Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Select the correct answer:Degree of (d^2y/(dx^2))^2+sin(dy/(dx))+x=0

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`1`
`1`
`2`
not defined

Answer :D
2.

Findpositive real numbers 'a' and 'b' such thatf(x) =ax-bx^(3) has four extrema on [-1,1] at each of which|f(x)|=1

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ANSWER :`a=3 , b=4 `
3.

The minimumvalueof7costheta+ 24 sinthetais

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25
`-25`
`6`
`0`

ANSWER :D
4.

If the roots of the equation sqrt((x)/(1-x))+sqrt((1-x)/(x))=(5)/(2) are p and q(q gt q) and the roots of the equation (p+q)x^(4)-pqx^(2)+(p)/(q)=0 are alpha,beta,gamma,delta, then (sum alpha)^(2)-sum alpha beta+alpha beta gamma delta=

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0
`(104)/(25)`
`(25)/(4)`
`(16)/(5)`

ANSWER :B
5.

int(x^(3m)+x^(2m)+x^(m))(2x^(2m)+3x^(n)+6)^(1//m)dx(xgt0)(m in N)

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ANSWER :)`(1)/(6(m+1))[2x^(3M)+3x^(2m)+6x^(m)]^(m+1//m)+C`
6.

Find the total number of times the digit '2' appears in the set of integers {1,2, ….2016}. For example, the digit '2' appears twice in the integer 229.

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ANSWER :619
7.

Integrate the following functions: sin^-1(cosx)

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Solution :`sin^-1(cosx)`
=`sin^-1 sin(pi/2-x) = pi/2-x`
THEREFORE` INT sin^-1 (cosx) DX,`
` = pi/2x-x^2/2+c`
8.

The middle term in the expansion of (x + 1/x)^(2n) is

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`""^(2N)C_n`
`""^(2n)C_nx `
`(""^(2n)C_n)/(X)`
`""^(2n)C_(n-1)x `

ANSWER :A
9.

A is one of 5 horses that entered the race and for it to be rided by one of the two jokeys P & Q and odds in favour of P rides it is 2 to 1. If P rides, A, all the horses are likely to win. If Q rides A, A' s chance of winning is tripled. The odds in favour of A's winning is

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`1 : 3`
`3 :1`
`1 : 2`
`2 : 1`

ANSWER :C
10.

Can a sum difference, product or quotient of irrational numbers be a rational number?

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ANSWER :YES
11.

Write down and simplify 6^("th") term in ((2x)/(3)+(3y)/(2))^(9)

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SOLUTION :N/A
12.

If x= a t^(2), y= 2 a t" then " (dy)/(dx) = …., where t ne 0

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`(1)/(t)`
t
`-t`
a

Answer :A
13.

If (2 le r le n) , then ""^(n)C_(r)+2""^(n)C_(r+1)+""^(n)C_(r+2) is equal to

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`2.""^(N)C_(R+2)`
`""^(n+1)C_(r+1)`
`""^(n+2)C_(r+2)`
`""^(n+1)C_(r)`

ANSWER :C
14.

If P(A) = 3/5P(B) = 1/5. Find P(A cap B) if A an B are independent events.

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ANSWER :`3/25`
15.

Find the vector equation of the plane passing through the intersection of the palnes vecr.(2hati+2hatj-hat3k) = 7, vecr.(2hati+5hatj+3hatk) = 9 and through the point (2, 1, 3)

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ANSWER :LET the required EQUATION be `vecr.[(2hati+2hatj-3hatk)+LAMBDA(2hati+5hatj+3hatk)] = 7+9lambda`
16.

If int e^(sqrt(x)) " dx = K.e"^(sqrt(x))f(x ) + c then K f(x) =

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2, `SQRT(X)- `1
`2 , sqrt(x) + 1`
`2 , x + 1`
`2 , x^(2) -1`

ANSWER :A
17.

A particle is acted upon by constant forces 4hati+hatj-3hatk and 3hati+hatj-hatk which displace it from a point hati+2hatj+3hatk to the point 5hati+4hatj+hatk. The work done in standard units by the forces is given by

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40 units
30 units
25units
15 units

Solution :TOTAL force, `F = (4hati + hatj - 3hatk) + (3hati + hatj- hatk)`
`F = 7hati +2hatj- 4hatk`
The PARTICLEIS displacedfrom
`A(hati + 2hatj + 3hatk) - (hati + 2hatj + 3hatk) = 4hati +2hatj- 2HATK`
`:.` Work DONE`= F . AB=(7hati + 2hatj - 4hatk ). (4hati + 2hatj - 2hatk)`
`= 28 + 4+ 8 = 40` units
18.

Find the order and degree (it defined) of the differential equation((d^(2)y)/(dx^(2)) )^(3) + ((dy)/(dx))^(2) + sin ((dy)/(dx))+ 1 = 0 .

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ANSWER :ORDER 2; DEGREE is not DEFINED.
19.

Find the number of odd positive integral solutions of a + b + c + d = 20.

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ANSWER :165
20.

The value of x, where the function : f(x) = (tan x log (x-2))/(x^(2) - 4x + 3) is discontinuous, is given by :

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`(- oo, 2)`
`(-oo, 2) UU {3}`
`(-oo, 2) uu {3, n pi + (pi)/(2), n ge 1}`
NONE of these

ANSWER :C
21.

Find the following integrals int(ax^(2)+bx+c)dx

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ANSWER :`a(x^(3))/(3)+b(x^(2))/(2)+cx+c_(1)`
22.

Express the -3+ipoints geometrically in the Argand plane.

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SOLUTION :`-3+i=(-3,1)`
23.

If overline(a), overline(b), overline(c) are non-coplanar vectors and the points with position vectors 3overline(a)+4overline(b)-2overline(c), overline(a)+lambdaoverline(b)+3overline(c),overline(a)-6overline(b)+6overline(c) and 2overline(a)+3overline(b)-overline(c)are coplanar, the lambda=

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`-2`
`2`
`-3`
`3`

ANSWER :A
24.

If vec(a)=hati+2hatj+hatk and vec(b)=hati-2hatj-3hatk then (vec(a)+vec(b)*(vec(a)-vec(b)) = ………..

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`-2`
`-8`
8
2

Answer :B
25.

Consider the curves C_1 : y^2 and C_2: x^2 +y^2-6x+1=0 Assertion(A) The common tangents to the curves C_1 and C_2 areothogonal. Reason ( R ) x-y+1=0 and x+y+1=0 are the common tangents to the curves C_1 and C_2 The correct answer is

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(A) is true, (R ) is true and (R ) is the CORRECT EXPLANATION of (A)
(A) is true , (R ) is true but (R ) is not a correct explanation of (A)
(A) is true but ( R) is FALSE
(A) is false but (R ) is true.

ANSWER :A
26.

Find the real values of theta , such that (3 + 2i sin theta)/(1 - 2i sin theta) is purely Real

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ANSWER :A
27.

A person who has been taken Maths or Computer can apply for M.Sc computer science

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Solution :Here we MEAN that the students who have been taken both MATHS and COMPUTER science can apply for M.Sc somputer science , as well as the students who have taken only one of these subject . So , in this case , we are USING inclusive "OR"
28.

What is the domain of the function sin^(2)x?

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ANSWER :`[-1, 1]`
29.

The value ofx + y + zis 15 if a, x, y, z, b are in A.P. while the value of(1)/(x) + (1)/(y) + (1)/(z) + (1)/(z) is (5)/(3)if a, x, y, z, b are in H.P. the value of a and b are

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9,1
7,4
8,2
`-1,3`

ANSWER :1
30.

(A) : The mod amplitude form of (1 + 7i)/((2- i)^(2)) is sqrt2 c is (3pi)/(4) (R) : The mod-amplitude form z = a+ ib is rcis thetawhere r = |z| , theta is amplitude of z

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A is true , R is true and R correct explanation of A
A is true , R is true and R is not correct EXPLANATIONOF A
A is true , R is false
A is false, R is true

ANSWER :A
31.

Find the transpose of each of each of the following matrics: [[-1,5,6],[sqrt3,5,6], [2,3,-1]]

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SOLUTION :`[[-1,sqrt3,2], [5,5,3], [6,6,-1]]`
32.

Choose the correct answer. Smaller area enclosed by the circle x^2+y^2 =4 and the line x+y=2 is:

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`2(PI-2)`
`pi-2`
`2pi-1`
`2(pi +2)`

ANSWER :B
33.

Find the sum 1 xx 2 xx .^(n)C_(1) + 2 xx 3xx .^(n)C_(2) + "….." + 2 xx (n+1) xx .^(n)C_(n).

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Solution :METHODI :
`1 xx 2 xx .^(n)C_(1)+ 2 xx 3 xx .^(n)C_(2) + "...." + n xx (n+1) xx .^(n)C_(n)`
`= underset(r=1)OVERSET(n)sumr(r+1)..^(n)C_(r)`
`= underset(r=1)overset(n)sum(r+1)[n..^(n-1)C_(r-1)]`
`= n underset(r=1)overset(n)sum((r-1)+2).^(n-1)C_(r-1)`
`= nxxunderset(r=1)overset(n)sum[(r-1)..^(n-1)C_(r-1)+2..^(n-1)C_(r-1)]`
`= nxx n(n-1)underset(r=2)overset(n)sum.^(n-2)C_(r-2)+(2n)underset(r=1)overset(n)sum.^(n-1)C_(r-1)`
`=n xx (n-1) xx 2^(n-2) + 2nxx 2^(n-1)`
` = n(n+3)xx2^(n-2)`
Method II :
We have `(1+x)^(n) = .^(n)C_(0) + .^(n)C_(1)x + .^(n)C_(2)x^(2) + "....." + .^(n)C_(n)x^(n)`
Differentiatingw.r.t.x we get
`n(1+x)^(n-1) = .^(n)C_(1) + 2 xx .^(n)C_(2)x + 3 xx .^(n)C_(3)x^(2)"....." + nxx .^(n)C_(n) xx x^(n-1)`
Multipyingwith `x^(2)`,we have
`n(1+x)^(n-1) x^(2) = .^(n)C_(1) x^(2) + 2 xx .^(n)C_(2)x^(3) + 3xx .^(n)C_(3)x^(4)"...."+n xx .^(n)C_(n)x^(n+1)`
Differentiating w.r.t. ,we get
`m(n-1)(1+x)^(n-2)x^(2) +2x xx n(1+x)^(n-1)`
`= 2.^(n)C_(1)x + 2 xx 3xx .^(n)C_(2)x^(2) + 3 xx 4 xx .^(n)C_(3)x^(3) + "...." + n(n+1) xx .^(n)C_(n)x^(n)`
Now putting ` x = 1`, we get
`1 xx 2 xx .^(n)C_(1) + 2 xx 3 xx .^(n)C_(2) + "...." + n xx (n+1) xx .^(n)C_(n)`
`= n (n+3) xx 2^(n-2)`
34.

Find the equation of line of the shortest distancebetween the lines (x - 1)/( -2) = (y + 3)/( 2) = ( z - 4)/( -1) and (x + 3)/( 6) = (y - 2)/( 2) = (z + 5)/( 3)

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Answer :`(x +(61)/(16))/(1)=(y-(41)/(20))/(0)=(z)/(-2)`
35.

The value of p and q so that the function f(x) = {{:((1|sin x|)^((p)/(sin x)),(-pi)/(6) lt x lt 0),(e^((sin 2x)/(sin 3x)), 0 lt x lt (pi)/(6)):} is continuous at x = 0, are

Answer»

<P>`p = (1)/(3), q = E^(2//3)`
`p = 0, q = e^(2//3)`
`p = (2)/(3), q = e^(-2//3)`
`p = - (2)/(3), q = e^(2//3)`

Answer :d
36.

Find the area of the smaller region bounded by the ellipse (x^(2))/(9) + (y^(2))/(4) = 1 and the line (x)/(3) + (y)/(2) = 1

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ANSWER :`3/2 (pi-2)`
37.

f(x) = e^(-1//x^2) sin(1//x) for x ne 0 and f(0) =0 . The function f(x) is

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DIFFERENTIABLE at x = 0
not differentiable at x = 0
INSUFFICIENT DATA
None of these

Answer :A
38.

IfS_1 and S_2 are the foci of the hyperbola whose transverse axis length is 4 and conjugate axis length is 6,S_3 and S_4 are the foci of the conjugate hyperbola , then the area of the quadrilateral S_1, S_2 , S_3 ,S_4is

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24
26
22
12

Answer :B
39.

Prove that .^(n)C_(0) + (.^(n)C_(1))/(2) + (.^(n)C_(2))/(3) + "……" + (.^(n)C_(n))/(n+1) = (2^(n+1)-1)/(n+1).

Answer»

SOLUTION :Method I :
We have
`T_(R ) = (.^(n)C_(r-1))/(r ) = (.^(n+1)C_(r))/(n+1)`
`:.`Requiredsum `= underset(r=1)overset(n+1)sumT_(r)`
` = underset(r=1)overset(n+1)sum(.^(n+1)CR)/(n+1)`
` = (.^(n+1)C_(1) + .^(n+1)C_(2) + "….." + .^(n+1)C_(n+1))/(n+1)`
` = ((.^(n+1)C_(0) + .^(n+1)C_(1) + .^(n+1)C_(2) + "......" + .^(n+1)C_(n+1))-1)/(n+1)`
`= (2^(n+1) - 1)/(n+1)`
Method II :
We have `(1+X)^(n)= .^(n)C_(0) + .^(n)C_(1)x+.^(n)C_(2)x^(2)+"...."+.^(n)C_(n)x^(n)`
` :. underset(0)overset(1)INT(1+x)^(n)dx = underset(0)overset(1)int(.^(n)C_(0) + .^(n)C_(1)x+.^(n)C_(2)x^(2) + "...." + .^(n)C_(n)x^(n))dx`
`rArr [((1+x)^(n+1))/(n+1)]_(0)^(1)=[.^(n)C_(0)x+(.^(n)C_(1)x^(2))/(2)+(.^(n)C_(2)x^(3))/(3) + "....."+ (.^(n)C_(n)x^(n+1))/(n+1)]_(0)^(1)`
`rArr (2^(n+1))/(n+1) -1/(n+1)=.^(n)C_(0)+(.^(n)C_(1))/(2)+(.^(n)C_(2))/(3)+ "......" + (.^(n)C_(n))/(n+1)`
40.

Every body in a room shakes hands with every body else. The total number of hand shakes is 66. The total number of persons in the room is

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11
12
13
14

Answer :B
41.

The mapping f: R rarrR , g, R rarr R are defined by f(x) = 5-x^2and g(x)=3x -4, then find the value of (fog)(-1)

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40
`-44`
`-40`
`-45`

ANSWER :B
42.

If two points are taken on the mirror axis of the ellipse (x^(2))/(25)+(y^(2))/(9)=1 at the same distance from the centre as the foci, then the sum of the sequares of the perpendicular distance from these points on any tangent to the ellipse is

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25
18
50
80

Answer :C
43.

Integrate the following functions w.r.t.x (e^(5logx) - e^(4logx))/(e^(3logx) - e^(2logx))

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SOLUTION :`(E^(5 logx) - e^(4 logx))/(e^(3 logx) -e^(2logx)) = (x^5-x^4)/(x^3-x^2)`
=`(x^2(x^3-x^2))/(x^3-x^2) = x^2`
`e^(a logx) = e^(logx^a) = x^a`
therefore The REQUIRED integral =`int x^2 dx = x^3/3 +C`
44.

a gt 1is a real numberf(x) = log_(a)x^2 , where x gt 0 If f^(-1)(x) is a inverse of f(x) andb and c are real numbers then f^(-1) (b+c) = ......

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`F^(-1)(B) .f^(-1)(C)`
`f^(-1)(b)+f^(-1)(c)`
`1/(f(b+))`
NONE of these

Solution :N/A
45.

( sin 70^(@) + cos 40^(@) )/( cos 70^(@) + sin 40^(@))=

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3
`SQRT(3)`
`1/(sqrt(3))`
`1//2`

ANSWER :B
46.

T_m denotesthenumber of trianglesthat can beformedwiththe verticesof aregularpolygonof msides. If T_(m+1)- T_m=15thenm=

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3
6
9
12

Answer :B
47.

Find two positive numbers x and y such that x+y=60 and xy^(3) is maximum.

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ANSWER :15 and 45
48.

intdx/(cos^2x)

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SOLUTION :`INT(DX)/(cos^2x)`=`intsec^2xdx=tanx+C`
49.

Four persons A,B,C,D cut a pack of 52 cards successively in that order given. If the person who cuts a spade first wins, find their probability of winning.

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ANSWER :`(27)/(175)`
50.

(y''')^(2) + (y'')^(3) + (y')^(4) + y^(5) = 0

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ANSWER :ORDER 3; DEGREE 2