Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Find the value of k if kx+ 3y - 1 = 0, 2x + y + 5 = 0 are conjugate lines with respect to the circle x^(2) + y^(2) - 2x - 4y - 4 =0.

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ANSWER :` 2`
2.

Number of bijections from Set-A containing n elements onto itself is 720 then n is

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5
6
4
7

Answer :B
3.

Find the vector equation of the line through the point whose position vector is 2hati-hatj+hatk and parallel to the line joining the points whose position vectors are hati+4hatj+hatk and hati+2hatj+2hatk. Also find the cartesian equation of the line.

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ANSWER :`VECR=(2hati-hatj+hatk)+LAMBDA(2hati-2hatj+hatk)`
`(x-2)/(2)=(y+1)/(-2)=(z-1)/(1)`
4.

Find the vector equation of the line passing through (1, 2, 3) and perpendicular to the plane vecr.(hati+2hatj-5hatk)+9=0

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ANSWER :`THEREFORE VECR=(hati+2hatj+3hatk)+lambda(hati+2hatj-5hatk),lambda EPSILON R`
5.

Examine the continuity of the function f(x)= x^(3) + 2x^(2)-1 " at " x=1

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ANSWER :x=1
6.

Let ' A'. and 'B' be independent events with 'P(A)=0 .3' and 'P(B)=0.4'. Findi) 'P(A nn B)'ii) 'P(A uu B)'iii) 'P(A | B)'iv) 'P(B | A)'

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<P>

SOLUTION :P(B/A) = P(B) = 0.4
7.

Let ADbe theanglebisector ofangle AofDelta ABCsuchthatAD= alphaAB + betaAC ,then

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`ALPHA =(|AB|)/(|AB|+|AC|),beta =(|AC|)/(|AB|+|AC|)`
`alpha =(|AB|+|AC|)/(|AB|),beta =(|AB|+|AC|)/(|AC|)`
`alpha =(|AC|)/(|AB|+|AC|), beta =(|AB|)/(|AB|+|AC|)`
`alpha =(|AB|)/(|AC|), beta =(|AC|)/(|AB|)`

SOLUTION :Clearly ,AD dividesBCin THERATIO`AB:AC`.
`thereforeAD =(|AB|AC||AC|AB)/(|AB|+|AC|)`
`implies |AD|= alpha AB + beta AC , ` where
` alpha =(|AC|)/(|AB|+|AC|)and beta =(|AB|)/(|AB|+|AC|)`
8.

Two person A and B have 16 and 15 fair coin respectively. If both of them tosses all the coin then probability that A gets more head than B is p then the value of 16p is

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Solution :Let A and B flips equal number of coins
i.e. 15 coins
`P_(A)` = probability that A OBTAINS more heads than B
`P_(B)` = probability that B obtains more heads than A
`P_(D)` = probability that A obtains as many heads as B
Such that `P_(A) + P_(B) +P_(D) = 1` ...(i)
DUE to symmetry `P_(A) = P_(B)` as both FLIP equal number of coins.
Now 'A' flips extra coin (`16^(TH)` coin).
If it gives tail then does not contribute but if it gives HEAD then A gets more head than B required probability = `P_(A) + 1/2.P_(D)`
`=P_(A) + 1/(2)(1-P_(A)-P_(B)) = 1/2`.
9.

Find the equation of the circle passing through (-2,3) and having centre (0,0)

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ANSWER :`X^(2) +y^(2) -13 =0`
10.

Find the maximum and minimum values, if any, of the functions given by f(x) = 9x^(2) + 12x + 2

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ANSWER :MINIMUM VALUE = – 2
11.

Evaluate the definite integrals int_(0)^(1)(xe^(x)+sin(pix/4))dx

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ANSWER :`1+4/PI-(2SQRT2)/pi`
12.

9 persons enter a lift from ground floor of a building which stops in 10 floors (excluding ground floor), if it is known that persons will leave the lift in groups of 2,3, & 4 in different floors. In how many ways this can happen?

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ANSWER :`907200`
13.

If f (x) = x^(n) then sum _(r=0) ^(n) (f ^((r))(1))/(r 1) =

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0
2
2n
`2 ^(N)`

ANSWER :D
14.

If alpha, beta, gamma are the roots of the equation x^3 - x^2 + 4 = 0, then form an equation where roots are (betagamma + beta + gamma)/(beta + gamma - alpha), (agamma + alpha + gamma)/(alpha + gamma - beta) , (beta alpha + beta + alpha)/(beta + alpha - gamma)

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Answer :`8dx^(3) - 4x^(2)(c^(2)+3D) + 2x(3d+2c^(2) -2CD) -(d+c^(2) + d^(2)-2cd)\0`
15.

The equation of the tangent to the parabola y^(2)=8x inclined at 30^(@) to the x axis is

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`3x-sqrt(3)y+4=0`
`2x-3y+14=0`
`2x-sqrt(2)y+7=0`
`x-sqrt(3)y +6=0`

ANSWER :D
16.

int_(0)^(pi) (x Sin x)/(1+Cos^(2)x)dx=

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`(PI^(2))/(4)`
`pi/4`
`(pi^(2))/(2)`
`(pi)/(2)`

ANSWER :A
17.

A natural number x is chosen at random from the first 100 natural numbers. Find the probability that ((x-20)(x-40))/((x-30)) lt 0.

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ANSWER :`(7)/(25)`
18.

find the general solution of (e^(x) + e^(-x))dy - (e^(x) - e^(-x)) dx = 0

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ANSWER :`y = LOG (E^(X) + e^(-x)) + C`
19.

Which of the following statements is contingency?

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<P>`(pvvq)vv ~Q`
`(p vv q) V~q`
`(p vvq) ^^ ~q`
`p to ( p vv q)`

Solution :OPTION (1) `(p vv q) vv ~ q`
`-= p vv (q vv q) -= p vv T`
`-= T` which is a TAUTOLOGY.
Option (2) `(p vv q) v ~`
`-= (p vv ~ p) vv q -= T vv q`
`-= T` which is tautology.
Option (3) `(p vv q) ^^ ~q`
`-= (p ^^ q) vv (q ^^ ~ q) -= ( p ^^ ~ q) vv F`
`-= (p ^^ ~ q)`
if `p to T, q to T`,
Then, `p ^^ ~ q to F`
if `p to T, q to F`
Then `p ^^ ~ q to T`
So, `(p ^^ ~q)` is a contingency.
Therefore statement `(p vv q) ^^ ~ q` is contingency.
20.

A person standingon thebankofa riverobservesthatthe angleof elevationof topofa treeon theoppositebank of theriveris 60^@ and whenthe retires 40metresaway fromthe treethe angleof elevationbecomes30^@the breadth of theriver is

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40 m
30m
20m
60m

Answer :C
21.

If bar(a)=(2,0,1) and bar(b)=(1,1,1) then sin(bar(a)""_(,)^(hat)bar(b))= …………..

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`SQRT((3)/(5))`
`sqrt((5)/(3))`
`sqrt((2)/(5))`
`sqrt((5)/(2))`

Answer :C
22.

Differentiate the following w.r.t x. (i) cos^(-1) (sin x) (ii) tan^(-1) ((sin x)/(1 + cos x)) (iii) sin^(-1) ((2^(x+1))/(1+4^(x)))

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Answer :(i) `f'(X)= -1`, (II) `f'(x)= (1)/(2)`, (III) `(2^(x+1) log 2)/(1 + 4^(x))`
23.

findthe area of theregionboundedby thecurvey=x^3 ,y = x+6 andx=0

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ANSWER :`10 ` SEQ .UNIT
24.

If 4 less than the product of b and 6 is 44, what is the value of b?

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`4`
`6`
`8`
`14`

Answer :C
25.

Check the injective and surjective of the following functions : f : Z rarr Z given by f(x) = x^3

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SOLUTION :We have `F(x_1) = f(x_2)`
`implies x_1^3 = x_2^3 implies x_1 = x_2` for all `x_1, x_2` in Z
`therefore` f is not SURJECTIVE
26.

Let S_(1),S_(2),S_(3) be three sets of complex numbers such thatS_(1)= {z:1m gt 1) S_(2) = {z : |z -2 -1|=3}S_(3) = {z : Re((1-i)z) = sqrt2, thenStatement -1The number of subsets of the setS_(1)cap S_(2) capS_(3) is 2.Statement -2Letz in S_(1) cap S_(2) cap S_(3) " then " |z +1-i|^(2) + |z -5-i|^(2) =36Statement -3 Let z be any point inS_(1) cap S_(2) Cap S_(3) and z_(1) " be any pointsatisfying " |z_(2)-2-i| lt 3, then(|z|-|z_(1)+3) lies between -3 and 9 ,.

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TTT
T T F
T F T
FF F

ANSWER :A
27.

If the normals at the four points (x_1,y_1),(x_2,y_2),(x_3,y_3) and (x_4,y_4) on the ellipsex^(2)/a^(2)+y^(2)/b^(2)=1 are concurrent, then the value of (sum_(i+1)^4x_1)(sum_(i=1)^(4)1/2)

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ANSWER :A::D
28.

If A is a squyare matrix then which one of the following is not a symmetric matrix

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A +A'
AA'
A'A
A-A'

Answer :D
29.

If |z-(4)/(z)|=2 then the miximum value of |z| is

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`3+sqrt(5)`
`2+sqrt(3)`
`3+sqrt(2)`
`1+sqrt(5)`

ANSWER :D
30.

Show that the equation of the circle with centre at origin and passing through the vertices of an equilateral triangle whose median is of length 3a is x^(2)+y^(2)=4a^(2).

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ANSWER :`4A^(2)`
31.

A purse contains 6 Silver coins and 3 Gold coins. Another purse contains 4 Silver coins and 5 Gold coins. A purse is selected at random and a coin is drawn from it. It's known that a coin is Gold then what is the probability that a Gold coin is selected from another (II^(nd)) purse?

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`(5)/(9)`
`(3)/(8)`
`(5)/(18)`
`(2)/(9)`

Answer :C
32.

Let f, g: R to R by f(x) = x|x| -1 AA x in R and g(x) = {{:(3/2x, if x gt 0),(2x, if x le 0):}. The number of subsets of S is

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2
4
16
infinite

ANSWER :B
33.

Find (dy)/(dx), if x= a (theta + sin theta), y= a (1- cos theta)

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ANSWER :`"TAN"(THETA)/(2)`
34.

The smaller side of the rectangle with the largest area, that can be inscribedinside a semi- circle of radius 2 units is of length

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`1/SQRT2`
`SQRT3`
`1/sqrt3`
`sqrt2`

ANSWER :D
35.

Solvetheequation x^5-x^4+ 8x^2 - 9x+ 15=0twoof its rootsbeing- sqrt(3) ,1-2 sqrt(-1)

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ANSWER :`+- SQRT(3) , 1_-2sqrt(-1) ,-1`
36.

Let R+ be the set of all non negative real numbers. Show that the function f: R_(+) to [4, infty]given by f(x) = x^2 + 4 is invertible and write inverse of 'f'.

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ANSWER :`F^(-1)(y) = SQRT(y-4)`
37.

IfPQis a focal chord of the parbolay^(2)=4ax withfocus at s then(2SP,SQ)/(SP+SQ)is equal to

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a
2a
3a
4a

Answer :B
38.

If n is an integer then the value of int_(0)^(pi) e^(cos^2x)cos^(3) ((2n+1)x)dx=

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1
0
-1
`1/2`

ANSWER :B
39.

The straight line x-2y+1=0 intersects the circle x^(2)+y^(2)=25 in points P and Q the coordinates of the point of intersection of tangents drawn at P and Q to the circle is

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(25,50)
(-25,50)
(25, -50)
(-25,-50)

ANSWER :B
40.

Simplify the following (sqrt(x+1) + sqrt(x-1))^(6) +(sqrt(x+1) - sqrt(x-1))^(6)

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SOLUTION :N/A
41.

Three fair dice are rolled. Find the probability that the greatest number on the dice must exceed 3.

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ANSWER :`(7)/(8)`
42.

Evaluate the following integrals. int(sec^(2)x)/((1+tanx))dx

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ANSWER :`(LN(1+tanx))+C`
43.

Integrate the following intsec(x+2)tan(x+2)dx

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SOLUTION :`intsec(x+2)cdottan(x+2)DX`
put `x+2=d THETA` then `dx=d theta`
`intsecthetacdot TANTHETA d theta`
`sectheta+C=sec(x+2)+C`
44.

The value of sec^(-1)((1)/(4)sum_(k=0)^(10)sec((7pi)/(12)+(kpi)/(2))sec((7pi)/(12)+((k+1)pi)/(2))) in the inerval [-(pi)/(4),(3pi)/(4)] equals..........

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SOLUTION :`therefore =sum_(k=0)^(10)sec((7pi)/(12)+(kpi)/(2))sec((7pi)/(12)+((k+1)pi)/(2))`
`=Sigma_(k=0)^(10) (1)/(cos ((7pi)/(12)+(kpi)/(2))cos((7pi)/(12)+((k+1)pi)/(2)))`
` =Sigma_(k=1)^(10) (sin [((7pi)/(12)+((k+1)pi)/(2))-((7pi)/(12)+(kpi)/(2))])/(cos ((7pi)/(12)+(kpi)/(2))cos ((7pi)/(12)+((k+1)pi)/(2)))`
`[because (7pi)/(12)+((k+1)pi)/(2)-((7pi)/(12)+(kpi)/(2))=(pi)/(2) and sin (pi)/(2)=1]`
`sin ((7pi)/(12)+((k+1)pi)/(2))cos ((7pi)/(12)+(kpi)/(2))`
`=Sigma_(k=0)^(10) (-sin ((7pi)/(12)+(kpi)/(2))cos ((7pi)/(12)+((k+1)pi)/2))/(cos ((7pi)/(12)+(kpi)/(2))cos ((7pi)/(12)+((k+1)pi)/(2)))`
`= Sigma _(k=0)^(10) [TAN ((7pi)/(12)+((k+1)pi)/(2))-tan ((7pi)/(12)+(kpi)/(2))]`
`=tan ((7pi)/(12)+(pi)/(2))-tan ((7pi)/(12))+tan ((7pi)/(12)+(2pi)/(2))-tan ((7pi)/(12)+(pi)/(2))+tan ((7pi)/(12)+(11pi)/(2))-tan((7pi)/(12)+(pi)/(2))`
`=tan ((7pi)/(12)+(11pi)/(2))-tan (7pi)/(12)=tan(pi)/(12)+COT (pi)/(12)`
`=(1)/(sin(pi)/(12)cos. (pi)/(12))=(2)/(sin.(pi)/(6))=4`
So, `sec^-1 ((1)/(4)Sigma_(k=0)^(10)sec((7pi)/(12)+(kpi)/(2))sec((7pi)/(12)+((k+1)pi)/(2)))=sec^-1(1)=0`
45.

Let ABC be a triangle having its centroid at G. If S is any point in the plane of the triangle then SA + SB + SC is equal to

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SG
2SG
3SG
0

Solution :We have, `SA+SB+SC=SA+(SB+SC)`
`IMPLIES SA+SB+SC=SA+2SD`
= (1+2) SG = 3SG
46.

Let a,b,c, d be the roots of x ^(4) -x ^(3)-x ^(2) -1=0. Also consider P (x) =x ^(6)-x ^(5) -x ^(3) -x ^(2) -x, then the value of p (a) +p(b) +p(c ) +p(d) is equal to :

Answer»


ANSWER :6
47.

The solution of (dy)/(dx) + (3)/(x) y = (1)/(x^(2)),at y=2, x=1

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`2X^(3)y = X^(2) - 3`
`2x^(3)y = x^(2) + 3`
`x^(3) y = x^(2) + 3`
`2x^(3)y = x^(2)+5`

Answer :B
48.

int sec^((2)/(3))x*"cosec"^((4)/(3))x dx=....

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`-3(tanx)^((1)/(3))+C`
`-3(tanx)^(-(1)/(3))+c`
`3(tanx)^(-(1)/(3))+c`
`(tanx)^(-(1)/(3))+c`

ANSWER :B
49.

Let u = int_(pi//6)^(pi//2) min. (sqrt(3)sinx, cosx) dx and V = int_(-3)^(5)x^(2)sgn (x-1) dx. If V =lambdaU, then find the value oflambda.

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SOLUTION :N//A
50.

Solve system of linear equations ,using matrix method4x-3y=3 3x-5y =7

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ANSWER :`X=(-6)/(11),y=(-19)/(11) `