InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 3651. |
Prove that the following equations has no solutions. (i) sqrt((2x+7))+sqrt((x+4))=0 (ii) sqrt((x-4))=-5 (iii) sqrt((6-x))-sqrt((x-8))=2 (iv) sqrt(-2-x)=root(5)((x-7)) (v) sqrt(x)+sqrt((x+16))=3 (vi) 7sqrt(x)+8sqrt(-x)+15/(x^(3))=98 (vii) sqrt((x-3))-sqrt(x+9)=sqrt((x-1)) |
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Answer» Solution :(i) We have `sqrt((2x+7))+sqrt((x+4))=0` This equation is defined for `2x+7ge0` and `x+4ge0implies{(xge-7/2),(xge-4):"` `:.xge-7/2` For `xge-7/2` , the left hand SIDE of the original equation is positive, but right hand side is ZERO. Therefore, the equation has no roots. (ii) We have `sqrt(x-4))=-5` The equation is defined for `x-4ge0` `:.xge4` For `xge4`, the left hand side of the original equation is positive but right hand side is negative. Therefore, the equation has no roots. (iii) We have `sqrt((5-x))-sqrt(x-8)=2` The equation is defined for `6-xge0` and `x-8ge0` `:.{(xle6),(xge8):}` Consequently, there is no `x` for which both expressions WOULD have sense. Therefore, the equation has no roots. (iv) We have `sqrt((-2-x))=root(5)((x-7))` This equation is defined for `-2-xge0impliesxle-2` For `xle-2` the left hand side is positive, but right hand side is negative. Therefore, the equation has no roots. (v) We have `sqrt(x)+sqrt((x+16))=3` The equation isdefined for `xge0` and `x+16ge0implies{(xge0),(xge-16):}` Hence `xge0` For `xge0` the left hand side `GE4`, but right hand side is 3. Therefore, the equation has no roots. (vi) We have `7sqrt(x)+8sqrt(-x)+15/(x^(3))=98` For `xlt0` the expression `7sqrt(x)` is meaningless, For `xgt0`, the expressionn `8sqrt(-x)` is meaningles and for `x=0` the expression `15/(x^(3))` is meaningless. Consequently the left hand side of the original equation ils meaningless for any `x epsilonR`. Therefore the equation has no roots. (vii) We have `sqrt((x-3))-sqrt((x+9))=sqrt(x-1)` This equation is defined for `{(x-3ge0),(x+9ge0),(x-1ge0):}implies{(xge3),(xge-9),(xge1):}` Hence `xge3` For `xge3, sqrt(x-3)ltsqrt(x+9)` i.e. `sqrt((x-3))-sqrt((x+9))LT0` Hence for `xge3`,the left hand side of the original equation is negative and right hand side is positive. Therefore, the equation has no roots. |
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| 3653. |
Usingintegrationfind theareaof theregionboundedby thetrianglewhosevertices are (-1,1) , (0,5) and (2,3) |
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| 3654. |
If (1 + ax)^(n) = 1 + 6x + 27/2 x^(2) + ...... + a^(n)x^(n), then the values of a and n are respectively |
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Answer» 2,3 |
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| 3656. |
Let E and F be the events such that, P(E )=(1)/(3), P(F) = (1)/(4) and P(E cap F)=(1)/(5), find P((barF)/(barE)). |
| Answer» Solution :N/A | |
| 3657. |
Find the power of the point P w.r.t. the circle S =0 whenP(2,4)and S = x^(2) + y ^(2)- 4x - 6y -12 |
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| 3658. |
The value of sum_(r=1)^(n) (-1)^(r+1)(""^(n)C_(r))/(r+1) is equal to |
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Answer» `-1/(N+1)` `= 1/(n+1)(0-1+(n+1))= (n)/(n+1)` |
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| 3659. |
int(dx)/((x^(2)+a^(2))^(2)')(agt0) |
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| 3660. |
Find the value of k if the point (4,2)and (k,-3)are conjugate points with respect to the circles x^(2)+ y ^(2)-5x +8y +6=0 |
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| 3661. |
Expand the following (-9a/2+b)^7 |
| Answer» SOLUTION :`((-9A)/2+b)^7` = `((-9a)/2)^7+"^7C_1 ((-9a)/2)^(7-1) b^1+^7C_2 ((-9a)/2)^7-2b^2+ .... + b^7` | |
| 3662. |
An integrating factor of the differential equation (1-x^(2))(dy)/(dx)+xy=(x^(4))/((1+x^(5)))(sqrt(1-x^(2)))^(3) is |
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Answer» `SQRT(1-X^(2))` |
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| 3663. |
Five red marbles, four white marbles and three blue marbles of the same shape and size are placed in a row .Find the total number of possible arrangements. |
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Answer» Solution :5 red , 4 white and 3 blue marbles of the same SIZE and shape are PLACED in a row. `:.` The total number of marbles is 12 out of which 5 are of ONE kind, 4 are of 2nd kind and 3 are of 3rd kind. `:.`The total number of possible ARRANGEMENTS `=(12!)/(5!4!3!)=(12*11*10*9*8*7*6)/(4*3*2*3*2) `=12*11*10*3*7=27720` |
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| 3664. |
Find the equation of tangent to the curve given by x=a sin^(3)t, y=b cos^(3)t at a point where t=(pi)/(2). |
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| 3665. |
The sum of first n terms of the series 1 + (1 + x) y+ (1 + x + x^(2)) y^(2) + (1 + x + x^(2) + x^(3))y^(3) + ……….. is |
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Answer» `(1/(1 - X))[(1-y^(N))/(1 - y) - y ((1 - x^(n)y^(n))/(1 - XY))]` |
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| 3666. |
If int(e^(x)-1)/(e^(x)+1)dx = f(x)+c, then f(x) is equal to |
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Answer» `2log(E^(X)+1)` |
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| 3667. |
Tibu and Babu are playing a game in which both the players roll a pair of dice. Tibu wins if the sum of the numbers appearing on the dice is a prime number while Babu wins if the product of the numbers appearing on the dice is prime. The chance that no one wins is (both players are allowed to win simultaneously) |
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Answer» `(19)/(36)` |
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| 3668. |
Which of the following fractions is larger? 9//10""10//1 |
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| 3669. |
If a compound proposition obtained by combining two propositions p and q is false only when both p and q are false and true in all the other cases, then the compound proposition is |
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Answer» CONJUCTION |
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| 3670. |
Find all positive real numbers x, y, z such that: 2x-2y + 1/z = 1/(2014), 2y-2z + 1/x = 1/(2014), 2z-2x + 1/y = 1/(2014) |
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| 3671. |
Find the value of the integral underset(0)overset(pi)int sin^(3)dx cos^(6) x dx |
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| 3672. |
After somehow escaping from the previous castle, pangs of hunger grip him. Mario visits a chocolate store nearby where the shopkeeper has 9 jars filled with 4,2,6,7,3,4,5,8,3 jellyfishes respectively. Each second he is allowed to either double the content of one jar, or eat 9 jellyfishes (one from each jar). Can Mario always empty all the jars using these moves?If yes, then give the minimum time required to empty the jars ? (Answer 0 if no) |
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Answer» Solution : First note that a jar shall not become zero with other jars being nonzero.(Think !). Yes mario can always empty the jars. Basic idea is to reduce one from every jar until a jar contains only one, then double that jar and CONTINUE. This will ensure emptying, though notin minimum steps. For minimum steps we shall reduce the unnecessary steps. The method is to first double each jar until it reaches a number less than or equal to the highest number, then deduct all jars by one until a jar BECOMES one OR if a jar can again be doubled under above condition (note that this doubling will not add any extra work & infact reduce some.). Then check above rule after every deduction & double the necessaryjars. For eg, CONSIDER only 2 jars with 1 4 as initial counts. Then he shall follow these steps 1. Double the jar 1 (GIVES 2 4 ) 2. Double the jar 1 (gives 4 4 ) 3. Reduce both jars one by one `(3 3 gt 2 2 gt 1 1 gt 0 0 )` ( 4 times )Which gives 6as the minimum steps to empty the jars.eg 2: in the case 2 6 8, the number shall drop as follows (11 steps)2 6 8 gtgt 4 6 8 gtgt 8 6 8 (double each jar close to highest number)`8 6 8 gt 7 5 7 gt6 4 6 gt 5 3 5 gt4 2 4` (reduce all ONLY until there is a double possibleagain!)`4 2 4 gtgt 4 4 4 gt3 3 3gtgt2 2 2gtgt1 1 1gtgt0 0 0`(then follow same procedure)Now that you have an idea, the original question will be easy to answer. ![]() Which gives that minimum 19 steps are required for emptying the jars. |
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| 3673. |
Find a vector in the opposite direction of a vector -3hati+2sqrt(3)hatj-2hatk which has magnitude 20 units. |
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| 3674. |
Let A (0,0) and B(8,2) be two fixed points on the curve y^(3) =|x| A point C (abscissa is less than 0) starts moving from origin along the curve such that rate of change in the ordinate is 2 cm/sec. After t_(0) seconds, triangle ABC becomes a right triangle. After t_(0) secods, tangent is drawn to teh curve at point C to intersect it again at (alpha,beta). Then the value of 4alpha+3 beta is |
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Answer» `4/3` |
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| 3675. |
Find the number of non negative integral solutions of x_1+x_2+x_3+4x_4=20 |
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| 3676. |
Let A (0,0) and B(8,2) be two fixed points on the curve y^(3) =|x| A point C (abscissa is less than 0) starts moving from origin along the curve such that rate of change in the ordinate is 2 cm/sec. After t_(0) seconds, triangle ABC becomes a right triangle. The value of t_(0) is |
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Answer» 1 SEC |
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| 3677. |
If veca = (2,-2,1), vecb = (2,3,6) and vecc = (-1,0,2), Find the magnitude and direction of veca-vecb+2vecc. |
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Answer» Solution :`veca-vecb+2vecc = (2,-2,1) - (2,3,6) + 2(-1,0,2) = (2,-2,1) + (-2,-3,-6) + (-2,0,4) = (2-2,-2,-2-3+0, 1-6+4) = (-2, -5, -1) MAGNITUDE of `veca-vecb+2vecc = sqrt(4+25+1) = sqrt(30)` D. CS of `veca-vecb+2vecc` are `-2/sqrt(30), -5/sqrt(30), -1/sqrt(30)` |
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| 3678. |
The sum of the coefficients of odd powers of x in the expansion of (1+x-x^2+x^3)^5 is |
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Answer» 510 |
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| 3679. |
If for a particle position x prop t^(2) then :- |
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Answer» velocity is CONSTANT |
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| 3680. |
If A , B , C , D are four points in a straight line such that distance from A to B is 10 , B to C is 5 , C to D is 4 and A to D is 1, then their correct sequence is |
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Answer» `A - B - C - D ` |
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| 3682. |
intsqrt((x+1)/(x+2))dx= |
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Answer» `SQRT(x^2+3x+2)-(1)/(4)log|x+(3)/(2)+sqrt(x^2+3x+2)|+c` |
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| 3683. |
Box B_(1) contains 4 white and 6 black balls and box B_(2) contains 6 white and 4 black balls. Now one balanced coin is tossed. If two head comes up then 2 balls are drawn from box B_(1) other wise 2 white balls are drawn from Box B_(2). Then find probability of an event that selected both balls are of white colour. |
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Answer» `(19)/(60)` |
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| 3684. |
findthe area ofthe regionenclosedby theparabola x^2 =yand the lineliney=x +2. |
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| 3685. |
if a*b = 2a^2 + ab then 2*5 = |
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Answer» 19 |
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| 3686. |
From first 100 natural numbers five are selected at random. Find the probability that no two of them are consecutive |
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| 3687. |
If int(dx)/(x+x^(2011))=f(x)+C_(1) and int(x^(2009))/(1+x^(2010))dx=g(x)+C_(2)(where C_(1) and C_(2) are constants of integration). Let h(x)=f(x)+g(x). If h(1)=0 then h(e) is equal to : |
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| 3688. |
If A is invertible matrix of order 3xx3 then |A^(-1)|="........." |
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| 3689. |
If the tangents at and t_(1) and t_(2)= on y^(2)=4ax meets on its axis then |
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Answer» `t_(1)=t_(2)` |
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| 3691. |
From 1980 to 1990, the population of Mitannia increased by 6%. From 1990 to 2000, it decreased by 3%. What was the overall percentage change in the population of Mitannia from 1980 to 2000? |
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| 3692. |
int(dx)/((x+1)sqrt(x^2-2))= |
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Answer» `-SIN^(-1)((x+2)/(sqrt(2)(x+1)))+C` |
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| 3693. |
If the points P(a + 2b + c), Q(2a + 3b), R (b + tc) are collinear, where a, b and c are three non-coplanar vectors, the value of t is |
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Answer» `-2` P(a + 2b + c), Q (2a + 3b) and R(B + t c) are collinear. `therefore PQ = lambda QR" for some SCALAR "lambda` `implies a+b-c=lambda(-2a-2b+tc)` `implies (2lambda+1)a+(1+2lambda)b-(t lambda+1)c=0` `implies 2lambda+1=0, 2lambda+1=0, tlambda+1=0` [`because` a, b and c are non-coplanar] implies t = 2 |
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| 3694. |
Using Cofactors of elements of second row, evaluate Delta ={:|( 5,3,8),( 2,0,1),( 1,2,3) |:} |
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| 3695. |
If A = ((cos alpha , -sin alpha ),(sin alpha,cos alpha)) then : |
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Answer» A is symmetric MATRIX |
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| 3696. |
The value of lambda for which the vectors 3bar(i)-6bar(j)+bar(k) and 2bar(i)-4bar(j)+lambda bar(k) are parallel is ….. |
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Answer» `(2)/(3)` |
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| 3697. |
Using the property of determinants andd without expanding in following exercises 1 to 7 prove that |{:(1+a^2-b^2,2ab,-2b),(2ab,1-a^2+b^2,2a),(2b,-2a,1-a^2-b^2):}|=(1+a^2+b^2)^3 |
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| 3698. |
The numberof waysthat theChief ministerand the14ministersof ourstatecansitaroundtablefora conferenceso thatthechiefministercanoccupy thefixedseatis |
| Answer» Answer :B | |
| 3699. |
Find which of the following statements convey the same meanings? i . If it is the bride's dress then it has to be red. ii. If it is not bride's dress then it cannot be red. iii. If it is a red dress then it must be the bride's dress. iv. If it is not a red dress then it can't be the bride's dress |
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Answer» (i, IV) and (II, III) |
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| 3700. |
Find the odd one out in the following : |
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Answer» `VECA+vecb` |
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