InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 451. |
A converging lens of focal length 20 cm is placed in contact with a converging lens of focallength 30 cm. The focal length of this combination is: |
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Answer» both are concave lens |
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| 452. |
104. There are two lenses. One is convex of focal length20 cm and another is concave of focal length 25 cm.What is focal length of the combination? |
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| 453. |
A convex lens of focal length 20 cm made of glass ofrefractive index 1.5 is immersed in water having refractiveindex 1.33. The change in the focal length of lens is(a) 62.2 cm (b) 5.82 cm (c) 58.2 cm (d) 6.22crm |
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| 454. |
13. Twó neutral particles are kept 1 m apart. Supposebysome mechanism some charge is transferred from onearticle to the other and the electric potential energylost is completely converted into a photon. Calculate thelongest and the next smaller wavelength of the photonpossible. |
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Answer» for smaller wavelength how you can divide by4 |
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| 455. |
55.In the hydrogen atom, an electron makes a transition fromn-2 ton-1. The magnetic field produced by the circulatingelectron at the nucleus(a) decreases 16 times(c) decreases 4 times(b)(d)increases 4 timesincreases 32 times |
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Answer» since the formula of bohr radius = 0.529n²/z so, r ∞ n² also, magnetic field ∞ 1/r=> magnetic field ∞ 1/n² so when n changes from 2 to 1magnetic field changes from 1/2²= 1/4 to 1 so , it increases 4times.. option B But ans is d Here i is not also constant value..... So itink i must e resolve. In n relationship I don't think.. answer should be d..how can it increase by 32times.. Use it Thanks anjum |
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| 456. |
A drop of olive oil of radius 0.30 mm spreads into arectangular film of 30 cm x 15 cm on the watersurface. Estimate the molecular size of olive oil. |
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Answer» Here olive oil spread as a film, supposing it is 1 molecule thick on water surface, then the thickness of the film will give the estimate of diameter of molecule So, we have d = Volume of oil drop ÷ Area of film d = 4/3 π (0.03)³ ÷ π (12)² d = 4/3 (0.000027) ÷ 144 d = 0.000036 ÷ 144 d = 0.00000025 or d = 2.5 x 10^(-7) cm |
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| 457. |
During a heavy rain, hailstones of average size 1.0 cm in diameter fall with an average speed of 20 misSuppose 2000 hailstones strike every square meter of a 10 m x 10 m roof perpendicularly in onesecond and assume that the hailstones do not rebound. Calculate the average torce exerted by thefalling hailstones on the roof. Density of hailstones is 900 ka/m3 take (n 3.14)E-3. |
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| 458. |
Hailstones fall from a certain height. If onlythe hailstones melt on reaching theound, find the height from which they fall.of0gr10 ms-2. L-80 calorie/g and4.2J/calorie)J |
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| 459. |
What is the net flux of a uniform electric field E 3x 10iNC1 through a cube of side 20 cm orentoriented3.hat its faces are parallel to the coordinate planes? |
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| 460. |
b) A 4000kg truck is traveling along a straight, level road at a constant speed of50m/s when the driver removes his foot from the accelerator. After 20s, thetruck's speed is 30m/s. What is the thagnitude of the average net force acting ontic truck during the 20s interval? |
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| 461. |
blem 14.5 Draw the pole zero diagram for the given network function /9)hence obtain i(t).20s |
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| 462. |
oW () Laand - लिLl [edetnd )1 AySOdSIA IRY0802 103 wimasey wmma" AL |
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Answer» Viscosity(μ) has dimension [ML-¹T-¹]Please hit the like button if this helped you |
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| 463. |
Determihe TIl TUExplain the formation of mirage? |
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| 464. |
DI Explain hoto tornatee solar cooker uithn(luminum til |
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Answer» 1.) cardboard box 2.) tin foil... 3.) tape or glue 4.) 2 pots (one ceramic and one clear glass). this first design uses the larger box (the one on the right). just open the box up (flaps and all) and lay it out flat on the floor. then start applying aluminum foil up and down each edge. attach with tape or glue. i just used tape. finally put the last piece of aluminum foil right down the center. then bring it outside and prop it up in a semi-circle (more or less). |
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| 465. |
DatePagegraphprove that1. Without usingDa V-utati se ut til atin zas= vz_uz |
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Answer» a correct answer is (2) |
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| 466. |
If |AxB|=√3(A.B), then the valtue of |A+B| is(1) (A^2+B^2 + AB)^1/2 (2) (A^2+B^2 +AB/√3)^1/2(3) A+B(4) (A^2+B^2 +√3AB)1/2 |
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Answer» |A×B| = √3(A•B) => ABsin∅ = √3ABcos∅=> sin∅/cos∅ = √3 => tan∅ = √3 .. so, angle between them = 60° now, |A+B| = √A²+B²+2ABcos60 = √A²+B²+AB option 1 |
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| 467. |
91.Average velocity of a particle executing SHM inone complete vibration is:A2zeroAωAω |
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Answer» velocity = Awcoswt as coswt average value in one complete vibration is zero so average velocity = 0 2) is the correct answer = zero 2)zero this right answer |
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| 468. |
The potential energy of a particle executing SHMchanges from maximum to minimum in 5s. Then theperiod of SHM is(a) 5s(c) 15s14.(b) 10 s(d) 20 s |
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Answer» The correct option is (d) . As it takes 4 rounds between maximum and minimum.So, 4×5s= 20 s |
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| 469. |
61.A particle executing SHM has an acceleration of64 cm/s” when its displacement is 4 cm. Its time periodin second isb) πd) 2 0 |
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Answer» Ans:-a)...................... a is the right answer |
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| 470. |
The shortest distance travelled by a particleexecuting SHM from mean position in 2seconds is equal to (root3/2) times it'samplitude. Determine it's time period |
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Answer» can you get the answer in cos function? |
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| 471. |
In 10 minutes, a car with speed of 60 kmh^-1travels a distance of - |
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Answer» 1/6 hour in 10minutes speed = distance /time60= x/1/6x= 60/610km In 10 minutes , a car with |
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| 472. |
The kinetic energy of a particle executing SHM is 16 Jwhen it is in its mean position. If the amplitude ofoscillations is 25 cm, and the mass of the particle is5.12 kg, the time period of its oscillation is(a) -s(b) 2Ď s(c) 20ms(d) 5Ď s |
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| 473. |
When the potential energy of a particle executingSHM is one fourth of its maximum value during theoscillation, the displacement of the particle from theequilibrium position in terms of its amplitude a is(a) a/4(c) a/2(b) a/3(d) 2a/3 |
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| 474. |
% A car moves with a speed of 60 km h-' for 20 min and then at a speed of 30 km hr for the next 20 min.The total distance covered by the car is(1) 10 km(2) 20 km(4) 40 km330 km |
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| 475. |
A car covers the first half of the distance betweentwo places at a speed of 40 km/hr and the second halfat 60 km/hr. The average speed of the car is(1) 100 km/hr(3) 50 km/hr(2) 55 km/hr(4) 48 km/hr |
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| 476. |
Example 3.11 A car covers the first half of the distance betweentwo places at a speed of 40 km/h and second half at 60 km/hCalculate the average speed of the car. |
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Answer» v1 = 40 km/h v2 = 60 km /hAverage speed v = (v1 + v2)/2 v = (40 + 60)/2= 50 km /h |
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| 477. |
100.A train covers the first half of the distance betweentwo stations at a speed of 40 km/h and the otherhalf at 60 km/h. Then its average speed is -(1) 50 km/lh(3) 52 km/h(2) 48 km/h(4) 100 km/h |
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Answer» Let the total distance be D now time taken to cover first half =( D/2)/(40)and time taken to cover 2nd half = (D/2)/(60) total time taken = D/80 +D/120 = 5D/240 = D/48 so, avg. speed = distance/(time) = D/(D/48) = 48km/h I have done that same thing in shorter time with help of formula 2.v1.v2/v1+v2 |
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| 478. |
chae poses o |
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Answer» Is many definition right or wrong ? yes, your definition is right. |
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| 479. |
A car moves a distance of 200m. It coversthe first half of the distance at speed40km/h and the second half of distance atspeed v. The average speed is 48km/hFind the value of v.(a) 56 km/h (b) 60 km/h(c) 50 km/h(d) 48 km/h |
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Answer» The answer is Option B pwolichu |
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| 480. |
A man is 25m behind a bus, when bus startsacceleration at 2m/s and man starts moving withconstant velocity of 10 m/s. Tine taken by him toboard the bus is(a) 2 s(c) 46o(d) 5 s v |
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Answer» Let time taken by man = time taken by bus =xfor bus:u=0a=2m/s²t=xS=ut+1/2at² =o×x +1/2×2×x² =x²for man :v=10m/st=xS=v×t = 10xdistance travelled by man - distance travelled by bus =25so, 10x-x² =25x²-10x+25=0(x-5)(x-5)=0x=5minimum time = 5sec hit like if you find it useful |
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| 481. |
(a) 32m11. A bus is moving with a speed of 10ms on a straight road. A scooterist wishes toovertake the bus in 100sec. If the bus is at a distance of 1 km from the scooterist withwhat speed should the scooterist chase the bus ? |
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| 482. |
A man is 25m bchind a bus, when bus startsacceleration at 2m/s and man starts moving withconstant velocity of 10 m/s. Time taken by him toboard the bus is(a) 2 s(b) 3s) 5 s |
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Answer» Let time taken by man = time taken by bus =xFor bus:u=0a=2m/s²t=xS=ut+1/2at² =o×x +1/2×2×x² =x²For man :v=10m/st=xS=v×t = 10xdistance travelled by man - distance travelled by bus =25so, 10x-x² =25x²-10x+25=0x²-5x-5x+25=0x(x-5)-5(x-5)=0(x-5)(x-5)=0x=5 time taken = 5sOption d is correct. |
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| 483. |
57. A bus is moving with velocity 10 ms. A scooteristwishes to overtake the bus in 100 secopds. If bus is ata distance of 1 km from the scooterist, with whatvelocity should the scooterist catch the bus:(a) 50 ms(c) 30 ms(b) 40 ms1(d) 20 ms |
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| 484. |
A bus is moving with a speed of 10 ms on astraight road A scooterist wishes to overtake thebus in 100 s If the bus is at a distance of 1 kmfrom the scooterist, with what speed should thescooterist chase the buAIPMT-2009) |
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| 485. |
bus is moving in crowded area what types of motion duet poses |
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Answer» non-uniform motion because bus cannot move with constant speed with equal interval of time |
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| 486. |
8116. An electron talls through a distance of3.2cm in a uniform electric field intensity9.1 x 104NC-Í. Find the time taken byelectron. (2 x 10-95) |
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| 487. |
Calculate the resistance of 0.5 kg wire of copper ofdiameter 8 x 10^-3m. Given density of copper 8900kgm^-3, sp. resistance of copper1.5 x 10^-8 ohm m.[Ans. 3.33 x 10-4 ohm] |
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| 488. |
. An alpha particle enters a hollow tube of 4m lengthwith an initial speed of 1 km/s. It is accelerated inthe tube and comes out of it with a speed of 9 km/s.The time for which it remains inside the tube is(a) 8 x 10-3 s(c) 800 x 10-3(b) 80 x 10-3 s(d) 8 x 10-4 s |
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Answer» v2=u2+2as⇒(9000)2−(1000)2=2×a×4⇒a=107m/s2Now t=v−ua⇒t= 9000−1000107=8×10−4sec |
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| 489. |
Calculate the resistance of 0.5 kg wire of copper ofdiameter 8 x 10^-3 m. Given density of copper 8900kgm^-3, sp. resistance of copper 1.5 x 10^-8 ohm m.3.[Ans. 3.33 x 10-4 ohm] |
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| 490. |
18. A pendulum bob of mass 8 x 10-5kgand carrying charge of 2 x 10-8C is at rest ina uniform horizontal electric field 2 x104Vm-1. Find the tension in the thread.(8.8 x 10-4N) |
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| 491. |
a car travel 100 km distance at a speed of 60 km/h and return with a speed of 40 km/h calculate it's average speed for the whole journey |
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| 492. |
DuLLICIOULOUILLOA car travels 100 km at a speed of 60 km/h and returns with a speed of 40 km/h. Calculate the averagespeed for the whole journey. |
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Answer» Tofal distance covered = (100+ 100) km = 200 kmTotal time taken = (100/60 + 100/40) = ( 5/3 + 5/2) = 25/6 hours.Average speed = (Total Distance÷ Total Time )= (200 ÷ 25/6 )= (200/1 × 6/25) Km/hr= 48 Km/hr . 48 km/HR is right answer |
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| 493. |
a)70D) DU36.A body has started from rest and is accelerated at 4m/s. The distance coveredby the body in first 7s is equal to the distance travelled by it in the last second.Find the total distance travelled by the body.a) 500mb) 1250mc) 625md) 750m |
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| 494. |
From the graph find the total distance travelled by aparticle and its average velocity29.02040 t(s) |
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| 495. |
To estimate the height of a bridge over a river, astone is dropped freely on the river from the bridge.The stone takes 2 s to touch the water surface ofthe river. Calculate the height of the bridge fromthe water level. Take g = 9.8 m/s". |
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| 496. |
and penetratesarest. Find the deceleration.18.) A particle starting from rest moves wiacceleration. If it takes 5 0 s to reach the speed 18.0km/h find (the average velocity during this period,and (b) the distance travelled by the particle during thisperiod.19. A driver takes 0 20 s to apply the brakes after he seesit rhis is called the reaction time of the |
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| 497. |
wo friends A and B are standing a distance x apartan open field and wind is blowing from A to B. A beaa drum and B hears the sound t, time after he sees thievent. A and B interchange their positions and texperiment is repeated. This time B hears the drumtime after he sees the event. Calculate the velocitysound in still air u and the velocity of wind u. Negled4the time light takes in travelling between the finends. 1550. T2. |
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| 498. |
The position-time graph for the motion of a car is given below:a) A far the car travelled in the time interval 2 to 6 s?(b)During which interval of time its speed was more?(c)Calculate the average speed of the car. |
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| 499. |
020. The position-time graph for the motion of a car is given below(a) A far the car travelled in the time interval 2 to 6 s?(b)During which interval of time its speed was more?(c)Calculate the average speed of the car. |
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| 500. |
The position-time graph for the motion of a car is given below:(a) A far the car travelled in the time interval 2 to 6 s?(b)During which interval of time its speed was more?(c)Calculate the average speed of the car.Q20.53- |
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