InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 51. |
If f = 20 kHz, what is the maximum value of Vi before the output distorts?(a) 0.397 V(b) 0.795 V(c) 1.192 V(d) 1.590 VThis question was addressed to me in an online interview.Query is from Large Signal Operations on operational Amplifiers in section Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The correct ANSWER is (b) 0.795 V |
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| 52. |
Determine the slew rate of the amplifier having full power bandwidth f0 and the rated output voltage as V0. Given that the input signal is of sinusoidal nature.(a) 2πf0V0(b) V0 / 2πf0(c) V0 / f0(d) f0 V0I have been asked this question during an online exam.Origin of the question is Large Signal Operations on operational Amplifiers topic in portion Operational Amplifiers of Electronic Devices & Circuits |
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Answer» CORRECT answer is (a) 2πf0V0 The explanation: V = V0sin wt dv/dt = wV0 sin wt max value of dv/dt = wV0 max value of w = W0 = 2πf0 w0 V0 = Slew RATE = 2πf0 V0. |
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| 53. |
Determine the expression for the transfer function for the circuit shown below.(a) (Rf/R)/(1+jωCRfC)(b) (Rf/R)/(1-jωCRfC)(c) –(Rf/R)/(1+jωCRfC)(d) –(Rf/R)/(1-jωCRfC)This question was addressed to me during a job interview.The query is from Integrators and Differentiators in portion Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Correct option is (c) –(Rf/R)/(1+jωCRfC) |
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| 54. |
It is required to connect a transducer having an open-circuit voltage of 1 V and a source resistance of 1 MΩ to a load of 1-kΩ resistance. Find the load voltage if the connection is done (a) directly and (b) through a unity-gain voltage follower.(a) 1 μV and 1 mV respectively(b) 1 mV and 1 V respectively(c) 0.1 μV and 0.1 mV respectively(d) 0.1 mV and 0.1 V respectivelyI got this question in semester exam.My doubt stems from The Non Inverting Configuration topic in chapter Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Correct choice is (B) 1 mV and 1 V respectively |
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| 55. |
You are provided with an ideal op amp and three 10kΩ resistors. Using series and parallel resistor combinations, how many different inverting-amplifier circuit topologies are possible?(a) 2(b) 3(c) 4(d) 5The question was asked by my school principal while I was bunking the class.I'd like to ask this question from The Inverting Configuration in chapter Operational Amplifiers of Electronic Devices & Circuits |
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Answer» RIGHT option is (c) 4 Best explanation: Consider series and PARALLEL combination of the RESISTANCES provided and ARRANGE then in the feedback region and as output resistance. |
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| 56. |
When does a resistance provide a negative feedback to an amplifier?(a) Resistance is connected between the positive input terminal and the output terminal(b) Resistance is connected between the negative input terminal and the output terminal(c) Resistance is connected betweenthe input terminals(d) Resistance is connected between the negative input terminal and groundI had been asked this question in exam.The query is from The Inverting Configuration in chapter Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Right option is (B) Resistance is CONNECTED between the NEGATIVE input terminal and the output terminal |
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| 57. |
The loop gain for an ideal operational amplifier with R1 = 10kΩ and R2(negative feedback) = 1MΩ is(a) 20 db(b) 40 db(c) 60 db(d) 80 dbThis question was addressed to me in an interview for internship.This question is from The Inverting Configuration topic in division Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Correct CHOICE is (b) 40 db |
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| 58. |
The non-inverting closed loop configuration features a high resistance. Therefore in many cases unity gain follower called buffer amplifier is often used to(a) Connect a high resistance source to high resistance load(b) Connect low resistance source to low resistance load(c) Connect low resistance source to a high resistancesource(d) Connect high resistance source to a low resistance loadThe question was posed to me during an online exam.My question comes from The Inverting Configuration in chapter Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Right answer is (d) Connect high RESISTANCE SOURCE to a low resistance load |
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| 59. |
The problem with the single operational difference amplifier is its(a) High input resistance(b) Low input resistance(c) Low output resistance(d) None of the mentionedThis question was addressed to me by my college professor while I was bunking the class.The origin of the question is Difference Amplifiers in portion Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Correct OPTION is (b) LOW input resistance |
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| 60. |
Assuming that when the power supply is turned on the capacitor voltage is zero, how long does it take for the amplifier to saturate?(a) 3s(b) 6s(c) 9s(d) 12sThis question was addressed to me in unit test.The doubt is from DC Imperfections in Operational Amplifiers topic in section Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The CORRECT choice is (B) 6s |
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| 61. |
In the non-inverting configuration of operational amplifier(a) The positive terminal is connected to the ground directly(b) The negative terminal is connected to the ground directly(c) The positive terminal is connected to the power source(d) The negative terminal is connected to the power sourceThis question was posed to me in unit test.Question is from The Non Inverting Configuration in chapter Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The CORRECT option is (c) The positive terminal is connected to the POWER SOURCE |
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| 62. |
In an inverting op-amp circuit for which the gain is −4 V/V and the total resistance used is 100 kΩ. Then the value of R1 and R2 (negative feedback)(a) R1 = 20KΩ and R1 = 80KΩ(b) R1 = 80KΩ and R1 = 20KΩ(c) R1 = 40KΩ and R1 = 60KΩ(d) R1 = 50KΩ and R1 = 50KΩThis question was posed to me in exam.This intriguing question originated from The Inverting Configuration topic in chapter Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Correct CHOICE is (a) R1 = 20KΩ and R1 = 80KΩ |
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| 63. |
Consider a symmetrical square wave of 20-V peak-to-peak, 0 average, and 2-ms period applied to a Miller integrator. Find the value of the time constant CR such that the triangular waveform at the output has a 20-V peak-to-peak amplitude.(a) 0.25ms(b) 0.50ms(c) 2.5ms(d) 5.0msThe question was asked at a job interview.The above asked question is from Integrators and Differentiators topic in section Operational Amplifiers of Electronic Devices & Circuits |
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Answer» RIGHT option is (b) 0.50ms To explain: ACCORDING to the QUESTION 1/CR = 2. |
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| 64. |
A single-pole model has __________ db/decade roll-off of the gain.(a) -3 db/decade(b) -6 db/decade(c) -10 db/decade(d) -20 db/decadeI had been asked this question during an online exam.The question is from Effect of Finite Open-Loop gain and Bandwidth on Circuit Performance topic in chapter Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The correct answer is (d) -20 db/decade |
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| 65. |
The slope of the frequency response of an integrator is(a) Linear with negative slope(b) Linear with positive slope(c) Exponential increase(d) Exponential decreaseThis question was addressed to me in an interview.I need to ask this question from Integrators and Differentiators in division Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Right OPTION is (a) LINEAR with NEGATIVE SLOPE |
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| 66. |
The other name for Miller Circuit is(a) Non-Inverting Integrator(b) Inverting Integrator(c) Non-Inverting Differentiator(d) Inverting DifferentiatorI had been asked this question in homework.My query is from Integrators and Differentiators topic in portion Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The correct answer is (B) Inverting Integrator |
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| 67. |
If for an amplifier v1 and v2 are the input signals, vc and vd represent the common mode and differential signals respectively, then the expression for CMRR (Common Mode Rejection Ratio) is(a) 20 log (|Ad| / |Ac|)(b) -10 log (|Ac| / |Ad|)^2(c) 20 log (v2 – v1 / 0.5(v2 + v1))(d) All of the mentionedThe question was posed to me in an international level competition.The query is from Difference Amplifiers in chapter Operational Amplifiers of Electronic Devices & Circuits |
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Answer» CORRECT answer is (d) All of the mentioned The BEST I can explain: NOTE that all the expressions are IDENTICAL. |
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| 68. |
The negative feedback causes(a) The voltage between the two input terminals to the very small, ideally zero(b) The voltage between the two input resistance very high, ideally infinite(c) Current flow through the positive input terminal and no current flows through the negative input terminal(d) Both a and cI got this question in examination.Origin of the question is The Inverting Configuration topic in chapter Operational Amplifiers of Electronic Devices & Circuits |
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Answer» RIGHT answer is (a) The voltage between the two INPUT terminals to the very SMALL, ideally zero To EXPLAIN I would say: Ideally the input terminals are at the same POTENTIAL but in real practice there is a very small potential between the two terminals. |
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| 69. |
For designing a non-inverting amplifier with a gain of 2 at the maximum output voltage of 10 V and the current in the voltage divider is to be 10 μA the resistance required are R1and R2where R2 is used to provide negative feedback. Then(a) R1= 0.5 MΩ and R2 = 0.5 MΩ(b) R1= 0.5 kΩ and R2 = 0.5 kΩ(c) R1= 5 MΩ and R2 = 5 MΩ(d) R1= 5 kΩ and R2 = 5 kΩThis question was addressed to me in exam.Enquiry is from The Non Inverting Configuration topic in division Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The correct choice is (a) R1= 0.5 MΩ and R2 = 0.5 MΩ |
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| 70. |
Consider an inverting amplifier circuit designed using an op amp and two resistors, R1 = 10 kΩ and R2 = 1 MΩ. If the op amp is specified to have an input bias current of 100 nA and an input offset current of 10 nA, find the output dc offset voltage resulting.(a) 0.1 mV(b) 1 mV(c) 10 mV(d) 100 mVI have been asked this question in an internship interview.I would like to ask this question from DC Imperfections in Operational Amplifiers in section Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The correct ANSWER is (d) 100 mV |
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| 71. |
What is the corner frequency of the resulting STC network?(a) 1 Hz(b) 0.16 Hz(c) 0.33 Hz(d) 0.5 HzThe question was asked in an international level competition.This key question is from DC Imperfections in Operational Amplifiers in division Operational Amplifiers of Electronic Devices & Circuits |
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Answer» CORRECT CHOICE is (B) 0.16 Hz The best I can EXPLAIN: The required answer is given by 1/6 Hz. |
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| 72. |
The phase in the integrator and differentiator circuit respectively are(a) +90 degrees and +90 degrees(b) -90 degrees and -90 degrees(c) -90 degrees and +90 degrees(d) +90 degrees and -90 degreesThis question was posed to me during a job interview.Origin of the question is Integrators and Differentiators topic in section Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The correct CHOICE is (d) +90 degrees and -90 degrees |
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| 73. |
For the circuit given below determine the input common mode resistance.(a) (R1 + R3) || (R2) || +(R4)(b) (R1 + R4) || (R2 + R3)(c) (R1 + R2) || (R3 + R4)(d) (R1 + R3) || (R2 + R4)I had been asked this question by my school principal while I was bunking the class.I need to ask this question from Difference Amplifiers in section Operational Amplifiers of Electronic Devices & Circuits |
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Answer» The correct answer is (c) (R1 + R2) || (R3 + R4) |
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| 74. |
If for an amplifier the common mode input signal is vc, the differential signal id vd and Ac and Ad represent common mode gain and differential gain respectively, then the output voltage v0 is given by(a) v0 =Ad vd – Ac vc(b) v0 =– Ad vd + Ac vc(c) v0 =Ad vd + Ac vc(d) v0 = – Ad vd – Ac vcI have been asked this question in an online quiz.Question is from Difference Amplifiers topic in chapter Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Correct answer is (c) V0 =AD VD + AC vc |
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| 75. |
What is the minimum number of terminals required in an IC package containing four operational amplifiers (quad op amps)?(a) 12(b) 13(c) 14(d) 15This question was posed to me during an interview.My query is from The Ideal Operational Amplifiers topic in portion Operational Amplifiers of Electronic Devices & Circuits |
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Answer» Right CHOICE is (c) 14 |
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