) - y^(4) is divisible by 5 is (17 n - 5)/(5(5n - 1)). |
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| 19. |
For x inR, f(x) is defined as follows : f(x)={{:(x+1,,0lexlt2),(|x-4|,,x ge 2):} Then the solution set of the equation isf(x)^(2)+x=f(x)+x^(2) is |
| Answer» ANSWER :(d) | |
| 20. |
If the radius of a sphere , is measured as 7m with an error of 0.02 m then find the approximate error in calculating its volume . |
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| 21. |
Using elementary transformations find the inverse of each of the following matrices , if it exist. [{:(1,2),(2,-1):}] |
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| 22. |
A positive integer n le 5 such that int_(0)^(1) e^(2 x-1) (x-1)^(n) dx= (1)/(4) ((7)/( e) -e) is |
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| 23. |
Evaluate the definite integrals . underset(0)overset(1)int (dx)/(sqrt(3-2x) |
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| 24. |
If 2a+3b-5c=0, then ratio in which c divides AB is |
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Answer» `3 : 2` internally `rArr""(2a+3b)/5=c` `rArr""(2a+3b)/(2+3)=c` `rArr""(a+3/2b)/(1+3/2)=c"...(1)"` Let c divides AB in the ratio `lamda:1` `"Then,"c=(a+lamdab)/(1+lamda)"…(ii)"` On comparing (i) and (ii), we GET `lamda=3/2` `:.""` REQUIRED ratio is 3 : 2 internally.
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| 25. |
Show that the points (2,3,4), (-1,-2,1), (5,8,7) are colinear |
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Answer» Then the direction ration of AB are -1, -2, -2, -3, 1-4 i.e., -3, -5, -3 and the direction ratios of AB are 5, -2, 8-3, 7-4 i.e., 3, 5, 3 Since `(-3)/3=(-5)/5=(-3)/5`, the direction ratios of AB and AC are proportional. Thus A, B and C are COLLINEAR |
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| 26. |
Evaluate the definite integralint_(-1//sqrt(3))^(1//sqrt(3))((x^(4))/(1-x^(4)))cos^(-1)((2x)/(1+x^(2)))dx. |
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| 27. |
A player tosses a coin and score one point for every head and two points for every tail that turns up. He plays on until his score reaches or passes n. P_(n) denotes the probability of getting a score of exactly n. The value of P_(n)+(1//2)P_(n-1) is equal to |
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Answer» `1//2` (i) by THROWING a head when the score is `(n-1),` (ii) by throwing a tail when the score is `(n-2)` Hence `P_(n)=P_(n-1)xx1/2+P_(n-2)+1/2""[becauseP("head")="(tail")=1//2"]"` `=1/2[P_(n-1)+P_(n-2)]""(1)` ` impliesP_(0)+1/2P_(n-1)=P_(n-1)+1/2P_(n-2)` `""("adding"(1//2)P_(n-1)"on both sides")` `=P_(n-2)+1/2P_(n-3)` `=P_(2)+1/2P_(1)""(2)` Now, a score of 1 can be obtained by throwing a head at a single toss. Therefore, `P_(1)=1/2` And a score of 2 can be obtained by throwing either a tail at a single toss or a head at the first toss as well as second toss. Therefore, `P_(2)=1/2+((1)/(2)xx(1)/(2))=3/4` From Eq. (2), we have `P_(n)+1/2P_(n-1)=3/4+1/2((1)/(2))=1` `or P_(n)=1-1/2P_(n-1)` `or P_(n)-2/3=1-1/2P_(n-1)-2/3` `or P_(n)-2/3=-1/2(P_(n-1)(2)/(3))` `=(-(1)/(2))^(2)(P_(n-1)-(2)/(3))` `=(-(1)/(2))^(3)(P_(n-3)-(2)/(3))` `=(-(1)/(2))^(n-1)(P_(1)-(2)/(3))` `=(-(1)/(2))^(n-1)((1)/(2)-(2)/(3))` `=(-(1)/(2))^(n-1)(-(1)/(6))` `(-(1)/(2))^(n)1/3` `or P_(n)=2/3+((-1)^(n))/(2^(n))1/3=1/3{2+((-1)^(n))/(2^(n))}` Now, `P_(100)=2/3+(1)/(3xx2^(101))gt2/3` and `P_(101)=2/3-(1)/(3xx2^(101))lt2/3` `P_(101)lt2/3ltP_(100)` |
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| 28. |
A player tosses a coin and score one point for every head and two points for every tail that turns up. He plays on until his score reaches or passes n. P_(n) denotes the probability of getting a score of exactly n. Which of the following is not true ? |
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Answer» `P_(100)gt2//3` (i) by throwing a head when the score is `(n-1),` (II) by throwing a tail when the score is `(n-2)` Hence `P_(n)=P_(n-1)xx1/2+P_(n-2)+1/2""[becauseP("head")="(tail")=1//2"]"` `=1/2[P_(n-1)+P_(n-2)]""(1)` ` impliesP_(0)+1/2P_(n-1)=P_(n-1)+1/2P_(n-2)` `""("adding"(1//2)P_(n-1)"on both sides")` `=P_(n-2)+1/2P_(n-3)` `=P_(2)+1/2P_(1)""(2)` Now, a score of 1 can be OBTAINED by throwing a head at a single toss. Therefore, `P_(1)=1/2` And a score of 2 can be obtained by throwing either a tail at a single toss or a head at the first toss as well as second toss. Therefore, `P_(2)=1/2+((1)/(2)xx(1)/(2))=3/4` From EQ. (2), we have `P_(n)+1/2P_(n-1)=3/4+1/2((1)/(2))=1` `or P_(n)=1-1/2P_(n-1)` `or P_(n)-2/3=1-1/2P_(n-1)-2/3` `or P_(n)-2/3=-1/2(P_(n-1)(2)/(3))` `=(-(1)/(2))^(2)(P_(n-1)-(2)/(3))` `=(-(1)/(2))^(3)(P_(n-3)-(2)/(3))` `=(-(1)/(2))^(n-1)(P_(1)-(2)/(3))` `=(-(1)/(2))^(n-1)((1)/(2)-(2)/(3))` `=(-(1)/(2))^(n-1)(-(1)/(6))` `(-(1)/(2))^(n)1/3` `or P_(n)=2/3+((-1)^(n))/(2^(n))1/3=1/3{2+((-1)^(n))/(2^(n))}` Now, `P_(100)=2/3+(1)/(3xx2^(101))gt2/3` and `P_(101)=2/3-(1)/(3xx2^(101))lt2/3` `P_(101)lt2/3ltP_(100)` |
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| 29. |
Find the value of lambda such that line (x-2)/(6) = (y-1)/(lambda) = (z+5)/(-4) is perpendicular to the plane 3x-y-2z=7. |
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| 30. |
Let A_(n)=sum_(r=1)^(n)cos^(-1).(r )/(n) and B_(n)=sum_(r=0)^(n-1)cos^(-1)((r )/(n))" for "n=1, 2, 3……., then |
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Answer» `a_(2010) GT 2010` |
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| 32. |
Evaluate the integrals in exercise. overset((pi)/(2)) underset(0)int (sinx)/(1+cos^(2)x)dx |
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| 33. |
Let a hyperbola whose centre is at origin. A line x + y =2 thuches this hyperbola at P (1,1) andintersects the asymtotes at A and B such that AB=6 sqrt2 units. (you can use the oncept that incase of hyperbola portion of tangent intercepted between asymptotes is bisected at the point of constant). Equation of the tangent to the hyperbola at (-1, (7)/(2)) is |
| Answer» Answer :B | |
| 34. |
Let a hyperbola whose centre is at origin. A line x + y =2 thuches this hyperbola at P (1,1) andintersects the asymtotes at A and B such that AB=6 sqrt2 units. (you can use the oncept that incase of hyperbola portion of tangent intercepted between asymptotes is bisected at the point of constant). Angle subtended by AB at centre of the hyperbola is |
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Answer» `SIN ^(-1) "" 4/5` |
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| 35. |
Let a hyperbola whose centre is at origin. A line x + y =2 thuches this hyperbola at P (1,1) andintersects the asymtotes at A and B such that AB=6 sqrt2 units. (you can use the oncept that incase of hyperbola portion of tangent intercepted between asymptotes is bisected at the point of constant). Equation of asymptotes are |
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Answer» `5XY+ 2x ^(2) + 2Y ^(2) =0` |
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| 36. |
If x^(n)=a_(0)+a_(1)(1+x)+a_(2)(1+x)^(2)+….+a_(n)(1+x)^(n)=b_(0)+b_(1)(1-x)+b_(2)(1-x)^(2)+….+b_(n)(1-x)^(n) then for n=101, (a_(50),b_(50)) equals: |
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Answer» `(-""^(101)C_(50), ""^(101)C_(50))` |
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| 37. |
For anyinteger n ge 1, underset(k=1) overset(n) sumK ( K+2)= |
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Answer» `(N(n+1)(n+2))/(6)` |
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| 39. |
intdx/(1+sinx) |
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Answer» SOLUTION :`I=intdx/(1+sinx)=INT(1-sinx)/cos^2xdx` =`intsec^2x-secxtanxdx` =tanx-secx+c |
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| 40. |
If f : IR to IRis defined by{:f(x)={("x - 1,","for "x le 1),(2-x^(2)",","for "1 lt x le 3),("X - 10,","for "3 lt x lt 5),("2x,","for " x ge 5):}thenthe set points of discontinuity of f is |
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Answer» LR - {1,5} |
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| 41. |
A line of fixed length (a + b) moves so that its ends are always on two fixed perpendicular straight lines. Prove that a marked point on the line which divides this line into portions of length 'a' and 'b' describes an ellipse and also find the eccentricity of the ellipse when a = 8, b=12. |
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| 42. |
Solve the following D.E's (dy)/(dx) = (2x+y+3)/(2y+x+1) |
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| 43. |
If the vertices of a angles are A (1 , 4, 2) , B (-2 , 1 ,2) , C (2 , 3, -4)then findangleA,angleB,angleC . |
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| 44. |
If the line x+y+1=0 and y=2x+5=0 are tangents to a parabola whose focus at (1,2) then the equation of normal to the parabola through (29/17, 14/17) is |
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Answer» `2x+4y-1=0` `y-2=-4(x-1)` `4x+y=6`
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| 45. |
The volume (in cubic unit ) of the tetrahedron with edges hati+hatj+hatk, hati-hatj+hatk and hati+2hatj-hatk, is |
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Answer» 4 `=1/6 |(1,1,1),(1,-1,1),(1,2,-1)|` `=1/6 [-1+2+3]=2/3` cu UNIT |
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| 46. |
The set of all x satisying the inequility (4x-1)/(3x+1) ge 1is |
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Answer» `(-OO , -1/3) UU [1/4 , oo)` |
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| 47. |
int (1)/(1 - x^(2)) " ln " ((1 + x)/(1 -x))dx = |
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Answer» `(1)/(2) "In" ((1 + X)/(1 - x))^(2) + C` |
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| 48. |
The set of all real values of x for which the real valued function f(x)= (1+(1)/(x))^(x) is defined is |
| Answer» Answer :C | |
| 49. |
If f(x) = sqrt(x) and g(x)=(1)/(sqrt(x)) for xin [3,12] then the value of c in (3,12) for which (f'(c))/(g'(c))=(f(12)-f(3))/(g(12)-g(3))hold is |
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Answer» `7.5` |
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