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12801.

Choose the correct answer. The general solution of a differential equation of the type (dx)/(dy) + P_1 x = Q_1 isa)y e^(int P_1 dy) = int (Q_1 e^(int P_1 dy))dy + cb)y e^(int P_1 dx) = int (Q_1 e^(int P_1 dx))dy + cc)x e^(int P_1 dy) = int (Q_1 e^(int P_1 dy))dy + cd)x e^(int P_1 dx) = int (Q_1 e^(int P_1 dx))dx + c

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`y e^(int P_1 dy) = int (Q_1 e^(int P_1 dy))dy + c`
`y e^(int P_1 dx) = int (Q_1 e^(int P_1 dx))dy + c`
`x e^(int P_1 dy) = int (Q_1 e^(int P_1 dy))dy + c`
`x e^(int P_1 dx) = int (Q_1 e^(int P_1 dx))dx + c`

ANSWER :C
12802.

Find the number of diagonals of a polygon having 20 sides

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ANSWER :170
12803.

Two aeroplanes I and II bomb a target in succession. The probabilities of I and II scoring a hit correctly are 0.3 and 0.2 respectively. The second plane will bomb only if the first misses the target. The probability that the target is hit by the second plane is

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`0.7`
`0.06`
`0.14`
`0.2`

ANSWER :C
12804.

If A=[{:(1,5),(7,12):}],B=[{:(9,1),(7,8):}] find a matrix C such that 3A+5B+2C is a null matrix.

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ANSWER :`=[{:(-24,-10),(-28,-38):}]`
12805.

Evaluate the following integrals (iii) int_(-1)^(2) (x^(2))/(x^(2)+2)dx

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ANSWER :`3-SQRT(2)(TAN^(-1)sqrt(2)+Tan^(-1)((1)/(sqrt(2))))`
12806.

L_(1)andL_(2) are two lines whose vector equations are L_(1):vecr=lamda((costheta+sqrt3)hati+(sqrt2sintheta)hatj+(costheta-sqrt3)hatk) L_(2):vecr=mu(ahati+bhatj+chatk), where lamdaandmu are scalars and alpha is the acute angle between L_(1)andL_(2).If the anglealpha is independent of theta then the value of alpha is

Answer»

`(pi)/(6)`
`(pi)/(4)`
`(pi)/(3)`
`(pi)/(2)`

Solution :Both the lines pass through the origin. Line `L_(1)` is parallel to the vector `vec(V_1)`
`""vec(V_1)= (costheta+sqrt(3))HATI+ (sqrt2 sin theta)hatj + (costheta-sqrt3)hatk`
and `L_(2)` is parallel to the vector `vec(V_2)`
`""vec(V_2) = ahati+bhatj+chatk`
`therefore ""cosalpha= (vec(V_1)*vec(V_2))/(|vec(V_1)||vec(V_2)|)`
`= (a(costheta+ sqrt3)+ (bsqrt2)sintheta+c(costheta-sqrt3))/(sqrt(a^(2)+B^(2)+c^(2))sqrt((costheta+sqrt3)^(2)+ 2sin^(2)theta+ (costheta-sqrt3)^(2)))`
`((a+c)costheta+bsqrt2sintheta+ (a-c)sqrt3)/(sqrt(a^(2)+b^(2)+c^(2))sqrt(2+6))`
For `cos ALPHA` to be INDEPENDENT of `theta`, we get
`""a+c=0 and b=0`
`therefore ""cosalpha = (2asqrt3)/(asqrt2 2sqrt2)= (sqrt3)/(2)`
or `""alpha= (pi)/(6)`
12807.

The points of intersection of the parabolas y^(2) = 5x and x^(2) = 5y lie on the line

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x+y=10
x-2y=0
x-y=0
2x-y=0

Answer :C
12808.

For 0 le theta ltpi/4,let x = sum_(n=0)^(oo)(sin theta )^(2n), y = sum_(n=0)^(oo)(cos theta)^(2n) then sum of the series {:(,P,Q,R,S),((A),2,4,1,3),((B ),3,2,4,1),((C ),1,3,2,4),((D),4,1,2,3):}

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ANSWER :B
12809.

""^4C_1 + ""^5C_2.(1/2) + ""^6C_3.(1/2)^2+….. to oo terms :

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30
40
900
15

Answer :A
12810.

A variablecircle is drawn to touch the x-axis at the origin. The locus of the pole of the straight line l x+my+n=0 w.r.t the variable circle has the equation:

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`X(my-n)-LY^(2)=0`
`x(my+n)-ly^(2)=0`
`x(my-n)+ly^(2)=0`
None of these

Answer :A
12811.

int (cos sqrt(x))/(sqrtx) dx

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ANSWER :`2sinsqrtx+C`
12812.

A be a square matrix of order 2 with |A| ne 0 such that |A+|A| adj (A) | = 0 , where adj(A) is a adjoint of matrix A, then the value of |A-|A| adj (A) | is

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1
2
3
4

Answer :D
12813.

Let f(x) be a non negative continuous and bounded function for all xge0 .If (cos x)f(x) lt (sin x- cosx)f(x) forall x ge 0, then which of the following is/are correct?

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`f(6)+f(5)gt0`
`x^(2)-3x+2+f(7)=0` has 2 distinct solution
f(5)f(7)-f(5)=0
`underset(xrarr6)lim (f(x)-sin (PIX))/(x-6)=1`

Solution :Let `g(x)=e^(x)cosxf(x)`
`therefore g(x)=e^(x)cosxf(x)+e^(x)(cosx-sinx)f(x)`
`=e^(x)(cosxf(x)+(cosx-sinx)f(x)`
`le0`
`therefore g(X)` is a NON increasing function
`therefore f(6)=e^(6)cos 6 f(6)le0`
`therefore f(6)le0`
But given that f(x) is non negative ltbegt `therefore f(6)=0`
with similar reasons f(5),f(7)=0
Thus `x^(2)-3x+2+f(7)=0`
or `x^(2)-3x+2=0` l has 2 distinct solution
`underset(xrarr6)lim(f(x)-sin(pix))/(x-6)`
=`underset(xrarr6)limf(x)-picos(pix)/(1)` (applying L hospital rule)
`=f(6)-pilt0`
12814.

If log_(e)5,log_(e)(5^(x) - 1)and log_(e)(5^(x) - 11/5) are in A.P., then the values of x are

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`log_(5)4` and `log_(5)3`
`log_(3)4` and `log_(4)3`
`log_(3)4` and `log_(3)5`
`log_(5)6` and `log_(5)7`

ANSWER :A
12815.

Find the vector and cartesian equations of the planes :(a) that passes through the point (1, 0, -2) and the normal to the plane is hati+hatj-hatk.(b) that passes through the point (1,4, 6) and the normal vector to the plane is hati-2hatj+hatk.

Answer»


Answer :(a) `IMPLIES` X + y - Z = 3
(b) `therefore` x-2y+z+1=0
12816.

Find the value of k so that the function: f(x) = [{:(kx + 1, if x le 5),(3x-5, if x gt 5):}] at x=5 is a continous function:

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ANSWER :`k-9/5`
12817.

Using elementary transformations, find the inverseof the matrices [(2,-3),(-1,2)]

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ANSWER :`[(2,3),(1,2)]`
12818.

Find the probability of getting a odd number in a single roll of the die

Answer»

<P>

Answer :Probability of GETTING an odd NUMBER
`=P(1)+P(3)+P(5)`
`1/21+ 3/21+5/21=9/21`
12819.

A variable plane is at a distance of 6 units from the origin. If it meets the coordinate axes in A, B and C, then the equation of the locus of the centroid of the Delta ABC is

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`1/x^(2)+1/y^(2)+1/Z^(2)=1/4`
`x^(2)+y^(2)+z^(2)=4`
`1/x^(2)+1/y^(2)+1/z^(2)=1`
`1/x^(2)+1/y^(2)-1/z^(2)=1/4`

ANSWER :A
12820.

The real x and y satisfy log_(8) x + log_(4) y^(2) = 5 " and " log_(8) y + log_(4) x^(2) = 7, find xy.

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ANSWER :`XY = 2^(9)`
12821.

Determine the order and degree of the differential equation y' + 5y = 0

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ANSWER :ORDER 1; DEGREE 1
12822.

Write the projection of the point (1,2,3) on xy-plane.

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SOLUTION :PROJECTION of the POINT (2,3,1) on y-axis is (0,3,0).
12823.

The solution of (dy)/(dx) = e^(x-y) (e^(x) - e^(y)) is

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`E^(y) = e^(X) -1+ CE^(-e^(x))`
`e^(y) = e^(x) + 1 + ce^(-e^(x))`
`e^(y) = e^(x) -1 - ce^(-e^(x))`
`e^(y) = e^(x) -2 + ce^(-e^(x))`

ANSWER :A
12824.

If cosalpha=(1)/(sqrt5)(0°ltalphalt90^(@))andcosbeta=(1)/(sqrt10),(270^(@)ltbetalt360^(@)) then the value of sin(alpha+beta) is

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`(1)/(SQRT2)`
`(1)/(5sqrt2)`
`-(3)/(5sqrt2)`
`-(1)/(5sqrt2)`

ANSWER :A::B
12825.

Number of ways in which n differentprizes can be distributedamong m-persons (m lt n)if each is entitled to receive atmost (n-1) prizes is

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`N^(m) - n`
`m^(n)`
MN
`m^(n) - m`

ANSWER :D
12826.

Protein present in eye lens is :

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Opsin
Collagen
Crystalline
Rhodopsin

Answer :A
12827.

If a, b,c be the sides of a triangle ABC with right angle at C. The medians AD and BE have slopes 1 and 2 respectively. Then ab = kc where 36 k equals………

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ANSWER :8
12828.

Which of the following statement is dual of p ^^ ( q vee r ) equiv ( p ^^ q) vee ( p ^^ r)

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<P>`pvee ( Q VEE r ) equiv ( p vee q ) ^^ ( p vee r ) `
`p vee ( q ^^ r ) equiv ( p vee q ) ^^ (p VV r) `
`p ^^ (q ^^ r ) equiv( p ^^ q) vv (q ^^ r)`
`p ^^ ( q ^^ r ) equiv ( p ^^ q ) vee ( q ^ r)`

Answer :B
12829.

When H_(2)O_(2) is reacted with K_(2)Cr_(2)O_(7)" in dilute "H_(2)SO_(4) and then ether is added. The ether layer gets -colour

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RED
Yellow
BLUE
Green

Answer :C
12830.

I. The number of all ten digited numbers that can be formed with all the distinct digits and which ar divisble by 4 is 15 times 81. II. The number of positive integers that can be formed by using the digits 0, 1, 2, 3, 4, 5 without any repetition is 630.

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Only I is true
Only II is true
Both I and II are true
Both I and IIare false

Answer :B
12831.

A cottage industry manufactures pedestal lamps and wooden shades, each requiring the use of a grinding/cutting machine and 2 hours on the sprayer to manufacture a shade.On any day, the sprayer is available for at the most 12 hours and the grinding/cutting machine for at the most 12 hours.The profit from the sale of a lamp is ₹ 5 and that from a shade is ₹ 3.Assuming that manufacturer can sell all the lamps and shades that he produces, how should he schedule his daily production in order to maximise his profit?

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Answer :Max.profit is ₹ 32 when 4 PEDESTAL LAMPS and 4 WOODEN shades are manufactured.
12832.

The mean and standard deviation of 20 items is found to be 10 and 2 respectively. At the time of checking it was found that one item 8 was incorrect. If it is replaced by 12, then find the mean and variance.

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ANSWER :10.2 and 3.96
12833.

Three lines drawn from origin with direction cosines l_1,m_1,n_1 , l_2, m_2,n_2 , l_3,m_3,n_3 are coplanar iff : |(l_1,m_1,n_1),(l_2,m_2,n_2),(l_3,m_3,n_3)|=0 since :

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intersecting LINES are coplanar
it is POSSIBLE to FIND a LINE perpendicular to all these lines
all lines pass through origin
None of these.

Answer :A
12834.

Find the area of the region given by : {(x,y): x ^(2) le y le |x|}. (ii) Find the area bounded by thte curves : {(x,y) : y ge x ^(2) and y= |x|}. (iii) Find the area of the region bounded by the parabola y = x ^(2) and y= |x|.

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ANSWER :`(i) -(III) (1)/(3)` (sq. units).
12835.

Numberof transformed equations ofx^3 +2x^2 +x+1=0byeliminatingthirdtermis

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`X^(4) + 6x^(3) - 12X + 8 = 0 " or " x^(4) - 6x^(3) + 42x + 53 = 0 `
`x^(4) + 6x^(3) - 12x - 8 = 0 " or " x^(4) - 6x^(3) + 42x - 53 = 0 `
`x^(3) + x^(2) + 1 =0 " or " 27x^(3) - 27x^(2) + 23 = 0 `
`x^(3) - x^(2) + 1 =0 " or " 27x^(3) + 27x^(2) + 23 = 0 `

ANSWER :4
12836.

Let f(x) be a real valued function such that f(0)=1/2 and f(x+y)=f(x)f(a-y)+f(y)f(a-x),forall x,y in R, then for some real a,

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f (X) is perodic FUNCTION
f (x) is a CONSTANT function
`f (x)= 1/2`
` f(x) =(cos x)/(2)`

Answer :A::B::C
12837.

Foran ellipse(x^2)/(a^2) +(y^2)/(b^2) =1, a gt b, the areaenclosedby two latusrectumis ……. ( whereis theeccentricityof anellipse )

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`b ( b e + a sin^(-1) 2E)`
`8b (b e+ a sin^(-1) e)`
`(2b ( be+ ASIN ^(-1)e)`
`4b( b e+ a sin^(-1) e)`

Answer :C
12838.

Let f(x)=(sinx-cosx+sqrt2)/(x^(3//2)), " where "x in [pi/4,(5pi)/4] . Let m be the maximum value of F(x) and M be the minimum value of F(x). Then [(2M)/(5m)] is equal to ([.]) denotesthe greatest interger function

Answer»

3
2
4
6

Answer :C
12839.

Evaluate the following definite intergrals as limit of sums. overset(4)underset(0) int (x+e^(2x))dx

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ANSWER :`(E^(8)+15)/(2)`
12840.

Expand the expression (1 - 2x)^(5).

Answer»


Answer :`= 1 - 10X + 40X^(2) - 80x^(3) + 80x^(4) - 32X^(5)`
12841.

The value of f(x).f(-x) for all x is

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4
9
12
16

Answer :B
12842.

If A denotes the area enclosed by 3|x|+4|y|le 12 then A is equal to

Answer»


ANSWER :24
12843.

The value of the expression |bar(a)xx bar(b)|^(2)+(bar(a).bar(b))^(2) is …………..

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ANSWER :`=|BAR(a)|^(2).|bar(B)|^(2)`
12844.

There is a point inside an equilateral triangle ABC of side d whose distance from the vertices is 3,4,5 . Rotate the triangle and P through 60^@ about C. Let A go to A' and P to P'. The angle APB is equal to

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`90^@`
`120^@`
`150^@`
none of these

Answer :C
12845.

There is a point inside an equilateral triangle ABC of side d whose distance from the vertices is 3,4,5 . Rotate the triangle and P through 60^@ about C. Let A go to A' and P to P'. The value of d^2 is

Answer»

`25+12sqrt3`
`25-12sqrt3`
`5 + 12 SQRT3`
`25 +24 sqrt3`

Answer :A
12846.

Ifroot3(-1) = -1 , -omega, -omega^(2) , then roots of the equation(x+1)^(3) + 64 =0are

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` 1- 4omega`
` -1-4 omega^(2)`
`-5`
`-4`

ANSWER :A::B::C
12847.

If X is a Poisson veriate with P(X = 0) = 0.8 , then the veriance of X is .

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` log_(e) 20`
`log_(10) 20`
`log_(e) 5//4 `
`0 `

Answer :C
12848.

Solve the given equations: x +y +z=0 x^(3) + y^(3) +z^(3)=18 x^(7) + y^(7) + z^(7) = 2058 where x,y,z in R

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ANSWER :(x, y, Z) = (2, -1, - 3), (2, - 3, - 1) (1-3,-2) (1-2,-3), (3,-1,-2), (3,-2.-1)
12849.

From the following data, find (i) regression coefficients (ii) regression equations

Answer»


Answer :`b_(yx-0.65,b_(XY)=-1.3`
REGRESSION equation of y on x;y=-0.65x+11.9
Regression equation of x on `y:x=-1.3y+16.4`
12850.

Find the locus of the point P(x,y) such that the area of the triangle PAB is 5, where A is the point (1,-1) and B is the point (5,2).

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<P>

SOLUTION :
`THEREFORE` AREA of the triangle PAB is
1/2{x(-1-2) + 1(2-y) + 5(y+1)}
= 1/2 (-3x+2-y+5y+5)
1/2(-3x+4y+7)
= 1/2 (-3x+4y+7) = 5
or, -3x+4y+7 = 10
or, 3x-4y+3 = 0
which is the locus of the point P(x,y).