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1. The birds flying in the sky exhibit random motion.

2. The wings of the birds show oscillatory motion.

1. The cycle itself shows linear motion. 

2. The wheels of the cycle show circular motion. 

3. The cycle chain shows periodic motion, if the speed is uniform. 

4. The handle bar shows random motion.

1. Oscillatory 

2. Circular 

3. Periodic 

4. Uniform

5. Linear 

6. Random

(1) Oscillatory motion.

(2) random

(3) linear

(4) non-uniform linear

(5) linear

Here u = 0

         v = 600 meters

        t = 1 minute = 60 sec

a=\(\frac{v-u}{t}=\frac{600-0}{60}=\frac{600}{60}= 10\,m/sec^2\)

The acceleration of the bus is 10 m/sec².

 C) \(\cfrac{3h}4\)

 B) \(\cfrac{Total \,displacement}{Total\,time}\)

A body is said to have a non- uniform motion if it travels unequal distances in equal intervals of time, no matter how small these intervals may be.

Eg. A freely ball from a certain height covers unequal distances in equal intervals of time, so its motion is non-uniform.

Non uniform motion is also called accelerated motion.

A body is said to have a uniform motion if it travels equal distances in equal intervals of time, no matter how small these intervals may be.

Eg. A vehicle running at a constant speed of 10m/sec will cover equal distances of 10metres every second, so its motion will be uniform.

(a) Mass remains same it does not change 

So mass of boy 30 kg on earth = 30 kg on moon surface 

(b) Weight of boy on moon becomes 1 / 6 

∴ 30 kg boy will weight 30 x 1/6 = 5 kg 

1 kg = 10 N ⇒ 5 × 10 N = 50 N 

∴ Weight of boy on moon surface = 50 N

B) Instantaneous velocity

Correct option is D) Mass

The given quantity represents change of velocity per unit time that is acceleration and its magnitude is 10 m/s² .

False 

A quantity which can be completely specified by magnitude as well as direction is not a scalar quantity, but a vector quantity.

A vector quantity has both magnitude and direction. 

Examples can be displacement, velocity, etc.

Correct option is B) vector

We know that, 

 \(Displacement\propto\,time^3\) …….1 

Now, \(Velocity=\frac{Displacement}{Time}\) …….2 

From equations 1 and 2, we get, 

\(Velocity\propto\,time^2\) …….3 

Now, we also know that, \(Acceleration =\frac{Change\,in\,velocity}{Time}\) …….4 

From equations 3 and 4, we get,

  \(Acceleration\propto\,time\) 

Since, acceleration is directly proportional with time, so it increases with time. 

Hence option A is correct.

C) both A & B

(B) Uniform motion

(A) Is always positive

When a body returns to the same point where it is started, then the displacement is zero.

 Ex: A man starts from his home, goes to a market and returns home. Then his displacement is zero.

S.I. unit of displacement is m

The distance and the magnitude of displacement become equal when the body moves along a straight line in one direction.

(A) It is always positive.

i. vector

ii. instantaneous

iii. speed

iv. m/s² and cm/s²

v. acceleration

vi. zero

i. Sir Isaac Newton

ii. Energy

iii. F

iv. Joule, erg

v. Newton, dyne

i. vector

ii. velocity

iii. instantaneous

iv. acceleration

v. force

Initial velocity, u=?

Final velocity, v=0m/s (car is stopped)

Retardation, a=-2.5 m/s²

Time, t=10s

v=u + at

0=u +(-2.5)x 10

u=25m/s

Yes, acceleration and force both are vector quantities, because both can be expressed completely only when magnitude and direction are given and the quantity which needs direction and magnitude both is called a vector quantity.

Force (F) = 1000 N

displacement (s) = 10m

work done (W) = ?

W = Fs

= 1000 × 10

W = 10,000 Joule

The correct answer is c) acceleration

a) Distance and time 

b) Speed and time

The graph represents a straight line which means that the object is moving with uniform acceleration.

Acceleration = \(\frac{change\,in\,velocity}{chang\,in\,time}\) = \(\frac{10-7.5}{(20-15)\times60}\)= m/s²