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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
In which following statement are correct. (a) Anhydrous hydrogen fluroide is a liquid at ordianry temperature while other halogen acid are gases. (b) Lead acetate does not form any precipitate with HF acid but other halogen acid from precipitates. (c) HF is heated with a mixture of `MnO_2` and `H_2SO_4`, no gas is evolved but In case of HCI, HBr and HI acids evolved gases. (d) HF is not oxidised by strong oxidising agent but other halogen acid are oxidised.A. (A) aB. (B) bC. (C) cD. d |
| Answer» Correct Answer - A::C::D | |
| 2. |
Give the preparation of a) `XeOF_(4)` and b) `XeO_(2)F_(2)` |
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Answer» Partial hydrolysis of `XeF_(6)` gives oxy fluorides `XeOF_(4)` and `XeO_(2)F_(2)` `XeF_(6)+H_(2)O to XeOF_(4)+2HF` `XeF_(6)+2H_(2)O toXeO_(2)F_(2)+4HF` |
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| 3. |
An amorphous solid (X) burns in air to form a gas (Y) which turns lime water milky. This gas decolourises aqueous solution of acidified `KMnO_4`. Gas (Y) reacts with oxygen to give another gas (Z) which is responsible for acid rain. X, Y and Z areA. X-C, Y-CO, Z-`CO_2`B. X-S, Y-`SO_2` , Z-`SO_3`C. X-P , Y-`P_2O_3` ,Z - `P_2O_5`D. X-S , Y-`SO_3` ,Z-`H_2SO_4` |
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Answer» Correct Answer - B `{:(S,+O_2,toSO_2),("(X)",,"(Y)"):}` `{:(SO_2+,Ca(OH)_2to , CaSO_3 darr , + H_2O),("(Y)",,"white ppt.",):}` `{:(2KMnO_4+,5SO_2+,2H_2OtoK_2SO_4+,2MnSO_4 +,2H_2SO_4),("Purple","(Y)",,"colourless",):}` `{:(2SO_2+,O_2to,2SO_3),("(Y)",,"(Z)"):}` `underset"(Z)"(SO_3) + H_2O to H_2SO_4` (responsible for acid rain ) |
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| 4. |
A solution of a salt in water on addition of dilute `HCL` gives a white ppt. solution in hot water. The salt contains:A. `Pb^(2+)`B. `Ag^(+)`C. `H^(2+)`D. `Fe^(2+)` |
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Answer» Correct Answer - A `PbCl_(2)` is soluble in hot water. |
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| 5. |
The correct order of decreasing ionic nature of lead dihalides isA. `PbI_(2) lt PbBr_(2) lt PbCl_(2) lt PbF_(2)`B. `PbF_(2) lt PbBr_(2) lt PbCl_(2) lt PbI_(2)`C. `PbF_(2) lt PbCl_(2) lt PbBr_(2) lt PbI_(2)`D. `PbF_(2) lt PbCl_(2) lt PbBr_(2) lt PbI_(2)` |
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Answer» Correct Answer - D Larger anions are more easily deformed to produce covalent nature. Also note decreasing ionic nature and not increasing |
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| 6. |
The heavier elements of groups 13 and 14 besides the group oxidation state exhibit another oxidation state which is two units lower than the group oxidation state and the stability of this lower oxidation state increases down the group. This concept which is commonly called inert pair effect has been used to explain many physical and chemical properties of the element of these groups. Element of group 13A. exhibit oxidation state of `+3` onlyB. form `M^(+)` and `M^(3+)` ionsC. exhibit oxidation states of +1 and +3D. form `M^(-)` and `M^(+)` ions |
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Answer» Correct Answer - C Since compound in +3 oxidation state are more covalent, therefore, they do not form `M^(3+)` ions. |
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| 7. |
Which of the following are used as catalyst in Friedel-Crafts reactions ?A. `AlCl_(3)`B. `SiCl_(4)`C. `BF_(3)` is the strongest Lewis acid among the other boron halidesD. `SnCl_(4)` |
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Answer» Correct Answer - A::C::D Because of big size of Cl atoms and weak interaction between lone pairs of Cl and Si, si cannot expland its covalency beyond 4 and hence `SiCl_(4)` cannot have as a catalyst. |
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| 8. |
Substances which readily undergo hydrolysis areA. `AlCl_(3)`B. `BCl_(3)`C. `SiCl_(4)`D. `PbCl_(4)` |
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Answer» Correct Answer - A::B::C::D All the chlorides being Lewis acids accept a pair of electrons from `H_(2)O` molecule hence undergo hydrolysis. |
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| 9. |
Hot concentrated sulpuric acis is a moderatly strong oxidizing agent. Which of the following reaction does not shwo oxidizing behaviour?A. `Cu + 2H_(2)SO_(4) rarr CuSO + SO_(2) + 2H_(2)O`B. `3S + 2H_(2)SO_(4) rarr 3SO_(2) + 2H_(2)O`C. `C + 2H_(2)SO_(4) rarr CO_(2) + 2SO_(2) + 2H_(2)O`D. `CaF_(2) + H_(2)SO_(4) rarr CaSO_4) + 2HF` |
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Answer» Correct Answer - D Key idea An oxidising agent is a species, which oxidises the other species and itself gets reduced. (i) `Coverset(0)u+2H_(2)SO_(4) rarr overset(+2)(C)uSO_(4) + SO_(2) + 2H_(2)O` (ii) `3underset(0)(S)+2H_(2)SO_(4) rarr 3overset(+4)(S)O_(2) + 2H_(2)O` (iii) `overset(0)(C) + H_(2)SO_(4) rarr overset(+4)(CO_(2)) + 2SO_(2) + 2H_(2)O` (iv) `overset(+2)(C)overset(-1)(F)_(2) + H_(2)SO_(4) rarr overset(+2)(C)aSO_(4) + 2Hoverset(-1)(F)`. In reaction (iv), oxidation number of elements remains unchanged Thus, in this reaction, `H_(2)SO_(4)` does not act as an oxidising agent. |
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| 10. |
The exhibition of highest co-ordination number depends on the availability of vacant orbitals in the central atom. Which of the following elements is not likely to act as central atom in `MF_(6)^(3-)` ?A. BB. AlC. GaD. In |
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Answer» Correct Answer - A Boron atom due to the non-availablity of empty d-orbtials. |
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| 11. |
The number of half filled orbitals in the valence shell of halogens isA. OneB. TwoC. ThreeD. Zero |
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Answer» Correct Answer - A The outer shell configuration is `ns^2 np_x^2 np_y^2 np_z^1`. Hence there is one unpaired electron. |
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| 12. |
Fluorine does not show variable oxidation states while other members of the halogen family exhibit variable oxidation states. Why ?A. its high electronegativityB. smallest size of its atomC. low bond dissociation energyD. non-availability of d-orbital |
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Answer» Correct Answer - D `F(1s^2 2s^2 2p^5)` does not have d-orbital . `therefore` No other oxidation other than -1 |
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| 13. |
The halogen having five vacant orbitals in the outermost shell belongs toA. 3rd periodB. 4th periodC. 2nd periodD. 5th period |
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Answer» Correct Answer - A Five vacant orbitals (3d-level) are present in Cl `(1s^2 2s^2 2p^6 3s^2 3p^5)` which belongs to 3rd period. |
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| 14. |
Halogen molecules areA. diatomic and form `X_2^(2-)` ionsB. diatomic and form `X^-` ionsC. monoatomic and form `X_2^(2-)` ionsD. monoatomic and form `X^-` ions |
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Answer» Correct Answer - B Diatomic `(X_2)F_2,Cl_2,Br_2,I_2` and it form `X^-` ion `(F^-, Cl^-, Br^- , I^-)` monoatomic |
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| 15. |
Which halogen cannot show oxidation state more than zero ?A. ChlorineB. FluorineC. IodineD. Bromine |
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Answer» Correct Answer - B F shows oxidation no. of -1 only in its compounds. |
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| 16. |
Aqueous hypo solution on reaction with aqueous `AgNO_(3)` gives :A. yellow precipitate changing to blackB. white precipitate changing to blackC. orange precipitate to blueD. no precipitate |
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Answer» Correct Answer - B `S_(2)O_(3)^(2-)+2Ag^(+) to Ag_(2)S_(2)O_(3)darr(white)`" , "`Ag_(2)S_(2)O_(3)+H_(2)O to Ag_(2)S darr(black)+H_(2)SO_(4)` This hydrolytic decompostion can be accelerated by warming. If hypo is in excess, then soluble complex is formed. `2S_(2)O_(3)^(2-)+Ag to [Ag(S_(2)O_(3))_(2)]^(3-)` (soluble complex) `[Ag(S_(2)O_(3))_(3)]^(5-)` |
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| 17. |
Fluorine is highly reactive due toA. its high electronegativityB. smallest size of its atomsC. low bond dissociation energyD. non-availability of d-orbitals |
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Answer» Correct Answer - C F electronic configuration is `1s^2 2s^2 2p^5` does not have d-orbital. (as second principal shell does not contain d-orbital) |
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| 18. |
Bleaching of a fabric cloth is done using A and excess of chlorine is removed using B.A and B are :A. `CaOCl_(2), Na_(2)SO_(3)`B. `Na_(2)S_(2)O_(3), CaOCl_(2)`C. `CaCl_(2), Na_(2)S_(2)O_(3)`D. `CaOCl_(2), Na_(2)S_(2)O_(3)` |
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Answer» Correct Answer - D `CaOCl_(2)` acts as bleaching agent while `Na_(2)S_(2)O_(3)` acts as antichlor according to the following reaction. `CaOCl_(2)+ H_(2)O to Ca(OH)_(2)+Cl_(2)`. `Na_(2)S_(2)O_(3)+4Cl_(2)+5H_(2)to 2NaHSO_(4)+8HCl`. |
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| 19. |
In `P_4 O_10`, the number of oxygen atoms bonded to each phosphorus atom is _____ . |
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Answer» Correct Answer - Four |
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| 20. |
_____phosphorus is reactive because of its highly strained tetrahedral structure. |
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Answer» Correct Answer - white |
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| 21. |
White phosphorus when boiled with strong solution of caustic soda prduces :A. sodium phosphideB. sodium phosphateC. sodium hypophosphiteD. red phosphorus |
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Answer» Correct Answer - C `3NaOH+P_(4)+3H_(2)O to underset("Phosphine")(PH_(3))+underset("Sodium Hypophosphite")(3NaH_(2)PO_(2))` |
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| 22. |
Which compound does not give oxygen on heating?A. HgOB. `KMnO_(4)`C. `(NH_(4))_(2)Cr_(2)O_(7)`D. `KCIO_(3)` |
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Answer» Correct Answer - C `(NH_(4))_(2)Cr_(2)O_(7)` "on heating gives" `N_(2)`. `(NH_(4))_(2)CrO_(7)overset(Delta)toN_(2)+Cr_(2)O_(3)+4H_(2)O`. |
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| 23. |
In group 16 the photosensitive elements areA. Oxygen and SulphurB. Oxygen and TelluriwnC. Seleniwn and TelluriwnD. Sulphur and Seleniwn |
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Answer» Correct Answer - C Se and Te are semiconductors |
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| 24. |
The basicity of phosphorus acid `(H_(3)PO_(3))` is ............ . |
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Answer» Correct Answer - Two |
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| 25. |
`H_2S` reacts with `O_2` to formA. `H_2O + S`B. `H_2O + SO_2`C. `H_2O + SO_3`D. `H_2SO_4 + S` |
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Answer» Correct Answer - A `2H_2S + O_2 to 2H_2O + 2S` |
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| 26. |
Oxygen can be obtained from bleaching powder by:A. adding dilute acidB. adding alkaliesC. heating with limeD. heating with a cobalt salt. |
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Answer» Correct Answer - D `2CaOCl_(2)overset(Co^(2+))to2CaCl_(2)+O_(2)` |
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| 27. |
On passing `H_2S` through acidified `FeCl_3` solution `FeCl_3` is converted intoA. `Fe(SO_4)_3`B. `FeS`C. `FeCl_2`D. `FeSO_4` |
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Answer» Correct Answer - C `4FeCl_2 + SO_2 + 4HCl to 4FeCl_3 + 2H_2O + S` |
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| 28. |
When`H_2S` gas is passed in acidified `KMnO_4` solution we getA. SB. `K_2S`C. `K_2SO_3`D. `MnO_2` |
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Answer» Correct Answer - A Reaction of `KMnO_4` in acidic medium with `H_2S` gives S. |
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| 29. |
On passing `H_2S` through acidified `FeCl_3` solution `FeCl_3` is converted intoA. `Fe_2(SO_4)_3`B. FeSC. `FeCl_2`D. `FeSO_4` |
| Answer» Correct Answer - C | |
| 30. |
Bleaching action of `SO_2` is due to itsA. oxidationB. acidic natureC. reductionD. basic nature |
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Answer» Correct Answer - C `SO_2 + 2H_2O to H_2SO_4 + 2[H]` Coloured matter + [H] `to` Colourless matter |
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| 31. |
Bleaching powder is obtained by the interaction of `Cl_2` andA. dilute solution of `Ca(OH)_(2)`B. concentrated solution of `Ca(OH)_(2)`C. dry calcuim oxideD. dry slaked lime |
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Answer» Correct Answer - D |
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| 32. |
Colourless salt `(A)` decolourise `I_(2)` solution and gives white precipitate (change to black) with `AgNO_(3)` solution. `(A)` also produces pink colour with `FeCl_(3)` solution. Identigy `(A)` and explain reactions. |
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Answer» `2S_(2)O_(3)^(2-)+I_(2) to S_(4)O_(6)^(2-) +2I^(-)` `S_(2)O_(3)^(2-) + 2Ag^(+) to Ag_(2)S_(2)O_(3) darr`(white) `Ag_(2)S_(2)O_(3) + H_(2)O to Ag_(2)S darr` (Black)`+H_(2)SO_(4)` `Fe^(3+) +2S_(2)O_(3)^(2-) to [Fe(S_(2)O_(3))_(2)]^(-)`(Pink or violet) |
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| 33. |
Bleaching action of `SO_2` is due to______.A. oxidationB. acidic natureC. reductionD. basic nature |
| Answer» Correct Answer - C | |
| 34. |
`SO_(2)` and `Cl_(2)` both are used as bleaching agent. What factors cause bleaching ? |
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Answer» `SO_(2)+2H_(2)O to H_(2)SO_(4)+2H` `Cl_(2)+H_(2)O to 2HCl+O` Bleaching action of `SO_(2)` is due to `H` (that causes reduction) and that of `Cl_(2)` is due to `O` (that cause oxidation) |
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| 35. |
Why has it been difficult to study the chemistry of radon ? |
| Answer» Radon is a radioactive element with very short half-life of 3.82 days. That is why, the study of chemistry of radon is a difficult task. | |
| 36. |
Give the reason for bleaching action of `Cl_(2)` ? |
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Answer» Bleaching action of chlorine is due to its oxidizing property. When chlorine reacts with water, it gives nascent oxygen which decoloures is the coloured substance. `Cl_(2)+H_(2)O to2HCl+[O]` Coloured substance `+ [O] to` Colourless substance Bleaching action of chlorine creates permanent effect. It bleaches the vegetable or organic matter in the presence of moisture. |
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| 37. |
Name some poisonous gases which can be prepared from chlorine gas. |
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Answer» i) Phosgene `(COCl_(2))` ii) Tear gas `(CCl_(3)NO_(2))` iii) Mustard gas `(ClCH_(2)CH_(2)SCH_(2)CH_(2)Cl)` |
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| 38. |
Balance the following equation : `XeF_(6)+H_(2)OtoXeO_(2)F_(2)+HF` |
| Answer» `XeF_(6)+2H_(2)O toXeO_(2)F_(2)+4HF` | |
| 39. |
Why is helium used in diving apparatus ? |
| Answer» Helium is used in diving apparatus due to its very low solubility in blood. | |
| 40. |
The orange solid ono heating gives a colourless gas and green solid which can be reduced to the metal by aluminium powder. The orange and the green solies are, respectively,A. `(NH_(4))_(2)Cr_(2)O_(7)andCr_(2)O_(3)`B. `Na_(2)Cr_(2)O_(7)andCrO_(3)`C. `K_(4)Cr_(2)O_(7)andCrO_(3)`D. `(NH_(4))_(2)CrO_(4)andCrO_(3)` |
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Answer» Correct Answer - A `underset("Orange solid")((NH_(4))_(2)Cr_(2)O_(7))overset(Delta)tounderset("Colouress gas")(N_(2))+underset("Green solid")(Cr_(2)O_(3))+4H_(2)O` `Cr_(2)O_(3)+2Aloverset(Delta)to2Cr+Al_(2)O_(3)` |
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| 41. |
Statement-I: Aluminium and zinc metal evolve `H_(2)` gas from NaOH solution Statement-II: Several non-metals such as P,S,Cl, etc. yield a hydride instead of `H_(2)` gas from NaOHA. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1.B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1.C. Statement-1 is True, Statement-2 is FalseD. Statement-1 is False, Statement-2 is True |
| Answer» Correct Answer - B | |
| 42. |
Statement-1: Oxygen is more electronegative than sulphur, yet `H_(2)S` is acidic, while `H_(2)O` is neutral. Statement-2: `H-S` bond is weaker than `O-H` bond.A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1.B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1.C. Statement-1 is True, Statement-2 is FalseD. Statement-1 is False, Statement-2 is True |
| Answer» Correct Answer - A | |
| 43. |
Concentrated `H_(2)SO_(4)` cannot be used to prepare HBr from NaBr , because it ,A. oxidizes HBrB. reduces HBrC. causes disproprotionation of HBrD. reacts too slowly with KBr |
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Answer» Correct Answer - A `H_2SO_4` will oxidise HBr to `Br_2` |
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| 44. |
Statement-1: Conc. `H_(2)SO_(4)` cannot be used to prepare pure HBr from NaBr Statement-2: It reacts slowly with NaBr.A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1.B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1.C. Statement-1 is True, Statement-2 is FalseD. Statement-1 is False, Statement-2 is True |
| Answer» Correct Answer - C | |
| 45. |
Conc. `H_(2)SO_(4)` cannot be used to prepared HBr form NaBr.A. reacts slowly with NaBRB. oxidises HBrC. reduces HBrD. disproportionates HBr |
| Answer» Correct Answer - B | |
| 46. |
On heating compound (A) gives a gas (B) which is a constituent of air. This gas when treted with 3 moles of hydrogen `(H_(2))` in the presence of a catalyat gives another gas (C ) which is basic in nature. Gas C on further oxidation in moist condition gives a compound (D) which is a part of acid rain. Identify compounds (A) to (D) and also give necessary equations of all the steps involved . |
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Answer» The main constituents of air are nitrogen `(78%)` and oxygen `(21%)` . Only `N_(2)` reacts with three moles of `H_(2)` in the presence of a catalyst to give `NH_(3)` (ammonia) which is a gas having basic nature. On oxidation , `NH_(3)` gives `NO_(2)` which is a part of acid rain . So the compounds A to D are as A `=NH_(4)NO_(2),B=N_(2),C=NH_(3),D=HNO_(3)` Reactions involved can given , as "(i)`underset((A))(NH_(4))NO_(2)overset(Delta)tounderset((B))(N_(2))+2H_(2)O` (ii)`underset((B))(N_(2))+3H_(2)hArrunderset([C])(2NH_(3)` (iii) `4NH_(3)+5O_(2)overset("Oxidation")to4NO+6H_(2)O` (iv) `2NO+O_(2)to2NO_(2)` (v) `3NO_(2)+H_(2)Otounderset((D))(2HNO_(3))+NO` |
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| 47. |
Assertion:- `SF_(6)` cannot be hydrolysed but `SF_(4)` can be. Reason:- Six F atoms in `SF_(6)` prevent the attack of `H_(2)O` on sulphur atom of `SF_(6)`A. Both Assertion and Reason are correct statements , and Reason is the correct explation of the Assertion.B. Both Assertion and Reason are correct statements , and Reason is not the correct explanation of the Assertion.C. Assertion is correct, but Reason is wrong statement.D. Assertion is wrong but Reason is correct statement. |
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Answer» Assertion and reason both are true and reason is the correct explaination of assertion. `SF_(4)` can be hydrolysed but `SF_(6)` can not because six F- atoms in `SF_(6)` prevent the attack of `H_(2)O` on sulphur atoms of `SF_(6)`. |
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| 48. |
Between `SiCl_(4)` and `C Cl_(4)`, only `SiCl_(4)` reacts with water. `SiCl_(4)` is ionic and `C Cl_(4)` is covalent.A. Statement I is correct, Statement II is correct Statement II is the correct explanation of Statement IB. Statement I is correct, Statement II is correct Statement II is no the correct explanation of Statement IC. Statement I is correct, Statement II is incorrectD. Statement I is incorrect, Statement II is correct |
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Answer» Correct Answer - C |
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| 49. |
The X - X bond dissociation energy is minimum in:A. (A) `F_2`B. (B) `Cl_2`C. (C) `Br_2`D. (D)`l_2` |
| Answer» Correct Answer - A | |
| 50. |
which of the following has maximum bond strength:A. (A) HIB. (B) HCIC. (C) HFD. (D) HBr |
| Answer» Correct Answer - C | |