Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Find |veca-vecb|, if two vectors veca and vecb are such that |veca|=2,|vecb|=3 and veca*vecb=4.

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`SQRT5`
5
3
`SQRT3`

ANSWER :A
2.

Given the following frequency distribution with some missing frequencies {:(Class , "Frequency") , (10-20 ,, 180), (20-30 ,, --), (30-40 ,, 34) , (40-50 ,, 180) , (50-60 ,, 136) , (60-70 ,, --) , (70-80 ,, 50):} If the total frequency is 685 and median is 42.6 then the missing frequencies are

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` 81, 24`
` 80 , 25`
` 82, 23`
` 832, 22`

Answer :C
3.

On a multiple choice examination with three possible answers for each of the five questions. Then what is the probabilitythat a candidate would get four or more correct answer is

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`(12)/(243)`
`(11)/(243)`
`(14)/(243)`
`(16)/(243)`

Answer :B
4.

Find the inverse of the following A=[[2,1,3],[4,-1,0],[-7,2,1]]

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SOLUTION :`A^(-1) = [(3,-1,1),(-15,6,-5),(5,-2,2)]`
5.

If A=[{:(1,2,1),(2,1,3),(1,1,0):}] then prove that A^3-2A^2-7A-4I_3=0. Hence find A^(-1)

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ANSWER :`A^(-1)=1/4[{:(-3,1,5),(3,1,-1),(1,1,5):}]`
6.

Trachea is supported by :-

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HYOID APPARATUS
Palate
Cartilage
All

Answer :A
7.

A vertical lamp-post, 6 m high stands at a distance of 2 m from a wall, 4 m high. A 105 m tall man starts to walk away from the wall on the other side of the wall, in line with the lamp-post. The maximum distance to which the man can walk remaining in the shadow is :

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`3/2 m`
`5/2 m`
`4M`
NONE of these

ANSWER :B
8.

Determine whether the solution set is finite or infinite or empty: x lt 1, x in Z (set of integers)

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SOLUTION :INFINITE
9.

intdx/((2x+5)sqrt(x+2))

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Solution :`intdx/((2x+5)sqrt(x+2))` [PUT x+2=t^2`
dx=2tdt]
=`int(2tdt)/([2(t^2-2)+5].t)=int(2dt)/(2t^2+1)`
=`intdt/(t^2+(1/sqrt2)^2)=sqrt2tan^-1(sqrt2t)+C`
=`sqrt2tan^-1(sqrt(2x+4))+C`
10.

The number of whole number solutions of x + y + z = 20 is

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231
230
232
234

Answer :A
11.

If y=e^(x)(log x), " then " xy_(2)+(x-1)y=

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`(2x-1)y_(1)`
`(x-1)y_(1)`
`(4-2x)y_(1)`
`(3x-1)y_(1)`

ANSWER :A
12.

If alpha, beta are roots of equation x^(2)-4x-3=0 and s_(n)=alpha^(n)+beta^(n), n in N then the value of (s_(7)-4s_(6))/s_(5) is

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4
3
5
7

Answer :D
13.

(dy)/(dx) + 2x tan (x-y) = 1 rArr sin (x-y) =

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`Ae^(-X^(2))`
`Ae^(2X)`
`Ae^(x^(2))`
`Ae^(-2x)`

ANSWER :C
14.

The shortest distance between the lines r = (3t-4) hati -2thatj -(1+ 2t) hatkand r ( 6 + s) hati + (2- 2s) hatj + 2 (1 + s) hatk is

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3
6
9
12

Answer :C
15.

int (dt)/((e^(t) + e^(-t))^(2)) =

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`(1)/(4)` sech `t`
`(1)/(4)` tanh `t`
`(1)/(4)` COTH `t`
`(1)/(4)` SINH `t`

ANSWER :B
16.

Evalute the following integrals int e^(-1"log(cosecx)")dx

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ANSWER :`-` COS X + C
17.

If A = [( 1, cos theta , 1),( - cos theta ,1,cos theta ),( -1 , - cos theta ,1)] where0 lethetale2 pithen …..

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DET (A)=0
Det (A)` in( 2 , PROP )`
Det` (A)in (2,4)`
Det(A) ` in[2,4]`

ANSWER :D
18.

Three normals from a point to the parabola y^(2)=4ax meet the axis of the parabola in points whose abscissa are in A.P. Find the locus of the point.

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ANSWER :`27ay^(2)=2(x-2a)^(3)`
19.

sec^(2)xtan y dx + sec^(2) y tan x dy = 0

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ANSWER :`TAN X tan y = C`
20.

If 2a + 3b + 6c = 0, then atleast one root of the equation ax^(2) + bx + c = 0 lies in the interval

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0,1
1,2
2,3
1,3

Answer :A
21.

The points O, A, B, X and Y are such that bar(OA)=bar(a), bar(OB)=bar(b), bar(OX)=3bar(a) and bar(OY)=3bar(b)," find "bar(BX) and bar(AY) in terms of bar(a) and bar(b). Further if the point p divides bar(AY) in the ratio 1 : 3 then express bar(BP) interms of bar(a) and bar(b).

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ANSWER :`(3BAR(a)-BAR(B))/(4)`
22.

From the following frequency distribution (i)Find mean. (ii)Calculate variance and standard deviation.

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ANSWER :`=8.56`
23.

Fromthe polynomial equation whose roots are 3,2,1+I,,1-I

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ANSWER :`x^4 -7x^3 +18 x^2 -8x+4=0`
24.

If f(x)={((sqrt(1+kx)-sqrt(1-kx))/x),((2x+1)/(x-1)):} if -1lexlt0 is continuous at x=0, then the value of

Answer»

k=1
k=-1
k=0
k=2

Answer :B
25.

Find the area enclosed between y=x^(2)-5x and y=4-2x

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ANSWER :`(125)/(6)`
26.

I: In a Delta ABC, if a=3,b=4, angle A=30^@ the number of possible triangles is 2 II. In a Delta ABC, ((a+b)cosC+(b+c)cosA+(c+a)cosB)/(sinA+sinB+sinC)=R

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only I is true
only II is true
both I, II are true
neither I nor II is true

Answer :A
27.

1+(log_(e)5)/(1!) +(log_e5)^2/(2!)+(log_e5)^3/(3!)+ .......oo =

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`e^(1/(log5))`
5
`1/5`
`1/7`

Answer :B
28.

A : (3^(2))/(2!)+(3^(4))/(4!)+(3^(6))/(6!)+...=cosh3-1.""R:coshx=1+(x^(2))/(2!)+(x^(4))/(4!)+....

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Both A and R are TRUE and R is the correct explanation of A
Both A and R are true but R is not correct explanation of A
A is true but R is FALSE
A is false but R is true

ANSWER :A
29.

If x+y ge 6, 2x+y ge 8, x ge 0, y ge 0 then the minimum value of f=x+y is

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6
8
14
48

Answer :A
30.

int_(1)^(32) (dx)/(x^(1//5)sqrt(1+x^(4//5)))=

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`2/5 (SQRT(17)+sqrt(2))`
`2/5 (sqrt(17)+sqrt(2))`
`5/2 (sqrt(17)-sqrt(2))`
`5/2 (sqrt(17) +sqrt(2))`

ANSWER :C
31.

Find the second order derivatives of the functions given in Exercises 1 to 10. e^(x) cos 3x.

Answer»
32.

Let I_(1) and I be two lines intersecting at P. If A_(1), B_(1), C_(1) are points on hi and A_(2), B_(2), C_(2),D_(2), E_(2) are points on l_(2) and if none of these coincides with P, then the number of triangles formed by these eight points, is

Answer»

56
55 
46
45

Answer :D
33.

{:(,"List-I",,"List-II"),((A),"In a "DeltaABC a+b=3c", then "cot.(A)/(2)cot.(B)/(2)" is",(i),b^(2)-c^(2)),((B),"If the sides a, b, c of a triangle are in A.P., then the value of "cot.(A)/(2)cot.(C)/(2)" is",(ii),(pi)/(3)),((C),"In a "DeltaABC a(bcosC-cosB)" is equal to",(iii),3),((D),"In a "DeltaABC a=2band|A-B|=(pi)/(3)" Then "angleC " is",(iv),2):}

Answer»


Answer :(A) `iff` (IV), (B) `iff` (III), (C ) `iff` (i), (D) `iff` (II)
34.

If x=phi(t) is a differentiable function of 't', then prove thatintf(x)dx=intf[phi(t)]phi'(t)dt.

Answer»

Solution :`x = phi(t)` is differentiable function of t.
`THEREFORE""(dy)/(dt)=phi'(t)`
`"LET"intf(x)dx=F(x)`
`therefore""(dx)/(dt)[F(x)]=f(x)`
`(d)/(dt)[F(x)]=(d)/(dx)[F(x)].(dx)/(dt)`
`"(Using chain rule)"`
`=f(x).(dx)/(dt)`
`=f[phi(t)].phi'(t)`
`therefore""` By the DEFINITION of integral,
`F(x)=INT f[phi(t)].phi'(t)dt`
`therefore""intf(x)dx=intf[phi(t)].phi'(t) dt.`
Hence PROVED.
35.

Consider thepolynomial fucntion f(x) = |{:((1+x)^(2),,(1+2x)^(b),,1),(1,,(1+x)^(a),,(1+2x)^(b)),((1+2x)^(b),,1,,(1+x)^(a)):}| a,b beingpositiveintegers. Whichof the followingis true ?

Answer»

All the rootsof theequationf(x)=0are positive
All therootsof theequation f(x)=0 are negative
At leastone of theequationf(x)=0isrepeatingone .
NONEOF these

Solution :Let
`|{:((1+x)^(a),,(1+2x)^(b),,1),(1,,(1+x)^(a),,(1+2x)^(b)),((1+2x)^(b),,1,,(1+x)^(a)):}|=A +Bx+Cx^(2)+…….`
Putting x=0 we get
`A= |{:(1,,1,,1),(1,,1,,1),(1,,1,,1):}|=0`
nowdifferentingboth sides withrespect to x and putting x=0 we get
`B= |{:(a,,2b,,0),(1,,1,,1),(1,,1,,1):}|+|{:(1,,1,,1),(0,,a,,2b),(1,,1,,1):}|+|{:(1,,1,,1),(1,,1,,1),(2b,,0,,a):}|=0`
HENCE ,coefficientof x IS0 .Since f(x)=0 and f(0)=0 ,x=0 isa repreatingroot ofthe equation f(x)=0
36.

If y= f(x) be an invertible function with inverseg and h(x) = x f(x), then int_(f(a))^(f(b)) g(x) dx+ int_(a)^(b) f(x) dx is equal to

Answer»

`H(a) - h(B)`
`h(b) - h(a)`
`h(a) + h(b)`
`BH(b) - AH(a)`

ANSWER :B
37.

If the straight lines 2x+3y-3=0 and x+ky+7=0 are perpendicular, then the value of k is

Answer»

1)`2//3`
2)`3//2`
3)`-2//3`
4)`-3//2`

Answer :C
38.

If A and B are any two events such that P(A) + P(B) -P(A and B) = P(A), then

Answer»

<P>P(B|A)= 1
P(A|B)= 1
P(B|A)= 0
P(A|B)= 0

Answer :b
39.

Solve the equation 6x^6-25x^5+31x^4-31x^2+25x-6=0

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ANSWER :`+- 1,2,1/2 ,(5 +- SQRT(11 i))/(6)`
40.

The solution of (dy)/(dx) = e^(2x-y) + x^(3) e^(-y) is

Answer»

`4e^(y) = 2E^(2X) - X^(4) + c`
`4e^(y) = 2e^(2x) + x^(4)- x^(2) + c`
`4e^(y) = 2e^(2x) + x^(4) + c`
`4e^(y) = 2e^(2x) - x^(4) +x^(2) + c`

Answer :C
41.

Find square root of a^2-1+2asqrt(-1)

Answer»

SOLUTION :`=a^2=i^2+2ai=(a+i)^2`
`:.SQRT(a^2-1+2asqrt(-1))= +-(a+i)`
42.

Let f(x) = sin a x^(- +) cos bx be a periodic function, then

Answer»

`a = (3pi)/(2), b = PI`
`a = sqrt(3), b = 5sqrt(3)`
`a = 3sqrt(2), b = 2sqrt(3)`
`a, b in R`

ANSWER :A::B
43.

Prove that two parabolas y_(2)=4ax "and" x^(2)=4by intersect (other than the origin ) at an angle ofTan^(-1)[(3a^(1//3)b^(1//3))/(2(a^(2//3)+b^(2//3)))] .

Answer»


ANSWER :`theta = Tan^(-1) [ ( 3A^(1//3) B^(1//3) )/( 2(a^(2//3) + b^(2//3) ) )]`
44.

Find the asymptotes of the following curves : y=x/(x^(2)+1)

Answer»


ANSWER :y=0
45.

A department store escalator is 25 feet long and forms an angle of 43^@ with the floor , with is horizontal . What of the follow is an expression for the horizontal distance of the escalator from beginning to end ?

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`25 sin 43^@`
`25 COS 43^@`
`25 tan 43^@`
`25 CSC 43^@`

Answer :B
46.

If M is the midpoint of the side vec(BC) of a triangle ABC, prove that vec(AB)+vec(AC) = 2vec(AM)

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Solution :Let M is the midpoint of BC of `triangleABC`
Clearly `VEC(BM)` and `vec(CM)` are equal and OPPOSITE.
Now `vec(AB)+vec(BM)` = `vec(AM)` and `vec(AC)+vec(CM)` = `vec(AM)`
`implies vec(AB)+vec(AC)+vec(BM)+vec(CM)` = `2vec(AM)`
`implies vec(AB)+vec(AC)` = `2vec(AM)`
47.

The value of int_(- pi//2)^(pi//2) ((2- sin theta)/( 2+ sin theta)) d theta is

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`0`
`1`
`2`
NONE of these

Answer :A
48.

For what values of x in R, the following expressions are negative i) -6x^(2)+2x -3 ii) 15+4x-3x^(2) iii) 2x^(2)+5x -3 iv) x^(2)-7x+10 v) x^(2)-5x-6

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ANSWER :i) For all real x ii) `x lt -(5)/(3)` or `x gt 3` iii) `-3 lt x lt (1)/(2)` iv) `2 lt x lt 5` v) `-1 lt x lt 6`
49.

For the first several weeks after hiring a private tutor, Teddy's score on a standardized test increased slowly . As Teddy began to understand the concepts more clearly , though , his standardized test scores improved more rapidly. After several more weeks, Teddy stopped working with his tutor and his scores did not imporve any more . Which of the following graphs could represent all of Teddy's standardized test scores as a function of times , in weeks, after he hired a private tutor ?

Answer»




ANSWER :A
50.

Let A_1,A_2,A_3,….,A_m be the arithmetic means between -2 and 1027 and G_1,G_2,G_3,…., G_n be the gemetric means between 1 and 1024 .The product of gerometric means is 2^(45) and sum of arithmetic means is 1024 xx 171 The number 2 A_(171,G_5^2+1,2A_(121)

Answer»

A.P
G.P
H.P
none of these

Solution :We have
`A_(171)+A_(172)=-2+1027=1025`
or `(2A_(171)+2A_(172))/2=1025`
Also,
`G_(5)=1xx2^(5)=32`
`rArrG_(5)^(2)=1024`
or `G_(5)^(2)+1=1025`
HENCE, `2A_(171),G_(5)^(2)+1,2A_(172)` are in A.P.