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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1301. |
The correct order of acid strength isA. `HCIO lt HCIO_(2) lt HCIO_(3) lt HCIO_(4)`B. `HCIO_(4) lt HCIO_(3) lt HCIO_(2) lt HCIO`C. `HCIO lt HCIO_(4) lt HCIO_(3) lt HCIO_(2)`D. `HCIO_(4) lt HCIO_(2) lt HCIO_(3) lt HCIO` |
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Answer» Correct Answer - A |
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| 1302. |
Which one of the following is a mixted anhydride?A. NOB. `NO_(2)`C. `N_(2)O_(3)`D. `N_(2)O_(5)` |
| Answer» Correct Answer - B | |
| 1303. |
`Cl_(2)O` is an anhydride ofA. `HClO_(4)`B. `HOCl`C. `HClO_(2)`D. `Cl_(2)O_(3)` |
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Answer» Correct Answer - B `Cl_(2)+H_(2)O to 2HClO` Chlorine has + 1 oxidation state in `Cl_(2)O` and `HOCl`. |
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| 1304. |
When `I^(Theta)` is oxidised by `MnO_(4)^(Theta)` in an alkaine medium, `I^(Theta)` converts intoA. `IO_(4)^(-)`B. `I_(2)`C. `IO_(4)^(-)`D. `IO^(-)` |
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Answer» Correct Answer - A `2MnO_(4)^(-)+ H_(2)O+l^(-) to 2MnO_(2)+ 2OH^(-) + lO_(3)^(-)` |
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| 1305. |
Decreasing order of reducing power of hydrogen halides isA. `HIgtHBrgtHClgtHF`B. `HFgtHIgtHBrgtHCl`C. `HIgtHFgtHBrgtHCl`D. None of these |
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Answer» Correct Answer - A The order of reducing power of halide ions is `l^(-)gt Br^(-) gt Cl^(-)gt F^(-)` |
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| 1306. |
Which of the following gives acetylene on hydrolysis ?A. `Al_(2)(C_(2))_(3)`B. `Mg_(2)C_(3)`C. `B_(4)C`D. `La_(4)C_(3)` |
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Answer» Correct Answer - 1 `Al_(2)(C_(2))_(3)+6H_(2)Orarr2Al(OH)_(3)+3C_(2)H_(2)" "," "Mg_(2)C_(3)+4H_(2)Orarr2Mg(OH)_(2)+CH_(3)-C equiv CH` |
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| 1307. |
Which compound is prepared by the following reaction ? `underset(("2:1 volume ratio"))(Xe+F_(2)) underset(673K)overset(Ni)to`A. `XeF_4`B. `XeF_2`C. `XeF_6`D. None of these |
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Answer» Correct Answer - B |
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| 1308. |
`XeF_(2)` reacts with `PF_(5)` to give :A. `XeF_6`B. `[XeF]^(+) [PF_6]^(-)`C. `XeF_4`D. `[PF_4]^(+)[XeF_3]^(-)` |
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Answer» Correct Answer - B |
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| 1309. |
Which one of the following forms vortex ringA. `P_(2)O_(5)`B. `PH_(3) `C. `NH_(3)`D. `P_(4)O_(10)` |
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Answer» Correct Answer - A Phosphine forms vortex rings of `P_(2)O_(5)` when it comes in contact air. These rings are in the form of white smoke . Therefore , they are used in making smoke screens in warfare. |
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| 1310. |
Pnicogens are the elements of groupA. 15B. 13C. VIIID. zero |
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Answer» Correct Answer - A Members of group 15 of VA of periodic table are called pnicogens. They include N,P,As,Sb and Bi. |
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| 1311. |
Structure of ammonia isA. pyramidalB. tetrahedralC. trigonalD. trigonal pyramidal |
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Answer» Correct Answer - A Structure of ammonia is pyramidal (distorted from tetrahedral to pyramidal due to repulsion between lone pair and bond pair of electron ). |
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| 1312. |
Which one of the following species acts as both Bronsted acid and base ?A. `H_(2)PO_(2)^(-)`B. `HPO_(3)^(2-)`C. `HPO_(4)^(2-)`D. All of these |
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Answer» Correct Answer - C `HPO_(4)^(2-) +H_(2)O iff H_(2)PO_(4)^(-) +OH^(-)` `HPO_(4)^(2-)+H_(2)O iff PO_(4)^(3-) +H_(3)O^(+)` `H_(3)PO_(2)^(-)` is a conjugate base of `H_3PO_(2)` ( a monobasic acid ) and does not give `H^(+),HPO_(3)^(2-)` is conjugate base of `H_2PO_(3)^(-)` and does not ionise further , since `H_(3)PO_(3)` is a dibasic acid . |
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| 1313. |
Statement-1 : `HCIO_4` is a more stronger acid than `HCIO_3` Statement-2 : Oxidation state of Cl in `HCIO_4` is +7 and in `HCIO_3` is +5A. Statement-1 is True, Statement-2 is True,Statement-2 is a correct explanation for Statement-1.B. Statement-1 is True, Statement-2 is True,Statement-2 is NOT a correct explanation for Statement-1.C. Statement-1 is True, Statement-2 is FalseD. Statement-1 is False, Statement-2 is True |
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Answer» Correct Answer - B |
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| 1314. |
Total number of elements of group 13 and 14 which form basic oxides isA. How many silicon atoms are present in the anion of a pyrosilicates ?B.C.D. |
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Answer» Correct Answer - 1 one, Tl only. |
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| 1315. |
Statement-1. Aluminium acts as a strong affinity for oxygen. Statement-2. Aluminium has a strong affinity for oxygen.A. Statement-1 is True, Statement-2 is True , Statement-2 is a correct explanation for statement-1.B. Statement-1 is True, Statement-2 is True , Statement-2 is not a correct explanation for statement-1.C. Statement-1 is True, Statement-2 is False.D. Statement-1 is False, Statement-2 is True. |
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Answer» Correct Answer - D Correct statement-1. Aluminium acts as a reducing agent. |
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| 1316. |
Which noble gas is radioactive ? How is it formed ? |
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Answer» Radon (Rn) is radio active noble gas. Radon is obtained as decay product of `""_(86)"Ra"^(226)` `""_(86)"Ra"^(226)to""_(86)"Rn"^(222)+""_(2)He^(4)` |
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| 1317. |
Name the following : radioactive noble gas |
| Answer» Radon is the radio active noble gas. | |
| 1318. |
A noble gas which is not adsorbed by coconut charcoal isA. HeB. NeC. ArD. Kr |
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Answer» Correct Answer - A He, separation of inert gases |
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| 1319. |
Which mineral was used in the isolation of HeliumA. Pitch blendeB. HaematiteC. MonaziteD. Clevite |
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Answer» Correct Answer - C It is an ore of thorium |
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| 1320. |
The source from where most of helium is obtained at present isA. SunB. Sea waterC. MineralsD. Natural gas |
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Answer» Correct Answer - A Sun has vast amount of He |
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| 1321. |
`CaOCl_(2)+NaI+HCl to __________+CaCl_(2)+H_2O+NaCl` |
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Answer» Correct Answer - `I_(2)` |
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| 1322. |
Cesium fluoride reacts with `XeF_(6)` to form ________ |
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Answer» Correct Answer - `CsXeF_(7)` |
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| 1323. |
`XeO_3` in strong alkaline medium _________ |
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Answer» Correct Answer - disproportionates. |
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| 1324. |
If a person is injured by the shot of a gun and all the pellets could not be removed, it may cause poisoning by :A. `Pb`B. `Hg`C. `Fe`D. `As` |
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Answer» Correct Answer - A Bullet of gun possesses lead |
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| 1325. |
The highest bond strength is shown byA. O-O bondB. S-S bondC. Se-Se bondD. Te-Te bond |
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Answer» Correct Answer - B As the size increases , bond strength decreased . But S-S bond is stronger than O-O bond because of smaller size of O-atoms . |
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| 1326. |
A monoatomic gas reacts with fluorine to form a fluoride which dissolve in HF to give a conducting solution. The fluoride isA. `XeF_2`B. `XeF_4`C. `XeF_6`D. `OF_2` |
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Answer» Correct Answer - C Solution of `XeF_6` dissolves in HF is conducting due to the formation of ions. `HF + XeF_6 to XeF_5^(+1) + HF_2^(-1)` |
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| 1327. |
The idea which prometed Bartlett to prepare first ever compound of noble gas wasA. High bond energy of `Xe-F`B. Low bond energy of `F-F` in `F_(2)`C. Ionisation energies of `O_(2)` and xenon were almost similarD. None of these |
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Answer» Correct Answer - C The idea which promoted Bartelett to prepare first ever compound of noble gas was ionisation energy of `O_(2)` and xenon were almost similar. |
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| 1328. |
The soliders of Napolean army while at Alps during freezing winter suffered a serious problem as regards the tin buttongs of their uniforms. White metallic tin buttons got converted into grey powder. This transformation is related toA. an interaction with nitrogen of the air at very low temperaturesB. a change in the crystallines structure of tin.C. a change iin the partial pressure of oxygen in the air.D. an interaction with water vapour contained in the humid air. |
| Answer» Correct Answer - B | |
| 1329. |
Maximum number of compound are known in the case of :A. neonB. xenonC. kryptonD. argon |
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Answer» Correct Answer - B |
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| 1330. |
Oxygen will directly react with each of the following elements exceptA. PB. ClC. NaD. S |
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Answer» Correct Answer - B Out of P , Na, S and Cl, chlorine does not react directly but Na, P and S react with oxygen directly. `P_(4)+5O_(2)rarrP_(4)O_(10)` `S + O_(2) rarr SO_(2)` `4Ne + O_(2) rarr 2Na_(2)O` |
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| 1331. |
Which of the following bonds will be most polar?A. N-ClB. O-FC. N-FD. N-N |
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Answer» Correct Answer - C The polar character arises due to the differen in electronegativity . The electronegativity difference of N-P bond is maximum, so it more polar bond. |
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| 1332. |
Elements of which of the following groups will form anions most readily ?A. Oxygen familyB. Nitrogen familyC. HalogensD. Alkali metals |
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Answer» Correct Answer - C Halogens have maximum electrons gain enthalpy due to the fact that the atoms of these elements have only one electrons less than stable noble gas `(ns^(2)np^(6))` configuration. Therefore they have maximum tendency to accept the electron to form negative ion (anion). |
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| 1333. |
strongest hydrogen bonding is shown byA. waterB. ammoniaC. HFD. hydrogen sulphide |
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Answer» Correct Answer - C HF has strongest hydrogen bonding due to the fact that it have small size and high electronegativity. |
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| 1334. |
For the reaction `X_2 (aq) + 2e^(-) to 2X^(-) (aq)` the value of `E_("red")^@` is highestA. `F_2`B. `Cl_2`C. `Br_2`D. `I_2` |
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Answer» Correct Answer - A `F_2` is the strongest oxidizing agent. |
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| 1335. |
Which of the following pairs represents 1st and 2nd most electronegative elements of the periodic table respectively ?A. Cl, FB. F, ClC. F, OD. F, S |
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Answer» Correct Answer - C F=electronegativity is 4 and O = electronegativity is 3.5 |
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| 1336. |
Which halogen exist as dark red liquid at ordinary temperature ?A. `Br_2`B. `Cl_2`C. `I_2`D. `At_2` |
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Answer» Correct Answer - A `Br_2` is reddish liquid at room temperature |
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| 1337. |
Which of the following halides is not oxidised by `M no_2` ?A. `Cl^-`B. `Br^-`C. `F^-`D. `I^-` |
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Answer» Correct Answer - C `F^-` ion cannot be oxidised by `MnO_2` because `F_2` is the strongest oxidising agent. |
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| 1338. |
Corundum is `"…………"` mineral of aluminiumA. silicateB. oxideC. double saltD. sulphate |
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Answer» Correct Answer - B Corundum is the oxide mineral `(Al_(2)O_(3))` of aluminium. |
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| 1339. |
Which is a stronger reducing agent, `SbH_(3)orBiH_(3),` and why? |
| Answer» As we move down the group 15 elements from Sb to Bi, the atomic size increases and hence the strength of the bond it makes with hydrogen decreases, i.e., Bi-H bond is weaker than Sb-H bond. In other works, `BiH_(3)` is thermally less stable than `SbH_(3)`. Therefore, on heating `BiH_(3)` has a greater tendency to liberate hydrogen than `SbH_(3)` and hence `BiH_(3)` is a stronger reducing agent than `SbH_(3)`. | |
| 1340. |
An alloy of copper and aluminium which has beautiful golden yellow colour is called `"………….."`. |
| Answer» Correct Answer - aluminimum bronze | |
| 1341. |
The soldiers of Napoleon army while at Alps during freezing winter suffered a serious problem with regard to the tin buttons of their uniform. White metallic tin buttons get converted to grey poweder. This transformation is relate toA. an interaction with water vapour contains in humid airB. an interaction with `N_(2)`of air at low temperatureC. a change in the partial pressure of `O_(2)` in airD. a change in crystalline structure of tin |
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Answer» Correct Answer - D White tin crumbles into powder due to formation of grey tin at low temperature. |
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| 1342. |
Why are carbon compounds relatively inert ? |
| Answer» Carbon-carbon bond dissociation enthalpy is quite high. | |
| 1343. |
Which element of group 14 exhibits maximum tendency for catenation ? |
| Answer» Among the element of group 14, C-C bond has the maximum bond strength and hence carbon shows maximum tendency for catenation. | |
| 1344. |
`"CCl"_(4)` does not reach with water but `SiCl_(4)` does . Why so ? |
| Answer» Due to the presence of d-orbitals in Si, `SiCl_(4)` reacts with water but due to the absence of d-orbitals in `C, "CCl"_(4)` does not react with `H_(2)O`. | |
| 1345. |
Out of `"CCl"_(4)` and `SiCl_(4)` which one reacts with water ? |
| Answer» Due to the presence of d-orbitals in `Si, SiCl_(4)` reacts with water but due to the absence of d-orbitals in C, `"CCl"_(4)` does not react with `H_(2)O`. | |
| 1346. |
Which of the two elements, carbon and silicon , forms multiple bonds ? |
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Answer» Due to smaller size and higher electronegatively , carbon undergoes `ppi- ppi` overlop to form multiple bonds but silicon does not. For example , `CO_(2)` has `C = O` double bond but `SiO_(2)` has only `Si-O` single bonds. |
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| 1347. |
Which halogen has the highest value of negative electron gain enthalpy ? |
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Answer» Correct Answer - B Definition |
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| 1348. |
Which is not correct?A. `GeCl_(2)` is more stable than `GeCl_(4)`B. `Ge(OH)_(2)` is amphotericC. `GeO_(2)` is weakly acidicD. `GeCl_(4)` in `HCl` forms `[GeCl_(2)]^(2-)`ion |
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Answer» Correct Answer - A `Ge` possess more tendency to show `+4` oxidation state. |
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| 1349. |
Glass is soluble inA. `HCIO_(4)`B. `H_(2)SO_(4)`C. `HF`D. aqua-regia |
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Answer» Correct Answer - C The `SiO_(2)` present in glass reacts with `HF` `SiO_(2) 6HFtounderset("(Soluble)")(H_(2)SiF_(6))+2H_(2)O` |
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| 1350. |
Asseration: Nitrogen forms `H_(2)N-NH_(2),N_(2)` and `N_(3)^(-)` ions whereas phosphorus form `P_(4)` molecule. Reason: Nitrogen can form of three `N-`atoms only, `P` has four catenated atoms.A. If both asseration and reson are true and the reason is the correct explanation of the asseration.B. If both asseration and reason are true ans the reason is the correct explanation of the asseration.C. If asseration is true but reason is false.D. If asseration is false but reason is true. |
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Answer» Correct Answer - C `N` can form `N_(3)^(-)` (azide ion) involving `3` atoms of `N`. |
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