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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1151. |
Pure chlorine is obtained:A. by heatingn `PtCl_(4)`B. by heating `MnO_(2)` with `HCl`C. by heating bleaching power with `HCl`D. by heating mixture of `NaCl` , `MnO_(2)` and Conc. `H_(2)SO_(4)` |
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Answer» Correct Answer - A Pure chlorine in obtained by `PtCl_(4)` `PtCl_(4)overset(Delta)(rarr)PtCl_(2)+Cl_(2)` |
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| 1152. |
Fluorine reacts with water to giveA. `HF` and `O_(2)`B. `HF` and `OF_(2)`C. `HF` and `O_(3)`D. `HF` , `O_(2)` and `O_(3)` |
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Answer» Correct Answer - D `2F_(2)+2H_(2)Orarr4HF+O_(2)` `3F_(2)+3H_(2)Orarr6HF+O_(3)` |
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| 1153. |
chlorine can be manufactring fromA. Elctrolysis of `NaCl`B. Elctrolysis of brineC. Elctrolysis of bleaching powderD. All of these |
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Answer» Correct Answer - B `2NaCl + 2H_(2)O overset("Electroysis")(rarr) underset((aq))(2NaOH) + underset((g))(Cl_(2)) + underset((g))(H_(2))` |
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| 1154. |
`Pb` and `sSn` are exerted from their chief ores by:A. carbon reduction and self-reductionB. self-reduction and carbon reductionC. electrolysis and self-reductionD. self-reduction and electrolysis |
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Answer» Correct Answer - B `{:(2PbS+3O_(2)overset(Delta)to2PbO+2SO_(2)),(2PbO+PbSoverset(Delta)to3Pb+SO_(2)):}}Self-reduction` `SnO_(2)+2Coverset(Delta)toSn+2CO` Carbon reduction. |
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| 1155. |
`PbO_(2)` isA. AcidicB. BasicC. NeutralD. Amophoteric |
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Answer» Correct Answer - D `PbO_(2)` amphoreric |
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| 1156. |
Assertion: `AlCl_(3)` ionishes in solution. Reason: The hydration energy of `AlCl_(3)` exceeds the ionization energy.A. If both assertion and reason are true and the reason is the correct explanation of teh assertion.B. If both assertion and reason are true but reason in not the correct explation of the assertion.C. If assertion is true but reason is false.D. If assertion is false but reason is true. |
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Answer» Correct Answer - A Ionisation energy required to convert `Al` to `Al^(3+)` is `5137 kJ mol^(-1). DeltaH_(hydration)` for `Al^(3+)` is `-4665 J mol^(-1)` and `DeltaH_(hydration)` for `Cl^(-)` is `-381 kJ mol^(-)`. So total hydration energy `-4665+(3xx-381)=-5808 kJ mol^(-1)` is greater than inosation energy. |
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| 1157. |
When a solution of `XeO_(3)` is treated with metal fluoride, the product obtained is……A. `M^(+)[XeO_(2)F_(2)]^(-)`B. `M+[XeO_(3)F]^(-)`C. `M+[XeO_(6)F]^(-)`D. None of these |
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Answer» Correct Answer - B When a solution of `XeO_(3)` is treated with `KF` or `CsF`, an oxofluoro salt, `M^(+)[XeO_(3)F]^(-)` is obtained. |
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| 1158. |
The oxidation number of xenon in `XeOF_(2)` isA. ZeroB. `2`C. `4`D. `3` |
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Answer» Correct Answer - C Suppose the oxidation state of `Xe` is `x.XeOF_(2)` `x+(-2)+2(-1)=0impliesx-2-2impliesx=4`. |
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| 1159. |
Fill in the blanks : `underset((A))ubrace(2NO+O_(2)) to underset((B))(2NO_2) undersetunderset"heat"(larr)overset"cold"to underset"(C )"(N_2O_4)`A. A-Colourless , B-Brown, Paramagnetic , C-Colourless DiamagneticB. A-Brown , B-Colourless Diamagnetic , C-Brown ParamagneticC. A-Colourless , B-Colourless, Paramagnetic , C-Brown , DiamagneticD. A-Brown , B-Brown, Paramagnetic , C-Brown , Diamagnetic |
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Answer» Correct Answer - A A-Colour less gases B-Brown, paramagnetic gas due to presence of an odd electron C-Colourless , diamagnetic solid |
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| 1160. |
A gas (X) is obtained when copper reacts with dilute `HNO_(3)`. The gas thus formed reacts with oxygen to give brown fumes of (Y). (Y) when dissolved in water gives an important acid (Z) and the gas (X). X, Y and Z respectively areA. `NO,NO_2 , HNO_3`B. `NO_2 , NO, HNO_3`C. `N_2O , NO, HNO_3`D. `NO, N_2O , HNO_3` |
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Answer» Correct Answer - A `3Cu+8HNO_3(dil.) to 3Cu(NO_3)_2+underset"(X)"(2NO)+ 4H_2O` `2NO+ O_2 to underset"(Y)"(2NO_2)` `3NO_2 + H_2O to underset"(Z)"(2HNO_3) + NO` |
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| 1161. |
`NH_(3)+O_(2)overset("Pt")to(A)` `(A)+O_(2)to (B)`(brown fumes) `(B)+H_(2)o to ( C)`(nitrogen in lower oxidation state) `+(D)`(nitrogen in higher oxidation state) `( C)` and `(D)` both are oxoacids of nitrogen. `( C)+I^(-)to (E)` (violets vapours). Identify `(A),(B),( C),(D)` and `(E)` |
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Answer» `4NH_(3)+5O_(2)underset(Delta)overset("Pt")to4NO+6H_(2)O` `NO+1//20_(2) toNO_(2)`(brown fumes) `NO_(2)+H_(2)O to HNO_(2)+HNO_(3)`(both oxoacids) `2HNO_(2)+2I^(-) + 2H^(+)toI_(2) ("violent vapours")+2NO+2H_(2)O`. So `( A)=NO, (B)=NO_(2), (C )=HNO_(2), (D)=HNO_(3)` and `(E)=I_(2)` |
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| 1162. |
Nitrogen comnines with metals to formA. NitritesB. NitratesC. Nitrosyl chlorideD. Nitrides |
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Answer» Correct Answer - D `6Ni+N_(2)rarr2Li_(3)N` Lithium nitride `3Mg+N_(2)rarrMg_(3)N_(2)` magnesium nitride |
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| 1163. |
Superphosphate of lime isA. A mixure of normal calcium phosphate and gypsumB. A mixure of primary calcium phosphate and gypsumC. Normal calcium phosphateD. |
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Answer» Correct Answer - B Superphophate of lime: It is a mixure of calcium dihydrogen phosphate and gypsum and is obtained by treating phosphatic rock will conc. `H_(2)SO_(40` `Ca_(3)(PO_(4))_(2)+2H_(2)SO_(4)+5H_(2)O` `rarrunderset("Superphosphate of lime")(Ca(H_(2)PO_(4))_(2).2H_(2)O)+2CaSo_(4)0.2H_(2)O` |
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| 1164. |
Boric acid is plymeric due to : |
| Answer» the acid is polymeric due to hydrogen bonding. | |
| 1165. |
Graphite conducts elecatricity because of theA. Highly polarized nature of `pi`-electrons.B. Highly delocalized nature of `pi`-electrons.C. Highly localized nature of `pi`-electrons.D. None of these |
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Answer» Correct Answer - B In graphite there is `sp^(2)` hybridilized carbon. Thus due to highly delocalized `pi` electrons it possess electrical conductivity. |
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| 1166. |
Which of the following does not exist?A. `[C Cl_(6)]^(2-)`B. `[GeCl_(6)]^(2-)`C. `[SiCl_(6)]^(2-)`D. `[SnCl_(6)]^(2-)` |
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Answer» Correct Answer - A Carbon cannot expands its octet due to absence of `d`-orbital in `2^(nd)` shell. |
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| 1167. |
`2X+6LiHoverset(450K)rarr B_(2)H_(6)+Y`. The compounds, X and Y areA. `X=BCl_(3), Y=LiCl`B. `X=BBr_(3), Y=LiBr`C. `X=BF_(3),Y=LiF`D. `X=B_(2)H_(5)Cl, Y=LiCl` |
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Answer» Correct Answer - C |
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| 1168. |
Write balanced equations for the folliowing. Chlorine is passed into a solution of NaI in water. |
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Answer» When chlorine water is added to a solution of sodium iodide a brown colour is formed. `Cl_(2)+2" NaI"to2" NaCl"+I_(2)` |
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| 1169. |
Assertion. Graphite is a good conductkor of heat and electricity. Reason. Graphite has all the electrons firmly held in C-C, `sigma`-bonds.A. If both assertion and reason are true, and reason is the true explanation of the assertion.B. If both assertion and reason are true, but reason not is the true explanation of the assertion.C. If assertion is true, but reason is false.D. If both assertion and reason are false. |
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Answer» Correct Answer - C Correct reason. Each carbon in graphite has one free electron which makes graphites a good conductor of electricity. |
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| 1170. |
How does `SO_(2)` react with the following ? `"Fe"^(+3)"ions"` |
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Answer» `"Fe"^(+3)`ions are reduced to `"Fe"^(+2)` ions by `SO_(2)`. `2"Fe"^(+3)+SO_(2)+2H_(2)O to2Fe^(+2)+SO_(4)^(-2)+4H^(+)` |
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| 1171. |
How does `SO_(2)` react with the following ? `"KMnO"_(4)` |
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Answer» `SO_(2)` gas decolourises acidified potassium permanganate (VII) solution. `5SO_(2)+2MnO_(4)^(-)+2H_(2)O to5SO_(4)^(-2)+4H^(+)+2Mn^(+2)` |
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| 1172. |
Starting from elemental sulphur, how is `H_(2)SO_(4)` prepared ? |
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Answer» Manufacture of `H_(2)SO_(4)` by contact process : Manufacturing of `H_(2)SO_(4)` involves three main steps, Step - I `SO_(2)` production : The required `SO_(2)` for this process is obtained by burning S(or) Iron pyrites in oxygen. `S+O_(2)toSO_(2)` `4FeS_(2)+15O_(2)to2Fe_(2)O_(3)to2Fe_(2)O_(3)+8SO_(3)` Step - 2 `SO_(3)` formation : `SO_(2)` is oxidised in presence of catalyst with atmospheric airto form `SO_(3)` `2SO_(2(g))+O_(2(g))underset(Delta)overset("catalyst")iff2SO_(3(g))` Step - 3 Formation of `H_(2)SO_(4)` : `SO_(3)` formed in the above step absorbed in `98% H_(2)SO_(4)` to get oleum `(H_(2)S_(2)O_(7))`. This oleum is diuted to get desired concentration of `H_(2)SO_(4)`. `SO_(3)+H_(2)SO_(4)toH_(2)S_(2)O_(7)` `H_(2)S_(2)O_(7)+H_(2)Oto 2H_(2)SO_(4)` |
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| 1173. |
The ion that cannot ne precipitated by both `HCl` and `H_(2)S` isA. `Pb^(2+)`B. `Fe^(3+)`C. `Zn^(2+)`D. `Cu^(2+)` |
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Answer» Correct Answer - A `Pb^(2+)` forms a precipitate of `PbCl_(2)` (white) and PbS (black). |
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| 1174. |
In graphie, the electron areA. localised on every third carbon atomB. present in antibonding orbitalsC. localised on each c arbon atomD. spread out between the structure. |
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Answer» Correct Answer - D Electrons are spread (delocalised) between the structure. |
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| 1175. |
The compound which has molecular nature is gas phase but ionic in solid state is :A. `PCl_(5)`B. `POCl_(3)`C. `P_(4)O_(10)`D. `PCl_(3)` |
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Answer» Correct Answer - A `PCl_(5)` remains covalent in gas as well as in liquid phase but in solid exists as `[PCl_(4)]^(+)` and `[PCl_(6)]^(-)` |
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| 1176. |
Which of the following set of species are diamagnetic?A. `S_(3),S_(8),S_(6)`B. `O_(3),S_(3),S(2)`C. `P_(4),N_(2),O_(2)`D. `Na_(2)ZnO_(2),KO_(2),ClO_(2)` |
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Answer» Correct Answer - A `S_(3),S_(6)" and " S_(8)` all are diamagnetic. |
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| 1177. |
When `P_(4)O_(10)` is dissolved in water, the acid formed finally is :A. `H_(3)PO_(2)`B. `H_(3)PO_(4)`C. `H_(3)PO_(3)`D. `H_(3)PO_(4)` |
| Answer» Correct Answer - B | |
| 1178. |
The compound which does not undergo hydrolysis at room temperature is :A. `C Cl_(4)`B. `SO_(2)Cl_(2)`C. `PCl_(5)`D. `NCl_(3)` |
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Answer» Correct Answer - A `C Cl_(4)` does not undergo hydrolysis at room temperature. Because C-atom does not have vacant orbital for accept for accept lone pair electrons of `H_(2)O` molecule (Nucleophile). ` C Cl_(4)+H_(2)O rarr `No hydrolysis |
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| 1179. |
Select the correct order(s).A. `HOCl gt HOBr gt HOI`-Acid strengthB. `HCIO_4 lt HCIO_3 lt HCIO_2 le HCIO`-oxidising powerC. `CIO_(4)^(-) lt BrO_4^(-) lt IO_4^(-)`-oxidising powerD. `IO^(-) gt BrO^(-) gt CIO^(-)` -ease of disproportionation. |
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Answer» Correct Answer - ABD |
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| 1180. |
The compounds which do not undergo hydrolysis at room temperature are:A. `NF_(3)`B. `C Cl_(4)`C. `SiH_(4)`D. `SF_(6)` |
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Answer» Correct Answer - A::B::D `NF_(3),C Cl_(4)` and `SF_(6)` compounds are undergo hydrolysis via `SN^(1)` mechanism means in ordinary condition they do not undergo hydrolysis. |
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| 1181. |
Name the following : noble gas with least boiling point |
| Answer» Helium has lowest boiling point (4.2K) | |
| 1182. |
A solution of `KI_(3)` in water contains :A. `K^(3+)` ionsB. `I^(-)` ionsC. `K^(+)` ionsD. `I_(3)^(-)` ions |
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Answer» Correct Answer - CD |
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| 1183. |
Which of the following statement(s) is/are incorrect for noble gases ?A. Argon is used in higher temperature metallurgical process because of their inert nature.B. Krypton and xenon form clathrate compounds with quinol having chemical formula not exact but approximately 3 quinol molecules : 1 gas molecule.C. All the noble gases are monoatomic.D. Noble gases are completely soluble in water. |
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Answer» Correct Answer - D |
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| 1184. |
Name the following : noble gas forming large number of compounds |
| Answer» Xenon forms large number of compounds. | |
| 1185. |
Compound (A) contains Cl in its structure and Cl has uninegative and unipositive carge in compound (A). On long standing, compound (A) undergoes auto oxidation and form (B) and ( C), but in presence of `CoCl_(2)` catalyst it forms B and D. B is also produced when compound (A) reacts with `H_(2)S` gas. Which of the following statements are correct about (A)?A. It is a powerful bleaching agent, bleaching action is due to oxidationB. It is used in the manufacture of dynes, drugs and organic compounds such as ` C Cl_(4),CHCl_(3),DDT` and refrigerantsC. It is used in preparation of poisonous gases such as phosgene `(COCl_(2))`, tear gas `(C Cl_(3)NO_(2))`,mustard gas `(ClCH_(2)CH_(2)SCH_(2)CH_(2)Cl)`D. It is used in sterlising drinking water. |
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Answer» Correct Answer - A::B::C::D `A rarr CaOCl_(2),B rarr CaCl_(2),C rarrCa(ClO_(3))_(2),D rarr O_(2)` |
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| 1186. |
Select the incorrect statement (s) about noble gases:A. Heavier noble gases can sometimes dimeriseB. Some of them are colouredC. They can diffuse through rubber, glass or plasticsD. They are liquefied at very low temperatures |
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Answer» Correct Answer - A::B Noble gas are monoatomic, colourless, odourless and tasteless |
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| 1187. |
`XeF_(6)` (s) can be prepared by:A. Xe:`F_(2)` in 1:20 mole ratio and high pressure (60-70 bar) and temperature 573 KB. `Xe:F_(2)` in 1:5 mole ratio and pressure (7 bar) and temperature 873 KC. From product of (b), followed by an interaction with `O_(2)F_(2)` at 143 KD. Taking Xe in excess at atmospheric pressure (1 bar ) and temperature (673 K) |
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Answer» Correct Answer - A::C `Xe(g)+F_(2)(g) overset(673K,1 " bar") rarr XeF_(2)(s)` (xenon in excess) `Xe(g)+2Fe_(2)(g) overset(873K,1 " bar ")rarr XeF_(4)(s)` (1:5 ratio) ` Xe(g)+3F_(2)(g) overset(573K,60-70" bar") rarr XeF_(6)(s)` (1:20 ratio) `XeF_(4)+O_(2)F_(2) rarr XeF_(6)+O_(2)` |
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| 1188. |
How are `XeF_(2),XeF_(4),XeF_(6)` prepared ? Give equation. |
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Answer» `underset(("Xenon in excess"))("Xe (g)"+F_(2))(g)overset(673"K",1" bar")to"XeF"_(2)(S),` `underset((1:5" ratio"))("Xe (g)"+2F_(2))(g)overset("873, 7 bar")to"XeF"_(4)(S)` `underset((1:20" ratio"))("Xe (g)"+3F_(2))(g)overset("573K, 70 bar")to"XeF"_(6)(S)` |
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| 1189. |
The inert gas abundantly found in atmosphere is:A. (A) ArB. (B) KrC. (C) HeD. (D) Xe |
| Answer» Correct Answer - A | |
| 1190. |
Catalytic oxidation of `NH_3` (passing a mixture of `NH_3` and air over heated `Pt` gauge) gives.A. NOB. `N_2O`C. `N_2O_3`D. `N_2O_5` |
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Answer» Correct Answer - a |
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| 1191. |
Which compound is prepared by the following reaction ? `underset"(2:1 volume ratio)"(Xe + F_2 ) underset"673 K"overset"Ni"to`A. `XeF_4`B. `XeF_2`C. `XeF_6`D. `XeF_2` and `XeF_6` |
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Answer» Correct Answer - A `Xe + 2F_2 underset"673 K"overset(Ni)to XeF_4` |
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| 1192. |
Write the name and formula of the first noble gas compound prepared by Bertlett. |
| Answer» The first noble gas compound prepared by Bertlett is `XePtF_(6)`. Name of the compound is xenon hexa fluoro platinate. | |
| 1193. |
Which one of the following statements regarding helium is incorrect?A. It is used to produce and sustain powerful superconducting magnetsB. It is used as a cryogenic agent for carrying out experiments at low temperaturesC. It is used to fill gas balloons instead of hydrogen because it is lighter and non-inflammableD. It is used in gas-cooled nuclear reactors |
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Answer» Correct Answer - 3 |
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| 1194. |
Which of the following is the wrong statement ?A. `ONCI` and `ONO^(-)` are not isoelectronicB. `O_(3)` molecule is bentC. Ozone is violet-black in solid stateD. Ozone is diamagnetic gas |
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Answer» Correct Answer - C |
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| 1195. |
The correct formula fo salt formed by the neutralization of hypophosphorus acid with NaOH isA. `Na_(3)PO_(2)`B. `Na_(3)P_(3)`C. `NaH_(2)PO_(2)`D. `Na_(2)HPO_(2)` |
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Answer» Correct Answer - C Hypophosphorus acid `(H_(3)PO_(2))` is a monobasic acid and hence forms `NaH_(2)PO_(2)` salt. `H_(3)PO_(4)toP_(4)O_(10)+6H_(2)O`. |
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| 1196. |
First ever compound of a noble gas was prepared byA. BarlettB. BerzeliusC. RamsayD. Cavendish |
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Answer» Correct Answer - A N. Barlett in 1962 |
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| 1197. |
Which one of the following statements regarding helium is incorrect?A. It is used to produce and sustain powerful superconducting magnetsB. It is used to as a cryogenic agent for crrying out experiments at low tempreturesC. It is used to fill gas balloons insteat of hydrogen because it is lighter and non-inflammableD. It is used in gas-cooled nuclear reactors |
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Answer» Correct Answer - C Helium is twice as heavy as hydrogen, its lifting power is `92%` of that of hydrogen. Helium fas the lowest melting and boiling point of any element which makes liquid helium an ideal coolant for many externely low temperature application such as super conducting magnet and cryogenic research where tempereature close to absolute zero are needed. |
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| 1198. |
When ammonia is kpassed over heated copper oxide, the metallic copper is obtained, the reactoion shows that ammonia isA. A dehydrating agentB. An oxidising agentC. A reducing agentD. A nitrating agent |
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Answer» Correct Answer - C `3CuO+2NH_(3)rarr3Cu+N_(2)+3H_(2)O`. |
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| 1199. |
Concentrated `HNO_3`, upon long standing, turns yellow-brown due to the formation ofA. `NO`B. `NO_(2)`C. `N_(2)O`D. `N_(2)O_(4)` |
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Answer» Correct Answer - B |
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| 1200. |
The salt formed by the neutralization of hypophosphorous and with NaOH isA. `Na_3PO_2`B. `Na_3PO_3`C. `NaH_2PO_2`D. `Na_2HPO_2` |
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Answer» Correct Answer - C `H_3PO_2 + NaOH to NaH_2PO_2 + H_2O` `H_2PO(OH) + NaOH to NaH_2PO_2 + H_2O` |
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