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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 101. |
Write an algorthim to find the arithmetic mean (AM) of the given five numbers |
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| 104. |
Calcualte the C.I. on Rs 3,500 at 6% per annum for 3 years, the interest being compounded half-yearly. Do not use mathematical tables. Use the necessary information from the following: (1*06)^(3)=1*19106,(1*03)^(3)=1*092727 (1*06)^(6)=1*418519,(1*03)^(6)=1*194052 |
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| 106. |
Find the hypotenuses of an isosceles right triangle whose side is 6 cm. |
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| 107. |
The mid-value of a class-interval of a frequency distribution is x and its lower -boundary is y. Then its upper -boundary= |
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Answer» 2X |
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| 108. |
The volume of a right circular cone is 9856 cm^(3). If the diameter of the base is 28 cm, find (i) height of the cone, (ii) slant height of the cone and (iii) curved surface area of the cone. |
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Answer» (ii) 50 cm (III) 2200 `cm^(2)` |
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| 109. |
If 2sinx^(@)-1=0 and x^(@) is an acute angle, find: (i) bsinx^(@)"(ii) "x^(@)"(iii) "cosx^(@) and tanx^(@). |
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| 110. |
To find the antilog of 2.3246. |
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Answer» Solution :We have to locate 0.32 in the LEFT hand column and side ALONG the horizontal and pick out the number in the vertical column headed by 4. we see that the number is 2109. the MEAN difference for 6 in the same line is 3. The signifincant DIGITS in the REQUIRED number are = 2109 + 3 = 2112. As the characteristic is 2. the required antilog is 211.2. |
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| 111. |
A metal pipe is 77 cm .long .The inner diameter of a cross section is 4 cm. the outer diameter being 4.4 cm .Find its (i) inner curved surface area outer curved surface area Total surface area. |
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Answer» (II) `10648 cm ^(2) ` (iii) ` 2035.44 cm ^(2) ` |
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| 112. |
State whether the statements are True or False. (ii) All parallelograms are quadrilaterals |
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| 114. |
Find four different solutions of the equation x+2y = 6 |
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| 115. |
Find the magnitude of angle A, if : 2tan3Acos3A-tan3A+1=2cos3A |
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| 116. |
If tan(A+B)=sqrt(3) and sqrt(3)tan(A-B)=1, find the angles A and B,where A and B are Acute Angles. |
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| 118. |
Reena opened an account on 2-3-2006 by depositing Rs 8000 she deposits Rs 3000 on the 15th of every month and withdraws Rs 2000 on the 20th of every month .If she closed her account if the bank paid an interest of 4% per annum? (approx) |
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Answer» RS 15427 (III) similarly find the minimum balance of may june and julyalso find the sum of all the minumum balance form march to july (iv) CALCULATE SIMPLE interest on the above sum at 4% per annum for 5 months (v) use amount = principal + interest |
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| 119. |
Pipes X,Y and Z are fittedto a tank. Each of Y and Z can fill the tank in 6 hours. The efficiency of X, which is an emptying pipe, is half Y. if X is fitted at one fourth of the heighest from the base and one fourth of the heigth of tank from the base and all the pipes ar opened simultaneously, the tank be filled in __________ hours. |
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Answer» 4 If Y TAKES x hours to fill the tank, then X takes 2x hours to empty the full tank. (ii) First = `(1)/(4)` of the will be filled by Y and Z in 3 hous (iii) Remaining `((3)/(4))` of the tank will be FILLEDBY X,y and Z whereX will be emptying |
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| 120. |
Divide the polynomial 2x^4-4x^3-3x-1 by (x-1) and verify the remainder with zero of the divisor. |
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| 121. |
In the given figure, PR gt PQ and PS bisects angle QPR. Prove that angle PSR gt angle PSQ. |
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| 122. |
M, A and P are the mid-points of the sides DE, DF and EF of Delta DEF respectively. Which of the following statements is true ? |
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Answer» AR `(Delta MPF)=2" ar "(Delta DEF)` |
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| 128. |
Calculate the mean deviation about mean for the following data. {:("Class Interval",f),(""10-14,5),(""15-19,6),(""20-24,3),(""25-29,10),(""30-34,4),(""35-39,15),(""40-44,8),(""45-49,10):} |
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| 130. |
The measure of an angle is four times the measure of its complementary angle. Then, the measureof that angle is ............ |
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Answer» `18^(@)` |
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| 132. |
Construct a triangle PQR in which QR=4.7 cm PR-PQ=2.3 cm and angleQ-angleR=50^(@). |
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Answer» SOLUTION :Step 1: Draw line segment `QR = 4.7 cm`. Step 2: Draw `bar(QX)`, such that `angleRQX=1/2(angleQ-angleR)=25^(@)`. Step 3: With `R` as the center and the radius `= 2.3 cm`, draw an arc intersecting `bar(QX)` at A. Step 4: Join `RA` and produce `bar(RA)`. Step 5, Draw the perpendicular bisector of `QA` to INTERSECT `RA` produced at `P`. Step 6: Join `PQ.` `PQR` is the required triangle. 
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| 133. |
Factorise : 8x^(3) - 125y^(3) - 60x^(2)y + 150 xy^(2) |
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| 134. |
Draw the graph of the equation 2x+3y=6. From the graph, find the value of y, when (i) x=3/2 (ii) x=-3. |
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Answer» Solution :We have `2x+3y=6 rArr 3y = 6-2x rArry=(6-2x)/3.""` …(i) Putting`x=0 " in (i) , we get" y= (6-(2 xx 0))/3 = (6-0)/3 = 6/3 =2.` Putting `y=0 " in (i) , we get "(6-2x) = 3 xx 0 = 0 rArr 2x = 6 rArr x = 3.` Putting `x=6" in (i), we get "y=((6-2 xx6))/3= ((6-12))/3=(-6)/3=-2.` Thus, we have the following table: `{:(x,0,3," "6),(y,2,0,-2):}` On the graph paper, draw lines X'OX and YOY' as the x-axis andy-axis RESPECTIVELY. PLOT the points `A(0,2), B(3,0) and C(6,-2)`on this graph paper. JOIN AB and BC to get the line ABC.Extend it in both the directions to get the required graph.  (a) On the x-axis, take a point P such that`OP=x=3/2.` Draw `PD bot X'OX`, meeting the graph line at `D(3/2,1).` Thus, `(x=3/2 rArr y=1)`. Thus, when `x=3/2`, then y=1. (b) On the x-axis , take a point Q such that `OQ=x=-3.` Draw `QE bot X'OX` , meeting the graph line at `E(-3,4).` Thus,`(x=-3 rArr y=4)`, i.e., when x=-3, then y=4. |
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| 135. |
A sum of money is invested at 10% per annum compounded half-yearly. If the difference of amounts at the end of 6 months and 12 months is Rs 189, find the sum of money invested, |
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| 138. |
At the time of closing the account what amount did the bank pay her when interest was paid at 3% simple interest per annum? |
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Answer» RS 40550 |
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| 139. |
Find the value of : (sin30^(@)-sin90^(@)+2cos0^(@))/(tan30^(@) times tan60^(@)) |
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| 140. |
P and Q borrowed Rs 600 each for a period of 3 years. P paid simple interest at 25% per annum, interest being compounded annually. Who paid more interest and by how much? |
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Answer» <P> Solution :P paid an additional amount of INTEREST of Rs 13.20 than Q |
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| 141. |
The points scored by a Kabaddi team in a series of matches are as follows: 17, 2, 7, 27, 15, 5, 14, 8, 10, 24, 48, 10, 8, 7, 18, 28 Find the median of the points scored by the team. |
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| 143. |
Write (3a+4b + 5c)^(2) in expanded form. |
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| 145. |
Find the value of each of the following polynomials at the indicated value of variables : p(t) = 4t^(4) + 5t^(3) - t^(2) + 6 at t = a. |
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| 146. |
If a + b = sqrt13 and a - b = sqrt9, then the value of 4ab is |
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Answer» (B) `1/2 (AB + 1/(ab))` |
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| 147. |
In triangleABC, BC=10 cm and the length of altitude AD is 5 cm. Then , ar(ABC)=….. cm^2. |
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Answer» 50 |
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| 148. |
Find for solutions of each of the following equation : x - y = 5 |
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| 149. |
The relative humidity (in %) of a certain City for a September month of 30 days was as follows: (i) Construct a grouped frequency distribution table with classes 84-86, 86,-88 etc. (ii) What is the range of the data? |
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| 150. |
Prove that the median of Delta ABC divides it into two triangles of equal area. . |
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