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the byoyant force on the body will be 20N AS DISPERSED

This force will be 50-30N= 20Nas Fb= total force in air- force in water

(a) Mercury poisoning

(b) Silica dust

At the surface of the earth a body weighs more, because as we go into mine the acceleration due to gravity decreases.

4) 67% is the correct answer

the percentage loss of the velocity of the colliding body during collision is 67%

Use formula- F = ma200 = 5*a=> a = 200/5=> a = 40m/s^2

gravitational force = (G.m1.m²)/r² = 6.67×10^-11×(1.67 ×10^-27)²/(10^-15)²

Force = 6.67*1.67*1.67 × 10^-31 = 1.86 × 10^-30N

First of all let assume mas of chain hanging down is "m" while it's length is "l".Total length of chain "L" while total mass is "M".So from the given data we know that M is equal to 4kgtotal length=L=2ml = 60 cm = 0.6 m As we know that 1 meter=100cmThus we know thatm= I/L * Mm=(0.6/2 )* 4= 1.2kgIn order to findout the tension of strain the formula is =mg =1.2*10 = 12 Newtonwe know that the tension is equal to force required and 0.6 is actually the displacement because that part is hangingSo also we knowwork done= force*displacementnow as we have readings so just put the valueWork done = 12 * 0.6 = 7.2 JSo the work done in this case will be equal to7.2 J.

Let the elevated point be P

The value of n is 5, as per the final answer.

time t = (v-u )/a = (0-49)/(- 9.8) = 5 t’ = 5 – 1 = 4 v’ = u + at’ = 49 – (9.8) * 4 = 9.8 m/s. ∴ The velocity is 9.8 m/s.

cons

tact velocity

Therefore there will be noacceleration; the ball will move at a constant velocity. The same applies to aprojectile.If we ignore air resistancethen there will be no net force acting on theprojectilein thehorizontaldirection. ... The vertical component of aprojectileis acted upon by gravity.

4. all of these1. when object is moving on circular path.2. when object is in free fall3. when object is in Free fall

wrong answer shishter

true..

In uniform circular motion, the direction of motion of the object keeps changing. Velocity changes with change in direction as it is vector and change in velocity means acceleration. Therefore uniform circular motion is accelerated motion.

thank you

option A is the answer

sisty eight

We know , acceleration is the change in velocity per unit time .e.g an instant time ; a = dv/dt a = dv/dt a∫dt = ∫dv now, integrate a.(t₂ - t₁) = v - u Let (t₂- t₁) = t then, at = v - u v = u + at ___ its a motion equation , _______________________________

now , v = u + at multiply both sides, with dt v.dt = u.dt + at.dt we know, v.dt = S { distance = speed * time } use this S = u(t₂-t₁) + a(t₂-t₁)²/2 hence, S = ut + 1/2at² ___motion, equation.______________________________now, S = ut + 1/2at² ___(1) v = u + atsquaring both sides, v² = u² + a²t² + 2uat v² = u² + 2a{ 1/2at² + ut } from eqn (1) v² = u² + 2aS ____motion equation, __________________________________or we know, v.dv/dx = a ∫v.dv = a∫dx integrate both sides, v² - u² = 2a( x₂ - x₁) Let ( x₂ - x₁) = S v² = u² + 2aS___motion equation

Acceleration = (35-15)/10= 2m sec^-2F= ma= 10*2= 20 N

Alight-emitting diode(LED) is asemiconductorlight sourcethat emits light whencurrentflows through it.Electronsin the semiconductor recombine withelectron holes, releasing energy in the form ofphotons. This effect is calledelectroluminescence.

Light-emitting diodes areusedinapplicationsas diverse as aviation lighting, automotive headlamps, advertising, general lighting, traffic signals, camera flashes, lighted wallpaper and medical devices.

1.to calculate the force or pull of gravity of the planets of the earth, earth included.2)This law also comes in handy when calculating the trajectory of astronomical bodies and to predict there motion.

Kindly replace P, Q and R with A, B and C.

in comparison to weight on earth, weight on the Moon is about 1/6 of (weight on earth ) and 2/5 on Mars. So, a 100 kg person would weigh about 16 kg on the Moon (plus gear) and 40 kg (38 kg exactly) on Mars (plus gear).

Let weight of five friends on earth .... Be.A=50kg B=30kg C=20kg D=60kg E=120kg.. (an assumption)

So as we know that the weight on moon is 1/6th of the weight on earth....

Wm=1/6We

[we is the weight on earth. And wm is the wieght on moon. ]So weight of friends on moon will be...A=1/6*50=8.3kgB=1/6*30=5kgC=1/6*20=3.3kgD=1/6*60=10kgE=1/6*120=20kg

Now,weight of friends on mars will beA= 1/3*50 = 16.6 KgB= 1/3*30 10 KgC=1/3*20 =6.6 KgD= 1/3*60= 20 KgE =1/3*120 = 40 Kg

please give me full information about this question

Ans :- When aforceacts on an object over a distance, it is said to havedone workon the object. Physically, thework doneon an object is the change in kinetic energy that that object experiences.

(3) is correct option

Since, ahorizontal force of 200Nis used to move a wooden cabinet, thus a frictionforce of 200Nwill be exerted on the cabinet. Because according to third law of motion, an equal magnitude offorcewill be applied in the opposite direction

option d is correct

(d) is the right answer

answer is C ) k,A because these determines the force along with the amplitude of the motion on the object

option d answer right

d is the right answer.....

Option c is the right answer

c.......

...........is the answer

The key concept is that they are asking about the TOTAL ENERGY. Correct option is (c). See proof below.

option B) is the correct answer

option d is the correct answer

option A ) is the correct answer

the answer coild be option a

Consider an object which has travelled displacement s in the time t under uniform acceleration a.Let intial velocity of the object be u and the final velocity v.s=1/2t(u+v)-1from the veocity relationv=u+at -2substitute 1 in 2s=1/2t(u+u+at)=1/2t(2u+at)s=ut+1/2at^2

ty

Consider an object which has travelled displacement s in the time t under uniform acceleration a.Let intial velocity of the object be u and the final velocity v.s=1/2t(u+v)-1from the veocity relationv=u+at -2substitute 1 in 2s=1/2t(u+u+at)=1/2t(2u+at)s=ut+1/2at^2