InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 5701. |
g Where is natural gas found?h Why is CNG being used as a fuel to run aut |
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Answer» Natural gasisfoundin deep underground rock formations or associated with other hydrocarbon reservoirs in coal beds and as methane clathrates |
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| 5702. |
Prrangovda o thei aut which ameng the aboue mctalCannot dluplac, hurhee these metels n the inceastngrT |
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| 5703. |
The equivalent capacitance between the points A and B of five identicalcapacitors each ofcapacity C, will be(1) C/2(2) 5 C(4) 2 C(3) C/5 |
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Answer» thanks |
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| 5704. |
-1)How frequency depends on time period? Write its SI unit.2Wat doen dan bermalaulibrium |
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Answer» Frequency=1/Time Periodsi unit is hertz |
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| 5705. |
A train is travelling at a speed of90 km h-1. Brakes are applied soas to produce a uniformacceleration of - 0.5 m s2. Findhow far the train will go before itis brought to rest. |
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| 5706. |
Sum of the present ages of Ram and Raju is 31. 3 years ago Ram's age was 4 times the age of Raju. Find their present ages. |
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Answer» Let the age of ram be X and age of Raju be y. X+y=31......so X=31-y-------->1 3yrs back X-3=4(y-3) X-3=4y-12 X-4y=-9 Now substitute eqn 1 in this eqn (31-y)-4y=-9 31-5y=-9 -5y=-9-31 5y=40 Y=8 So substitute y=8 in X=31-y X= 31-8 X=23. So ram is 23 and Raju is 8 Thank You So Much |
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| 5707. |
A particle starts from rest and moves with uniform acceleration. Then the ratio of distance in nth secto that in n sec. is-a)n²/2n +1b) 2n-1/n²c) n²/2n-1d) 2n+1/n² |
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| 5708. |
3. A body starting from rest, was observed to cover20 m in 1 second and 40 m during the nextsecond. How far had it travelled before the first[Ans. 2.5 m]observation was taken ? |
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| 5709. |
9. A body is dropped from a balloon which ismoving upward with a speed of10 m/s. The body is dropped when the balloonis at a height of 390 m from thesurface of the earth. Find the approximatetime taken by the body to reach thesurface of the earth. Take g = 10 m/s2.LA10 |
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Answer» First, we write all the known quantitiesa= -10m's^2s= 390 mu= +10m/ss=ut + 1/2at^2s=10t + 5t^2-390=10t + 5t^2-78= 2t - t^2t^2 - 2t - 78 = 0d= b^2 - 4acd= 4 + 312d= 316-b±√d/2a2±2√79/2=1±79. therefore time taken to hit the ground will be 1+√79(In the answer 1 is being added, because it is the time taken to reverse the direction of velocity from upwards to downwards. Aa initially the object is moving upwards and then it starts to fall downwards. |
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| 5710. |
18.An aeroplane fles 400 m north and 300 m south and then flies 1200 m upwards then net displacement isA) 1200 mB) 1300 mC) 1400 mmD) 1500 m |
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Answer» option A must be an answer |
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| 5711. |
An aeroplane flies 400 m north and 300 m south and then flies 1200 mA) 1200 m18.upwards then net displacement is300 nC) 1400 mD) 1500 m |
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Answer» Option (B) is correct. |
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| 5712. |
4.An aeroplane flies 400 m north and 300 m south and thenflies 1200 m upwards then net displacement is [KCET 1999:JIPMER 1999; DCE 2000; AFMC 2003, 04]r (a) 1200 m(b) 1300 m(d) 1500 m(c) 1400 m |
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Answer» 1300m |
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| 5713. |
A car starting from rest and moving with uniformacceleration on a straight road travels for sometimesuch that the paths described by it in the last secondand in the penultimate second of its motion are inthe ratio 4 3, respectively. Calculate the total timetraveled by the bodyla first 20 |
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| 5714. |
ABC is a triangle. If the perpendicular distance from particular point(s) lying in the same plane tothe three sides of the triangle are all equal, then there exist(s)A) one such point only(B) three such points only(D) two such points onlys (C) four such points |
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| 5715. |
9Abus increases its speed from 36 kmh to 72 km/h in 10 seconds. Its acceleration is: |
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| 5716. |
A car increase its s(A) 30 mscrease its speed from 20 kmh- to 50 kmh-in 10 s. its acceleration is -(B)3 ms-(C) 18 ms-2(DX0.83 ms? |
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Answer» O. 83m/s Using formula v = u + at v = final speedu = initial speeda = accelerationt = time taken 50*5/18 = 20*5/18 + a*10a*10= 5/18(50 - 20)a = 5/18 * (30)/10a = 5/6 = 0.83 m/s^2 (D) is correct option |
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| 5717. |
explain how does photoelectric current and kinetic energy of the photoelectrons emitted in a photocell varies if the frequency of incident radiation is doubled but keeping the intensity same show the graphical variation in the about two cases |
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Answer» still more is required if I draw this graph ,I will get only 1\2mark out of 3 mark equation for photoelectric effect from which you can get almost all informations about photoelectric effect. eVo=(1/2)mv( max)^2=h(f-fo)=hf-W=hc[1/(Lambda)-1/(Lambda,o)]. Here, e is electronic charge. m is mass of electron. v(max) is maximum speed of photo electrons. h is Planck's constant. f is frequency of the incident radiation. fo is threshold frequency( minimum frequency at which photoelectric effect starts.) W(=hfo) is work function of photo sensitive surface.( The minimum energy to be spent by electron before emission.) c is velocity of light. Lambda is wave length of incident radiation. Lambda,o is wave length corresponding to threshold frequency. From the above equation, it can be seen immediately that when frequency of incident radiation is f, the maximum kinetic energy is (1/2)mv(max)^2=K1=hf-W………..(1). When frequency is doubled, K2=2hf-W……………….(2). Change in kinetic energy, K2-K1=hf……………….(3) The number of photo electrons determines photo electric current. The number of photo electrons depends on the intensity of incident radiation and NOT on the frequency of incident radiation. Hence, change in frequency will not change the photoelectric current. We know that incident photons with energy hf are absorbed by the electrons of the photosensitive surface. So, electrons get this much energy in the form of kinetic energy,but they are not emitted with the same kinetic energy. This is because electrons are bound in the surface by a kind of potential well. So, before electrons are emitted they have to spend energy to come out from potential well. The minimum amount of energy that electrons have to spend is called work function (W) of the metal. Then, account of energies is hf(gain by electron)-W( spent by electron)=(1/2)mv( max)^2 (maximum kinetic energy of emitted electron ). Note that in the general formula nowhere number of electrons appear. According to photon aspect of light, more the number of photons, more the intensity of light. If the frequency of incident is less than the threshold frequency then with any number of photons( with any intensity) the photo electrons will not be emitted. Also, intensity of light has nothing to do with the frequency of light. The photoelectric effect can be obtained with low enough intensity of light, but, having frequency sufficiently large. this is not the answer related to the question this is CBSE 2017-2018 sample question paper question,question no. is 19 |
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| 5718. |
Find \vec { A } \times \vec { B } \text { if } \vec { A } = \hat { i } - 2 \hat { j } + 4 \hat { k } \text { and } \vec { B } = 2 \hat { i } - \hat { j } + 2 \hat { k } |
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| 5719. |
38. Radius of the curved road on national highwayis R. Width of the road is b. The outer edge ofthe road is raised by h with respect to inneredge so that a car with velocity v can passsafely over it. The value of h is :-Vv²bY Rg2) Reb |
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Answer» option 1 is the right answer v2b/Rg is the right answer 1 is appropriate for the question 1 option 1 is the correct answer |
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| 5720. |
A bird is sitting on a branch of a tree which is 18 m and the speed of wind is 10 ms-1. Suddenly that bird flew from there and that branch has broken then is how much time a leaf of that branch of mass 0.98 gm will touch the ground? |
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| 5721. |
The current ntowing through branch BD for the giventwill be |
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Answer» 0 will be the answerfor currentcurrent flowing through3ohm resistance will be(25-15/6)+(25-30/3) =0 |
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| 5722. |
If the sum of two unit vectors is also a unit vector,then magnitude of their difference and anglebetween the two given unit vectors is(1) V3, 60°(2) 3, 120°(3) V2, 60(4) V2, 120° |
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| 5723. |
of banking is10. What is banking? Why the curved roads are banked? Derive an expression for angle of bankingcurved road. |
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Answer» to this qonton derived |
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| 5724. |
What is banking of road, why it is necessary |
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Answer» Banking of rad means providing slopes to the road such that the outer edge is raised. This is necessary because:1) the force of friction providing the centripetal force is not reliable2) it prevents skidding3) the speed can be increased without skidding4) wear and tear of the tyres can be reduced |
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| 5725. |
roadQ.4. Show that the angle of banking is independent of mass of vehicle. |
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Answer» Let a vehicle of mass 'm ' is moving in circular road of radius r and angle of banking is ∅ as shown in figure. see figure, upward force is balanced by downward force.so, Ncos∅ = mg .....(1) leftward force is balanced by rightward force .so, Nsin∅ = mv²/r ......(2) dividing equations (2) by (1), tan∅ = v²/rg∅ = tan^-1 (v²/rg) here you can see that, angle of banking is independent of mass of vehicle. |
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| 5726. |
The laws of addition of velocities applies only whenthe two velocities are(a) in opposite direction(b) in same direction(c) any preferred direction(d) only when v >>c |
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Answer» when two velocities are in opposite direction so we add them |
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| 5727. |
4.Hexadecimal Number system17, What is function of Half-Adder?) functian af Half.Adder |
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Answer» The half adder adds two one-bit binary numbers (AB). Theoutputis thesumof the two bits (S) and the carry (C). |
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| 5728. |
3R R4 where R' is the rangeC2Abulet is fired from horizontal ground at some angle passes through the pointof the bulet. Assume point of the fire to be origin and the bulet moves in x-y plane with x axis horizontal and y-axis vertically upwards Angle of projection isαπradian. Find α180 |
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| 5729. |
Usha swims in a 90 m longpool. She covers 180 m in one minuteby swimming from one end to the otherand back along the same straight path.Find the average speed and averagevelocity of Usha. |
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Answer» Length of the pool: 90mAverage speed:Speed= Distance/Timespeed=180/60speed=30 m/s Velocity:velocity=displacement/time displacement=0( Since she comes back to the same place) velocity=0 the average speed of usha is 3m s and her average velocity's s |
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| 5730. |
xample8.3 Usha swims in a 90m longpool. She covers 180 m in one minby swimming from one end to the otherand back along the same straight pathFind the average speed and averagevelocity of Usha. |
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Answer» Length of the pool: 90mAverage speed:Speed= Distance/Timespeed=180/60speed=30 m/s Velocity:velocity=displacement/time displacement=0( Since she comes back to the same place) velocity=0 |
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| 5731. |
Example 8.3 Usha swims in a 90 m longpool. She covers 180 m in one minuteby swimming from one end to the otherand back along the same straight path.Find the average speed and averagevelocity of Usha. |
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Answer» Length of the pool: 90mAverage speed:Speed= Distance/Timespeed=180/60speed=30 m/s Velocity:velocity=displacement/time displacement=0( Since she comes back to the same place) velocity=0 |
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| 5732. |
(c) the voltagĂŠ ĂcrUSS/Iesistoi(i) How are image distance, object distance and focal length of a lensrelated to each other? Why focal length of convex lens is considered151(ii) An object is placed at a distance of 20 cm from a concave lens of radiuspositive and that of concave lens is considered negative?of curvature of 20 cm. Find the nature and position of the image.rting Snll's laand with the help of a |
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Answer» The relation is :1/v - 1/u = 1/fFocal lens of a convex lens is positive as its focus is behind the lens whereas the focus of concave lens is in front of the lens so its focal length is negative. |
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| 5733. |
Example 8.3 Usha swims in a 90 m longpool. She covers 180 m in one minuteby swimming from one end to the otherand back along the same straight pathFind the average speed and averagevelocity of Usha. |
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Answer» Length of the pool: 90mAverage speed:Speed= Distance/Timespeed=180/60speed=30 m/s Velocity:velocity=displacement/time displacement=0( Since she comes back to the same place) velocity=0 |
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| 5734. |
Why does a paper catch fire if a concave mirror is used to focus sunlight? |
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Answer» when ligt ray which comes from infinity after reflecting it converge in focus and then large amount of heat occur and it burns the paper but the paper should be kept in focus, thank you |
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| 5735. |
FILL IN THE BLANKS1.2. Real image can be taken on3. Concave mirror has a4. Speed of light is in air..mirror is used in solar farms.focus.mirror. |
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Answer» 1. Concave2. Screens3. Real principal4. 3*10^8 m/sec.5. Converging Mirror |
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| 5736. |
Example 10.1A convex mirror used for rear-view on an automobile has a radiuscurvature of 3.00 m. If a bus is located at 5.00 m from thisofOrfind the position, nature and size of the image. |
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| 5737. |
| What is the physical significancediffraction of lightof |
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Answer» Diffraction refers to various phenomena that occur when a wave encounters an obstacle or a slit. It is defined as the bending of waves around the corners of an obstacle or aperture into the region of geometrical shadow of the obstacle. In classical physics, the diffraction phenomenon is described as the interference of waves according to the Huygens–Fresnel principle that treats each point in the wave-front as a collection of individual spherical wavelets. These characteristic behaviors are exhibited when a wave encounters an obstacle or a slit that is comparable in size to its wavelength. Similar effects occur when a light wave travels through a medium with a varying refractive index, or when a sound wave travels through a medium with varying acoustic impedance. Diffraction has an impact on the acoustic space. Diffraction occurs with all waves, including sound waves, water waves, and electromagnetic waves such as visible light, X-rays and radio waves. What is he physical significance of diffraction of light |
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| 5738. |
the object and image positions.8. The radius of curvature of a convex mirror used as a rear view minror in a moving car is 2.0 m. A truck iscoming from behind it at a distance of 3.5 m. Calculate (a) position, and (b) size, of the image relative to thesize of the truck. What will be the nature of the image ? |
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| 5739. |
1.Write the significance of positive sign of the magnification. |
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Answer» If magnification has a magnitude greater than 1 the image is larger than the object, and an m with a magnitude less than 1 means the image is smaller than the object. If themagnificationispositive, the image is upright compared to the object; if m is negative, the image is inverted compared to the object |
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| 5740. |
3. Does the phrase "direction of zero vector" have physicalsignificance? Discuss in terms of velocity, force etoc. |
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Answer» Although the existence of null vector is essential for vector algebra as it acts as the essential additive inverse, there is no physical significance of null vector. Actually its direction is undeterminable.If a man applies 0 N of force, he is not applying any force so its direction can’t possibly have any physical significance. |
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| 5741. |
A concave mirror used for rear-view on an automobile has a radius of curvature of 3.00m.If a bus is located at 5.00m from this mirror ,find the position, nature and size of the image. |
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Answer» thanks a lot |
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| 5742. |
16.A wheel rotates around a stationary axis so that the rotation angle φ=at, where a=0.20 rad/s. Find the total accelerationa of the point A at the rim at the moment t-2.5s if the linear velocity of the point A at this moment v-0.65 m/s.ends |
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| 5743. |
A convex mirror used for rear-view on an automobile has a radius ofcurvature of 3.00 m. If a bus is located at 5.00 m from this mirror,find the position, nature and size of the image. |
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| 5744. |
a pie 10.A convex mirror used for rear-view on an automobile has a radius ofcurvature of 3.00 m. If a bus is located at 5.00 m from this mirror,find the position, nature and size of the image. |
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Answer» The image is 1.15 m at the back of the mirror. Magnification, m=h'/h=-v/u=-1.15m/(-5.00m)=+0.23 The image is virtual, erect and smaller in size by a factor of 0.23.Read more on Sarthaks.com - https://www.sarthaks.com/22987/a-convex-mirror-used-for-rear-view-on-an-automobile-has-a-radius-of-curvature-of-3-00m |
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| 5745. |
Q9.Explain the physical significance of radius of gyration. |
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Answer» Radius of gyration is the distance from the axis of rotation at which if instead of the whole body, a point object is placed, the system will have the same moment of inertia.It's physical significance can be explained by the fact that if a point object is placed at the radius of gyration, the motion can be considered as that of a point object and not as a continuous body. It represents the stability against the axial force. |
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| 5746. |
2. Give reasons for drop in voltage of a battery |
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Answer» Please like the solution 👍 ✔️ An excessive resistance of your high amperage circuit is an overlooked problem that cancauseyourvoltstodropin yourbatteries. |
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| 5747. |
A car is travelling with linear velocity v on acircular road of radius r. If it is increasing itspeed at the rate of 'a' metre/sec2, then theresultant acceleration will be- |
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| 5748. |
d 10. A body of mass 5 kg is acted upon by twoperpendicular forces 8N and 6 N. Give themagnitude and direction of the acceleration of thebodyAns : 2 ms 2 in the direction of the resultant force |
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| 5749. |
Qus. 9 A rear view mirror used in a bus has a radius of curvature 3.5m . If the driver of the bus locate a car at 10mbehind the bus, find the position, nature and size of the image of the car. |
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Answer» R=3.5 , f=R/2= 1.75mu= -10cm, v=? 1/f =1/v + 1/u1/1.75 = 1/v - 1/10v= 1.5 mmagnification (m)= -v/u =0.15image is real, erect and diminished... |
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| 5750. |
7. The charge is fed into the blast furnace through the -b) Stackd) Tuyerea) Throatc) Bosh |
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Answer» The charge is fed into the blast furnace through the throat. the charge os fed through throat of the furnace because in a blast furnace charge is continuosly supplied through the top of the furnace while the blast of air is blown into lower section of furnace |
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