InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 4951. |
If, in triangleABC, tanA : tan B : tan C= 2:3:4, then: sec^(2)C= |
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Answer» `(1-COTA)(1-cot C)=2` |
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| 4952. |
A line makes the angle alpha, beta , gamma and delta with the diagonals of a cube. The cos^2 alpha + cos^2 beta + cos^2 gamma + cos^2 delta =............. |
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Answer» `4/3` |
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| 4953. |
Examine the continuity of the following functions at indicated points.f(x)={((1+2x)^(1/2)if xne0),(e^2 if x=0at x=0):} |
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Answer» Solution :We KNOW that a function F(x) is CONTINUOUS at a point x=a if `LIM(xtoa)f(x)=f(a)` Now `lim_(xto0)f(x)=lim_(xto0)(1+2x)^(1/x)=e^2` Again `f(0)=e^2` THUS `lim_(xto0)f(x)=f(0)` So f(x) is continuous at x=0 |
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| 4954. |
If A = {1,2,3,4} , define relations on A which have properties of being : Symmetric but neither reflexive nor transitive |
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| 4955. |
Given that, a alpha^(2) + c ne 0 and that the system of equations (a alpha +b) x + ay + bz=0, (b alpha + c ) x + by + cz, =0, (a alpha +b) y+ (b alpha + c) z=0 has a non-trivial solution, then a,b, and c lie in |
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Answer» ARITHMETIC peogression |
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| 4956. |
Prove that C_(1)^(2) - 2. C_(2)^(2) + 3. C_(3)^(2) - …. -2n . C_(2n)^(2) = (-1)^(n). C_(n) |
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Answer» Solution : We KNOW that , `(1 + x )^(2n) = C_(0)+ C_(1)x + C_(2) x^(2) + …+ C_(2n) x^(2n)` On differntiating both sides w.r.t.x, we get ` 2n (1 + x)^(2n-1) = C_(1) + 2.C_(2) x + 3. C_(3) x^(3) + …+ 2nC_(2n x^(2n-1) ` …(i) and ` (1 - (1)/(x))^(2n) = C_(0) - C_(1).(1)/(x) + C_(2) .(1)/(x^(2)) C_(3) . (1)/(x^(3)) + ...+ C_(2n). (1)/(x^(2n))`...(II) On multiplying Eqs. (i) and (ii) , we get ` 2n (1 + x)^(2n-1) (1 - (1)/(x))^(2n)` = `[C_(1) + 2*C_(2)x + 3. C_(3) x^(2) +...+ 2n*C_(2n)x^(2n-1)] xx[C_(0) - C_(1) ((1)/(x)) + C_(2) ((1)/(x^(3))) -...+C_(2n) ((1)/(x^(2n)))]` Coefficent of ` ((1)/(x))`on the LHS = Coefficient of ` (1)/(x) `in 2n `((1)/(x^(2n)))(1 + x)^(2n - 1) (x - 1)^(2n)` Coefficient if ` x^(2n - 1)` in 2n ` (1 - x^(2))^(2-1) (1 - x)` ` 2n (-1)^(n-1) . (2n -1) C_(n-1) (-1)` ` = (-1)^(n) (2n) ((2n -1)!)/((n-1)!n!) = (-1)^(n)n((2n)!)/((n!^(2)))n` ` = - (-1)^(n)n . C_(n)`...(iii) Again , the coefficient of `((1)/(x))` on the RHS ` = - (C_(1)^(2) - 2 *C_(2)^(2) + 3*C_(3)^(2)-...-2nC_(2n)^(2))`...(iv) From Eqs. (iii) and (iv), `- C_(1)^(2) - 2 *C_(2)^(2) + 3*C_(3)^(2)-...-2nC_(2n)^(2) = (-1)^(n) n.C_(n)`. |
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| 4957. |
Form the equation whose roots are m times the roots of the equation x^3+(x^2)/(4)-x/(16)+1/(72)=0and deduce the case when m =12 . |
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Answer» 3 |
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| 4958. |
Evaluate the following integrals int_0^1(2x+1)^4 |
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Answer» SOLUTION :`int_0^1(2x+1)^4dx=(1/2)[(2x+1)^5/5]_0^1` (1/2)((243-1)/5)=121/5 |
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| 4959. |
Prove that Bernoulli inqeuality (1+x_(1)) [1+x_(2)).....(1+x_(n)) ge 1+x_(1)+x_(2)+......+x_(n). Where x_(1), x_(2),.....x_(n) are numbers of like sign, and 1+x_(1) gt 0(i=1,2,.....n) |
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| 4960. |
The probability that a certain kind of component will survive a electrical test is (3)/(4) . Find the probability that exactly 3 of the 5 components tested survive . |
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| 4961. |
The value of K_(p) for the reaction NH_(2)COONH_(4)(s) hArr2NH_(3)(g)+CO_(2)(g)" is "2.9xx10^(-5)"atm"^(3). The total pressure of gases at equilibrium when NH_(2)COONH_(4)(s) is taken to start the reaction at the initial concentration of 1.0 mole is |
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Answer» 0.0620 atm. `{:("Initial conc.",1.0"mole",,0,,0),("EQM. conc.",0,,2,,1):}` Let P be the equilibrium pressure then the PARTIAL pressure of ammonia `=(2)/(3)P` and the of carbon dioxide is `(1)/(3)P`. Or`""K_(p)=[(2P)/(3)]^(2)[(P)/(3)]=(4P^(3))/(27)` Or `""2.9xx10^(-5)=(4P^(3))/(27)" or "4P^(3)=27xx2.9xx10^(-5)` Or `""P=root(3)((27xx2.9xx10^(-5))/(4))` Or `""P=0.0582" atm. "` |
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| 4962. |
There are 4 Oranges, 4 apples and 6 mangoes in a fruit basket. In how many ways can a person makes a selection of one or more fruits from among the fruits in the basket if all the fruits of same type are identical |
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| 4963. |
There are 4 Oranges, 4 apples and 6 mangoes in a fruit basket. In how many ways can a person makes a selection of one or more fruits from among the fruits in the basket if all the fruits of same type are different |
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| 4964. |
If from a pack of 52 well shuffled cards, cards are drawn one by one without replacement and thethird card is found to be ACE. What is the probability that first two cards are not ACES ? |
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Answer» `260/329` `=(4.^48C_2)/(4 .^48C_2+12.^48C_1+12)` |
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| 4965. |
Expand the following (7a+3b)^6 |
| Answer» SOLUTION :`(7A+3B)^6` = `(7a+3b)^6` = `7a^6+"^6C_1 7a^(6-1) (3b)^1 + ^6C_2 7a^(6-2)(3b^2)+...(3b)^6` | |
| 4966. |
If a square with length of each side equal to a is inscribed in the circle x ^(2) + y ^(2) + 4x + 10 y + 21 =0,then a is equal to |
| Answer» Answer :D | |
| 4967. |
A boat is to be manned by 9 crew with 4 on the stroke side, 4 on the row side and one to steer. There are 11 men of which 2 can stroke only and 1 can row only while 3 can steer only. The number of ways the crew can be arranged for the boat is |
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Answer» 10 |
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| 4968. |
Which of the following statements (s) is/are true? |
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Answer» `underset(x to a)(LIM) (a^(x) - x^(a))/(x^(x) - a^(a)) = - 1` then a is 1 |
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| 4969. |
A student is instructed to answer 8 out of 12 questions. i. How many differnet ways can he choose the questions? ii. How many different ways can he choose the questions so that question number 1 will be included? iii. How many different ways can he choose the questions so that question number 1 will be included and question number 10 will be excluded? |
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Answer» II. 330 iii. 120 |
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| 4970. |
Solve as directed: abs(x-3) lt 11 , in N and in R. |
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Answer» Solution :`ABS(X-3) lt 11` `rArr -1 lt x - 3 lt 11 `rArr -11 + 3 lt x - 3 + 3 lt 11 + 3` ` rArr -8 lt x lt 14 ` If x `in` N the solution set is S = {1,2,3,4,5,…….12,13} If x `in` R then the solution set is : S -= {x:x `in` R and -8 `lt x lt 14} =(-8,14) |
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| 4971. |
Through the vertex O of the parabola y^(2)=4ax a perpendicular is drawn to any tangent meeting it at P and the parabola at Q. Then OP.OQ= |
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Answer» `a^(2)` |
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| 4972. |
int(1-tanx)/(1+tanx)dx=..... |
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Answer» `LOG SEC((pi)/(4)-x)+c` |
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| 4973. |
A manufacturing company makes tow models A and B of product. Each piece of model A reqwuires 9 labour hours for fabricating and 1 hour labour for finishing . Each piece of model Brequires 12 labour hours for fabricating and 3 labourhours for fininshing. for fabricating and finishing, the maximum labour hours available are 180 and 30 respectively. The company makes a profit of Rs. 8,000 on each piece of modleA and Rs 12,000 on each piece of model B. How many pieces of model A and B should be manufactured per week to realise a maximum profit ? What is the maximum profit per week ? |
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| 4974. |
Find the area of the loop of the curve 3ay^(2)= x(x-a)^(2) |
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| 4975. |
Let **' be the binary operation on the set {1,2,3,4,5} defined by a**'b= H.C.F. of a and b. Is the operation **' same as the operation ** defined in Exercise 4 above ? Justify your answer. |
Answer» SOLUTION :YES
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| 4976. |
The vector equation of the line 6x-3=3y+4=2z-2 is |
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Answer» `VECR=hati-hatj+hatk +LAMBDA(6hati+hatj+hatk)` |
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| 4977. |
If a chord of the parabola y^(2)=4x passes through its focus and makes an angle theta with the X-axis, then its length is |
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Answer» `4cos^(2) theta` |
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| 4978. |
If overline(a) and overline(b) are tow parallel vectors wth equal magnitude, then |
| Answer» Answer :D | |
| 4979. |
""^(37)C_(4)+sum_(r=1)^(5)(42-r)_(C_(r))= |
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Answer» `""^(38)C_(4)` |
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| 4980. |
If in the triangle ABC, "tan"(A)/(2), "tan"(B)/(2) and "tan"(C )/(2) are in harmonic progression then the least value of "cot"^(2)(B)/(2) is equal to : |
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| 4981. |
Find int x sqrt(1+x-x^(2))dx as the limit of sum. |
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| 4982. |
If x = (1-sqrt(y))/(1+sqrt(9)), then (x+1)(d^(2)y)/(dx^(2))+((3sqrt(y)+1)/(sqrt(y)))(dy)/(dx) = |
| Answer» Answer :B | |
| 4983. |
The volume of the solid formed by revolving the area of the circle x^2+y^2=9 about y axis is : |
| Answer» ANSWER :D | |
| 4984. |
If |z + 4| + |z - 4| = 10 represents an ellipse then length of its minor axis is |
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Answer» 3 |
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| 4985. |
For matrics A and B, verify that (AB)^T=B^T .A^T, where A=[[0],[1],[2]], B=[[1,5,7]] |
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Answer» SOLUTION :`AB=[[1],[-4],[3]] [[-1,2,1]]=[[-1,2,1],[4,-8,-4],[-3,6,3]]` therefore `(AB)^T=[[-1,4,-3],[2,-8,6],[1,-4,3]]` `B^T A^T=[[-1],[2],[1]] [1,-4,3]]=[[-1,4,-3],[2,-8,6][1-4,3]]` , thus `(AB)^T=B^T A^T` |
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| 4986. |
Find the numerically greatest term of (2x-3y)^(12), x=1, y=(5)/(3) |
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| 4987. |
The value of k for which the system of linear equations (2k+2)x+10y=k 2kx+(2k+3)y=k-1 ha sno solution is________________. |
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| 4988. |
I : Value of i^i=e^(-pi/2)II : z=ilog(2+sqrt3) then sinz=2which of above statement is true |
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Answer» only I |
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| 4989. |
Equation of a line passing through the point (2,-3, 2) and equally inclined to the Line L_(1) and L_(2) may be equal to : |
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Answer» `(x-2)/(2) = (y-3)/(-1) = (z-3)/(1)` |
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| 4990. |
If int(x+1)/((x^(2)+x+1))(dx)/(sqrt(x^(2)+x+1))=K(x-1)/(sqrt(x^(2)+x+1))+C then the value of K is |
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Answer» 1//3 |
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| 4991. |
If four whole numbers taken at random are multiplied together. Then the chance that the last digit in the product is 1 or 3 or 7 or 9 is.(A) 16/625(B) 16/125(C) 16/625(D) NONE OF THESE |
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| 4992. |
Solve the following systems of linear inequalities graphically : x - y lt 1 , y - x = 1 |
Answer» SOLUTION :
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| 4994. |
Estimate the integral from above I = int_(0)^(1) (sin x)/( 1 + x^(3)) dx |
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| 4995. |
If the total number of ways in which 8-digit numbers can be formed by using all the digits 0, 1, 2, 3, 4, 5, 7, 9 such that no two even digits appear together is (5!)k, then k is equal to ______ |
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| 4996. |
In the following figure, identify collinear but not equal vector |
| Answer» Solution :`veca "and" vecd`their LINES of ACTION are parallel and they have OPPOSITE DIRECTIONS. | |
| 4997. |
N is 50 digit number in decimal form). All digits except the 26^("th")digit (from left) are 1. If N is divisible by 13, find the 26^("th")digit. |
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| 4998. |
For any vector bar(a), the value of (bar(a)xx i)^(2)+(bar(a)xx j)^(2)+(bar(a)xx bar(k))^(2) is ……….. |
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Answer» `|BAR(a)|^(2)` |
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| 4999. |
Find the maximum value of the 2+3sinx+4cosx |
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Answer» SOLUTION :Maximum VALUE of 3sinx+4cosx is `SQRT(3^2+4^2)=5` `THEREFORE` Maximum value of 2+3sinx+4cosx is 2+5=7 |
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| 5000. |
If z_(1)=a+ib,z_(2)=-a+ib then z_(1)-z_(2) lies on …………. |
| Answer» Answer :A | |