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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1651. |
How is chlorine obtained in the laboratory ? How does it react with the following ? cold dil. NaOH |
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Answer» In the laboratory chlorine is prepared by the oxidation of HCl with `MnO_(2)`. `4HCl+"MnO"_(2)to"MnCl"_(2)+2" H"_(2)O+Cl_(2)uarr` Chlorine reacts with cold dil. NaOH to form sodium hypochlorite. `Cl_(2)+2" NaOH"to NaCl+NaOCl+H_(2)O` |
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| 1652. |
Sulphur trioxide can be obtained by which of the following reactions:A. `CaSO_(4) + Coverset(Delta)rarr`B. `Fe_(2)(SO_(4))_(3) overset(Delta)rarr`C. `S+H_(2)SO_(4) overset(Delta)rarr`D. `H_(2)SO_(4) + PCl_(5) overset(Delta)rarr` |
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Answer» Correct Answer - B (a) `CaSO_(4) + C overset(Delta)rarr CaO + SO_(2) + CO` (b) `Fe_(2)(SO_(4))_(3) overset(Delta)rarr Fe_(2)O_(3) + 3SO_(3)` (c ) `S + 2H_(2)SO_(4) overset(Delta)rarr 3SO_(2)+ 2H_(2)O` (d)`H_(2)SO_(4) + PCl_(5) overset(Delta)rarr underset("Chloro sulphonic acid")(SO_(3)HCl)` Thus, `SO_(3)` is obtained by heating `Fe_(2)(SO_(4))_(3)`. |
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| 1653. |
Explain the following giving an appropriate reason in each case. (i) `O_(2)` and `F_(2)` both stabilize higher oxidation states of metals but `O_(2)` exceeds `F_(2)` in doing so. (ii) Structure of Xenon fluorides cannot be explained by Valence Bond approach. |
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Answer» Correct Answer - (i)It is due to higher lattice energy of oxides as compared to fluorides as oxide ion is dinegative whereas fluoride ion is mononegative. (ii)It is because Xe is noble gas and has lone pair of electrons in its d-orbitals.Size of 5d orbitals in Xe is large enough for effective overlapping. 5p and 5d orbitals of Xe differ by `960kJ "mol"^(-1)`, that in `sp^(3)d` hybridisation, contribution of 5d orbital is objectionable. |
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| 1654. |
Which of the following is called oxymuriatic acid ?A. HClB. `Cl_2`C. HBrD. HF |
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Answer» Correct Answer - B Oxymuriatic acid is `Cl_2` |
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| 1655. |
Sulphur trioxide can be obtained by which of the following reactions:A. `S+H_(2)SO_(4)overset(Delta)(rarr)`B. `H_(2)SO_(4)+PCl_(5)overset(Delta)(rarr)`C. `CaSO_(4)+Coverset(Delta)(rarr)`D. `Fe+_(2)(SO_(4))_(3)overset(Delta)(rarr)` |
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Answer» Correct Answer - D By heatiing ferric sulphate strongly, we get sulphur trioxide. `Fe_(2)(SO_(4))_(3)overset(Delta)(rarr)Fe_(2)O_(3)+3SO_(3)` |
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| 1656. |
(a)Account for the following : (i)The acidic strength decreases in the order `HCl gt H_(2)S gt PH_(3)` (ii)Tendency to form pentahalides decreases down the group in group 15 of the periodic table. (b)Complete the following chemical equations. : (i)`P_(4)+SO_(2)Cl_(2)to` (ii)`XeF_(2)+H_(2)O to` (iii)`I_(2)+underset(("conc"))(HNO_(3)) to` |
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Answer» Correct Answer - (a)(i)HCl is stronger acid than HF.The acid strength of hydrogen halide is `HFltHClltHBrltHI`. (ii)Element of this group form both ionic and covalent compounds in +3 oxidation state.In net shell, the covalent character decreases in the order : `NgtPgtAsgtSbgtBi`. Due to inert pair effect. (b)(i)`P_(4)+10 SO_(2)Cl_(2)tounderset("Phosphorus pentachloride")(4PCl_(5)+10 SO_(2))` (ii)`2XeF_(2)+H_(2)Oto2Xe+4HF+O_(2)` (iii)underset(("conc."))(`I_(2)+10HNO_(3))tounderset("Iodine to Iodine acid")(2HIO_(3)+10NO_(2)+)4H_(2)O` |
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| 1657. |
Bromine vapours will turn moist starch iodide paperA. BrownB. RedC. BlueD. Colourless |
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Answer» Correct Answer - C Blue, because of presence of iodine in starch iodide. `Br_2` will displace `I_2` from starch iodide turning paper blue. |
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| 1658. |
Which of the following does not give oxygen on heating?A. `(NH_(4))_(2)Cr_(2)O_(7)`B. `K_(2)Cr_(2)O_(7)`C. `Zn(ClO_(3))_(2)`D. `KClO_(3)` |
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Answer» Correct Answer - A `(NH_(4))_(2)Cr_(2)O_(7)overset(Delta)(rarr)N_(2)+Cr_(2)O_(3)+4H_(2)O:` rest all gives oxygen. |
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| 1659. |
The correct order of acidic strength isA. `SO_(2)gtCl_(2)O_(7)gtP_(4)O_(10)`B. `Cl_(2)O_(7)gtSO_(2)gtP_(4)O_(10)`C. `P_(4)O_(10)gtSO_(2)gtCl_(2)O_(7)`D. `N_(2)O_(5)gtP_(4)O_(10)gtSO_(7)` |
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Answer» Correct Answer - B The correct order of acidic strength is `Cl_(2)O_(7)gtSO_(2)gtP_(4)O_(10).` |
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| 1660. |
Which one of the halogen acid is a liquid?A. `HF`B. `HCl`C. `HBr`D. `H` |
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Answer» Correct Answer - A `HF` is liquid because of intermolecular `H`-Bonding. |
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| 1661. |
Which of the following has greatest reducing power?A. `HI`B. `HBr`C. `HCl`D. `HF` |
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Answer» Correct Answer - A `HI` is the strongest reducing agent among halogen acids because of lowest bond dissociation energy. |
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| 1662. |
`Br^(-)` is converted into `Br_(2)` by usingA. `Cl_(2)`B. `Conc.HCl`C. `HBr`D. `H_(2)S` |
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Answer» Correct Answer - A `Cl_(2)+2Br^(-)rarr2Cl^(-)+Br_(2)` |
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| 1663. |
A salt , which on heating with conc. `H_(2)SO_(4)` gives violet vapour isA. IodideB. NitrateC. SulphateD. Bromide |
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Answer» Correct Answer - A `KI+underset(Conc.)(H_(2)S)O_(4)overset(Delta)(rarr)2Cll+Br_(2)` Conc. `H_(2)SO_(4)+2HIrarr2H_(2)underset("Violet"_("Vapour"))(O)+I_(2)+SO_(2)uarr` |
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| 1664. |
A salt, which on heating with conc. `H_(2)SO_(4)` gives violet vapour isA. IodideB. NitrateC. Sulphate sulpharD. Bromide//iodide respectively with dil. `HPO_(3)` |
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Answer» Correct Answer - A `Kl + underset("Conc.")(H_(2)SO_(4)) overset(Å)(rarr) KHSO_(4) + Hl` Conc. `H_(2)SO_(4) + 2Hl rarr 2H_(2)O + underset("vapour")underset("Violet")(I_(2)) + SO_(2) uarr` |
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| 1665. |
Write the balanced chemical equation for the reaction of `Cl_(2)` with hot and concentrated NaOH. Is this reaction a disproportionation reaction ? Justify. |
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Answer» `3" Cl"_(2)+6" NaOH"to5" NaCl"+"NaClO"_(3)+3" H"_(2)"O"` Yes. Chlorine from zero oxidation state is changed to -1 and +5 oxidation states. |
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| 1666. |
The susbtance that sublimes on heating isA. `F_2`B. `Cl_2`C. `Br_2`D. `I_2` |
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Answer» Correct Answer - D `I_(2(s)) to I_(2"(vapour)")`. It sublimes readily |
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| 1667. |
Among halogen acids (hydrogen halides) ….. Is the strongest reducing agent |
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Answer» Correct Answer - HI (hydrogen iodide) |
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| 1668. |
Which of the following is used to prepare `Cl_(2)` gas at room temperature from concentrated HCl ?A. `MnO_(2)`B. `H_(2)S`C. `KMnO_(4)`D. `Cr_(2)O_(3)` |
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Answer» Correct Answer - C `2MnO_(4)^(-)+16H^(+)+10Cl^(-) to 2Mn^(2+) +5Cl_(2)+8H_2O` `KMnO_4` is used to prepare ` Cl_(2)` at room temperature from conc. HCl |
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| 1669. |
In the manufacture of bromine from sea water the mother liquor containing bromide is treated withA. `CO_(2)` and `H_(2)O`B. `Cl_(2)`C. `I_(2)`D. `SO_(2)` |
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Answer» Correct Answer - B `MgBr_(2)+Cl_(2)rarrMgCl_(2)+Br_(2)` |
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| 1670. |
In the manufacture of bromine from sea water the mother liquor containing bromide is treated withA. carbon dioxideB. chlorineC. iodineD. sulphur dioxide |
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Answer» Correct Answer - B `Cl_(2)` being a strong oxidising agent , oxidises bromide present in the mother liquor to `Br_(2)` . `underset(" From mother liquor")(2Br^(-))+ Cl_(2) to underset("Bromine")(Br_(2))+2Cl^(-)` |
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| 1671. |
An inorganic compound (3c-2e) and (2c-2e) bonds when reacts with `NH_(3)` at a certain temperature, gives a compound X which is isostuctrul x with benzene and when reacts at high temperature, forms a substance Y. The substance Y isA. `B_(2)H_(6)`B. `B_(3)N_(3)H_(6)`C. inorganic graphiteD. `B_(2)H_(6)cdot2NH_(3)` |
| Answer» Correct Answer - (c ) | |
| 1672. |
`C Cl_(4)` does not show hydrolysis but `SiCl_(4)` is readily hydrolysed because:A. `IP` of carbon is higher than that of siliconB. electronegativity of carbon is higher than that of siliconC. carbon cannot expand its octate but silicon can expandD. carbon forms doyble and triple bonds but not silicon |
| Answer» Correct Answer - C | |
| 1673. |
When chlorine is bubbled through aqueous solution of potassium iodide, iodine gas is liberated becauseA. chlorine is more electropositiveB. chlorine has higher electron affinityC. chlorine is more powerful oxidising agent than iodine.D. none of the above |
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Answer» Correct Answer - C |
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| 1674. |
The increase in the solubility of iodine in an aqueous solution of potassium iodide is due to the formation of ___________ . |
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Answer» Correct Answer - `KI_(3)` |
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| 1675. |
The deep colour produced when iodine dissolves in potassium iodide solution is due to the presence ofA. `I^+`B. `I^-`C. `I_3^-`D. `I_2^(-)` |
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Answer» Correct Answer - C `underset"(from Kl)"(I_2 + I^(-) to I_3^(-))` |
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| 1676. |
The Lewis acid nature of `BX_(3)` follows the order:A. `BF_(3) gt BCl_(3) gt BBr_(3) gt BI_(3)`B. `BF_(3) lt BCl_(3) lt BBr_(3) lt BI_(3)`C. ` BCl_(3)gt BF_(3) gt BBr_(3) gt BI_(3)`D. `BF_(3) lt BBr_(3) lt BCl_(3) lt BI_(3)` |
| Answer» Correct Answer - B | |
| 1677. |
Ozone is an unstable, dark blue diamagnetic gas. It absorbs strongly the UV radiation, thus proteching the people on the earth from the harmful UV radiation from the sun. The use of chloroflurocarbon (CFC) in aeroslos and refrigrators, and their subsequent escape into the atomsphere, is blamond for making holes in the ozone layer over the Antarctic, and Arctic. Ozone acts as a strong oxdising agent in acidic and alkaline medium. For this property ozone is used as a germicide and disinfectant for sterillising water and improving the atmosphere of croweded places. CFC damages ozone layer by reactions :A. `O_(3)+hv to O+O_(2)`B. `CI+O_(3) to CIO+O_(2)`C. `CIO+O to CI +O_(2)`D. All of these. |
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Answer» Correct Answer - D All reactions are responsible for the depletion of ozone layer. |
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| 1678. |
Ozone is an unstable, dark blue diamagnetic gas. It absorbs strongly the UV radiation, thus proteching the people on the earth from the harmful UV radiation from the sun. The use of chloroflurocarbon (CFC) in aeroslos and refrigrators, and their subsequent escape into the atomsphere, is blamond for making holes in the ozone layer over the Antarctic, and Arctic. Ozone acts as a strong oxdising agent in acidic and alkaline medium. For this property ozone is used as a germicide and disinfectant for sterillising water and improving the atmosphere of croweded places. which of the following statements is correct ?A. The dark blue colour of ozone is due to intense absorption of green light.B. oxides of nitrogen and the halogen can not damage the `O_(3)` later.C. Ozone oxidises dry iodine to `I_(2)O_(9)`D. Ozone forms oragne coloured `KO_(3)` with potassium hydroxide. |
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Answer» Correct Answer - D (A) The dark blue colour of ozone is due to intense absorption of red light. (B) Oxides of nitrogen and the halaogen can damage the `O_(3)` layer. (C ) `2l_(2)+9[O_(3)] to l_(4)O_(9)+9O_(2)` (D) `2KOH +5O_(3) to 2KO_(3)+5O_(2)+H_(2)O` |
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| 1679. |
Why does `O_(3)` act as a powerful oxidising agent ? |
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Answer» Because ozone liberates nascent oxygen very easily. `underset("Ozone")(O_(3))overset(Delta)to underset("Dioxygen")( O_(2))+underset("Nascent oxygen")([O])` |
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| 1680. |
Statement-1: Liquid `IF_(5)` conducts electricity. Statement-2: Liquid `IF_(5)` self ionizes as, `2IF_(5) iff IF_(4)^(+)+IF_(6)^(-)`A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1.B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1.C. Statement-1 is True, Statement-2 is FalseD. Statement-1 is False, Statement-2 is True |
| Answer» Correct Answer - A | |
| 1681. |
Statement-I: `NaBO_(3)//OH^(-)` can be used for oxidation of `Cr^(3+) "to" Cr^(6+)` Statement-II: In alkaline medium `NaBO_(3)` produces `H_(2)O_(2)`A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1.B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1.C. Statement-1 is True, Statement-2 is FalseD. Statement-1 is False, Statement-2 is True |
| Answer» Correct Answer - A | |
| 1682. |
`Na_(2)B_(4)O_(7).10H_(2)Ooverset(triangle)toNaBO_(2)+A+H_(2)O`,`A+MnOoverset(triangle)toB` A and B are :A. `Na_(3)BO_(3), Mn_(3)(BO_(3))_(2)`B. `Na_(2)(BO_(2))_(2), Mn(BO_(2))_(2)`C. `B_(2)O_(3), Mn(BO_(2))_(2)`D. None is correct |
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Answer» Correct Answer - C `A = B_(2)O_(3), B = MnO+B_(2)O_(3)toMn(BO_(2))_(2)` |
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| 1683. |
`{:(Column-I," "Column-II),((NH_(4))_(2)S_(2)O_(8)+H_(2)Ooverset(Distillation)to," "(p)"Hydrolysis"),(NaBO_(2)H_(2)O+H_(2)O_(2)overset(OH^(-))to," ""(q)One of the product has peroxide linkage"),(Na_(2)SO_(3)overset("fusion")underset("temperature")to," "(r)"Disproporationation"),("2-Ethyl anthraquinol+Air"`rarr`," "(s)"In one of the products the central atom has "sp^(3)" hybridisation."):}` |
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Answer» (A) `(NH_(4))_(2)S_(2)O_(6)+H_(2)Ooverset(Distillation)underset(Hydroylsis)to2NH_(4)HSO_(4)+H_(2)O_(2)` (B) `NaBO_(2)+2H_(2)O_(2)+6H_(2)to overset(sp^(3))(Na_(2))underset(sp^(3))([(OH))_(2)B_(2)[O-O]_(2)(OH)_(2)].6H_(2)O` (C ) `4Na_(2)SO_(2)to Na_(2)S+3Na_(2)S+3underset(sp^(3))(Na_(2))SO_(4)` ("disproportionation") (D) `2 "Enthyl anthraquinol"+air (O_(2))underset("oxidation")overset(Air)to2-"ethylanthraquinone"+`H_(2)O_(2)` |
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| 1684. |
The pronounced change from non-metallic behaviour and also increase in the basicity of oxides from nitrogen to bismuth in group `15` is principally due to incresing size of the atoms. The ionisation potential of nitrogen is very high on account of its small size. However, ionisation potential decreases regularly on descending the group. Which one of the following fluorides does not exist ?A. `NF_(5)`B. `PF_(5)`C. `AsF_(5)`D. `SbF_(5)` |
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Answer» Correct Answer - A Nitorgen does not form pentahalide because it does not have vacant d-orbital. |
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| 1685. |
The gas which liberates bromine from a solution of KBr isA. `Cl_2`B. `I_2`C. `SO_2`D. `HI` |
| Answer» Correct Answer - A | |
| 1686. |
The gas which liberates bromine from a solution of KBr isA. `I_(2)`B. `HI `C. `Cl_2`D. `SO_2` |
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Answer» Correct Answer - C `Cl_2+2KBr to Br_2 +2KCl ` |
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| 1687. |
`B_(2)H_(6)` is symmetrically cleaved by:A. `NH_(3)`B. `CH_(3)NH_(2)`C. `(CH_(3))_(2)NH`D. none of these |
| Answer» Correct Answer - D | |
| 1688. |
A solution of `KBr` is treated with each of the following which one would liberate bromine?A. Hydrogen iodideB. Sulphur dioxideC. ChlorineD. lodine |
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Answer» Correct Answer - C Chlorine is good oxidising agent than bromine, so, `Cl_(2)` oxidise `Br^(-)` to bromine. `2KBr + Cl_(2) rarr 2KCl + Br_(2)` |
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| 1689. |
Which of the following pairs of metals would liberate hydrogen gas with dilute nitric acid ?A. Mn,CuB. Mn,MgC. Zn,MgD. Fe,Cu |
| Answer» Correct Answer - B | |
| 1690. |
Which of the following will liberate iodine on treatment with KI solution ?A. `N_2`B. `Cl_2`C. `H_2`D. `He` |
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Answer» Correct Answer - B `Cl_2 + 2KI to 2KCl + I_2` |
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| 1691. |
Choose the reactions which would liberate nitrogen gas?A. `Ca(Ocl)Cl+NH_(3) underset("medium") overset("Aqueous")rarr`?B. `NH_(3)+PbO overset(Delta)rarr?`C. `NH_(3)("excess") +Cl_(2) overset(Delta) rarr`?D. `NH_(4)Cl+NaNO_(2) overset(Delta) rarr?` |
| Answer» Correct Answer - A::B::C::D | |
| 1692. |
An aqueous solution of hydrated aluminium chloride contains the following set of ionsA. `Al^(3+)` and `Cl^(-)`B. `[AlCl_(2)(H_(2)O)_(4)]^(+)` and `[AlCl_(4)(H_(2)O)_(2)]^(-)`C. `[Al(H_(2)O)_(6)]^(3+)` and `Cl^(-)`D. `AlCl_(3)` and `H_(2)O` |
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Answer» Correct Answer - B Hydrated aluminium chloride is `AlCl_(3).6H_(2)O`. It is ionic in nature and its aqueous solution contains `[AlCl_(2)(H_(2)O)_(4)]^(+)` and `[AlCl_(4)(H_(2)O)_(2)]^(-)` ions `AlCl_(3).6H_(2)Ooverset(ionisation) to [AlCl_(2)(H_(2)O)_(4)]^(+)+[AlCl_(4)(H_(2)O)_(2)]^(-)` |
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| 1693. |
Monazite is a source ofA. HeB. KrC. ArD. Ne |
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Answer» Correct Answer - A Minerals /sources of inert gases |
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| 1694. |
What are alums? Give the chemcial formulae of the following alums: |
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Answer» Alums are the special type of double salts of certain compounds with the general formula `M_(2)SO_(4)M_(2)(SO_(4))24H_(2)O` Here M: monovalent cation link `Na^(+) ,K^(+),Rb^(+),NH_(4)^(+)` M: trivalent cation like `Al^(3+),Fe^(3+)` or `Cr^(3+)`. Potash alum : `K_(2)SO_(4),Al_(2)(SO _(4)) _(3) .24 H_(2)O` Ferric alum: `(NH_(4))_(2)SO_(4).Fe_(2)(SO_(4))_(3).24H_(2)O` Chrome alum : `K_(2)SO_(4)Cr_(2)(SO_(4))_(3).24 H_(2)O`. |
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| 1695. |
Which of the following statements regarding sulphur is incorrect?A. `S_(2)` molecule is paramagneticB. The vapour at `200^(@)`C consists mostly of `S_(8)` ringsC. At `600^(@)`C, the gas mainly consists of `S_(2)` moleculesD. The oxiadation state of sulphur is never less than `+4` In its compounds |
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Answer» Correct Answer - D Oxidation states of sulphur in `H_(2)S` is `-2` . Thus , incorrect (valency can be less than 4). |
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| 1696. |
Density of `N_(2)` gas prepared from air is slightly higher than that of nitrogen prepared by chemical reaction from a compound of nitrogen because aerial nitrogen containsA. `CO_(2)`B. argonC. some `N_(2)` molecules analogous to `O_(2)`D. greater amount of `N_(2)` molecules derived from `N^(15)` isotope |
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Answer» Correct Answer - D Air contains 1% argone which is heavier than `N_(2)`. |
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| 1697. |
Which of the following is a Lewis acid?A. `PCl_(3)`B. `AlCl_(3)`C. `NCl_(3)`D. `AsCl_(3)`. |
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Answer» Correct Answer - B `AlCl_(3)` is Lewis acid because Al atom has three electron pairs only after sharing . |
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| 1698. |
Which of the following acts as in oxidising agent?A. `B^(3+)`B. `Al^(3+)`C. `Ti^(3+)`D. None of these gases. |
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Answer» Correct Answer - C `Ti^(3+)` is unstable and is reduced to more stable `Ti^(+)` Therefore, `Ti^(3+)` is an oxidixing agent. |
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| 1699. |
The linear shape of `CO_(2)` is due to `"……………."`A. `sp^(3)` hybridisation of carbonB. `sp` hybridisation of carbonC. `ppi-ppi` bonding between carbon and oxygenD. `sp^(2)` hybridisation of carbon |
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Answer» Correct Answer - B::C The linear shape of `CO_(2)` is due to sp-hybridization of carbon and `ppi-ppi` bonding between carbon and oxygen. Thus, option (b) and (c ) ar` correct. |
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| 1700. |
In which process does the nitrogen undergo oxidation ?A. `N_(2) rarr 2NH_(3)`B. `N_(2)O_(4) rarr 2NO_(2)`C. `2NO_(3)^(-) rarr N_(2)O_(5)`D. `NO_(2)^(-) rarr NO_(3)^(-)` |
| Answer» Correct Answer - A | |