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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Determine the voltage gain for the given circuit known that R1 = R3 = 10kΩ abd R2 = R4 = 100kΩ.(a) 1(b) 10(c) 100(d) 1000This question was posed to me in semester exam.The doubt is from Difference Amplifiers in section Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The CORRECT OPTION is (B) 10 |
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| 2. |
The expression for the integration frequency is(a) CR(b) 1/CR(c) R/C(d) C/RI had been asked this question in semester exam.My question comes from Integrators and Differentiators in division Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Right OPTION is (b) 1/CR |
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| 3. |
For operation with 10-V output pulses with the requirement that the sum of the rise and fall times represent only 20% of the pulse width (at half amplitude), what is the slew-rate requirement for an op amp to handle pulses 2 µs wide? (Note: The rise and fall times of a pulse signal are usually measured between the 10%- and 90%-height points.)(a) 10 V/µs(b) 20 V/µs(c) 40 V/µs(d) 80 V/µsI had been asked this question during a job interview.Origin of the question is Large Signal Operations on operational Amplifiers topic in section Operational Amplifiers of Electronic Devices & Circuits |
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Answer» RIGHT answer is (c) 40 V/µs Best EXPLANATION: None. |
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| 4. |
For an ideal non-inverting operational amplifier having finite gain (A), the ratio of output voltage (v0) to input voltage (vi) is (given R2 is the feedback resistance)(a) (1+R2/R1)/(1+((1+R2/R1)/A))(b) (R2/R1)/(((1+R2/R1)/A))(c) (1+R2/R1)/(((1+R2/R1)/A))(d) (R2/R1)/(1+((1+R2/R1)/A))I got this question at a job interview.Asked question is from The Non Inverting Configuration topic in section Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Correct OPTION is (a) (1+R2/R1)/(1+((1+R2/R1)/A)) |
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| 5. |
For an ideal operational amplifier (except for the fact that it has finite gain) one set of the value for the input voltages (v2 is the positive terminal v1 is the negative terminal) and output voltage (v0) as determined experimentally is v1= 2.01V, v2=2.00V and v0= -0.99V. Experiment was carried with different values of input and output voltages. Which of the following is not possible considering experimental error?(a) v1= 1.99V, v2= 2.00V, v0 = 1.00V(b) v1= 1.00V, v2= 1.00V, v0 = 0V(c) v1= 1.00V, v2= 1.10V, v0 = 10.1V(d) v1= 0.99V, v2= 2.00V, v0 = 1.00VThis question was addressed to me during an online exam.My question is from The Ideal Operational Amplifiers in portion Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Right ANSWER is (d) V1= 0.99V, v2= 2.00V, V0 = 1.00V |
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| 6. |
The units of the full power bandwidth is(a) Watt(b) Joule(c) Seconds(d) HertzI have been asked this question during an interview.My question comes from Large Signal Operations on operational Amplifiers in portion Operational Amplifiers of Electronic Devices & Circuits |
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Answer» CORRECT OPTION is (d) Hertz The EXPLANATION: It has the UNITS of FREQUENCY. |
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| 7. |
In an ideal op amp the open-loop gain is 10^3. The op amp is used in a feedback circuit, and the voltages appearing at two of its three signal terminals are measured as v2 = 0V and v3 = 2V where it is assumed that v1 and v2 are input terminals and v3 is the output terminal. The value of the differential (vd) and common-mode (vcm)signal is(a) Vd = 2 mV and vcm = 1 mv(b) Vd = 2 mV and vcm = -1 mV(c) Vd = 2 mV and vcm = 2mV(d) Vd = 2 mV and vcm = -2mVThis question was posed to me during an online exam.Asked question is from The Ideal Operational Amplifiers in portion Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Correct answer is (b) Vd = 2 mV and VCM = -1 mV |
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| 8. |
An internally compensated op amp has a dc open-loop gain of 106 V/V and an AC open-loop gain of 40 dB at 10 kHz. Estimate its gain–bandwidth product and its expected gain at 1 kHz.(a) 0.1 MHz and -60 db(b) 10 MHz and -60 db(c) 10 MHz and 60 db(d) 1 MHz and 60 dbThe question was asked during an interview for a job.I want to ask this question from Effect of Finite Open-Loop gain and Bandwidth on Circuit Performance topic in section Operational Amplifiers of Electronic Devices & Circuits |
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Answer» RIGHT option is (d) 1 MHZ and 60 db Explanation: s: USE the FOLLOWING results. |
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| 9. |
The frequency transfer function of a differentiator is given by(a) jωCR(b) 1/jωCR(c) – jωCR(d) – 1/jωCRI had been asked this question in semester exam.My doubt stems from Integrators and Differentiators topic in section Operational Amplifiers of Electronic Devices & Circuits |
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Answer» RIGHT CHOICE is (a) jωCR Explanation: Standard mathematical expression for the TRANSFER function of a differentiator. |
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| 10. |
For the difference amplifier shown below, let all the resistors be 10kΩ ± x%. The expression for the worst-case common-mode gain is(a) x / 50(b) x / 100(c) 2x / (100 – x)(d) 2x / (100 + x)I had been asked this question in exam.My enquiry is from Difference Amplifiers in portion Operational Amplifiers of Electronic Devices & Circuits |
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Answer» CORRECT option is (d) 2X / (100 + x) The EXPLANATION is: NONE. |
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| 11. |
For an ideal negative feedback configuration which of the following is true?(a) There is a virtual open circuit between the input terminals(b) The closed loop gain for a negative feedback does not depend only on the external parameters(c) There is a virtual short circuit between the input terminals(d) There is a virtual ground at the negative input terminalThe question was posed to me by my school teacher while I was bunking the class.I want to ask this question from The Inverting Configuration in chapter Operational Amplifiers of Electronic Devices & Circuits |
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Answer» CORRECT option is (c) There is a virtual short circuit between the input terminals The explanation is: There is ALWAYS a virtual short circuit in this TYPE of CASE. There will be a virtual ground if and only if one of the terminals is grounded. |
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| 12. |
The full-power bandwidth, fM, is the maximum frequency at which(a) an output sinusoid with an amplitude equal to the op-amp rated output voltage (Vo max) can be produced without distortion(b) it is the range of the frequencies in which the amplitude of output signal is equal to or greater than half of the op-amp rated output voltage(c) it is the range of the frequencies in which the amplitude of output signal is equal to or less than half of the op-amp rated output voltage(d) It is the range of the frequencies in which the power gain is half or more than half of the maximum rated power gain of the op-ampI had been asked this question in a national level competition.Question is from Large Signal Operations on operational Amplifiers in section Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Right CHOICE is (a) an OUTPUT sinusoid with an amplitude equal to the op-amp rated output voltage (VO max) can be produced without distortion |
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| 13. |
Single-pole model is also known as(a) Frequent pole(b) Stable pole(c) Dominant pole(d) Responsive poleThe question was asked in exam.This key question is from Effect of Finite Open-Loop gain and Bandwidth on Circuit Performance in chapter Operational Amplifiers of Electronic Devices & Circuits |
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Answer» RIGHT choice is (c) Dominant pole The BEST EXPLANATION: Single-pole MODEL is ALSO called dominant pole. |
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| 14. |
The circuit is to operate at a constant temperature?(a) 8.5 mV(b) 9 mV(c) 9.5 mV(d) 10 mVThis question was posed to me during an interview for a job.My enquiry is from DC Imperfections in Operational Amplifiers topic in division Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Right option is (d) 10 mV |
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| 15. |
Which of the following is not true for a voltage follower amplifier?(a) Input voltage is equal to output voltage(b) Input resistance is infinite and output resistance is zero(c) It has 100% negative feedback(d) None of the mentionedThe question was asked in an international level competition.This interesting question is from The Non Inverting Configuration in section Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Right option is (d) NONE of the mentioned |
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| 16. |
One of the DC imperfections of the amplifiers are dc offset voltage which is(a) Existence of output signal even when the common mode signal is zero(b) Existence of common mode signal causing zero output signal(c) Existence of output signal even when the differential signal is zero(d) Existence of differential signal causing zero output signalI got this question in an internship interview.I want to ask this question from DC Imperfections in Operational Amplifiers topic in portion Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Right option is (c) EXISTENCE of output SIGNAL EVEN when the differential signal is zero |
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| 17. |
For the difference amplifier as shown in the figure show that if each resistor has a tolerance of ±100 ε % (i.e., for, say, a 5% resistor, ε = 0.05) then the worst-case CMRR is given approximately by (given K = R2/R1 = R4/R3)(a) 20 log [K+1/4ε].(b) 20 log [K+1/2ε].(c) 20 log [K+1/ε].(d) 20 log [2K+2/ε].The question was posed to me in an international level competition.My question is taken from Difference Amplifiers topic in section Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The CORRECT OPTION is (a) 20 log [K+1/4ε]. |
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| 18. |
Slew rate of an amplifier is defined as(a) Minimum rate of change of the output possible in a real operational amplifier(b) Maximum rate of change of the output possible in a real operational amplifier(c) Average rate of change of the output possible in a real operational amplifier(d) Ratio of the maximum and the average rate of change of the output in a real amplifierThe question was asked in class test.This interesting question is from Large Signal Operations on operational Amplifiers in chapter Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Correct OPTION is (b) Maximum RATE of change of the OUTPUT possible in a real operational amplifier |
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| 19. |
The slope of the frequency response of a differentiator is(a) Linear with negative slope(b) Linear with positive slope(c) Exponential increase(d) Exponential decreaseI have been asked this question in an international level competition.My question comes from Integrators and Differentiators topic in portion Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The correct answer is (b) Linear with POSITIVE slope |
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| 20. |
For ideal non-inverting operational amplifier(a) Input and output resistances are infinite(b) Input resistance is infinite and output resistance is zero(c) Input resistance is zero and output resistance is infinite(d) Input and output resistances are zeroThe question was asked during an online interview.This interesting question is from The Non Inverting Configuration topic in portion Operational Amplifiers of Electronic Devices & Circuits |
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Answer» CORRECT answer is (b) Input resistance is infinite and output resistance is zero The best I can explain: It is an ideal CHARACTERISTIC of the non-inverting op AMP. |
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| 21. |
What are the units of slew rate?(a) Second/Volt(b) Volt/second(c) It is a ratio, no units(d) Ohm/secondThis question was posed to me in an international level competition.I'd like to ask this question from The Ideal Operational Amplifiers in division Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The correct answer is (B) Volt/second |
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| 22. |
The following is a circuit of weighted summer capable of summing coefficients of both sign. The expressions for the output voltage v0 is(a) v0 = v1 (R1/Ra ) (Rc/Rb ) + v1 (Ra/R2 ) (Rc/Rb ) – v1 (Rc/R3 ) – v1 (Rc/R4 )(b) v0 = – v1 (R1/Ra ) (Rc/Rb ) – v1 (Ra/R2 ) (Rc/Rb ) + v1 (Rc/R3 ) + v1 (Rc/R4 )(c) v0 = v1 (Ra/R1 ) (Rc/Rb ) + v1 (Ra/R2 ) (Rc/Rb ) – v1 (Rc/R3 ) – v1 (Rc/R4 )(d) v0 = – v1 (Ra/R1 ) (Rc/Rb ) – v1 (Ra/R2 ) (Rc/Rb ) + v1 (Rc/R3 ) + v1 (Rc/R4 )I have been asked this question in a job interview.My doubt is from The Inverting Configuration topic in portion Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The correct answer is (c) v0 = v1 (Ra/R1 ) (Rc/Rb ) + v1 (Ra/R2 ) (Rc/Rb ) – v1 (Rc/R3 ) – v1 (Rc/R4 ) |
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| 23. |
A particular op amp using ±15-V supplies operates linearly for outputs in the range −12 V to +12 V. If used in an inverting amplifier configuration of gain –100, what is the rms value of the largest possible sine wave that can be applied at the input without output clipping?(a) 120 mV(b) 60 mV(c) 84.85 mV(d) 42.42 mVI had been asked this question in class test.This interesting question is from Large Signal Operations on operational Amplifiers in chapter Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The correct ANSWER is (c) 84.85 mV |
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| 24. |
An op amp having a slew rate of 20 V/µs is to be used in the unity-gain follower configuration, with input pulses that rise from 0 to 3 V. What is the shortest pulse that can be used while ensuring full-amplitude output?(a) 0.10 µs(b) 0.15 µs(c) 0.20 µs(d) 0.30 µsThe question was posed to me at a job interview.My question is based upon Large Signal Operations on operational Amplifiers topic in section Operational Amplifiers of Electronic Devices & Circuits |
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| 25. |
Consider an inverting amplifier with a nominal gain of 1000 constructed from an op amp with an input offset voltage of 3 mV and with output saturation levels of ±10 V. What is (approximately) the peak sine-wave input signal that can be applied without output clipping?(a) 7 mV(b) 10 mV(c) 13 mV(d) 9mVI had been asked this question in quiz.Origin of the question is DC Imperfections in Operational Amplifiers topic in portion Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The correct choice is (a) 7 mV |
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| 26. |
Find the ft required for internally compensated op amps to be used in the implementation of the closed loop amplifiers with dc gain of +100 V/V and 3db bandwidth of 100kHz?(a) 1 kHz(b) 10 kHz(c) 100 kHz(d) 1 MHzThis question was addressed to me by my school teacher while I was bunking the class.My question is taken from Effect of Finite Open-Loop gain and Bandwidth on Circuit Performance in portion Operational Amplifiers of Electronic Devices & Circuits |
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Answer» CORRECT choice is (b) 10 kHz For EXPLANATION I would say: NONE |
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| 27. |
The expression for the differentiator time constant is(a) CR(b) 1/CR(c) R/C(d) C/RI had been asked this question during an interview.My question is from Integrators and Differentiators topic in division Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The correct OPTION is (a) CR |
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| 28. |
The integrating transfer function has the value of(a) jωCR(b) –jωCR(c) 1 / jωCR(d) -1 / jωCRThis question was posed to me in an interview for internship.I'd like to ask this question from Integrators and Differentiators topic in portion Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Correct option is (d) -1 / jωCR |
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| 29. |
An op amp having a 106-dB gain at dc and a single-pole frequency response with ft= 2 MHz is used to design a non-inverting amplifier with nominal dc gain of 100. The 3-dB frequency of the closed-loop gain is(a) 10 kHz(b) 20 kHz(c) 30 kHz(d) 40 kHzI have been asked this question by my school teacher while I was bunking the class.My question is from Effect of Finite Open-Loop gain and Bandwidth on Circuit Performance topic in division Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The CORRECT answer is (b) 20 kHz |
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| 30. |
If Vi = 0.5 V, what is the maximum frequency before the output distorts?(a) 31.8 kHz(b) 318 kHz(c) 3.18 kHz(d) 3.18 MHzThe question was asked in final exam.Query is from Large Signal Operations on operational Amplifiers in portion Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The correct option is (a) 31.8 KHZ |
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| 31. |
The circuit is to operate at a temperature in the range 0°C to 75°C and the temperature coefficient of VOS is 10 μV/°C?(a) 8.5 mV(b) 9 mV(c) 9.5 mV(d) 10 mVI got this question during an internship interview.This question is from DC Imperfections in Operational Amplifiers topic in portion Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Right OPTION is (c) 9.5 mV |
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| 32. |
Operational amplifiers are(a) Differential input and single-ended output type amplifier(b) Single-ended input and single-ended output type amplifier(c) Single-ended input and differential output type amplifier(d) Differential input and differential output type amplifierI had been asked this question during an online interview.This is a very interesting question from The Ideal Operational Amplifiers topic in chapter Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Right option is (a) Differential input and single-ended output TYPE amplifier |
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| 33. |
Consider the figure given below. Known that vo = 4V and vi = 2V, determine the gain for the op amp assuming that it is ideal except for the fact that it has finite gain(a) 1001(b) 2002(c) 3003(d) 4004The question was posed to me in a job interview.My query is from The Ideal Operational Amplifiers in portion Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The CORRECT answer is (b) 2002 |
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| 34. |
An internally compensated op amp is specified to have an open-loop dc gain of 106 dB and a unity gain bandwidth of 3 MHz. Find fb and the open-loop gain at fb.(a) 15Hz and 103 db(b) 30Hz and 103 db(c) 15 Hz and 51.5 db(d) 30 Hz and 51.5 dbThe question was asked in an international level competition.My doubt stems from Effect of Finite Open-Loop gain and Bandwidth on Circuit Performance topic in chapter Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Correct option is (a) 15HZ and 103 db |
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| 35. |
Select the largest possible value for a feedback resistor RF so that at least ±10 V of output signal swing remains available.(a) 10 kΩ(b) 100 kΩ(c) 1 MΩ(d) 10 MΩThis question was addressed to me in unit test.My doubt is from DC Imperfections in Operational Amplifiers in portion Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The correct OPTION is (d) 10 MΩ |
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| 36. |
Consider the circuit shown below which reduces the impact of the input bias current. If IB1 = IB2 = Input bias current, then determine the value of R3 so that the output voltage (v0) is not impacted by the input bias current.(a) (R1 R2)/(R1+R2)(b) (R1 R2)/(R1-R2)(c) R1-(R1 R2)/(R1+R2)(d) R2-(R1 R2)/(R1+R2)The question was posed to me in my homework.I would like to ask this question from DC Imperfections in Operational Amplifiers topic in section Operational Amplifiers of Electronic Devices & Circuits |
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| 37. |
The effect of the inverting configuration is(a) The output signal and the input signal are out of phase by 180^o(b) The output signal and the input signal are in phase(c) The output phase is leading the input phase by 90^o(d) The output phase is lagging behind the input phase by 90^oThis question was addressed to me in final exam.This interesting question is from The Inverting Configuration in section Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The CORRECT choice is (a) The output signal and the input signal are out of phase by 180^o |
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| 38. |
The gain for an ideal non-inverting operational amplifier is (given R2 is the feedback resistance)(a) R2/R1 – 1(b) R2/R1(c) -R2/R1(d) R2/R1 + 1The question was asked during an interview for a job.The question is from The Non Inverting Configuration topic in section Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The CORRECT CHOICE is (d) R2/R1 + 1 |
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| 39. |
For the difference amplifier which of the following is true?(a) It responds to the difference between the two signals and rejects the signal that are common to both the signal(b) It responds to the signal that are common to the two inputs only(c) It has a low value of input resistance(d) The efficacy of the amplifier is measured by the degree of its differential signal to the preference of the common mode signalI got this question in an international level competition.My question is from Difference Amplifiers topic in chapter Operational Amplifiers of Electronic Devices & Circuits |
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Answer» CORRECT CHOICE is (a) It responds to the difference between the TWO signals and REJECTS the signal that are common to both the signal The best explanation: All the STATEMENTS are not true except for the fact that it responds only when there is difference between two signals only. |
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| 40. |
What is the minimum number of pins for a dual operational amplifier IC package?(a) 4(b) 6(c) 8(d) 10The question was asked in an international level competition.My query is from The Ideal Operational Amplifiers in section Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The CORRECT ANSWER is (c) 8 |
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| 41. |
Which of the following is not a terminal for the operational amplifier?(a) Inverting terminal(b) Non-inverting terminal(c) Output terminal(d) None of the mentionedThe question was posed to me during an interview.My query is from The Ideal Operational Amplifiers in chapter Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The correct option is (d) NONE of the mentioned |
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| 42. |
Find the ftrequired for internally compensated op amps to be used in the implementation of the closed loop amplifiers with dc gain of -2 V/V and 3db bandwidth of 10 MHz?(a) 7.5 MHz(b) 15 MHz(c) 22.5 MHz(d) 30 MHzThis question was posed to me in quiz.My doubt is from Effect of Finite Open-Loop gain and Bandwidth on Circuit Performance in division Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The CORRECT option is (d) 30 MHz |
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| 43. |
Which of the following is not limitation of the operational amplifier(a) Output voltage saturation(b) Output current limits(c) Slew rate(d) None of the mentionedI got this question in an interview for job.I'd like to ask this question from Large Signal Operations on operational Amplifiers topic in chapter Operational Amplifiers of Electronic Devices & Circuits |
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Answer» CORRECT answer is (d) NONE of the MENTIONED The explanation: None of the mentioned are the limitations of the operational AMPLIFIER. |
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| 44. |
Determine Ad and Ac for the given circuit.(a) Ac = 0 and Ad = 1(b) Ac ≠ 0 and Ad = 1(c) Ac = 0 and Ad ≠ 1(d) Ac ≠ 0 and Ad ≠ 1The question was posed to me in an interview for internship.My question is from Difference Amplifiers in chapter Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Right choice is (a) Ac = 0 and Ad = 1 |
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| 45. |
For the circuit shown below express v0 as a function of v1 and v2.(a) v0 = v1 + v2(b) v0 = v2 –v1(c) v0 = v1 –v2(d) v0 =-v1 – v2I had been asked this question during a job interview.This is a very interesting question from Difference Amplifiers in chapter Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The correct ANSWER is (b) V0 = v2 –v1 |
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| 46. |
The finite voltage gain of a non-inverting operational amplifier is A and the resistance used is R1 and R2 in which R2 is the feedback resistance. Under what conditions it can one use the expression 1 + R2/R1to determine the gain of the amplifier?(a) A ~ R2/R1(b) A >> R2/R1(c) A |
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Answer» Correct choice is (b) A >> R2/R1 |
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| 47. |
While performing an experiment to determine the gain for an ideal operational amplifier having finite gain, a student mistakenly used the equation 1 + R2/R1 where R2 is the feedback resistance. What is the percentage error in his result? Given A is the finite voltage gain of the ideal amplifier used.(a) (R2/R1)/(A+ R2/R1) X 100%(b) (1+R2/R1)/(A+R2/R1) X 100%(c) (1+R2/R1)/(A+1+R2/R1) X 100%(d) (R2/R1)/(A+1+R2/R1) X 100%This question was addressed to me in an interview.This intriguing question originated from The Non Inverting Configuration in division Operational Amplifiers of Electronic Devices & Circuits |
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Answer» RIGHT option is (c) (1+R2/R1)/(A+1+R2/R1) X 100% Easiest explanation: The correct FORMULA is (1+R2/R1)/(1+((1+R2/R1)/A)). |
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| 48. |
The advantage of a weighted summer operational amplifier is(a) It is capable of summing various input voltages together(b) Each input signal may be independently adjusted by adjusting the corresponding input resistance(c) If one needs both sign of a voltage signal then two operational amplifiers are needed(d) All of the mentionedThe question was asked by my college professor while I was bunking the class.This interesting question is from The Inverting Configuration topic in chapter Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Correct ANSWER is (d) All of the MENTIONED |
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| 49. |
Which of the following is not a property of an ideal operational amplifier?(a) Zero input impedance(b) Infinite bandwidth(c) Infinite open loop gain(d) Zero common-mode gain or conversely infinite common mode-rejection.The question was asked by my school teacher while I was bunking the class.Origin of the question is The Ideal Operational Amplifiers in chapter Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Correct CHOICE is (a) Zero INPUT impedance |
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| 50. |
Express the input voltages v1 and v2 in terms of differential input (vd) and common-mode input(vc). Given v2 > v2.(a) Vd = V1 – V2, Vc = 0.5(V1 + V2)(b) Vd = V2 – V1, Vc = V1 + V2(c) Vd = V1 – V2, Vc = V1 + V2(d) Vd = V2 – V1, Vc = 0.5(V1 + V2)The question was posed to me by my college director while I was bunking the class.My question is taken from The Ideal Operational Amplifiers in portion Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Correct choice is (d) VD = V2 – V1, VC = 0.5(V1 + V2) |
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