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7751.

Define path function and point function

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Path function-depends upon the path at which system arrives at a given state. Example,Work and Heat.Point functions-which does not depend on path.Example, temperature, pressure, density, mass, volume, entropy, internal energy.They are the properties of the system.

7752.

ILUVIUA particle of mass 10 g moves along a circle ofradius 6.4 cm with a constant tangentialacceleration. What is the magnitude of thisacceleration if the kinetic energy of the particlebecomes equal to 8 x 10 J by the end of thesecond revolution after the beginning of themotion?(a) 0.18 m/s2(b) 0.2 m/s?(c) 0.1 m/s?(d) 0.15 m/s(NEET-I 2016)

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7753.

A particle of mass 10 g moves along a circle ofradius 6.4 cm with a constant tangentialacceleration. What is the magnitude of thisacceleration if the kinetic energy of the particlebecomes equal to 8 x 10-4 J by the end of thesecond revolution after the beginning of themotion?

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7754.

A particle moves along a circle of radiusm20h constandtangential acceleration. If the velocity of the particle is 80mls at the end of the second revolution after motion hasbagin, the tangential acceleration is (CBSE(a) 640 π me(c) 40 r mlsPMT 20031(b) 160 π me(d) 40 m/s

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7755.

A particle moves along a straight line such that itsdisplacement at any time t is give by:s (t3- 3t2 +2) m.The displacement when the acceleration becomes zero is:(a) 0 m(c) 3 m(b) 2m(d)-2m

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7756.

particle starting from rest moves with a constantangular acceleration α in a circular path. The time atwhich the magnitudes of tangential and radialacceleration are equal is -1(B) α1(C) Ya(D)a

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7757.

A particle moves in a circle of radius 10 m.Its linear speed is given by vin second and v is in m s-1- 3t where t isdax(a) Find the centripetal and tangentialacceleration at t-2 s.(b) Calculate the angle between theresultant acceleration and the radiusvector.

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7758.

A particle begins to move with a constant tangential acceleration of 0.6 m/s? in a circular path. If it slipswhen its total acceleration becomes 1 m/s?, find the angle in degrees that it would have turned before itstarts to slip..

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7759.

Àparticleof mass 10 g moves along a circle ofradius 6.4 cm with a constant tangentialacceleration. What is the magnitude of thisacceleration if the kinetic energy of the particlebecomes equal to 8 x 104 J by the end of thesecond revolution after the beginning of the[NEET-2016)motion?

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7760.

(3) 10. When pressure remaining constant, at whattemperature will the r.m.s. speed of a gasmolecules increase by 10% of the rms, speed atNTP?(1) 57.3 K(3) 557.3 K(2) 57.3°C(4) -57.3°0C

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1

2

7761.

If the temperature in a room is20 degree celcius. What is the|temperature in degree Fahrenheit?

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7762.

At what temperature will the volumeof a gas be double that at 15degree celcius, pressure remainingconstant?

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7763.

When the temperature of a metalsphere of radius 0.5 may is raisedby 100 degree celcius, the radiusincreases bv 1 cm. Calculate thecoefficient of cubical expansion formetal.

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7764.

A rod is found to be 0.04 cm longerat 30 degree celcius than it is at 10degree celcius. Calculate its length at0 degree celcius

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7765.

2. The structure of a water molecule is shown in figurethe or9-E). Find the distance of the centre of mass of themolecule from the centre of the oxygen atom.t0-100.96 x 10m/104"\096 × 10m4. A unidisc oFigure 9-EI

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7766.

10.45g of water at 50 C in a beaker is cooled when50 g of copper at 18°C is added to it. The contentsare stirred till a final constant temperature is reached.Calculate the final temperature. The specific heatcapacity of copper is 0.39 J g K-1 and that of wateris 4.2 J g-1 K-1. State the assumption used.Ans. 47oc

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7767.

List the characteristics of metal powder

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The main characteristics of metal powders include the particle sizedistribution, particle shape, the surface condition and thestructure of the powder. These impact bulk properties such asreactivity, flow ability, compressibility, porosity and hardenability that all improves as the particle size gets smaller.

7768.

瞽阿1 (g = 9.8 m/s2)[HS '02)

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7769.

i The silve represents toleranee valueLe

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The silver band represents tolerance value 10%

please hit the like button if this helped you

7770.

what is the formula for calculating focal length of concave mirror

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1/f= 1/u+1/v is the correct answer of the given question

7771.

YOUR FRIEND HAS DOUBT HET HERA CONC AVE MieRRレgx NjTRROR ES USED AS REAR VSEM MIRROR그겪 THE VEHICLES, WHAT QUESTION INTLLyOU ASKTOCLARIFY HIS DOUBTS

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only convex mirror is capable of producing large field of view so that number of object is fit in an object.that's why it is used

7772.

joule.a) 36x 10b) 36x10c) 3.6x10d) 3.6 10*

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7773.

(d) A hollow glass sphere which floats with itsentire volume submerged in water at 4°C,sinks when water is heated above 4°C.

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7774.

1. A beam monochrovof monochromatic blue light havingwavelength 4200 A in air travels in water43Its wavelength in water will be

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7775.

)Using dimensions, show that 1 joule10' erg.

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7776.

mass 6 kg ?An object undergoes an acceleration of 8 m/s starting from rest. Find the distancetravelled in one second.

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s=ut+1/2at^2u=0 a=8 t=1ss=1/2*8*(1)^2s=4m

use the formula:S=1/2at^2

your, initial velocity(u)=0 acceleration(a)=8 time(t)=1secyou got final answer=4mS=4m(ans)

7777.

A particle is released from a height h. At acertain height, its KE it two times its potentialenergy. Height and speed of the particle at thatinstant areh gh3"V3(3)2h 2gh(4) 2gh

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Total mechanical energy at hieght=k.e +p.e=mgh(as v=0)total mechanical enegy at hieght at the point=k.e+p.e=k.e+5/2k.e=7/2k.eby law of conservation of energymgh=7/2k.e2*mgh=2*7/2k.emgh=7*1/2mv^2gh=7/2v^22gh/7=v^2square root (velocity at height/7)=vH/3, 2√gH/3 is the ans to ur question

7778.

Conversion of a galvanometer into a voltmeter.

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Since Galvanometer is a very sensitive instrument, therefore it can not measure high potential difference. In order to convert a Galvanometer into voltmeter, a very high resistance known as "series resistance" is connected in series with the galvanometer.

Let resistance of galvanometer = Rgand resistance Rx(high) is connected in series to it. Then combined resistance = (Rg+ Rx).

If potential between the points to be measured = V and if galvanometer gives full-scale deflection, when current "Ig" passes through it. Then,

V = Ig(Rg+ Rx)V = IgRg+ IgRxV – IgRg= IgRxRx= (V – IgRg)/Ig

Thus Rxcan be found.

7779.

2.Two bodies of mass 6 kg and 4 kg are tied to a string as 4koshown in the figure. If the table is smooth and pulleymfrictionless, then acceleration of mass 6 kg will be (g 10m/s2)(A) 60 m/s(C) 6 m/s6kg(B) 40 m/s(D) 4 m/s2

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7780.

eraphat are the advantages of AltenAging current over direct anddatO1applicati on of each아 egon.

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1)We all know that we got ac supply in our homes and we got this supply by transmitting ac over long distances. AC can be transmitted using step up transformers but direct current or dc can not be transmitted by this method.

2)The ac is easy to generate than dc.

3)It is cheaper to generate ac than dc.

4)The ac generators have higher efficiency than dc.

5)The loss of energy during transmission is negligible for ac.

6)The ac can be easily converted into dc.

7)The variation of ac can easily be done using transformers either step up or step down.

8)The value or magnitude of ac can be decreased easily without loss of excess of energy. This can be done by using choke coil.

7781.

0.The conversion ratio of a breeder reactor is

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Conversion ratio is more than 1 of a breeder reactor

7782.

If energy of an electron is 11.375 eV, then its de-Broglie wavelength associated with the moving elec-tron is(1) 32.3 Å(2) 40.5 Å(3) 36 4 Å(4) 3

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LAMDA= h/√(2mE)= (6.626×10^-34)/√(2×9.1×10^-31×11.375×1.6×10^-19)=3.6406×10^-10 m=3.6406 A°

7783.

If stopping potentials corresponding to wavelengths4000 Å and 4500 Å are 13 V and 0.9 V, respectively,then the work function of the metal is

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2.3 ev is correct answer

7784.

(g) Vam- De- graff Generatorवेन डी ग्राफ जेनरेटर।

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AVan de Graaff generatoris anelectrostatic generatorwhich uses a moving belt to accumulateelectric chargeon a hollow metal globe on the top of an insulated column, creating very highelectric potentials. It produces veryhigh voltagedirect current(DC) electricity at low current levels. It was invented by American physicistRobert J. Van de Graaffin 1929.Thepotential differenceachieved by modern Van de Graaff generators can be as much as 5 megavolts. A tabletop version can produce on the order of 100,000 volts and can store enough energy to produce a visible spark. Small Van de Graaff machines are produced for entertainment, and for physics education to teachelectrostatics; larger ones are displayed in somescience museums.

7785.

Q. 4. What is direct current generator?Explain its working and construction.

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DC Generator

A dc generator is anelectrical machinewhich converts mechanical energy intodirect current electricity. This energy conversion is based on the principle of production of dynamically induced emf. This article outlinesbasic construction and working of a DC generator.

Construction Of A DC Machine:

Note:A DC generator can be used as a DC motor without any constructional changes and vice versa is also possible. Thus, a DC generator or aDC motorcan be broadly termed as aDC machine. These basic constructional details are also valid for theconstruction of a DC motor. Hence, let's call this point asconstruction of a DC machineinstead of just 'construction of a dc generator'.

A DC machine consists of two basic parts; stator and rotor. Basic constructional parts of a DC machine are described below.

Yoke:The outer frame of a dc machine is called as yoke. It is made up of cast iron or steel. It not only provides mechanical strength to the whole assembly but also carries the magnetic flux produced by the field winding.

Poles and pole shoes:Poles are joined to the yoke with the help of bolts or welding. They carry field winding and pole shoes are fastened to them. Pole shoes serve two purposes; (i) they support field coils and (ii) spread out the flux in air gap uniformly.

Field winding:They are usually made of copper. Field coils are former wound and placed on each pole and are connected in series. They are wound in such a way that, when energized, they form alternate North and South poles.

Armature core:Armature core is the rotor of a dc machine. It is cylindrical in shape with slots to carry armature winding. The armature is built up of thin laminated circular steel disks for reducing eddy current losses. It may be provided with air ducts for the axial air flow for cooling purposes. Armature is keyed to the shaft.

Armature winding:It is usually a former wound copper coil which rests in armature slots. The armature conductors are insulated from each other and also from the armature core. Armature winding can be wound by one of the two methods; lap winding or wave winding. Double layer lap or wave windings are generally used. A double layer winding means that each armature slot will carry two different coils.

Commutator and brushes:Physical connection to the armature winding is made through a commutator-brush arrangement. The function of a commutator, in a dc generator, is to collect the current generated in armature conductors. Whereas, in case of a dc motor, commutator helps in providing current to the armature conductors. A commutator consists of a set of copper segments which are insulated from each other. The number of segments is equal to the number of armature coils. Each segment is connected to an armature coil and the commutator is keyed to the shaft. Brushes are usually made from carbon or graphite. They rest on commutator segments and slide on the segments when the commutator rotates keeping the physical contact to collect or supply the current.

Working Principle Of A DC Generator:

According toFaraday’s laws of electromagnetic induction, whenever a conductor is placed in a varying magnetic field (OR a conductor is moved in a magnetic field), an emf (electromotive force) gets induced in the conductor. The magnitude of induced emf can be calculated from theemf equation of dc generator. If the conductor is provided with a closed path, the induced current will circulate within the path. In a DC generator, field coils produce an electromagnetic field and the armature conductors are rotated into the field. Thus, an electromagnetically induced emf is generated in the armature conductors. The direction of induced current is given byFleming’s right hand rule.

7786.

-. Afr. st.rぴunrer attains a. maximum-speed ofom Is , what twill be his speed in m/h

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Speed=10m/s

multiply the speed value by 3.6Speed=10×3.6=36Km/hr

7787.

With the help of neat diagram, describe the construction, working and uses of van de Graaff generator.

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7788.

The potential energy of a particle varies withdistance x from a fixed origin as Vawhere A and B are constants. The dimensionsof AB arex +B

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7789.

Describe the Principle, construction and working of Van de Graff generator.

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Theworking of Van de Graaff generatoris based on theprincipleof electrostatic induction and action of points. A hollow metallic sphere A is mounted on insulating pillars as shown in the animation. A pulley B is mounted at the centre of the sphere and another pulley C is mounted near the bottom.

construction

7790.

Will a changed particle move when placed at rest in uniform i) electric field.

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Yes, The charged particle would experience a force in the direction(if +ve)or opposite to the direction(if-ve) of electric field, according to equation ,F= qE(where F and E are vectors).

7791.

7. The position x of a particle with respect to time t along x - axis is given by, x 9t2- t3 where x is inmetres and t in second. What will be the position of this particle when it achieves maximum speed alongthe +x directionA) 32 mm(6) 54 m(C) 81 m(D) 24 m

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7792.

(48) If the position (x) of a particle varies withtime (t) as x = At2 + B. The dimensions of(AB)12 are same as that of(a)Angle(c)Acceleration (d) Distance(b) Velocity

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X = At²+B

so, B should have dimension of L and A should have dimension of L/T² so (√AB) has dimension of L/T , that is Velocity

option B.

7793.

Z ;7 VAN DE GRAAFF GENERATOF

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A Van de Graaff generator is an electrostatic generator which uses a moving belt to accumulate electric charge on a hollow metal globe on the top of an insulated column, creating very high electric potentials. It produces very high voltage direct current electricity at low current levels.

7794.

Quel: 60 for what orientation thus an electricdipol experiences a zoo tongue butnon-zero sorce in a uniform eldefield

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from which chapter tell me

7795.

Q.1The position x of a particle varies with time (t) asx = at - bt. The acceleration at time t of theparticle will be equal to zero, where t is equal to-[AIPMT-1997)(2)(4) zero

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Given, x = at^2 - bt^3

Then, Velocity = dx/dt= 2at - 3bt^2

Acceleration = d^2x/dt^2 = 2a - 6bt

Now, Acceleration = 02a - 6bt = 0t = 2a/6b = a/3b

(3) is correct option

option 3 is correct answer

option 3 is correct using calculas method

7796.

2) In 1729 AD, Pieter Van Musschenbroekused the term 'PHYSICS' for the first time.What was the subject called so far?

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Natural philosophy was earlier name of Physics.

7797.

Q.1 Give reason:1.Large block of stone can be easily lifted while it is in the water

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According to Archimedes principle, a body when immersed in a fluid shows an apparent loss of weight which is equal to the weight of the fluid displaced by the body. So a heavy stone when under water, is acted upon by upthrust due to water , which ultimately reduces the true weight of the stone.

7798.

e “न 22. _ 2 resitanceहल टिक काल लाल_ #स टन ८ दर्द n Facceleli o 51 YL

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7799.

Q.1 Give reason:1. Large block of stone can be easily lifted while it is in the water2. Broad foundations below the buildings and dams.

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1)According to Archimedes principle, a body when immersed in a fluid shows an apparent loss of weight which is equal to the weight of the fluid displaced by the body. So aheavy stonewhen underwater, is acted upon by upthrust due towater, which ultimately reduces the true weight of thestone.

1. According to Archimedes principle, a body when immersed in a fluid shows an apparent loss of weight which is equal to the weight of the fluid displaced by the body. So a heavy stone when under water, is acted upon by upthrust due to water , which ultimately reduces the true weight of the stone.

2.smaller the area - larger the pressure on the surfaceto make sure the foundation of the tall buildings and dams are strong, they are built with a broader basement .so, if the area in the bottom is higher then the pressure exerted by the buildings and dams on the ground would automatically be less .

2) Buildingsare massive structures which exerts tremendous pressure on the ground and likely to sink. To avoid sinking theirfoundationsare madewide, so that pressure on the ground decreases.

7800.

A helicopter is ascending ically with àspeed of 8.0 ms1. At a height of T2 m abovethe earth, a package is drppped from a windowHow much time does i take for the packageto reach the ground?2) 3.23 s2 53 s1) 1.23 s

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