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101.

Give the uses of sulphuric acid?

Answer»

1. Sulphuric acid is used in the manufacture of fertilisers, ammonium sulphate and super phosphates and other chemicals such as hydrochloric acid, nitric acid etc… 

2. It is used as a drying agent and also used in the preparation of pigments, explosives etc..

102.

Why is ICl more reactive than I2 ?

Answer»

ICl bond is weaker than I – I bond. Therefore ICl can break easily to form halogen atoms which readily brings about the reaction.

103.

Assertion (A) – Sulphuric acid is highly reactive. Reason (R) – Sulphuric acid can act as strong acid and an oxidising agent.(a) A and R are correct and R explains A (b) A and R are correct but doesn’t explains A (c) A is correct but R is wrong (d) A is wrong but R is correct

Answer»

(a) A and R are correct but doesn’t explains A

104.

Why is N2 less reactive at room temperature?

Answer»

Due to the presence of triple bond between the two nitrogen atoms, the bond dissociation energy of N2 (941.4 kJ mol-) is very high. Therefore, N2 is less reactive at room temperature.

105.

Why fluorine is more reactive than other halogens?

Answer»

Fluorine is the most reactive element among halogen. This is due to the minimum value of F – F bond dissociation energy. Hence fluorine is more reactive than other halogens.

106.

Among the following the correct order of acidity is …………(a) HClO2 < HCIO < HClO3 < HClO4(b) HClO4 < HClO2 < HCIO < HClO3 (c) HClO3 < HClO4 < HClO2 < HCIO (d) HCIO < HClO2 < HClO3 < HCIO4

Answer»

(d) HCIO < HClO2 < HClO3 < HCIO4

107.

Suggest a reason why HF is a weak acid, whereas binary acids of the all other halogens are strong acids.

Answer»

The hydrogen halides are extremely soluble in water due to the ionisation. 

X + H2O → H3O+ + X-

(X = F, Cl, Br or I)

Solutions of hydrogen halides are therefore acidic and known as hydrohalic acids. Hydrochloric, hydrobromic and hydroiodic acids are almost completely ionised and are therefore strong acids but HF is a weak acid. For HF,

  • HF + H2O ⇌ H3O+ + F- 
  • HF + F- → HF2-

At high concentration, the equilibrium involves the removal of fluoride ions is important. Since it affects the dissociation of hydrogen fluoride, therefore it is a weak acid.

108.

More reactive element is (a) Fluorine (b) Chlorine (c) Bromine (d) Iodine

Answer»

(a)  Fluorine

109.

Consider the following statements (i) In inter halogen compounds, the central atom will be the smaller one. (ii) It can be formed only between two halogen and not more than two halogens. (iii) They are strong reducing agents.Which of the above statement(s) is / are not correct? (a) (i) only (b) (ii) and (iii) (c) (i) and (iii) (d) (iii) only

Answer»

(c)  (i) and (iii)

110.

The correct order of the acidity of hydrohalic acids? (a) HF &gt; HCI &gt; HBr &gt; HI (b) HCI &gt;HF &gt;HBr &gt;HI (c) HBr &gt; HCI &gt;HF &gt; HI (d) HI &gt; HBr &gt; HCI &gt; HF

Answer»

(d) HI > HBr > HCI > HF

111.

Find out the incorrect pair.(a) H2SO4 drying agent (b) Chlorine – Deacon’s process (c) HCI – purification of bone black (d) Helium – flash bulbs

Answer»

(d) Helium – flash bulbs

112.

The geometry of XeF4 is.

Answer»

Square planar

It is square planar in shape
113.

Explain the following:(i) NO2 readily forms a dimer(ii) BiCl3, is more stable than BiCl5.

Answer»

(i) It is because NO2 contains odd number of valence electrons. On dimerisation, it is converted to stable N2O4 , molecule with even number of electrons.

(ii) In group-15 the stability of +5 oxidation state decreases and that of +3 oxidation state increases due to inert pair effect.

Thus, BiCl3 , is more stable than BiCl5.

114.

Why is helium used in diving apparatus?

Answer»

Helium is used in diving apparatus because of its very low solubility in blood.

115.

Account for the following :SO3 is more covalent than SO2.

Answer»

Due to high charge and small size of sulphur in +6 oxidation state in SO3 it is more covalent than SO2, in which sulphur is in +4 oxidation state.

116.

Halon – 1301 is    1. CC2 F.CClF2   2. C2 F4 Br2   3. CCl3 F 4. CF3 Br

Answer»

Halon – 1301 is C2 F4 Br2 .

117.

Assertion: Pcl4 is covalent in gaseous and liquid states but ionic is shlid state.    Reason: In solid state it have   Pcl5+ and   Pcl6- ions.    1. A and R are true, R is correct explanation of A.  2. A and R are true, r is not correct explanation of A.  3. A is true, but R is false.  4. A is false, but R is true.

Answer»

3. A is true, but R is false. 

118.

Assertion: Red phosphorous is less volatile than white phosphorous.  Reason: Red phosphorous has a does create tetrahedral structure.  1. A and R are true, R is correct explanation of A.  2. A and R are true, r is not correct explanation of A.  3. A is true, but R is false.  4. A is false, but R is true.

Answer»

3. A is true, but R is false.

119.

Diamond is covalent, yet it has high melting point. Why?

Answer»

Diamond has three-dimensional network structure involving strong C-C bonds. These bonds are difficult to break and hence the melting point of diamond is very high.

120.

Which halogens oxidises water to oxygen exothermally?  1. Fluorine 2. Chlorine 3. Bromine 4. Iodine

Answer»

Fluorine halogens oxidizes water to oxygen exothermally.

121.

List the important sources of sulphur.

Answer»

Sulphur occurs in the earth’s crust in the combind state primarily in the form of sulphates and sulphides.

(i) As sulphates: Gypsum, (CaSO4.2H2O), Epsom salt (MgSO4 7H2O), Baryte (BaSO4) etc.

(ii) As Sulphides: Galena (PbS), Zine blende (ZnS), Copper pyrites (CuFeS2), Iron pyrites (FeS2) etc.

Traces of sulphur occur as H2S and in organic matter such as eggs, proteins, onion, mustard, hair and wool etc.

122.

Complete the following reactions:(i) B(OH)3 + 2HOH →(ii) 2NaBH4 + I2 →(iii) B2H6 (g) + 6H2O(l) →(iv) B2H6 + 3O2 →(v) 2BF3 + 6NaH \(\overset{450K}{\rightarrow}\) B2H6 + 6NaF

Answer»

(i) B(OH)3 + 2HOH → [B(OH)4 ] + H3O+

(ii) 2NaBH4 + I2 → B2H6 + 2NaI + H2

(iii) B2H6 (g) + 6H2O(l) → 2B(OH)3 (aq) + 6H2 (g)

(iv) B2H6 + 3O2 → B2O3 + 3H2O

(v) 2BF3 + 6NaH \(\overset{450K}{\rightarrow}\) B2H6 + 6NaF

123.

What happens when (only give reaction) (i) Aluminium dissolves in dilute HCl. (ii) Borax dissolves in water. (iii) Acidifying an aqueous solution of borax. (iv) Treating boron trifluoride with LiAlH4 in diethyl ether. (v) Ammonia reacts with diborane.

Answer»

(i) 2Al(s) + 6HCl(aq) → 2Al3+(aq) + 6Cl(aq) + 3H2(g)

(ii) Na2B4O7 + 7H2O → 2NaOH + 4H3BO3

(iii) Na2B4O7 + 2HCl + 5H2O → 2NaCl + 4B(OH)3

(iv) 4BF3 + 3LiAlH4 → 2B2H6 + 3LiF + 3AlF3

(v) 3B2H6 + 6NH3 → 3[BH2(NH3)2] +[BH4] \(\overset{\Delta}{\rightarrow}\) 2B3N3H6 + 12H2

124.

Why is H2S more acidic than water?

Answer»

It is because bond dissociation energy of S – H bond is less than O – H bond due to longer bond length.

125.

Which one of the following is more acidic? (a) HOCl (b) HCIO2 (c) HClO3 (d) HClO4

Answer»

HClO4 is more acidic.

126.

When XeF reacts with 2.5 M NaOH gives ………… (a) Na4XeO6 (b) Na2XeO3 (c) XeO2F3(d) XeO3

Answer»

When XeF6 reacts with 2.5 M NaOH gives Na4XeO6.

127.

What is phosgene?

Answer»

When carbon monoxide is treated with chlorine in presence of light or charcoal, it forms a poisonous gas carbonyl chloride, when is also known as phosgene.

CO + Cl2 ⟶ COCl2

128.

What is producer gas? How will you prepare producer gas?

Answer»

On industrial scale carbon monoxide is produced by the reaction of carbon with air. The carbon monoxide formed will contain nitrogen gas also and the mixture of nitrogen and carbon monoxide is called producer gas.

2C + O/N2(air) ⟶ 2CO + N2

129.

(i) Explain the formation of (a) water gas (b) Producer gas. Give their uses.(ii) What happens when CO2 is passed through lime water?(a) For short duration(b) For long duration.

Answer»

(i) Preparation of water gas and producer gas-

(a) C(s) + H2O(g) → CO(g) + H2(g)

(b) 2C(s) + O2 + 4N2 (g) → 2CO(g) + 4N2 (g) (Producer gas)

Water gas and producer gas are used as fuel.

(ii) (a) Ca(OH)2 + CO2 → Ca(HCO3)2 (Soluble)

(ii) (a) Ca(OH)2 + CO2 → Ca(HCO3)2 (Soluble)

130.

What is phosphorescence?

Answer»

White (yellow) phosphorous glows in the dark due to oxidation which is called phosphorescence.

131.

In diborane, the number of electrons that accounts for banana bonds is ………… (a) six (b) two (c) four (d) three

Answer»

(c) four

There are two 3c – 2e- bonds i.e., the bonding in the bridges account for 4 electrons.

132.

Which one of the following compound is important for photosynthesis? (a) CO (b) CO2(c) COCl2(d) C

Answer»

CO is important for photosynthesis.

133.

General empirical formula of silicone is ……….. (a) (R2SiO) (b) (RSiO) (c) (R2CO) (d) (RSiH)

Answer»

General empirical formula of silicone is (R2SiO)

134.

The basic structural unit of silicates is ………… (a) (SiO3)2-(b) (SiO4)2-(c) (SiO)- (d) (SiO4)4-

Answer»

(d) (SiO4)4-

135.

Carbon atoms in fullerene with formula C50 have ………… (a) sp3 hybridised (b) sp hybridised (c) sp2 hybridised (d) partially sp2 and partially sp3 hybridised

Answer»

(c) sp2 hybridised

136.

What are Wade’s Rule?

Answer»

Wade’s rules are used to rationalize the shape of borane clusters by calculating the total number of skeletal electron pairs (SEP) available for cluster bonding.

137.

Why boron has non-metallic character?

Answer»

The atomic radius of boron is very small and it has relatively high nuclear charge and these properties are responsible for its non-metallic character.

138.

Why-1 oxidation state is more common in halogens. Explain.

Answer»

The halogens have a strong tendency to gain an electron to give a stable halide ion with completely filled electronic configuration (ns2sp6) and hence-1 oxidation state is more common in halogens

139.

Oxidation state of carbon in its hydrides …………(a) +4 (b) -4 (c) +3 (d) +2

Answer»

(a) +4

CH4+ in which the oxidation state of carbon is 4.

140.

Which element has a greater tendency to form a chain of bonds with itself? (a) Boron (b) Silicon (c) Tin (d) Carbon

Answer»

Carbon has a greater tendency to form a chain of bonds with itself.

141.

More common oxidation state for halogens is ………… (a) +1 (b) +2 (c) -1 (d) -2

Answer»

More common oxidation state for halogens is -1.

142.

Consider the following statements. (i) The first member of the group-13, boron is a metalloid while others are reactive metals. (ii) The oxides of boron and silicon are similar in their acidic nature. (iii) Both boron and silicon form metallic hydrides. Which of the above statement(s) is/are not correct? (a) (i) only (b) (ii) only (c) (ii) and (iii) (d) (iii) only

Answer»

(d) (iii) only

143.

Noble gases are chemically inert. This is due to ………… (a) unstable electronic configuration (b) stable electronic configuration (c) only filled p-orbital (d) only filled 5-orbital

Answer»

(b) stable electronic configuration

144.

Electronic configuration of noble gases is ………… (a) ns2 (b) ns2 np5 (c) ns1 np6 (d) ns2 np6 

Answer»

Electronic configuration of noble gases is ns2np6.

145.

Why group 18 elements are called inert gases? Write the general electronic configuration of group 18 elements.

Answer»

The elements of group-18 have completely filled s and p orbitals, hence they are more stable and have least reactivity. Therefore group-18 elements are called inert gases. ns2np6 is the general electronic configuration of group elements.

146.

In the following questions a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices. (a) A and R are correct and R explains A. (b) A and R are correct and R not explains A. (c) A is correct but R is wrong. (d) A is wrong but R is correct.Assertion (A) – Noble gases are least reactivity. Reason (R) – Noble gases have completely filled s and p-orbital and attain stable electronic configuration.

Answer»

(a) A and R are correct and R explains A.

147.

Match the following :(i) Graphene(a) Honeycomb crystal(ii) Diamond(b) Aromatic character(iii) Fullerene(c) Lubricant(iv) Graphite(d) Very hard

Answer»

(i) – (c) 

(ii) – (d) 

(iii) – (b) 

(iv) – (a)

148.

Match the following :(i) Boron(a) Optical(ii) Borax(b) Neutron absorber(iii) Boric acid(c) Welding torches(iv) Diborane(d) Eye lotion

Answer»

(i) – (b) (ii) – (a) (iii) – (d) (iv) – (c)

149.

Fill in the blanks1. …………… are high temperature polymers. 2. The viscosity of silicon oil remains …………… 3. …………… are used as insulating material. 4. In beryl, each aluminium is surrounded by …………… 5. …………… is carcinogenic silicates. 6. Three dimensional by replacing units by …………… 7. …………… crystal to act as a molecular sieve. 8. Borax is a sodium salt of ……………

Answer»

1. silicones

2. constant 

3. Silicones 

4. six oxygen 

5. Asbestos 

6. [SiO4]4- ; [AlO4]5-

7. Zeolite

8. tetraboric acid

150.

Match the following :(i) Borax(a) Na2B4O7(ii) Prismatic form (b) Na2B4O75H2O(iii) Jeweller borax(c)  Na2B4O7.10H2O(iv) Borax glass(d) [B4O5(OH)4]2

Answer»

(i) – (c) 

(ii) – (d) 

(iii) – (b) 

(iv) – (a)