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1.

Distinguish between analog communication and digital communication

Answer»
Analog communicationDigital communication
1. Analog signal is a signal having infinite number of values.1. Digital signal is represented by  finite set of discrete values.
2. It uses AM.FM,PAM, PWM types of modulation.2. It uses PCM.
3. Needs simple circuitry’.3. Needs complex circuitry.
4. It has low transmission speed and noise level.4. It has high transmission speed and low noise level.
5. Their bandwidth is less.5.  Their bandwidth is large.
6. Signal transmitted is analog.6.  Digital signals are coded using 1 and 0.
2.

What is digital communication?

Answer»

Digital communication is a mode of communication where the information is encoded digitally as discrete signals and electronically transferred to the recipients.

3.

What is the need for modulation?

Answer»

Modulation is needed

(i) to reduce length of antenna

(ii) to increase operating range

(iii) for wireless communication and

(iv) to reduce interference.

4.

Which is better for high sensitivity reception FM or AM?

Answer»

FM is better for high sensitivity reception.

5.

Mention different types of modulation.

Answer»

(i) Amplitude modulation.

(ii) Frequency modulation.

(iii) Phase modulation.

6.

What is SSB-SC?

Answer»

Single side band suppressed carrier.

7.

What is SSB-TC?

Answer»

Single side band transmitted carrier.

8.

Which is better for high fidelity reception FM or AM?

Answer»

Frequency modulation.

9.

What is angle modulation? Which are different types of angle modulation?

Answer»

In angle modulation, total angle φ = wct + θ of the carrier wave is varied. Different types of angle modulation are

(i) Frequency modulation.

(ii) Phase modulation.

10.

What are advantages of SSB system over conventional DSB system?

Answer»

(i) Power saving is 83.3%

(ii) Operating cost is less.

(iii) Reduced interference of noise.

(iv) Requires only small power supply.

11.

Define frequency deviation.

Answer»

Frequency deviation is the change in carrier frequency produced by the modulating signal from its centre frequency.

12.

State Carsons rule of FM bandwidth.

Answer»

According to Carsons rule, bandwidth is twice the sun of maximum frequency deviation and highest modulating frequency.

13.

What is the maximum permitted frequency deviation in FM?

Answer»

75 kHz is the maximum permitted frequency deviation in FM.

14.

Why is transmission of sideband important in AM?

Answer»

The sideband transmission is important in AM because it contains the information signal.

15.

Define deviation ratio.

Answer»

Deviation ratio is the ratio of maximum allowed frequency deviation to the maximum frequency of modulating signal.

16.

What is bandwidth of a FM station?

Answer»

Bandwidth of FM wave is defined as width of the frequency spectrum that contains all side frequency components having amplitude equal to or greater than one percent of the amplitude of the carrier.

17.

Define modulation index for an AM wave. What is its significance?

Answer»

Modulation index of AM wave is the ratio of amplitude of modulating signal (Vm) to the amplitude of the carrier wave (Vm) It indicates the depth of modulation.

18.

What are applications of AM?

Answer»

AM is used for broadcasting:

(i) Radio on long medium and short waves.

(ii) TV picture in ultra short waves.

(iii) Radio telephony on short waves.

19.

What are guard bands?

Answer»

Guard band is the range of frequencies added on either side of channel width to prevent interference between adjacent channels.

20.

Define carrier swing.

Answer»

Carrier swing is the total variation in frequency from minimum to maximum value.

21.

What are significant side bands?

Answer»

Significant side bands are the side bands having amplitude more than or equal to 1% of carrier amplitude.

22.

How many side bands are present in FM wave?

Answer»

Infinite side bands.

23.

Define transmission efficiency and state its relation with in.

Answer»

Transmission efficiency is the ratio of power contained in the side band to the total power.

Transmission efficiency,

\(\eta=\frac{m^2_a}{2+m^2_a}\)

24.

What is the power present in each side band in AM, when ma = 1

Answer»

The power in each side band in AM when ma= 1 is one sixth of total power of AM wave.

25.

Why is transmission of side bands important?

Answer»

As the side bands contain the required signal, their transmission is important.

\(m=\sqrt{m_1^2+m_2^2+m_3^2+.....M_n^2}\)

26.

Define efficiency of transmission.

Answer»

Transmission efficiency of an AM wave is the ratio of power contained in the side bands to the total power.

27.

The amplitude of signal and carrier of an AM wave are 4V and 6V respectively. Calculate the Vmin of AM wave.

Answer»

Vmin = Vc – maVm
= Vc  – Vm  (\(\therefore\) m = 1)
= 6 – 4
= 2V

28.

Calculate the modulation index if sinusoidal wave of peak value 4V is used to modulate the carrier of peak value of 5V.

Answer»

Modulation index,

= ma\(\frac{V_m}{V_c}=\frac{4}{5}=0.8\)

29.

What is total modulation index when a carrier wave is modulated by a number of sinewaves.

Answer»

Total modulation index.

30.

What are important considerations while selecting an IF of a radio receiver?

Answer»

(i) A lower value of IF improves selectivity’ but elimination of image frequency becomes difficult.

(ii) If IF is low, the selectivity becomes two sharp resulting in sideband cutting. Very high selectivity makes a receiver more difficult to tune oscillator circuits.

(iii) IF should not be too high because high IF leads to reduction in selectivity, gam sue adjacent channel rejection.

31.

Write a note on choice of local oscillator frequency.

Answer»

If the frequency of local oscillator is higher than the required signal frequency, then maximum to minimum capacitance ratio required by the variable capacitor is 4.4:1 But the tuning capacitors available commercially have a capacitance ratio of 10:1.

If the oscillator frequency is kept lower than the signal frequency, the maximum to minimum capacitance ratio required is 158:1. It is not practicable to make a tunable capacitance with this type of range. Hence the local oscillator frequency is made higher than the signal frequency in all AM receivers.

32.

Define selectivity.

Answer»

Selectivity is the ability of a radio receiver to distinguish between desired signal to which the receiver is tuned and the other signal frequencies.

33.

What is de-emphasis?

Answer»

De-emphasis is the process of attenuating the relative amplitude of high frequency components of the modulating signal.

34.

What is an envelop detector?

Answer»

Diode detector is also called envelop detector.

35.

Define demodulation.

Answer»

Demodulation is the process of recovering a modulating signal from the modulated wave.

36.

What is the purpose of limiter in an FM receiver?

Answer»

The limiter keeps IF amplifier output voltage constant.

37.

What are transmission lines?

Answer»

Transmission lines are the material structure used for transport of electrical signals or energy from one location to another far off destination.

38.

What ‘yagi’ stand for in yagi antenna.

Answer»

Yagi is used to describe type of antenna and is credited to famous Japanese antenna experts Yagi and Uda.

39.

What is the purpose of using transmission lines in communication?

Answer»

They are used for transport of electrical signals from one location to another far off destination.

40.

Briefly in explain Yagi antenna?

Answer»

Yagi antenna is called so in memory of Japanese antenna experts Yagi and Uda. It is an array of parallel, straight antenna elements.

41.

Write any two applications of Horn antennas.

Answer»

(i) Horn antennas are used as feeders for parabolic antennas.

(ii) They are active elements in dish antennas.

42.

Distinguish between loop antenna and horn antenna.

Answer»

Loop antenna is designed to receive radio signals more efficiently than horn antenna. The loop is wound on a form, which may be either box or spiral wound.

Horn antenna has a metal waveguide shaped like a horn to direct radio waves into beam. They are used at frequencies above 300 MHfc

43.

Show that the total power in AM is \(\frac{3}{2}\).

Answer»

Total power,

PT = Pc\((1+\frac{m^2_a}{2})\)

For ma = 1,

PT = Pc\((1+ \frac{1^2}{2})\)

PT\(\frac{3}{2}\)Pc.

∴ Total power in AM is \(\frac{3}{2}\)

44.

Determine the percent modulation of an AM wave whose total power content is 2500W and whose sidebands each contain 300W.

Answer»

PT = Pc + PLSB + PUSB

2500 = Pc + 300 + 300

Pc = 2500 - 600

Pc = 1900W

PT = Pc(1 + \(\frac{m_a^2}{2}\))

2500 = 1900[1 + \(\frac{m_a^2}{2}\)]

\(\frac{2500}{1900}\) = 1 + \(\frac{m_a^2}{2}\)

1.315 - 1 = \(\frac{m_a^2}{2}\)

\(m_a^2\) = 2(0.315) = 0.631

ma\(\sqrt{0.631}\)

ma = 0.794

= 0.794 x 100

= 79.4%

45.

Determine the power content of the carrier an each of side bands of an AM wave having a percent modulation of 80% and a total power of 2200W.

Answer»

ma = 80%

\(\frac{80}{100}\)

= 0.8

PT = 2200 W

PT = Pc(1 + \(\frac{m_a^2}{2}\))

2200 = Pc[1 + \(\frac{(0.8)^2}{2}\)]

2200 = Pc[1 + 0.32]

Pc\(\frac{2200}{1.32}\)

Pc = 1666W

PT = Pc + Power in the sidebands

Power in two sidebands = PT - Pc

= 2200 - 1666W

= 534W

Power in each sideband = \(\frac{534}{2}\)

= 267W

46.

Calculate the frequency deviation for an FM signal with a modulating frequency of 5kHz and modulation index of 0.5. in = 5kHz, m = 0.5

Answer»

fm = 5kHz,

m = 0.5

m = \(\frac{\Delta f}{f_m}\)

0.5 = \(\frac{\Delta f}{5}\)

Δf = 2.5kHz

47.

Determine modulation index of an FM carrier having a frequency deviation of 25 kHz and modulating signal of 5kHz. Also determine carrier swing.

Answer»

Δf = 25 kHz, fm = 5kH
m = \(\frac{\Delta f}{f_m}=\frac{25}{5}=5\)
Carrier swing, Cs = 2.Δf
= 2 x 25kHz
= 50 kHz

48.

Explain amplitude modulation. Derive the voltage equation of an AM wave.

Answer»

Let the instantaneous voltage of modulating signal be given by the expression Vm = Vm Sin ωt.
Let the instantaneous voltage of high frequency carrier be given by vc = Vsinωct. In amplitude modulation, amplitude of carrier varies proportional to instantaneous amplitude of modulating signal.
Hence amplitude of modulated signal is
A = Vc + Vm
= Vc + Vm sin ωmt
= Vc[1 + \(\frac{V_m}{V_c}\)sin ωmt]
= Vc[1 + ma Sin ωmt ]
The instantaneous value of amplitude modulated signal is
VAm = A Sin ωct
Vam - Vc[1 + ma Sinωmt] Sin ωct. where ma is called modulation index.