InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 12851. |
For1le rlen,thevalueof""^(n)C_(r) +""^(n-1) C_(r) +""^(n-2)C_(r) + . . .+ ""^(r ) C _(r)is |
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Answer» `""^(N)C_r+1` |
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| 12853. |
Which one of the following releation is true regarding the angles of the quadrilateral shown in the figure? |
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Answer» `/_A = /_C` |
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| 12855. |
{:("Column A" , "The functons f(x,y) is defined for all","ColumnB"),(, "the geometric mean of x and y",),(, "(geometric mean of x and y equals)",),(, sqrt(xy)",and the function g(x,y)",),(,"defined as the least common",),(,"multiple of x and y.a and b are",),(, "two different prime numbers",),( f(a,b), ,f(a,b)):} |
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Answer» If column A is LARGER |
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| 12858. |
The side if an equilateral triangle are increasing at the rate of 4 cm/sec. the rate at which its areais increasing, when the side is 14 cm. |
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Answer» 1)`42cm^(2)//SEC` |
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| 12859. |
.......... is the probability of an event that there are 53 sundays in year 2019. |
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Answer» `(2)/(7)` |
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| 12860. |
Prove the inequalities : (a) n! lt ((n+1)/2)^(n) for a natural n gt 1: (b) 1/3 .3/4. 5/6 ......(2n-1)/(2n) lt (1)/sqrt(2n+1) |
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| 12861. |
The real value of n for which substitutor transform differential equation 2x^(2)y.Into a homogeneous equation |
| Answer» Answer :C | |
| 12863. |
Find all values of x, y and k for which the system of equations. sinx cos2y = k^(4)-2k^(2)+2 cosx sin2y=k+1 has a solution. |
| Answer» SOLUTION :`X = 2NPI +-pi/2, y= (NPI)/2` | |
| 12864. |
|bar(a)|=2,|bar(b)|=3 and bar(a) and bar(b) are perpendicular to each other. The area of the triangle with vertices bar(0),bar(a)+bar(b) and bar(a)-bar(b) is …………… |
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Answer» 5 |
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| 12865. |
The corner points of the bounded feasible region are (0, 0), (0, 8), (4, 10), (6, 8),(6, 5) and (5, 0). For the objective function z = 3x -4y ………(Maximum value of z + Minimum value of z) is equal to |
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Answer» 13 |
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| 12866. |
The sum of variance and mean of a binomial distribution for 10 trials is 7.5. Find thedistribution. |
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| 12867. |
If the operation oplusis defined bya oplus b = a^(2)+b^(2)for allreal numbers'a' and 'b' then (2 oplus 3) oplus 4 = __________ |
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Answer» 185 |
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| 12869. |
If a given line is tangent to the circle then perpendicular distance from centre of the circle is equal to radius of the circle solve the following : If 4l^(2)-5m^(2)+6l+1=0 then the director circle of the circle whose tangent is lx + my + 1 = 0 is |
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Answer» `X^(2)+y^(2)+6x-1=0` |
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| 12870. |
If a given line is tangent to the circle then perpendicular distance from centre of the circle is equal to radius of the circle solve the following : If 16m^(2)-8l-1=0 the equation fo circle whose tangent is lx + my +n=0 is |
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Answer» `X^(2)+y^(2)+8x=0` |
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| 12871. |
If x=(1)/(5)+(1.3)/(5.10)+(1.3.5)/(5.10.15)+….oo then find 3x^(2)+6x. |
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Answer» 1 |
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| 12872. |
C_1is a circle of radius 1 and touching both the axis . C_2 is another circle which touch both the axis and also circleC_1whose radius gt1 then radius of C_2 is |
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Answer» ` (3-2SQRT2) ` |
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| 12873. |
Write down negations of Fifteen is greater than five. |
| Answer» SOLUTION :FIFTEEN is not GREATER than FIVE. | |
| 12874. |
Using the method of integration find the area of the triangle ABC, coordinates of whose vertices are A(2,0),B(4,5)" and "C(6,3). |
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| 12875. |
int_(pi/4)^(pi/2) cot^(9)x dx= |
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Answer» `(-7)/(42)+1/2 LOG2` |
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| 12876. |
If u sin t+v cos t=5 and u cos t-v sin t=7, find the value of uvu v, where u,v denote the first and second derivatives of u with respect to t and v,u have sililar meanings. |
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| 12877. |
An urn contains 6 balls of which two are red and four are black. Two balls are drawn at random. Probability that they are of the different colours is : |
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Answer» (2/5) |
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| 12878. |
I= int ( x^(2) + 3x+ 5) cos 2x dx. |
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| 12879. |
Let f(x)=ax^(4)+bx^(3)+x^(2)+x-1. If 9b^(2) lt 24a, then number of real roots of f(x) = 0 are |
| Answer» Answer :B | |
| 12880. |
Express the value of sin "cos"^(-1) tan sec^(-1)sqrt2in simplest form. |
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Answer» Solution :`"SINCOS"^(-1) "tansec"^(-1) sqrt2` `"SIN cos"^(-1)"TAN" pi/4 ` ` "sin cos"^(-1)= "sin" 0=0` |
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| 12881. |
If the expression 1/2(x+c)(x-c), where c is a positive constant, can be rewritten as 1/2x^2-5, what is the value of c? |
| Answer» Answer :B | |
| 12882. |
Find the equation of the ellipse whose focus (-1,1) e=1/2 and directrix is x-y+3=0 |
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Answer» `(II) 7x^(2)-4xy+7y^(2)-26x+10y+10=0` |
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| 12883. |
Determine a binomial distribution whose mean is 9 and variance is 6. |
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| 12884. |
Integrate the following functions: (1-cosx)/(1+cosx) |
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Answer» SOLUTION :`(1-cosx)/(1+cosx) = (2 sin^2(x/2))/(2 cos^2(x/2))` = `tan^2(x/2) = sec^2(x/2)-1` THEREFORE` int(1-cosx)/(1+cosx) DX = (tanx/2)/(1/2)-x+c` `x+c-=2tan(x/2)` |
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| 12885. |
Which of thefollowingfunctionis non- differentiable ? |
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Answer» `f(x) =(e^(x)-1)|e^(2X)-1|"in" R` |
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| 12886. |
The moment about the point M(-2, 4, -6) of the force represented in magnitude and position AB, where the points A and B have the coordinates (1, 2, -3) and (3, -4, 2) respectively, is |
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Answer» `8hati-9hatj-14hatk` `= 2hati- 6 hatj +5hatk` MOMENT of FORCEF withrespectto M `=MAxxF ` ` :'MA =(1+2)hati+(2-4)hatj+(-3+6)hatk =3hati- 2hatj + 3 hatk` Now `,MA xxF =|{:(hati,hatj,hatk),(3,-2,3),(2,-6,5):}|` `=hati (-10+18)-hatj (15-6)+hatk(-18+4)` `=8 hati -9hatj -1hatk` |
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| 12887. |
If int(dx)/(sin x cos x)=log|f(x)|+C then |
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Answer» F(x) = SIN x + cos x |
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| 12888. |
Six horses take part in a race. In how many ways can these horses come in the first, second and third place, if a particular horse is among the three winners (Assume NO Ties)? |
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| 12889. |
If the equation ax^(2)+bx+c=0, a gt 0, has two distinct real roots alpha" and "beta such that alpha lt -5" and "beta gt 5, then |
| Answer» Answer :D | |
| 12890. |
Let R be a relation defined on the set of natural numbers N as follow : R= {(x,y):x in N,y in N and 2x+y=24} Find the domain and range of the relation R. Also, find R is an equivalence relation or not. |
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| 12891. |
Integration using rigonometric identities : int(1+cosx)/(sin xcos x)dx=....+c |
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Answer» `log|sinx|+log|cosx|` |
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| 12892. |
Evaluate : (i) int_(-pi//2)^(pi//2)sin^(2)xcos^(2)x(sinx+cosx)dx , (ii) int_(0)^(pi)xsin^(5)xdx (iii) int_(0)^(2)x^(3//2)sqrt(2-x)dx, (iv) int_(0)^(2pi)x(sin^(2)xcos^(2)x) |
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| 12893. |
intcos^-1xdx |
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Answer» SOLUTION :`intsox^-1x.dx` [Choose cos^-1x=1st and 1=2nd FUNCTION] =`cos^-1x.x-int(-1)/sqrt(1-xx^2) .XDX` =`xcos^-1x+int1/sqrt(1-xx^2) .xdx` [PUT `1-x^2=t^2` Then xdx=-tdt] =`xcos^-1x+int(-tdt)/t` `xcos^-1x-t+C` =`xcos^-1x-sqrt(1-x^2) +C` |
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| 12894. |
The value of k, if (1,2) (k,-1) are conjugate point with respect to the ellipse 2x^(2)+3y^(2)=6 is |
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Answer» 2 |
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| 12895. |
If A= {:((3a,2b),(-a,b)):}and B = {:((-a,b),(2a,2b)):}, then find a matrix X such that XA = B. |
| Answer» SOLUTION :`1/6{:((4,4,2),(11,8,-5),(10,10,2)):}` | |
| 12896. |
** is a binary operation on the set Q. a"*"b = (2a+b)/4 then find 2"*"3. |
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| 12897. |
An arch is in the shape of a parabola whose axis is vertically downwords and measures 24 mts across its boltom on the ground. Its highest point is 24 mts. The measure of the horizontal beam acrossits cross section at a height or 18 mts is |
| Answer» ANSWER :B | |
| 12898. |
If the radius of a sphere is measured as 9m with an error of 0.03m, then find the approximte error in calculating its surface area. |
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