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-Pressure inside liquids are due to the random movement of the liquid molecules and the weight of the liquid. The pressure inside solids occurs only due to the weight of the solid.-The liquid pressure acts on the sides of the liquid as well as the bottom. The pressure due to solids only appears at the bottom of the solid.

Explanation:Pressure of Liquids

To understand the concept of pressure of liquids, one must first understand the concept of pressure in general. The pressure of a static fluid is equal to the weight of the fluid column above the point the pressure is measured. Therefore, the pressure of a static (non-flowing) fluid is dependent only of the density of the fluid, the gravitational acceleration, the atmospheric pressure and the height of the liquid above the point the pressure is measured. The pressure can also be defined as the force exerted by the collisions of particles. In this sense, the pressure can be calculated using the molecular kinetic theory of gasses and the gas equation. The term “hydro” means water and the term “static” means non-changing. This means hydrostatic pressure is the pressure of the non-flowing water. However, this is also applicable to any fluid including gasses. Since the hydrostatic pressure is the weight of the fluid column above the measured point it can be formulated using P= hdg, where P is the hydrostatic pressure, h is the height of the surface of the fluid form the measured point, d is the density of the fluid and g is the gravitational acceleration. The total pressure on the measured point is the unison of the hydrostatic pressure and the external pressure (i.e. atmospheric pressure) on the fluid surface. The pressure due to a moving fluid varies from that of a static fluid. The Bernoulli theorem is used to calculate the dynamic pressure of non-turbulent incompressible fluids.

Pressure of Solids

The pressure of a solid can also be interpreted using the argument based on liquid pressure. The atoms inside a solid can be considered static. Therefore, no pressure is created by the momentum change of a solid. But the weight of the solid column above a certain point is effective on the said point. Therefore, a pressure inside a solid can appear. However, solids do not expand or contract by large amounts due to this pressure. The pressure on the side of the solid normal to the weight vector is always zero. Therefore, the solid has its own shape unlike liquids, which take the shape of the container.

Thanks Aarya..

distance travelled in east=15*2=30m

distance travelled in north=5*8=40m

since east and north are perpendicular to each other.

So, displacement=sq. root of [(30)^2+(40)^2]=50m

average velocity=dispacement/total time taken=50/(8+2)=5m/s

plsss...answer.........

Displacement is the shortest distance possible between initial and final position.As the athlete is in circular motion , displacement is zero. [ THis is because , the initial and final position is the same ]

Distance covered in 1 round = Circumference of the circle

Circumference of the circle = 2πr

Diameter = 200 mRadius = 100 m

Distance covered in 1 round[ 40 sec ] = 2 × 22/7 × 100 = 628.57 m

Distance covered in 1 sec = 628.57 ÷ 40 = 15.71 m

2min 20 sec = 140 secDistance covered in 140 sec = 15.71 × 140 = 2199.4 m

Image is formed from the mirror at a distance equal and opposite to that of the object-mirror distance.

It means that distance will be doubled that is given in question.

So, image-mirror distance is 10cm, and object image distance is 20cm.

the answer is 10/2 to see his own image

hope it helps u

T=nm*a=ma..........eq 1

Mg-T=maMg-mna

=maMa+mna

=mga(M+nm)

=mga=mg/m+nm

Sub a valve in eq 1

T=nm*a

T=nm*mg/M+nm

Option a is correct na

* sign means

Speed = Distance/Time = 120/4 = 30 km/hr

s=d/t =120/4 =30km/h

Whenreverse bias is increased,the electrons break the covalent bonds due toelectric fieldwhich increases reverse current eventually causing zener breakdown.

From conservation of momentum , the final velocity after the bullet gets embedded is

V' = mu/(m+m) = u/2

now we know tha velocity is = u/2

so, using Newton's 3rd formula of motion, at maximum height , velocity will be 0

=> 0² = (u/2)² -2gH=> H = u²/8g

option C

A cross B = [I j k 2 3 0 3 5 0]I [0] +[0]J + K[10-9)

pure rotational Motion..

Petals, sepals, pistil and stamens

Callyx,corrolla,petal,sepal

कूलॉम-नियम(Coulomb's law) विद्युतआवेशोंके बीच लगने वालेस्थिरविद्युत बलके बारे में एक नियम है जिसे कूलम्ब नामक फ्रांसीसी वैज्ञानिक ने १७८० के दशक में प्रतिपादित किया था। यह नियमविद्युतचुम्बकत्वके सिद्धान्त के विकास के लिये आधार का काम किया। यह नियम अदिश रूप में या सदिश रूप में व्यक्त किया जा सकता है। अदिश रूप में यह नियम निम्नलिखित रूप में है-

दो बिन्दु आवेशों के बीच लगने वाला स्थिरविद्युत बल का मान उन दोनों आवेशों के गुणनफल केसमानुपातीहोता है तथा उन आवेशों के बीच की दूरी के वर्ग केव्युत्क्रमानुपातीहोता है।

Answer: (d) of theseExplanation: Specific resistance depends on the nature of material.

Copper wire is longer than manganin because manganin have high resistance than a copper metal so to become equal resistance copper wire's length should be long because R is directly proportional to length

Distance Traveled150 + 120 = 270-displacement√(150^2 +120^2)=√36900=30√41

correct answer

(i) It states that for a body falling freely the total mechanical energy remains conserved.(ii) Suppose a ball of mass ‘m’ falls under the effect of gravity as shown in figure.Let us find the kinetic and the potential energy of the ball at various points of its free fall. Let the ball fall from point A at a height h above the surface of the earth.At Point A:At point A, the ball is stationary; therefore, its velocity is zero.Therefore, kinetic energy, T = 0 and potential energy, U = mghHence, total mechanical energy at point A isE = T + U = 0 + mgh = mgh… (i)At Point B :Suppose the ball covers a distance x when it moves from A to B. Let v be the velocity of the ball point B. Then by the equation of motion v^2-u^2 = 2aS, we havev^2 - 0 = 2gx or v^2 = 2gx Therefore,Kinetic energy, T = 1/2 mv^2 = 1/2 x m x (2gx)= mgxAnd Potential energy, U = mg (h - x)Hence, total energy at point B isE = T + U = mgx + mg(h-x) = mgh …(ii)At Point C :Suppose the ball covers a distance h when it moves from A to C. Let V be the velocity of the ball at point C just before it touches the ground. Then by the equation of motion v^2 - u^2 = 2aS, we have V^2 - 0 = 2gh or V^2 = 2gh.Therefore,Kinetic energy,T = 1/2 mV^2 = 1/2 x m x (2gh) = mghand Potential energy, U = 0Hence, total energy at point E = T + U= mgh + 0 = mgh… (iii)Thus, it is clear from equations (i), (ii) and (iii), that the total mechanical energy of a freely falling ball remains constant.

X=CaO and Y=Ca(OH)2it is exothermic reaction

Borosilicate Glass

Normal reaction is = mgcos(60) = 2*10*1/2 = 10N

now friction force will act opposite to F so, Friction force = μN = 10*0.4 = 4N

so, work done for distance 2m , in opposite direction will be = -4N*(2) = -8J

option 4

10 ka sure hata go sin cos

Since limiting friction is 12 N, Maxm. Static friction will be 12 N. When force slightly less than 12 N is applied on block A ,block B will move together with block A .

The accln.of the block together will be 12/12 = 1 m/s^2 when the force is applied on A.

If the force is applied on B,Accln. of B will be F/12(if F is the force.)

Now let us consider blockA

Force on the blockA will be( F*4/12 -12)N

If both the blocks are to move together

this must will be equal to zero

F*4/12–12must be equal toor less than zero

F*4/12–12= 0

4F=144

F= 144/4= 36N( F must be less than 36N.

the answer given at back is 24N

thanku

For a freely falling object :a=g;

Initial velocity=u=0 m/s

g=9.8m/s²

from second equation of motion:S=ut+1/2 at²

for First object we get :

h1= gT1²/2

⇒T1=√2h1/g

For second object we geth2=gT2²/2

⇒T2=√2h2/g

T1/T2 =√h1/h2

But here h1= a and h2 =bso, T1/T2=√a/b

d. 6 combinations

Following 6 groups are possoble:

1 single resistor

2 resistors in series

3 resistors in series

2 in parallel

2 in parallel and one in series with that connection

3 in parallel

In parallel the resulting resistance is1/R=1/1+1/1+1/11/R=3R=1/3ohmhencein series =1/3+1/3+1/3=3/3=1ohm

because R(a)=R(b)=R(c)=Rthen R1= R/3R2= R/3R3= R/3

Slope under (v-t) curve gives accelerationa = 0.5m/s²Force = m * a=50 * 0.5=25N

50×2=💯 so option (4) 100 N

total resistance= 1/4.5+1/4.5+1/4.51/R=1/1.5R=1.5V=1.5I=V/R =1.5/1.5I=1

Total resistance =1/4.5 + 1/4.5 +1/4.51/R = 1/ 1.5R= 1.5I=V/RI= 1.5/1.5I=1 ampere

In Parallel connections Voltage across common points is same

Taking V as the potential applied

The Current through 2 Ohm resistor is V/2

The Current through 3 Ohm resistor is V/3

The Current through 4 Ohm resistor is V/4

Hence the ratio of the current in this case is 1/2 : 1/3: 1/4

In Parallel connections Voltage across common points is same

Taking V as the potential applied

The Current through 2 Ohm resistor is V/2

The Current through 3 Ohm resistor is V/3

The Current through4 Ohm resistor is V/4

Hence the ratio oth the current in this case is 1/2 : 1/3: 1/4