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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1701. |
A sample of gas in a small test tube produces a pop when a burning splint is inserted. Which gas could it be ?A. `H_(2)`B. `O_(2)`C. `Cl_(2)`D. `NO` |
| Answer» Correct Answer - B | |
| 1702. |
Which is the best procedure to follow if a student spills several drops of concentrated HCl on his hand?A. Cover the area with solid sodium hydrogen carbonateB. Rinse with large amounts of cold water.C. Wash with concentrated sodium hydroxide solutionD. wrap the hand with sterile gauze. |
| Answer» Correct Answer - D | |
| 1703. |
Which of the following will not give anhydroues chloride by heating?A. `FeCl_(3).6H_(2)O`B. `MgCl_(2).6H_(2)O`C. `AlCl_(3).6H_(2)O`D. `CuSO_(4).5H_(2)O` |
| Answer» Correct Answer - A::B::C | |
| 1704. |
Very pure nitrogen can be obtained by :A. themal decomposition of `Ba(N_(3))_(2)`B. themal decomposition of `NaN_(3)`C. themal decomposition of `(NH_(4))_(2)Cr_(2)O_(7)`D. reaction of `NH_(4)Cl` with `NaNO_(2)` |
| Answer» Correct Answer - A::B | |
| 1705. |
Boron forms a numbr of hydrides having the general formuale `B_(n)H_(n+4)1` and `B_(n)H_(n+6)` These hydrides are called boranes. The simpest hydride of boron is diborane, `B_(2)H_(6)`. Boranes contain special types of bonds known as multicientre bonds. Bornaes have high of combustion. The type of hybridisation of boron in diborane isA. `sp`B. `sp^(2)`C. `sp^(3)`D. `dsp^(2)` |
| Answer» `sp^(3)` hybridisation is present . | |
| 1706. |
Which of the following option is /are correct? `Ca_(2)B_(6)O_(11)+Na_(2)CO_(3) overset(Delta) rarr CaCO_(3)+A+B` `A+CO_(2) rarr B`A. `B contains 5`B-O-B` linkageB. A will be obtained by thermal decomposition of BC. Aqueous solution of B used as a acidic buffer in titrationD. A exists in a polymeric form. |
| Answer» Correct Answer - A::B::C::D | |
| 1707. |
(i) `P+C("carbon")+Cl_(2)toQ+COuarr, (ii) Q+H_(2)OtoR+HCL` (iii) `BN+H_(2)OtoR+NH_(3)uarr, (iv) Q+LiAH_(4)toS+LiCl+AlCl_(3)` (v) `S+H_(2)OtoR+H_(2)uarr, (vi) S+NaHtoT` (P,Q,R,S, & T do not represent their chemical symbols) Compound T is used as `a//an`A. Oxidising agentB. Complexing agentC. Bleaching agentD. Reducing agent |
| Answer» Correct Answer - D | |
| 1708. |
The following flow diagram respresents the industrial preparation of nitric acid from ammonia: Formation of `HNO_(3)` when ( C) is dissolved in `H_(2)O` reaction not observed in this step.A. `NO_(2)+H_(2)O rarr HMO_(3)+HNO_(2)`B. `HNO_(2) rarrH_(2)O+NO+NO_(2)`C. `NO_(2)+H_(2)O rarrHNO_(3)+NO`D. None of the above |
| Answer» Correct Answer - D | |
| 1709. |
(i) `P+C("carbon")+Cl_(2)toQ+COuarr, (ii) Q+H_(2)OtoR+HCL` (iii) `BN+H_(2)OtoR+NH_(3)uarr, (iv) Q+LiAH_(4)toS+LiCl+AlCl_(3)` (v) `S+H_(2)OtoR+H_(2)uarr, (vi) S+NaHtoT` (P,Q,R,S, & T do not represent their chemical symbols) Compound Q has I. zero dipale moment, II. A planer trigonal structure III. An electron deficent compound, IV. A lewis base Choose the correct codeA. I,IVB. I,III,IVC. I,II,IIID. I,II,III,IV |
| Answer» Correct Answer - C | |
| 1710. |
Boron forms a number of hydrides having general formulae `B_(n)H_(n+4)` and `B_(n)H_(n+6)`. These hydrides called boranes. The simplest hydride of boron is diborane. Boranes contains special types of bonds known as multi centre bonds. Boranes have high heat of combustion Which hydride does not existA. `BH_(3)`B. `H_(2)F_(2)`C. `SbH_(3)`D. `N_(2)H_(4)` |
| Answer» `BH_(3)` does not exist. | |
| 1711. |
Boron forms a numbr of hydrides having the general formuale `B_(n)H_(n+4)1` and `B_(n)H_(n+6)` These hydrides are called boranes. The simpest hydride of boron is diborane, `B_(2)H_(6)`. Boranes contain special types of bonds known as multicientre bonds. Bornaes have high of combustion. Which of the following is electron deficient compounds?A. `C_(2)H_(6)`B. `SiH_(4)`C. `PH_(3)`D. `B_(4)H_(10)` |
| Answer» `B_(4)H_(10)` is an electron deficient compound. | |
| 1712. |
`Ca_(2)B_(6)O_(11)+Na_(2)CO_(3) overset(Delta)rarr[X]+CaCO_(3)+NaBO_(2)` ( unbalanced equation) correct choice for [X] is :A. Structure of anion of crystalline [X] has one boron atom `sp^(3)` hybridised and other three boron atoms `sp^(2)` hybridised.B. (X) with NaOH (aq.) gives a compound which on reaction with `H_(2)O_(2)` in alkaline medium yields a compound used as brightner in soapsC. Hydrolysis of (X) with HCl or `H_(2)SO_(4)` yields a compound which on reaction with HF gives fluoroboric acidD. [X] on heating with cobalt salt in oxidising flame give blue coloured bead |
| Answer» Correct Answer - B::C::D | |
| 1713. |
(i) `P+C("carbon")+Cl_(2) to Q+CO uaarr` (ii) `Q+H_(2)O to R+HCl` (iii) `BN+H_(2)O to R+NH_(3) uarr` (iv) `Q+LiAlH_(4) to S+LiCl+AlCl_(3)` (v) `S+H_(2) to R+H_(2) uarr` (vi) `S+NaH to T` (P,Q,R,S annd T do not represent their chemical symbols) Q. Compound Q has: (I) zero dipole moment. (II) a planar trigonal structure (III) an electron deficient compound (IV) a lewis base Chose the correct code:A. K,NB. K,M,NC. K,L,MD. K,L,M,N |
| Answer» Correct Answer - C | |
| 1714. |
Borax is converted into amorphous Boron by following steps `"Borax"overset(X)toH_(3)BO_(3)overset(triangle)toB_(2)O_(3)underset(triangle)overset(Y)toB` X and Y are respectivelyA. HCL,MgB. HCL,CC. `triangle,Al`D. HCl,Al |
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Answer» Correct Answer - A `B_(2)O_(3)underset(triangle)overset(Mg)toB`(Amorphous) `B_(2)O_(3)underset(triangle)overset(Al)toB`(crystalline) |
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| 1715. |
Complete the following chemical equations: (i) `z+3LiAlH_(4)rarrX+3LiF+3AlF_(3)` (ii) `x+6H_(2)Orarry+6H_(2)` (iii) `x+3O_(2)overset(Delta)rarrB_(2)O_(3)+3H_(2)O` |
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Answer» (i) `4BF_(3)+3LiAlH_(4)rarr2B_(2)H_(6)+3LiF+3AlF_(3)` (ii) `B_(2)H_(6)+6H_(2)Orarr2H_(3)BO_(3)+6H_(2)` (iii) `B_(2)H_(6)+3O_(2)overset("heat")rarrB_(2)O_(3)+3H_(2)O` |
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| 1716. |
Assertion: The borax `Na_(2)[B_(4)O_(5)(OH)_(4)].8H_(2)O` is a useful primary standard for titrating against acids. Reason: Aqueous solution of borax contains equal ammounts of weak acid and its salt.A. If both assertion and reason are true and the reason is the correct explanation of teh assertion.B. If both assertion and reason are true but reason in not the correct explation of the assertion.C. If assertion is true but reason is false.D. Ifassertion is false but reason is true. |
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Answer» Correct Answer - A Assertion: `Na_(2)[B_(4)O_(5)(OH)_(4)].8H_(2)O+2HClto2NaCl+4H_(3)BO_(3)+5H_(2)O` Indicator methyle orange `pH` range `3.1-4.4` In water, borax gives both `B(OH)_(3)` and `[B(OH)_(4)]^(-)` and only the `[B(OH)_(4)]^(-)` reacts with `HCl` Reason: `[B_(4)O_(5)(OH)_(4)]^(2-)+5H_(2)OhArr underset("weak acid")(3B(OH)_(3))+underset("its salt")(2[B(OH)_(4)])` thus acts a buffer. |
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| 1717. |
Aqueous solution containing `1` mol of borax raects with `2` mol of acids. Thic is because of:A. formation of `2` mol of `B(OH)_(3)` onlyB. formation of `2` mol of `[B(OH)_(4)]^(-)` onlyC. formation of `1` mol each of `B(OH)_(3)` and `[B(OH)_(4)]^(-)`D. formation of `2` mol each of `[B(OH)_(4)]^(-)` and `B(OH)_(3)`, of which only `[B(OH)_(4)]^(-)` reacts with acid |
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Answer» Correct Answer - D `[B_(4)O_(5)(OH)_(4)]^(2-)+5H_(2)O hArr2B(OH)_(3) "weak acid"+2[B(OH_(4))]^(-)("salt")` |
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| 1718. |
An aqueous solution of borax isA. neutralB. amphotericC. basicD. acidic |
| Answer» Correct Answer - C | |
| 1719. |
Boron compound behaves as Lewis acids because of theirA. Acidic natureB. Covalent natureC. Electron defficient characterD. Ionising property |
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Answer» Correct Answer - C Boron compounds behave as Lewis acid character because in boron its valence shell electron is three. Thus its octet is imcomplete. `F-underset([6e^(-)])underset(F)underset(|)B-FCl-underset(Cl)underset(|)(Al) underset([6e^(-) "incomplete octate"])underset()(-Cl)` |
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| 1720. |
Boron compound behaves as Lewis acids because of theirA. Acidic natureB. Covalent natureC. Electron deficient characterD. Ionization property |
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Answer» Correct Answer - C Boron compounds are electron deficient and therefore, behave as Lewis acids. |
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| 1721. |
The power of halides of boron to act as Lewis acids decreases in the orderA. `BF_(3)gtBCl_(3)gtBBr_(3)`B. `BBr_(3)gtBCl_(3)gtBF_(3)`C. `BCl_(3)gtBF_(3)gtBBr_(3)`D. `BCl_(3)gtBBr_(3)gtBF_(3)` |
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Answer» Correct Answer - B Order of Lewis acid strength of boron halides is `BI_(3)gtBBr_(3)gtBCl_(3)gtBF_(3)` This order is explained on the basic of `ppi-ppi` back bonding opposite to excepted order due to electronegativity |
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| 1722. |
Hallides of boron and aluminium are Lewis Acids. Assign reason. |
| Answer» In halides `(MX_(3))`, both these atoms have six electrons after sharing since these are electron in nature. They behave as Lewis acids. | |
| 1723. |
Addition of mineral acid to an aqueous solution of borax, the following compound is formed :A. boron hydrideB. pyroboric acidC. metaboric acidD. orthoboric acid |
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Answer» Correct Answer - D Orthoboric acid is formed. `Na_(2)B_(4)O_(7) +H_(2)SO_(4) rarr underset(" Orthoboric acid ") (4H_(3)BO_(3)) + Na_(2)SO_(4)` |
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| 1724. |
The correct formula of borax isA. `Na_(2)[B_(4)O_(4)(OH)_(3)].9H_(2)O`B. `Na_(2)[B_(4)O_(5)(OH)_(4)].8H_(2)O`C. `Na_(2)[B_(4)O_(6)(OH)_(5)].7H_(2)O`D. `Na_(2)[B_(4)O_(7)(OH)_(6)].6H_(2)O` |
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Answer» Correct Answer - B the correct structure of borax has `4OH` groups and 8 molecules of water of crystallization. Thus, option (a) is correct. |
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| 1725. |
Which of the following are Lewis acids ?A. `PH_(3)` and `BCl_(3)`B. `AlCl_(3)` and `SiCl_(4)`C. `PH_(3)` and `SiCl_(4)`D. `BCl_(3)` and `AlCl_(3)` |
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Answer» Correct Answer - D `BCl_(3)` and `AlCl_(3)` are Lewis acid. |
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| 1726. |
Which of the following is a Lewis acid ?A. `NaH`B. `NF_(3)`C. `PH_(3)`D. `B(CH_(3))_(3)` |
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Answer» Correct Answer - D `B(CH_(3))_(3)` has only six electrons in the valence shell. There it can accept a pair of electrons and hence acts as a Lewis acid. Due to presence of a lone pair of electrons on `P, PH_(3)` acts as a Lewis base. Due to strong `-I` effect of F, N cannot donate its pair of electrons and hence it does not act as a Lewis base. `Na^(+) H^(-)` is , howeverm a strong Bronsted base. |
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| 1727. |
Bucky ball or Buckminster fullerence is :A. an allotrope of carbonB. it is referred as `C-60`C. it has `sp^(2)`-hybridised nature and resembles with a soccer ballD. all of the above |
| Answer» Correct Answer - D | |
| 1728. |
The correct order of reducing abilites of hydrides of group 15 elements isA. `NH_(3)ltPH_(3)ltAsH_(3)ltSbH_(3)ltBiH_(3)`B. `NH_(3)gtPH_(3)gtAsH_(3)gtSbH_(3)gtBiH_(3)`C. `NH_(3)ltPH_(3)gtAsH_(3)gtSbH_(3)gtBiH_(3)`D. `SbH_(3)gtBiH_(3)gtAsH_(3)gtNH_(3)gtPH_(3)` |
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Answer» Correct Answer - C `NH_(3) lt PH_(3) gt AsH_(3) gt BiH_(3)` |
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| 1729. |
Clathrates are the compounds obtained from noble gases andA. waterB. quinolC. liquid ammoniaD. both (a) and (b) |
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Answer» Correct Answer - D Clathrate compounds are prepared by passing Ar, Kr or Xe in the solution of quinol in water under high pressure and the solution is subject to crystallisation |
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| 1730. |
In order to prevent the hot metal filament from getting burnt, when the electric current is switched on, the bulb is filled withA. `Cl_2`B. `H_2`C. `NH_3`D. An inert gas |
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Answer» Correct Answer - D Inert gas |
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| 1731. |
Carbon suboxide `(C_(3)O_(2))`A. is obtained by dehydrating malonic acid with `P_(2)O_(5)`B. is a linear moleculeC. is a foul smelling gasD. all the above are correct |
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Answer» Correct Answer - D All the above statements are correct. |
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| 1732. |
Whatis the electronic configuration of Argon ?A. `1s^2 2s^2 2p^6`B. `1s^2 2s^2 2p^6 3s^2 3p^6`C. `1s^2 2s^2 2p^6 3s^2 3p^4`D. `1s^2 2s^2 2p^6 3s^2 3p^5` |
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Answer» Correct Answer - B Ar (Ar. No. 18) = `1s^2 2s^2 2p^6 3s^2 3p^6` |
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| 1733. |
In graphite and diamond, the percentage of p-character of the hybird orbitals iin hybridisation are respectivelyA. 33 and 75B. 50 and 75C. 33 and 25D. 67 and 75 |
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Answer» Correct Answer - D Graphite (`sp^(3), 67%` p-charater) and diamond (`sp^(3), 75%` p-character). |
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| 1734. |
Which of the following anions is present in the chain structure of silicated ?A. `SiO_(4)^(4-)`B. `Si_(2)O_(7)^(6-)`C. `(Si_(2)O_(5)^(2-))_(n)`D. `(SiO_(3)^(2-))_(n)` |
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Answer» Correct Answer - D Chain structure of silicates contain `(SiO_(3)^(2-))_(n)` anions. |
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| 1735. |
Which is least acidic ? `SbH_(3),PH_(3),NH_(3),AsH_(3)` ? |
| Answer» A compound which is most basic is obviously least acidic. Since `NH_(3)` is most acidic, therefore, it is least acidic. | |
| 1736. |
Complete the following chemical reaction equations : (i) `l_(2)+HNO_(3) (conc.) to` (ii) `H_(g)Cl_(2)+PH_(3) to` |
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Answer» `(i) l_(2)+10HNO_(3) (conc.) to 2HIO_(3)+10NO_(2)+4H_(2)O` (ii) `3HgCl_(2)+2PH_(3) to Hg_(3)P_(2)+6HCl` |
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| 1737. |
Which is least basic ? `SbH_(3),PH_(3), NH_(3),AsH_(3)` ? |
| Answer» A compound which is most acidic is obviously least basic. Since `SbH_(3)` is most acidic, therefore, is it least basic.or As the size of the atom increases, electron density on the central atom decrease and hence basicity decreases. Thus `SbH_(3)` is least basic. | |
| 1738. |
In what way can it be proved that `PH_(3)` is basic in nature ? |
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Answer» `PH_(3)` reacts with acids like HI to form `PH_(4)` I which shows that it is basic in nature. `PH_(3)+HI to PH_(4)I` Due to lone pair on phosphorus atom, `PH_(3)` is acting as a Lewis base in the above reaction. |
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| 1739. |
By means of a balanced equations show how `B(OH)_(3` behaves as an acid in water. |
| Answer» `B(OH)_(3) + 2HOH rarr [B(OH)_(4)]^(-) + H_(3)O^(+)` | |
| 1740. |
When treated with conc. `HNO_(3)` aluminium is rendered `"………….."` due to the formation of protective layer of its `"………….."` on the surface of the metal. |
| Answer» Correct Answer - passive, oxide | |
| 1741. |
One mole of calciium phosphide on reaction with excess water givesA. One mole of phosphineB. Two moles of phosphoric acidC. Two moles of phosphineD. One mole of phosphorus pentoxide |
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Answer» Correct Answer - A::C `Ca_(3)P_(2)+3H_(2)Orarr3Ca(OH)_(2)+2PH_(3)` |
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| 1742. |
One mole of sodium phosphide on reaction with excess of water givesA. one mole of phosphineB. two moles of phosphoric acidC. two moles of phosphineD. one mole of phosphorus oxide |
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Answer» Correct Answer - A `{:(Na_3P +,3H-OHto,3NaOH+,PH_3),("1 Mole","3 Mole","3 Mole","1 Mole"):}` |
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| 1743. |
The HNH angle is higher than `HPH`, HAsH and HSbH angles - Why ? |
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Answer» The central atom `epsilon` (where, `epsilon` = N, P, As, Sb, Bi) in all given hydrides is `"Sp"^(3)` hybridized However, its electronegativity decreases and atomic size increase on moving down the group. Therefore is a gradual decrease in the force of repulsion between the shared electron pairs around the central atom. Thus, bond angle decreases as we move down the group. `{:("Molecule",,"NH"_(3),,"PH"_(3),,"AsH"_(3),,"SbH"_(3),,"BiH"_(3)),("Bondangle",,107.8^(@),,93.6^(@),,91.8^(@),,91.3^(@),,90^(@)):}` |
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| 1744. |
How do calcium phosphide and heavy water react ? |
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Answer» Calcium phosphide reacts with heavy water to form Deutero phosphine. `"Ca"_(3)P_(2)+6D_(2)O to" Ca (OD)"_(2)+2"PD"_(3)` |
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| 1745. |
Cold solution of barium nitrite on mixing with sulphuric acid produces :A. `BaSO_(4)+HNO_(2)`B. `BaSO_(4)+HNO_(3)`C. `BaSO_(4)+NO_(2)`D. `BaSO_(4)+N_(2)+O_(2)` |
| Answer» Correct Answer - A | |
| 1746. |
In between `P_(4)O_(6) " and " P_(4)O_(10)` Which of the following option is correct ? [State(T) for true and (F) false] (P) Both having cyclic structure. (Q)Both having same number of `p pi-d pi` bonds. (R ) Both having same `P-O-P` bond length. (S) Both having same hybridisation of P atoms.A. TFFTB. TTTTC. TFFFD. FTTT |
| Answer» Correct Answer - A | |
| 1747. |
When chlorine gas is passed through an aqueous solution of a potassium halide in the presence of chloroform, a violet colouration is obtained. On passing more of chlorine water, the violet colour disappears and solution becomes colouless. This thet confirms the presence of ......... in aqueous solution.A. chlorineB. fluorineC. bromineD. iodine |
| Answer» Correct Answer - D | |
| 1748. |
Which of the following sets of elements are called aerogens ?A. He, Ne, ArB. F, Cl, BrC. O, S, SeD. N, P, As |
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Answer» Correct Answer - A As He, Ne , Ar are present in air they are also called aerogens |
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| 1749. |
The formula of sodium perxenate is ______.A. `Na_3XeO_6`B. `Na_4XeO_6`C. `Na_2XeF_8`D. None |
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Answer» Correct Answer - B `Na_4XeO_6 . XeO_6^(-4)` ion is called perxenate ion |
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| 1750. |
The oxidation state of central atom in the anion of compound `NaH_(2)PO_(2)` will be ……… .A. `+3`B. `+5`C. `+1`D. `-3` |
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Answer» Correct Answer - C `overset(+1)(Na)overset(+1)((H)_(2))overset(x)Poverset(-2)O` Here, `(+1)+2(+1)+x+2(-2)=0,i.e.,x=+1`. |
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