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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The noble gases which do not form any clatherateA. HeB. NeC. KrD. Xe. |
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Answer» Correct Answer - A::B He and Ne due to their very small size do not form clathrates. |
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| 2. |
The noble gases which do not form any clatherateA. HeB. ArC. KrD. Xe. |
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Answer» Correct Answer - A Helium because of its Nuclear size. |
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| 3. |
Hybridization and shape of `XeF_(4)` isA. `sp^(3)d`, trigonal bipyramidalB. `sp^(3)`, tetrahedralC. `sp^(3)d^(2)`, square planarD. `sp^(3)d^(2)`, hexagonal. |
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Answer» Correct Answer - C In `XeF_(4)` No. of electrons around Xe = 8 + 4 = 12 No. of electrons pairs = 12/2 = 6 Hybridisation = `sp^(3)d^(2)` Bond pairs = 4 Lone pairs = 6 - 4 = 2 Therefore, `XeF_(4)` is square planar. |
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| 4. |
The state of hybridization of xenon in `XeF_(2)` isA. `sp^(3)`B. `sp^(2)`C. `sp^(3)d`D. `sp^(2)d` |
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Answer» Correct Answer - C In `XeF_(2)` Xe atom has 10(8 + 2) electrons around it. For `5(10//2)` pairs of electrons the hybridisation is `sp^(3)d`. |
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| 5. |
The shape of `XeF_(4)` molecule isA. square planarB. TetrahedralC. OctahedralD. trigonal planar. |
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Answer» Correct Answer - A Shape of `XeF_(4)` is square planar. |
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| 6. |
Hybridization and shape of `XeF_(4)` isA. `sp^(3)`B. `sp^(3)d`C. `sp^(2)`D. `sp^(3)d^(2)`. |
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Answer» Correct Answer - D In `XeF_(4)`. Xe is linked to four F atoms and there are two lone pairs around it. |
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| 7. |
The state of hybridization of xenon in `XeF_(2)` isA. `sp^(2)`B. `sp^(3)d`C. `sp^(2)`D. `sp^(3)d^(2)`. |
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Answer» Correct Answer - B In `XeF_(4)`, Xe is linked to two F atoms and there are three lone pairs around it. |
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| 8. |
Which of the following contains maximum number of pairs around Xe atom ?A. `XeF_(4)`B. `XeF_(6)`C. `XeOF_(2)`D. `XeF_(2)`. |
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Answer» Correct Answer - D In `XeF_(4), XeF_(6), XeOF_(2)` and `XeF_(2)`, the lone pairs around Xe are 2, 1, 2 and 3. |
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| 9. |
The shape of `XeF_(4)` molecule isA. Planar triangularB. TetrahedralC. Square pyramidalD. Square planar. |
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Answer» Correct Answer - D `XeF_(4)` is square planar. In `XeF_(4)`, Xe is in `sp^(3)d^(2)` hybrid state and there are two lone pairs around it. |
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| 10. |
In `XeF_(2)`, the three lone pairs occupyA. Three equatorial positionB. Two axial and one equatorial positionC. Two equatorial and one axial positionD. Three axial positions. |
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Answer» Correct Answer - A In `XeF_(2)`, the three lone pairs are present at the three equatorial positions of the trigonal bipyramid. |
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| 11. |
Xenon hexa fluoride reacts with potassium fluoride to yieldA. `[XeF_(5)]^(+)[KF_(2)]^(-)`B. `K^(+)[XeF_(7)]^(-)`C. `XeF_(4)`D. `[XeF_(4)]^(2+)[KF_(2)]^(3-)` |
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Answer» Correct Answer - B KF is a fluoride ion donor, hence it reacts with `XeF_(6)` to give a fluoroanion. `XeF_(6) + KF rarr K^(+) [XeF_(7)]^(-)` |
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| 12. |
The xenon fluoride which acts as a fluoride ion acceptor with RbF isA. `XeF_(2)`B. `XeF_(4)`C. `XeF_(6)`D. Both (A) and (B). |
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Answer» Correct Answer - C Only `XeF_(6)` acts as fluoride ion acceptor with alkali metal fluorides. |
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| 13. |
A clathrate may be defined as aA. Cage compoundB. Liquid crystalC. MixtureD. Solid solution. |
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Answer» Correct Answer - A A clathrate is a cage compound. |
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| 14. |
The state of hybridization of xenon of `XeF_(6)` isA. `sp^(3)d`B. `sp^(3)d^(2)`C. `sp^(3)d^(3)`D. `sp^(3)`. |
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Answer» Correct Answer - C In `XeF_(6)`, Xe is linked to six F atoms and there is one lone pair around it. |
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| 15. |
The shape of `XeF_(4)` molecule isA. Planar triangularB. Tetrahedral C. Square pyramidalD. Square planar. |
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Answer» Correct Answer - D `XeF_(4)` is square planar. In `XeF_(4)`, Xe is in `sp^(3)d^(2)` hybrid state and there are two lone pairs around it. |
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| 16. |
Xenon best reacts withA. most electropositive elementB. most electronegative elementC. hydrogen halidesD. alkali metals. |
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Answer» Correct Answer - B Xe has very little tendency to lose electrons. Hence, it reacts with most electronegative elements. |
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| 17. |
Assertion : He and Ne do no form any clathrates Reason : Both He and Ne are very small in sizeA. Both A and R are true and R is the correct explanation of AB. Both A and R are true but R is not a correct explanation AC. A is true but R is falseD. A is false but R is true |
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Answer» Correct Answer - A Both A and R are correct and R is the correct explanation of A. |
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| 18. |
In the clathrates of xenon with water , the nature of bonding between xenon and water molecule is _________.A. covalentB. Hydrogen bondingC. Co-ordinateD. Dipole-induced hipole interaction. |
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Answer» Correct Answer - D In clathrates the bonding between noble gas atom and water is dipole-induced dipole interaction. |
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| 19. |
Which of the following is not the correct uses of clathrates ?A. In the separating of isotopes of noble gasesB. In transporting of isotopes of noble gasesC. Kr-85 clathrate provide a useful source of `beta`-radiationsD. Clathrates compounds are used for producing compounds of noble gases. |
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Answer» Correct Answer - D All except (D) are uses of clathrates. |
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| 20. |
The molecular structure of noble gases areA. DiatomicB. MonoatomicC. TetraatomicD. Triatomic. |
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Answer» Correct Answer - B Noble gases exist as monoatomic gases. |
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| 21. |
Maximum number of compounds are formed byA. HeB. NeC. ArD. Xe. |
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Answer» Correct Answer - D Xenon forms maximum number of compounds due to its lowest ionisation energy. He, Ne and Ar do not form compounds. |
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| 22. |
On moving down the group from He to Rn the boiling points.A. increaseB. decreaseC. increase but irregularlyD. decrease but irregularly. |
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Answer» Correct Answer - A Increases due to increase in the van der Waal forces of attraction with the increase in the size and atomic weights. |
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| 23. |
The electron affinity of Noble gases isA. highB. lowC. zeroD. negative. |
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Answer» Correct Answer - C Zero because these have stable `ns^(2)np^(6)` electronic configuration so have no tendency to add electron. |
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| 24. |
`XeF_(6)` on hydrolysis givesA. `XeO_(4)`B. `XeOF_(2)`C. `XeOF_(4)`D. `XeO_(3)`. |
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Answer» Correct Answer - D `XeF_(6) + 3H_(2)O rarr XeO_(3) + 6HF`. |
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| 25. |
The oxidation state of Xe in `XeF_(6)` is |
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Answer» Correct Answer - C The oxidation state of Xe in `XeF_(6)` is + 6. |
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| 26. |
Which of the following is an explosive compound ?A. `XeF_(2)`B. `XeF_(4)`C. `XeO_(3)`D. `XeF_(3)`. |
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Answer» Correct Answer - C `XeO_(3)` is explosive. |
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| 27. |
Which of the following contains odd electron bond ?A. NOB. `NO_(2)`C. `ClO_(2)`D. All. |
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Answer» Correct Answer - D In these molecules, two atoms are linked with each other by means of a bond that has an odd number of electrons (generally three). Such bonds are called odd electron bonds, For example NO or `:overset(..)(N) = overset(..)(O):` |
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| 28. |
Which of the following does not existA. `PCl_(5)`B. `PF_(5)`C. `PBr_(5)`D. `PI_(7)`. |
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Answer» Correct Answer - D `PI_(7)` does not exist because seven large sized iodide ions cannot coordinate of phosphorus and phosphorus cannot have coordination number more than five. |
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| 29. |
Which of the following is an explosive compound ?A. `XeOF_(4)`B. `XeOF_(2)`C. `XeF_(2)`D. `XeO_(3)`. |
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Answer» Correct Answer - D `XeO_(3)` is an explosive compound and explodes violently when dry. |
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| 30. |
The most abundant noble gas in the atmosphere isA. XeB. KrC. ArD. He. |
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Answer» Correct Answer - C Argon is the most abundant noble gas (0.93 % by volume) in the atmosphere. |
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| 31. |
Which of the following noble gas is not present in atmosphere ?A. HeB. NeC. ArD. Rn. |
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Answer» Correct Answer - D Radon is not present in atmosphere. |
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| 32. |
Which of the following statements is not correct for a noble gas ?A. Ar is used in electric bulbs.B. Neon is obtained during radioactive disintegration.C. Half life of Rn is only 3-8 daysD. He is used in producing very low temperature. |
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Answer» Correct Answer - B Neon is not obtained during radioactive disintegration. |
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| 33. |
The noble gas was first time discovered byA. CavendishB. William RamsayC. LockyerD. Frankland. |
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Answer» Correct Answer - B The noble gas (Ar) was first time discovered by William Ramsay. |
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| 34. |
The noble gas which was discovered first in the sun and then on the earthA. ArgonB. XenonC. NeonD. Helium. |
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Answer» Correct Answer - D Helium was discovered in the sun and later on the earth. |
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| 35. |
Noble gases are adsorbed byA. Anhydrous calcium chlorideB. Ferric hydroxideC. Conc. `H_(2)SO_(4)`D. Activated coconut charcoal. |
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Answer» Correct Answer - D Activated coconut charcoal adsorbs noble gases (except helium). |
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| 36. |
Which of the following does not react with fluorine ?A. KrB. XeC. ArD. All of these. |
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Answer» Correct Answer - C Argon does not react with fluorine due to higher ionisation energy. |
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| 37. |
Which one of the following noble gases is not found in atmoshphere?A. NeB. RnC. ArD. Kr. |
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Answer» Correct Answer - B Rn is obtained artificially by the disintegration of radium. |
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| 38. |
The correct order of solubility in water for `He,Ne,Ar,Kr,Xe,` isA. `He gt Ne gt Ar gt Kr gt Xe`B. `Ne gt Ar gt Kr gt He gt Xe`C. `Xe gt Kr gt Ar gt Ne gt He`D. `Ar gt Ne gt He gt Kr Xe`. |
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Answer» Correct Answer - C Solubility of noble gases increases down the group. |
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| 39. |
`XeF_(2)` molecule isA. LinearB. Trigonal planarC. PyramidalD. Square planar. |
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Answer» Correct Answer - A `XeF_(2)` molecule is linear. |
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| 40. |
Which of the possible following florides of xenon is impossible ?A. `XeF_(2)`B. `XeF_(3)`C. `XeF_(4)`D. `XeF_(6)`. |
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Answer» Correct Answer - B Noble gases cannot show oxidation state of 3 hence `XeF_(3)` is not possible. Possible oxidation states for noble gases (except He and Ne) are 2, 4, 6 and 8. |
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| 41. |
The atomic mass of noble gases is determined with the help of the following relationshipA. Atomic mass = Equivalent mass `xx` valencyB. Atomic mass = Equivalent mass/valencyC. Atomic mass = `2 xx` Vapour density = Molecular massD. Atomic mass = Valency/Equivalent mass. |
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Answer» Correct Answer - C As noble gases, normally, do not react with other elements, their equivalent mass cannot be determined. However, their vapour density (i.e., the number of times a gas is heavier than hydrogen under similar conditions of temperature and pressure) can easily be determined. From this its atomic mass and hence its molecular mass (which will be equal to its atomic mass as these gases are always monoatomic) can be found out. |
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| 42. |
`XeF_(4)` and `XeF_(6)` are expected to beA. oxidizingB. reducingC. interactiveD. strongly basic. |
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Answer» Correct Answer - A `XeF_(4)` oxidizes `KI^(-)` , `XeF_(4) + 4I rarr 2I_(2) + 4F^(-) + Xe` `XeF_(6)` oxidizes hydrogen like other xenon fluorides. |
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| 43. |
A noble gas which is not absorbed by coconut charcoal isA. HeB. `N_(2)`C. ArD. Kr. |
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Answer» Correct Answer - A Helium is not adsorbed by coconut noble gases. Natural gas found in certain parts of America and Canada contains 2 to 7 % helium. At present most of the helium is obtained from this source. |
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| 44. |
The spectrum of `He` is expected to be similar to that ofA. HB. `Li^(+)`C. NaD. `He^(+)`. |
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Answer» Correct Answer - B The spectrum of helium will be similar to `Li^(+)` as both have two electrons each. |
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| 45. |
Neon gives a characteristic spectrum withA. Green linesB. Orange linesC. Red linesD. Yellow lines. |
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Answer» Correct Answer - D Yellow lines. |
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| 46. |
The electronic configuration of neon isA. `1s^(2)`B. `1s^(2)2s^(2)2p^(3)`C. `1s^(2)2s^(2)2p^(5)`D. `1s^(2)2s^(2)2p^(2)`. |
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Answer» Correct Answer - C Ne (Z = 10) : `1s^(2) 2s^(2) 2p^(6)`. |
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| 47. |
The elements which occupy the peaks of ionization energy curve areA. Na, K, Rb, CsB. Na, Mg, Cl, IC. Cl, Br, I, FD. He, Ne, Ar, Kr. |
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Answer» Correct Answer - D Noble gas (He, Ne, Ar, Kr) occupy peaks of ionisation energy curve i.e., these elements have highest ionisation energies in their respective periods. |
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| 48. |
Which of the following cannot be formed ?A. `He^(2+)`B. `He^(+)`C. `He`D. `He_(2)`. |
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Answer» Correct Answer - D `He_(2)` cannot be formed, because `He(1s^(2))` has no tendency to give, accept or share any electron. |
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| 49. |
`KClO_(3)` on warming with conc. HCl givesA. MedicineB. Bleaching agentC. Washing agentD. Desiccant |
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Answer» Correct Answer - B `3KClO_(3) + 4HCl rarr 2KCl + 2ClO_(2) + Cl_(2) + 2H_(2)O` euchlorine `(Cl_(2) + ClO_(2))`, a bleaching agent is formed. |
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| 50. |
Sea divers go deep in the sea water with a mixture of which of the following gasesA. `O_(2)` and HeB. `O_(2)` and ArC. `O_(2)` and `CO_(2)`D. `CO_(2)` and Ar. |
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Answer» Correct Answer - A Deep sea divers use a mixture of `O_(2)` and He for breathing. |
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