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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1351. |
Asseration: White phosphorus is less stable whereas red phosphorus is more stable. Reason: White phosphorus exists as individual `P_(4)` having more strained geometry while red phosphorus has `P_(4)` tetrahedron structure linked together.A. If both asseration and reson are true and the reason is the correct explanation of the asseration.B. If both asseration and reason are true ans the reason is the correct explanation of the asseration.C. If the asseration is true but reason is false.D. If asseration is false but reason is true. |
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Answer» Correct Answer - A Both asseration and reason are true and the reason is the correct explanation of the asseration. |
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| 1352. |
Identify the compound in which phosphorus exists in the oxidation state of +1.A. Phosphonic acid `(H_3PO_3)`B. Phosphinic acid `(H_3PO_2)`C. Pyrophosphorus acid `(H_4P_2O_5)`D. Orthophosphoric acid `(H_2PO_4)` |
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Answer» Correct Answer - B Information |
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| 1353. |
Is boric acid a protic acid? Explain. |
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Answer» Boric acid is not a proton acid. It is a Lewis acid and acepts electron pair from hydroxyl ion of `H_(w)O` molecule. `B(OH)_(3)+2HOHrarr[B(OH)_(4)]^(-)+H_(3)O^(+)` |
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| 1354. |
Explain the following reactions (a) Silicon is heated with methyl chloride at high temperature in the presence of copper, (b) Silicon dioxide is treated with hydrogen fluoride, (c) CO is heated with ZnO, (d) Hydrated alumina is treated with aqueous NaOH solution. |
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Answer» (a) Silicon upon heating with methyl chloride to about `300^(@)C` in the presence of copper catalyst reacts as follows: `2CH_(3)Cl(g)+Si(s)overset(Cu//300^(@)C)rarr(CH_(3))_(2)SiCl_(2)(l)` The compound upon hydrolysis leads to the formation of silicon polymers. for more details, consult Section 11.11. (b) On reacting silicon dioxide with hydrogen fluoride, silicon tetrafluoride `(SiF_(4))` is formed. `SiO_(2)+4HFrarrSiF_(4)+2H_(2)O` `SiF_(4)` reacts further with hydrogen fluoride to form hydrofluorosilicic acid. `SiF_(4)+2HFrarrH_(2)SiF_(6)` ( c) ZnO is reduced to Zn by CO which is a strong reducing agent. `ZnO+COoverset("Heat")rarrZn+CO_(2)` (d) The two compounds react upon heating under pressure to form a soluble complex. `Al_(2)O_(3)(s)+2Na(OH)(aq)+3H_(2)O(l)rarr2Na[Al(OH)_(4)](aq)` |
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| 1355. |
`C(OH)_(4)` is unstable because a carbon atom cannot hold more than one `-OH` groups but `Si(OH)_(4)` is a stable compound becauseA. `C-O` bond energy is lowB. `C-O` bond energy is highC. `Si-O` bond energy is lowD. `Si-O` bond energy is high |
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Answer» Correct Answer - A::D `C(OH)_(4)` is unstable because acarbon atom cannot hold more than one `-OH` group but `Si(OH)_(4)` is a stable compoumd because `C-O` bond energy is low. |
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| 1356. |
Which of the following statement `is//are` correct regarding graphite?A. Graphite is thermodynamically more stable than diamond.B. `d_(C-C)` among the layers and within the layers are not same.C. Graphite is more effective than diamond.D. Graphite conducts electricity due to its bond polarity. |
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Answer» Correct Answer - A,B,C Electrical conductivity of graphite is due to presence of free `es^(-)` |
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| 1357. |
Aqueous solution of boric acid is treated with Salicylic acid. Which of the following statements `is//are` incorrect for the product formed in the above reactionA. No product will be formed because both are acid.B. Product is 4-coodinated complex and optically resolvable.C. Product is 4-coodinated complex and optically non-resolvable.D. There are two rings only which are five membered. |
| Answer» Correct Answer - A::C::D | |
| 1358. |
Boric acid :A. exists in polymeric form due ot inter-molecular hydrogen bondingB. is used in manufacturing of optical glassesC. is a tri-basic acidD. with borax, it is used in the preparation of a buffer solution |
| Answer» Correct Answer - A::B::D | |
| 1359. |
Which of the following statements regarding boric acid is false?A. It act as a tribasic acidB. It has a planar structureC. It acts as a monobasic acidD. It is soluble in hot water |
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Answer» Correct Answer - A Boric acid is monobasic. `H_(3)BO_(3) +H_(2)O hArr H^(+)+[B(OH)_(4)]^(-)` |
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| 1360. |
The halogen in the gaseous state isA. `Br_2`B. `I_2`C. `Cl_2`D. `F_2` and `Cl_2` |
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Answer» Correct Answer - D `F_2` and `Cl_2` are gases , `Br_2` is liquid and `I_2` is solid |
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| 1361. |
Which of the following do not contain fluorine ?A. FluorsparB. CryoliteC. FluorapatiteD. Carnallite |
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Answer» Correct Answer - D Carnallite = KCl, `MgCl_2 . 6H_2O` where as fluorspar : `CaF_2`, Cryolite : `Na_3AlF_6`, fluorapatite : `3Ca_3(PO_4)_2CaF_2` |
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| 1362. |
Noble gases are parmagnetic in nature. |
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Answer» Correct Answer - F |
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| 1363. |
Neon lights are visible even in fog and moist. |
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Answer» Correct Answer - T |
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| 1364. |
The high activity of fluorine is due to its …. Dissociation energy |
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Answer» Correct Answer - low |
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| 1365. |
Fluorine is present in a small quantities inA. KidneyB. HeartC. Bones and teethD. Liver |
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Answer» Correct Answer - C Traces of Fluorine occurs in bones and teeth. |
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| 1366. |
The formula of carnallite isA. `KCl, MgCl_2 . 6H_2O`B. `AgCl , MgBr_2 . 7H_2O`C. `NaCl , MgCl_2 . 5H_2O`D. `FeSO_4 , (NH_4)_2SO_4. 7H_2O` |
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Answer» Correct Answer - A Occurrence of `Cl_2` - Carnallite (KCl, `MgCl_2. 6H_2O`) |
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| 1367. |
seaweed contains iodine uptoA. `0.5%`B. `6%`C. `0.60%`D. `0.05%` |
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Answer» Correct Answer - A Occurrence of `I_2`- See weeds contains `I_2` upto 0.5% |
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| 1368. |
On heating `NH_(4)NO_3` strongly which is obtained ?A. `NO_(2)`B. `NH_(3)`C. `N_(2)`D. `N_(2)O` |
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Answer» Correct Answer - D On heating ammonium nitrate , nitrous oxide or nitrogen (I) oxide is formed . `NH_4NO_3 overset(475^(@)-530^(@))to underset("Nitrous oxide ")(N_2O)+2H_2O` |
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| 1369. |
` PCl_5` on treatment with sulphuric acid givesA. Thionyl chlorideB. Sulphur monochlorideC. Sulphuryl chlorideD. Sulphur tetrachloride |
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Answer» Correct Answer - C `2PCl_5 + H_2SO_4 to 2POCl_3 + SO_2Cl_2 + 2HCl` |
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| 1370. |
What is the hybridization of S in `SF_6` ?A. `sp^3d^2`B. `sp^3` dC. `sp^3 d^3`D. `sp^3` |
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Answer» Correct Answer - A In `SF_6`, S is `sp^3 d^2` hybridised. |
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| 1371. |
In `OF_2`, the number of bond pairs and lone pairs of electrons are respectively,A. 2, 8B. 2, 6C. 2,9D. 2, 10 |
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Answer» Correct Answer - A `[:underset(* * )overset(* * )F-underset( * *)overset(* * )O-underset(* * )overset(* * )F:]` |
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| 1372. |
Which of the following ions does not have S-S linkage ?A. `S_2O_8^(2-)`B. `S_2O_6^(2-)`C. `S_2O_4^(2-)`D. `S_2O_3^(2-)` |
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Answer» Correct Answer - A `S_2O_8^(2-)` ion is : `O=underset(O^-)underset|overset(O)overset(||)S-O-O-undersetunderset(O^-)|oversetoverset(O)(||)S=O` |
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| 1373. |
Which of the following reactions would proceed inn the forward direction ?A. `[Co(NH_(3))_(6)]^(3+)+3en iff [Co(en)_(3)]^(3+)+6NH_(3)`B. `2Na[Al(OH)_(4)]+CO_(2) rarr 2Al(OH)_(3)+Na_(2)CO_(3)+H_(2)O`C. `AlN+H_(2)O rarr Al(OH)_(3)+NH_(3)`D. all of the above |
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Answer» Correct Answer - D If the `DeltaG rarr`Negative, reaction proceed in the forward direction. (a) `[Co(NH_(3))_(6)]^(3+)+3 en iff [Co(en)_(3)]^(3+)+6NH_(3)` stability of `[Co(en)_(3)]^(3+) gt [Co(NH_(3))_(6)^(3+)` (b) `2Na[Al(OH)_(4)]+CO_(2) rarr 2Al(OH)_(3)+Na_(2)CO_(3)+H_(2)O` Precipitation reaction ( c) `AlN+H_(2)O rarr Al(OH)_(3)+NH_(3)` Evolved gas. |
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| 1374. |
Which of the following is similar to graphite ?A. `B_(4)C`B. `B_(2)C`C. `BN`D. `B` |
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Answer» Correct Answer - C BN has layered structure similar to graphite. |
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| 1375. |
Which one of the following is called Inorganic graphite ?A. `B`B. `B_(4)C`C. `B_(2)H_(6)`D. `BN` |
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Answer» Correct Answer - D BN is called inorganic graphite because its structure resembles with that of graphite. |
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| 1376. |
Among the following, the correct statement(s) is(are)A. `Al(CH_(3))_(3)` has the three-centre two-electron bonds in its dimeric strucutresB. `BH_(3)` has the three-centre two-electrons bonds in its dimeric structureC. the Lewis acidity of `BCl_(3)` is greater than that of `AlCl_(3)`D. `AlCl_(3)` has the three-centre two-electron bonds in its dimeric structure. |
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Answer» Correct Answer - A::B::C In dimeric structure of `AlCl_(3)`, the bridged Cl forms a convalent bond with one Cl atom and coordinate bond with the other. As such it does have a `3c-3c` bond as in `Al_(2)(CH_(3))_(6)` and `B_(2)H_(6)`. The option (d) is not correct while all other options (a,b,c) are correct. |
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| 1377. |
Select the most appropriate statemen. In `BF_(3)`A. all the bonds are completely ionicB. the B-F bond is partially ionicC. B-F bond has partial double bond characterD. all the bonds are covalent |
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Answer» Correct Answer - C::D Due to back donation of a lone pair of electrons from F to B , B-F bonds has partial double character. |
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| 1378. |
When formic acid is treated with conc. `H_(2)SO_(4)`, the gas evolved is :A. `H_(2)S`B. `SO_(2)`C. `CO`D. `CO_(2)` |
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Answer» Correct Answer - C `HCOOH overset("conc."H_(2)SO_(4))rarr CO + H_(2)O` |
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| 1379. |
The tendency for catenation is much higher for C than for `Si`. |
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Answer» Correct Answer - T |
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| 1380. |
Diamond is harder than graphite. |
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Answer» Correct Answer - T |
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| 1381. |
Out of diamond graphite which is (i) harder (ii) good conductor of electricity? |
| Answer» (i) Diamond (ii) Graphite | |
| 1382. |
Dehydration of formic acid gives `"………….."`. |
| Answer» Correct Answer - `CO` | |
| 1383. |
On reactly discovered allotrope, `C_(60)`, is known as `"………….."`. |
| Answer» Correct Answer - Buckminster fullerene | |
| 1384. |
`SnCl_(2)` acts as a agent. |
| Answer» Correct Answer - reducing | |
| 1385. |
The hydrolysis of alkyl-substituted chlorosilanes gives ……………….. |
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Answer» Correct Answer - silicones |
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| 1386. |
On controlled hydrolysis and condensation, `R_(3)SiCl` yields |
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Answer» Correct Answer - `(R_(3)SiO)_(2)` |
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| 1387. |
Bleaching action of `SO_(2)` is due toA. oxidising propertyB. Acidic propertyC. basic propertyD. Redicing property |
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Answer» Correct Answer - D `SO_(2)` acts as bleaching agent due to its reducing property. `SO_(2)+2H_(2)OrarrH_(2)SO_(4)+2H` Coloured matter`+Hrarr`colourless matter |
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| 1388. |
Boiling/melting points of the following hydrides follow in order.A. `NH_(3)gtAsH_(3)gtPH_(3)gtSbH_(3)`B. `SbH_(3)gtAsH_(3)gtPH_(3)gtNH_(3)`C. `SbH_(3)gtNH_(3)gtAsH_(3)PH_(3)`D. `NH_(3)gtPH_(3)gtAsH_(3)gtSbH_(3)` |
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Answer» Correct Answer - C Boiling points of `SbH_(3)(254 K),NH_(3)(238 K),AsH_(3)(211 K)` and `PH_(3)(185 K),` therefore boiling points are of the order `SbH_(3)gtNH_(3)gtAsH_(3)gtPH_(3)`. |
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| 1389. |
Which of the following statements are correct ?A. Fullerenes have dangling bondsB. Fullerenes are cage-like moleculesC. Graphite is thermodynamically most stable allotrope of carbonD. Graphite is slippery and hard and therefore used as a dry lubriant in machines |
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Answer» Correct Answer - B::C Fullerenes are cage-like (soccer or rugby ball) molecules and graphite is thermodynamically most stable allotrope of carbon. Thus, option (b) and (c ) are correct. |
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| 1390. |
State what happens when halogens react with a cold dilute solution of NaOH? |
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Answer» Correct Answer - `2F_(2)+2NaOHtoOF_(2) + 2NaF + H_(2)O` |
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| 1391. |
What idea lead to the discovery of Xenon fluorides? |
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Answer» Correct Answer - Neil Bartlett obtained an orange yellow solid from the reaction of xenon with `PtF_(6)` to have `Xe^(+)[PtF_(6)]^(-)` He noticed earlier that `O_(2)` with `PtF_(6)` reacts to give `O_(2)^(+)[PtF_(6)]^(-)` and since ionisation enthalpies of `O_(2)` and `Xe` were close to each other `(Xe=1170, O_(2)=1175 kJ mol^(-1))`, he could succed to prepare `Xe^(+)[PtF_(6)]^(-)` from `Xe` and `PtF_(6)`. |
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| 1392. |
Iodine is liberated from sodium iodate by reacting with :A. dilute `H_2SO_4`B. `KMnO_(4)`C. `NaHSO_4`D. concentrated `H_2SO_4` & NaI |
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Answer» Correct Answer - CD |
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| 1393. |
Select correct statement(s)A. `CIO_2` and `CI_2O` are used as bleaching agents for paper pulp and textilesB. `O Cl^(-)` disproportionates in alkaline mediumC. `BrO_(3)^(-)` liberates `Br_2` with iodine in acidic mediumD. `HCIO_2` liberates iodine form Kl |
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Answer» Correct Answer - ABCD |
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| 1394. |
HI can not be prepared by heating Nal with concentrated `H_2SO_4`. Give the method which is preferred for the preparation of HI. |
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Answer» Correct Answer - `HI` is a strong reducing agent and, therefore, reduces `H_(2)SO_(4)` to `SO_(2)` and itself get oxidised to `I_(2)`. `3NaI+H_(3)PO_(4)toK_(3)PO_(4) + HI` |
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| 1395. |
Ozone reacts with neutral KI solution to yieldA. `KIO_(3)`B. `KOH`C. `KCl`D. `KO_(2)` |
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Answer» Correct Answer - B `O_(3)+2KI+H_(2)Orarr2KOH+I_(2)+O_(2)` |
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| 1396. |
`PCI_(3)` reacts with water to yieldA. `PH_(3)`B. `H_(3)PO_(3),HCl`C. `POCl_(3)`D. `H_(3)PO_(4)` |
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Answer» Correct Answer - B `PCI_(3)+3H_(2)PO_(3)+3HCIOrarrH_(3)` |
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| 1397. |
Freon-12 is used as aA. RefrigerantB. InsectideC. FungicideD. Herbicide. |
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Answer» Correct Answer - A Freon -12 is a refrigerant. |
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| 1398. |
`[SiF_(6)]^(2-)` is known wheares `[SiCl_(6)]^(2-)` not. Give possible reasons. |
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Answer» The main reasons are : (i) Due to smaller size of F as compared to Cl, six small F atoms can be easily accomodated around Si atom but six large Cl atoms cannot. (ii) The lone pair of electrons on F are present in a smaller 2p-orbital but in Cl they are present on a larger 3p-orbital. Therefore, interaction of F lone pair electrons with d-orbitals of silicon are stronger than that of Cl lone pairs. |
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| 1399. |
Three pairs of compounds are given below, identify that compound in each of the paris which has group 13 element in more stable oxidation state. Give reson for your choice. (i) `TiCl_(3).TICl` (ii) `AlCl_(3).AlCl` (iii) `InCl_(3).InCl` |
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Answer» This is explained on the bais of inert pair inert pair effect . Memebers of group 13 have tendency to exhibit both, 1+1 and +3 states the stability of +3 oxidation state decreases down the group while that of +1 oxidisation state increase. On this basis. (i) TICI is more stable than `TICl_(3)` (+1 oxidations taet is more stable than +3 oxidations state) (ii) `AlCl_(3)` is more stable than AlCl (+3 oxidisation stable than +1 oxidation state) (ii) InCl is more stable than `InCl_(3)` (+1 oxidation is more stable +3 oxidation state) |
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| 1400. |
The reason for small radius of Ga compared to Al is ……..A. poor screening effect of d and f orbitals.B. inc rease in nuclear chargeC. presence of higher orbtials.D. higher atomic number. |
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Answer» Correct Answer - A::B Both the option are correct |
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