InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 26851. |
Match the following. {:(I." If "(5x^(2)+2)/(x^(3)+x)=A/x+(Bx)/(x^(2)+1) " then "B=, "a) "2), (II." If "(4x)/(x^(2)-1)=A/(x-1)+B/(x+1) " then "A=, "b) "3), (III. " If "(3x+2)/(2-x-x^(2))=A/(2+x)+B/(1-x)" then "A=, "c) "-3//2), (IV." If "(2x+1)/((x-1)(x^(2)+1))=A/(x-1)+(Bx+C)/(x^(2)+1) " then "B=, "d) "-4//3):} |
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Answer» c, d, a, b |
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| 26852. |
Evaluate the following integrals int_1^2e^(4x+1)dx |
| Answer» SOLUTION :`int_1^2e^(4x+1)DX=[E^(4x+1)/4]_1^2=(1/4){e^9-e^5}` | |
| 26853. |
What is the maximum slope of the curve y=-x^(3)+3x^(2)+2x-27 ? Also find the point. |
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| 26854. |
int (1)/(sqrt(sin^(2) x cos^(2) x - sin^(4) x))dx= |
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Answer» `- cos^(-1)` (cot x ) + C |
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| 26855. |
What is the maximum value of the function sin x + cos x? |
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| 26856. |
Let x_(1), x_(2) be the roots of x^(2)-3x +a=0 and x_(3), x_(4) be the roots of x^(2)-12x+b=0. If x_(1) lt x_(2) lt x_(3) lt x_(4) and x_(1), x_(2), x_(3) , x_(4) are in G.P., then ab equals |
| Answer» Answer :B | |
| 26857. |
Show that the altitude of the right circular cone of maximum volume that can be inscribed in a sphere of radius r is 4r/3. Also, find maximum volume in terms of volume of the sphere. |
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| 26858. |
Evaluate(i) int(xe^(x))/((x+1)^(2))dx(ii) int x^3e^(-x) dx |
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| 26859. |
Show that * on R-{-1} defined by (a*b) =(a)/(b+1) is neither commutative nor associative |
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Answer» Solution :(i)` 2*3=(2)/(3+1)=2/4=1/2and 3*2=(3)/(2+1)=3/3=1` `therefore 2*3 NE 3*32` so * is not ocmmutative (II) `(2*3)*1=1/2*1=(1//2)/(1+1)=1/4` `(3*3)=(3)/(1+1)=3/2 ` `therefore 2*(3*1)=2*3/2=(2)/(3/2+1)=(2xx2/5)=4/5` Thus (2*3)*1 ne 2*(3*1) |
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| 26860. |
Expand :3sqrt(3) in ascending powers of (1)/(3) |
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| 26861. |
Which of the followingstatement(s) is/are incorrect ? |
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Answer» The lines`(x-4)/(-3)=(y+6)/(-1)=(z+6)/(-1) and (x-1)/(-1)=(y-2)/(-2)=(z-3)/(2)` are ORTHOGONAL |
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| 26862. |
A die marked 1,2,3 in red and 4,5,6 in green is tossed. Let A be the event "the number is even" and B be the event."the number is red".Are A and B are independent? |
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Answer» SOLUTION :S={1,2,3,4,5,6},A={2,4,6} and B={1,2,3}THEREFORE `AnnB`={2}`rArr` P`(AnnB)`=1/6 P(A) =3/6=1/2 and P(B) =3/6=1/2therefore P(A) P(B)=1/2xx1/2=1/4`ne` P`(AnnB)` Thus,A and B are not independent. |
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| 26863. |
Image of sphere x^(2)+y^(2)+z^(2)=9 in plane 2x+3y+4z-29=0 is |
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Answer» `X^(2)+y^(2)+Z^(2)-8x-12y-16z+107=0` |
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| 26864. |
Find the values of the following integrals int(sinhx+(1)/(sqrt(x^(2)-1)))dx,|x|gt1 |
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| 26865. |
Find the value of integral int_(0)^(t)int(|cos2x|+|sin2x|)dx,"where "npilttlt(npi+(pi)/(4)). |
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| 26866. |
If planes ax+by+cz+d=0 and a'x+b'y+c'z+d'=0 are perpendicular, then |
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Answer» `aa'+bb'+cc'+dd'=0` |
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| 26867. |
If alpha=5vec(i) -3vec(k) and beta= 2vec(i)-vec(j)+2vec(k) , then find the value of alpha . beta |
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| 26868. |
If y^(2) = ax^(2) + bx + c where a, b c are contants then y^(3)(d^(2)y)/(dx^(2))=? |
| Answer» Answer :A | |
| 26869. |
Let alpha != beta satisfy alpha^(2)+1=6alpha, beta^(2)+=6beta . Then, the quadraticequation whose roots are (alpha)/(alpha+1),(beta)/(beta+1) is |
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Answer» `8X^(2)+8x+1=0` |
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| 26870. |
Find the values of a and b such that the function defined by f(x)={{:(5," if "x le 2),(ax+b," if "2 lt x lt 10),(21," if "x ge 10):} is a continuous function. |
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Answer» `a=3, b=1` |
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| 26871. |
If the pole of a line w.r.t to the circle x^(2)+y^(2)=a^(2) lies on the circle x^(2)+y^(2)=a^(4) then the line touches the circle |
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Answer» `x^(2)+y^(2)=2` |
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| 26872. |
In a bank, principal increases continuously at the rate of 5% per year. An amount of Rs 1000 is deposited with this bank, how much will it worth after 10 years (e^(0.5) = 1.648). |
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| 26873. |
Obtain the following integrals : int (x)/(x^(4)-1)dx |
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| 26874. |
Solve the differential equation (x dy - y dx) y sin ((y)/(x)) = (y dx + x dy) x cos ((y)/(x)). |
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| 26875. |
Let 2 planes are being contained by the vectors alpha hati+3hatj-hatk, hati+(alpha-1)hatj+2hatk and 3hati+5hatj+2hatk. If the angle between these 2 planes is theta, then the value of cos^(2)theta is equal to |
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Answer» `(15)/(17)` |
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| 26876. |
A plano-convex lens (focal length f_2, refractive indexmu_(2), radius of curvature R) fits exactly into a plano-concave lens (focal lengthf_(1) refractive index mu_1, radius of curvature R). Their plane surfaces are parallel to each other. Then, the focal length of the combination will be : |
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Answer» `f_(1)-f_(2)` |
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| 26877. |
Solvethe equation 15x^3- 23x^2+ 9x-1=0 |
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| 26878. |
D, E and F are the mid points of the sides BC, CA and AB respectively of Delta ABC. 'O' is any point Match List-I to List-II. {:(,"List I",,"List II"),((I),"OA + OB + OC is equal to......",(a),OD + OE + OF),((II),"AD + BE + CF is equal to",(b),O),((III),OE + OF + "DO is",(c),OA),((IV),AD + (2)/(3)BE + (1)/(3)"CF equal",(d),(1)/(2)C):} The correct match is |
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Answer» `I RARR a, II rarr B, III rarr c, IV rarr d` |
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| 26879. |
A die is thrown. If E is the event the number appearing is a multiple of 3' and F be theevent the number appearing is even then |
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Answer» E and FARE mutally exclusive |
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| 26880. |
The total revenue in Rupees received from the sale of x units of a product is give by R(x)=13x^(2)+26x+15. Find the marginal revenue when x = 7. |
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| 26881. |
Find the vector equation of the plane vecr=hati-hatj+lambda(hati+hatj+hatk)+mu(hati-2hatj+3hatk) in scalar product form. Reduce it to normal form. |
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Answer» `vecr.((5)/(SQRT(38))HATI-(2)/(sqrt(38))HATJ-(3)/(sqrt(38))hatk)=(7)/(sqrt(38))` |
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| 26882. |
The solution of x cos. (y)/(x) (y dx + x dy) = y sin.(y)/(x) (x dy - y dx) is |
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Answer» `C xy Cos((2y)/(X)) = 1` |
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| 26883. |
Lets have first derivative at c such that f'(c) = 0 and f'(c) gt 0, AA x in (c- delta c), also f'(c)gt 0, AA x in (c,c+delta), then c is a point of |
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Answer» LOCAL maximum |
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| 26885. |
Let f(x) be a function which is differentiable any number of times and f(2x^(2)-1)=2x^(3)f(x), AA x in R. Then f^((2010))(0)= (Here f^((n))(x)=n^(th) order derivative of f at x) |
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Answer» `-1` `therefore""f(2x^(2)-1)=-2x^(3)f(-x)` `""2x^(3)f(x)=-2x^(3)f(-x)` `RARR""f(-x)=-f(x)` `therefore"f(x) or ODD function"` `therefore""f^((n))(0)=0`, when n is EVEN |
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| 26886. |
Let f(x) =x^(3)-3(7-a)X^(2)-3(9-a^(2))x+2 The values of parameter a if f(x) has points of extrema which are opposite in sign are |
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Answer» `pi` f(X)=`3x^(2)-6(7-a)x-3(9-a^(2))` for real root `Dge0` or `49+a^(2)-14a+9-a^(2)ge0 or ale58/14` when point of minma is negativepoint of maxima is also negative Hence EQUATION f(x) =`3xA^(2)-6(7-a)x-3(9-a^(2))` =0 has both roots negative sum or roots =`2(7-a)lta or a gt 7 ` which is not possible as form (1) `ale58/14` When pointof maxima is POSITIVE point of minima is also positive ltrbgt Hence equation `f(x) =3x6(2)-6(7-a)x-3(9-a^(2))=0` has both roots positive sum roots =`2(7-a)gt0 or alt7` Also product of roots is positive or `-(9-a^(2))gt0 or a^(32)gt9 or a in (-oo,-3)cup(3,oo)` From (1),(2) and (3) in `(-oo,-3)cup(3,58//14)` For points of extrema of opposite sign equation (1) has roots of opposite sign Thus `a in (-3,3). |
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| 26887. |
The reflection of the point (alpha,beta,gamma) in the xy - plane is .......... |
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Answer» `(ALPHA,BETA,0)` |
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| 26888. |
Iff(x) = x^(4) - 12x^(3) + 17x^(2) - 9x + 7then f(x + 3) = |
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Answer» `x^(4) - 37X^(2) - 123x +110 ` |
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| 26889. |
Consider the lines given by L_(1):x+3y-5=0 L_(2):3x-ky-1=0 L_(3):5x+2y-12=0 Match the following lists. |
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Answer» `L_(1): x+3y-5 = 0` `L_(2): 3x-ky-1 = 0` `L_(3): 5x+2y-12 = 0` `L_(1) " and " L_(3)` intersect at (2, 1) `therefore L_(1), L_(2), L_(3)` are concurrent if 6-k-1 = 0 or k=5 `"For " L_(1), L_(2)` to be parallel `(1)/(3) = (3)/(-k) RARR k = -9` `"For " L_(2), L_(3)` to be parallel `(3)/(5) = (-k)/(2) rArr k = (-6)/(5)` Thus, for k = 5, lines are concurrent and for `k = -9, (-6)/(5),` at least two lines are parallelk. So, for these values of k, lines will not FORM triangle. Obviously, for `k ne 5, -9, (-6)/(5),` lines form triangle. |
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| 26891. |
Out of 20 consecutive integers two are drawn at random. Then find the probability that the sum is even. |
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| 26892. |
Equations of tangents to the hyperbola 4x^(2)-3y^(2)=24 which makes an angle 30^(@) with y-axis are |
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Answer» `sqrt3x+y= pm SQRT10` |
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| 26893. |
Show that sqrt3" cosec "20^(@)-sec 20^(@)=4 |
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Answer» 4 |
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| 26894. |
Which of the following is NOT true e? |
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Answer» `{(PTOQ)^^(qtor)}to(ptor)` is a TAUTOLOGY |
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| 26895. |
If a + xb + yc = 0,a xx b + b xx c + c xx a = 6 (bxxc) then the locus of the point (x,y) is |
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Answer» `x^(2) + y^(2) = 1` |
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| 26896. |
The probability of a shooter hitting a target is (3)/(4). How many minimum number of times must "he" // "she" fire so that the probability of hitting the target at least once is more than 0.99? |
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| 26897. |
Iff: NtoN, f(x)= 2x +3then ……. |
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Answer» fisnotone -one |
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| 26898. |
Differentiate w.r.t x f (x) sin 3xsin^(3)x |
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Answer» SOLUTION :y = sin 3X ` sin ^(3) x` ` (dy)/(dx) = sin 3 x d/(dx) (sin^(3) x) + sin^(3) x d/(dx) (sin 3x)` = (sin 3x) ( ` 3 sin^(2) x . Cos x) + sin^(3) (3 cos 3x)` ` 3 sin^(2) x (sin 3x cos x + cos 3x sin x) ` ` 3 sin^(2) x sin 4X` |
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| 26899. |
The locus represented by xy + yz = 0 is ......... |
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Answer» A PAIR of PERPENDICULAR LINES |
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| 26900. |
If the two circles x^(2)+y^(2)+2gx+c=0 and x^(2)+y^(2)-2fy-c=0 have equal radius then locus of (g,f) is |
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Answer» `x^(2)+y^(2)=c^(2)` |
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