Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Integrate the following functions: (cos2x+2 sin^2 x)/cos^2x

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SOLUTION :`(cos2x+2 sin^2x)/cos^2x)`
`=(1-2sin^2x+2sin^2x)/cos^2x = sec^2x`
THEREFORE `INT (cos2x+2sin^2x)/cos^2x) = tanx+c`
2.

Find the area of the region bounded by the curve y^(2) = 4xand line x=3.

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ANSWER :`=8sqrt(3)` SQ. UNITS.
3.

If A,B,C are mutually exclusive and exhaustive events such that P(A)=2P(B)=3P(C ) then P(BuuC)=

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`(6)/(11)`
`(5)/(11)`
`(4)/(11)`
`(7)/(11)`

ANSWER :B
4.

Consider the three vectors p, q, r such that p=hat(i)+hat(j)+hat(k) and q=hat(i)-hat(j)+hat(k) , ptimesr=q+cp and p*r=2 Q. If y is a vector satisfying (1+c)y=ptimes(qtimesr), then the vectors x, y and r

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are collinear
are coplanar
represent the coterminus EDGES of a TETRAHEDRON whose volume is c CU. Units
represent the coterminus edges of a parallelopiped whose volume is c cu. Units

Answer :C
5.

Drawa rough sketch of thegivencurvey=1 +|x+1|,x =-3 , x =3 , y=0and findthe areaof theregionbounded by them , usingintegration

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ANSWER :`=16` SEQ . UNIT
6.

Consider the function f(x) =(x^(3))/(4)-sin pi x+3

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f(x) does not attain VALUE within the INTERVAL [-2,2]
f(x) takes on the value `2 (1)/(3)` in the interval `[-2,2]`
f(x) takes on the value `3(1)/(4)` in the interval [-2,2]
f(x) takes no value no value p `1LT p lt 5` in the interval [-2,2]

Answer :B::C
7.

Write the absolute maximum and absolute minimum of the function f(x)=x/|x| in [-2, 2].

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SOLUTION :
8.

In triangle ABC, angle A gt pi/2. A A_(1) and A A_(2) are the medium and altitude, espectively. If angle B A A_(1)= angle A _(1) A A_(2)=angle A _(2) AC, then sin^(3)""A/3 . Cos ""A/3is equal to

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`(3A^(3))/(16b^(2)c)`
`(3a^(3))/(64b ^(2)c)`
`(3a^(2))/(4b^(2)c)`
`(3a^(3))/(12 b^(2)c)`

ANSWER :D
9.

If a xx I + 2a - 5j = 0 then a =

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2I + k
I + 2k
2j + k
j + 2k

Answer :C
10.

sinh (ix) is equal to

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`i SIN X`
`sinix`
`-i sin x`
`i sin IX`

ANSWER :a
11.

If P(A) = 2/3, P(B) = 4/9 " and " P(AcapB)=4/5, then find the value of P(AcupB) " and " P(A'capB').

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<P>

SOLUTION :`P(ACUPB)=38/45 " and " P(A'capB')=7/45`
12.

Solve the following system of linear equation by matrix method. x-y+2z=1 2y-3z=1 and 3x-2y+4z=2.

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ANSWER :x=0, y = 5 and Z = 3
13.

Integrate the following functions : intsqrt(4x^(2)-5)dx

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ANSWER :`xsqrt(X^(2)-(5)/(4))-(5)/(4)log|x+sqrt(x^(2)-(5)/(4))|+C`
14.

Prove that : int_(pi//4)^(3pi//4) (x)/(1+sin x)dx=pi(sqrt(2)-1)

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15.

Find the equation of the circle passing through the points (3,4) (3,2) ,(1,4)

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ANSWER :` X^(2) + y ^(2)-4X -6Y +11=0 `
16.

A pair of fair dice are rolled till a sum of 2 or 3 is obtained. Find the probability of getting sum 2 before getting sum 3.

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ANSWER :`(1)/(3)`
17.

int_(pi//2)^(pi//2)e^(sin^(2)x).sin^(2n+1)xdx=

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2e
0
1
`e/2`

ANSWER :B
18.

From 5 apples, 4 mangoes & 3 bananas, in how many ways we can select atleast two fruits of each variety if fruits of same species are identical?

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ANSWER :24
19.

Centres of circles touching both the axes and also the line 3x+4y-12=0 is

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(1,1), (6,6), (-2,2) and (3,-3)
(1,-1) and (6,-6)
(-1,1) and (-6,6)
(-1,-1) and (-6,-6)

ANSWER :A
20.

If hata, hatb are unit vectors and vec c is such that vec c=veca xx vec c +vecb, then the maximum value of[veca vecb vec c] is :

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1
`(1)/(2)`
2
`(3)/(2)`

ANSWER :B
21.

Which one of the following must equal p + q , if x - y = p and 2x + 3y = q ?

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`X + y`
`3x - 2y`
`2X -3Y`
`3x + 2y`

Answer :D
22.

If A and B are mutually exclusive events, given that P(A)=3/5,P(B)=1/5, then P(A or B) is

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ANSWER :`2/25`
23.

bar(d)=lambda(bar(a)xx bar(b))+mu(bar(b)xx bar( c ))+v(bar( c )xx bar(a)) and [bar(a)bar(b)bar( c )]=(1)/(8) then lambda+mu+v = …………..

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`bar(d)*(bar(a)+bar(B)+bar( C ))`
`2BAR(d).(bar(a)+bar(b)+bar( c ))`
`4bar(d).(bar(a)+bar(b)+bar( c ))`
`8bar(d)*(bar(a)+bar(b)+bar( c ))`

Answer :D
24.

Find the angle between the linesvecr = (3 + lambda)hati + 2(1 + lambda)hatj + 2(1 – 2lambda)hatkand vecr=5hatj-2hatk+mu(3hati+2hatj-6hatk).

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ANSWER :ANGLE `theta=cos^(-1)((19)/(21))`
25.

which of the following lines are asymptotes for the graph of y=(3x^2-13x-10)/(x^2-4x-5) ? I. x=-1 II. x=5 III. Y=3

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I only
II only
I and II
I and III

Solution :Factor the NUMERATOR and denominator: `((3x+2)(x-5))/((x+1)(x-5))`, Since the x-5 DIVIDE out, the only vertical asymptote is at x=-1. Since the degree of the numerator and denominator are equal, y approaches 3 as x approaches`+-oo`, so y=3 is a HORIZONTAL asymptote. [9]
26.

The minimum radius of the circle which contains the threecircles, x^(2)+y^(2)-4y-5=0,x^(2)+y^(2)+12x+4y+31=0 and x^(2)+y^(2)+6x+12y+36=0 is

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`(7)/(18)sqrt(900)+3`
`(sqrt(845))/(9)+4`
`(5)/(36)sqrt(949)+3`
none of these

Solution :`S_(1)-=x^(2)+y^(2)-4y-5=0`
`S_(2)-=x^(2)+y^(2)+12x+4y+31=0`
and `S_(3) -=x^(2)+y^(2)+6x+12y+36=0`
`C_(1) -= (0,2),r_(1)=3`
`C_(2) -= (-6,-2), r_(2)=3`
`C_(3) -= (-3,-6) , r_(3)=3`

All circles have the same radius,
THERADIUS of the CIRCLE touching all the circles is
`CP=C C_(1)=C_(1)P+3`
Let `C(h,k)` be the center of the required circle. Then,
`C C_(1)= C C_(2) = C C_(3)`or `C C_(1)^(2) = C C_(2)^(2)= C C_(3)^(2)`
or `(h-0)^(2)+(k-2)^(2)=(h+6)^(2)+(k+2)^(2)`
`=(h+3)^(2)+(k+6)^(2)`
or `-4k+4=12h+4k+40=6h+12k+45`
or `3h+2k+9=0` and `6h-8k-5=0`
Solving, we get
`h=(-31)/(18),k=(-23)/(12)`
`:. C C_(1)=sqrt((0+(31)/(18))^(2)+(2+(23)/(12))^(2))=(5)/(36)sqrt(949)`
Now, `CP =C C_(1)+3=(5)/(36)sqrt(949)+3`
27.

For the vectors A(-1,-2,3) and B(1,2,-1) the direction cosines of vec(AB) are ……………

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`(1)/(3),(2)/(3),(-2)/(3)`
2, 4, -4
`(2)/(sqrt(6)),(4)/(sqrt(6)),(-4)/(sqrt(6))`
`(-1)/(3),(-2)/(3),(2)/(3)`

ANSWER :A
28.

Find the coefficient of x^(-7)" in "((2x^(2))/(3)-(5)/(4x^(5)))^(7)

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ANSWER :` - 4375/324`
29.

Distance from the point (-3,2,5) to the point where the line (x+3)/2= (y-2)/2=(z-5)/2 meets the plane x+y +2z = 3 is

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`7/18`
`8/17`
`17/8`
`18/7`

ANSWER :D
30.

Show that the function f(x)=|cosx| is a continuous function.

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Solution :Write `g(X)=cosx`and`H(x)=|x|.` Then g and h are CONTINUOUS functions `therefore(hog)(x)=h(g(x))=h(cosx)=|cosx|` is a continuous function i.e.,f(x) is a continuous function.
31.

Find the equation of all lines having slope 2 which are tangents to the curve y=(1)/(x-3), x ne 3.

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ANSWER :`(x-3)^(2)GT 0`
32.

Compute the integrals :int_(1) ^(15) "arc tan " sqrt(sqrt(x) - 1)dx

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ANSWER :`(16 PI)/(3) - 2 sqrt(3)`
33.

A point charge ..................

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Solution :LET a vessel is closed by a disc of radius 'R'. Then the flux linked with the closed vessel will be
`phi=Q/epsi_(0)`
Now flux linked with the disc will be
`phi_("disc")=Q/(2 epsi_(0)) (1- x/sqrt(x^(2)+R^(2)))`
`phi_("total")=phi_("disc")+phi_("vessel")`
`phi_("vessel")=Q/(2 epsi_(0)) (1+ x/sqrt(x^(2)+R^(2)))`
34.

There are 2n things out of which 'n' are alike and 'n' are different, the number of ways of selecting 'n' things is

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`""^(2N)C_(N)`
`2^(n)-1`
`2^(n)`
n

Answer :C
35.

A point charge .................

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SOLUTION :As sphere is grounded, its NET potential must be 0,
Hence `(KQ)/x+(Kq)/R=0`
`(QR)/x=q`
`i=(dq)/(dt)=+(QR)/x^(2) xx (dx)/(dt)`
`i=(QRV)/x^(2)`
36.

A person gets Rs. 2 if head comes and loses Rs. 5 when a tail comes then how much money can he expect in the long run per game, when an unbiased coin in tossed twice.

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ANSWER :3 (LOSS)
37.

The volume of a cube is increasing at a rate of 8 cubie centimeters per second. How fast is the surface area increasing when the length of the edge is 12 cm?

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ANSWER :`(8)/(3) "CM"^(2)` /sec
38.

Evaluate intx^(2) cos x dx

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ANSWER :`(X^(2)-2)sinx+2xcosx+c`
39.

Write in the simplest form of tan^(-1)sqrt((1-cosx)/(1+cosx)),0ltxltpi

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ANSWER :`x/2`
40.

The value of lim_(n to oo)((n!)/(n^(n))^(2n^(4+1))/(5n^(5)+1)) is equal

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e
`(2)/(e)`
`((1)/(e))^(2)/(5)`
NONE of these

ANSWER :C
41.

Indicate which of the following is a tautology .

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<P>`(~p VV Q) ~ (p vv ~q)`
`(~p vv ~q) to p vv q`
`(p vv ~q) ^^ (p vv q)`
`(~p vv ~q) vv (p vv q)`

ANSWER :D
42.

There are 25 girls and 15 boys in class XI and 30 boys and 20 girls in class XII. If a student chosen from a class, selected at random, happens to be a boy, find the probability that he has been chosen from class XII.

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<P>

Solution :LET `E_1`= The student is choosen from class XI.
`E_2` The student is choosen from class XII.
A= The student is a boy.`P(E_1)=P(E_2)=1/2`
`P(A//E_1)=15/40=3/8`
P(A//E_2)=30/50=6/10`
We WENT to find `P(E_2//A)`. By Baye.s theoren
`P(E_2|A)=(P(E_2)P(A//E_2))/(P(E_1)P(A//E_1)+P(E_2)P(A//E_2))`
`=(1/2cdot 6/10)/(1/2cdot3/8+1/2cdot6/10)=(6/10)/((15+24)/40)=24/39=8/13`
43.

AA|x|le1,cos^(-1)(-x)=

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`cos^(-1)(x)`
`PI=cos^(-1)(x)`
`pi - cos^(-1)(x)`
`(pi)/2-cos^(-1)(x)`

ANSWER :C
44.

If the position vectors of the vertices of Delta ABC are 3hati+hatj+2hatk, hati-2hatj+7hatk and -2hati+3hatj+5hatk, then the DeltaABC is

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right angled and isosceles
right angled, but not isosceles
isosceles but not right angled
equilateral

Solution :Given vertices are
`A(3hati+hatj+2hatk),B(hati-2hatj+7hatk)andC(-2hati+3hatj+5hatk)`.
Now, `AB=(hati-2hatj+7hatk)-(3hati+hatj+2hatk)`
`=-2hati-3hatj+5hatk`
`THEREFORE |AB|=sqrt(4+9+25)=sqrt(38)`
Similarly, `|BC|=|CA|=sqrt(38)`
`therefore |AB|=|BC|=|CA|=sqrt(38)`
HENCE, triangle is an equilateral triangle.
45.

Statement 1: If a circle S = 0 intersects a hyperbola xy =4at four points , Three of them are (2,2) , (4,1)and ( 6, 2//3)then coordinates of the fouth points are (1//4 , 16 ) Statement 2: If a circle S=0 intersects a hyperbola xy= c ^(2)att_1, t_2, t_3 , t_4thent_1.t_2.t_3.t_4=1.Then correct statement is

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Both the STATEMENT are TRUE and II is the CORRECT explanation of I
Both the statement are True but Statement II is Not the correct explanation of Statement I.
statement -I is True and Statement -II is False
statement -I is False and statement -II is True

Answer :D
46.

If I_(n) = int Cot^(n)xdx then I_(4) + I_(6) =

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` - (Cot^(5)x)/(5)`
`Cot^(5)` x
`(1)/(5) Cot^(5)` x
`-(1)/(5) Cot^(5) x - (1)/(3)Cot^(3)` x

ANSWER :A
47.

Evalute the following integrals int (x^(2) - 1)/(x^(4) + x^(2) + 1) dx

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Answer :`(1)/(2 SQRT(3)) LOG | (x^(2) - sqrt(3) x + 1)/(x^(2) + sqrt(3X) + 1) | + c `
48.

[(1+ cos((pi)/(12))+ i sin ((pi )/(12)))/(1+ cos((pi)/(12))-i sin((pi)/(12)))^(72)]

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0
`-1`
`1`
`1/2`

ANSWER :C
49.

Which of the following is a contradiction?

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<P>`(p ^^ Q) ^^ (~(p VV q))`
`p vv (~p ^^ q)`
`( p to q) to p`
NONE of these

ANSWER :A
50.

Let veca,vecb,vecc be three mutually perpendicular vectors having same magnitude and vecr is a vector satisfying vecaxx((vecr-vecb)xxveca)+vecbxx((vecr-vecc)xxvecb)+veccxx((vecr-veca)xxvecb)=vec0, then vecr is equal to

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`1/3(veca+vecb+vecc)`
`1/2(veca+vecb+vecc)`
`3/2(veca+vecb+vecc)`
`2(veca+vecb+vecc)`

SOLUTION :NA