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Resultant F = √5²+5²+2(5)(5)cos(60) = √3*5² =5√3 = 8.662N

thnx

Above reaction is the electrolysis of water.

Magnitude of resultant force isR = √(A^2 + B^2 + 2ABcosX)R = √(5^2 + 5^2 + 2*5*5*cos60)R = √(50 + 25)R = √(75)R = 5√3

Aresultant forceis the single force and associatedtorqueobtained by combining a system offorcesand torques acting on a rigid body. The defining feature of a resultant force, or resultant force-torque, is that it has the same effect on the rigid body as the original system of forces.[1]

The point of application of the resultant force determines its associated torque. The termresultant forceshould be understood to refer to both the forces and torques acting on arigid body, which is why some use the term

Let the magnitudes of the two equal forces be x.Suppose they make a right triangle..with hypotenuse as 14.14 N..(as resultant is the closing side according to triangle law of vector addition).

By using Pythagoras theorem

14.14^2=x^2+x^2

On solving ,we get

x=9.906 N

hence x~10N

Letboththeequalforces beFF

The resultant​ will be

=√(F²+F²+2F.F.cos(θ))=√(F²+F²+2F.F.cos(θ))(θis the angle​ between the forces)

=√(2F²+0)=√(2F²+0)(cos(90) is 0)

=√2.F=√2.F

=>√2.F=1414=>√2.F=1414

=>F=1.414∗1000/√2=>F=1.414∗1000/√2

=>F=1000N

I think the correct option must be (d)

sry in the above answer I have done some mistake.The correct answer is 10N

please like the solution thank you so much

let vectors be 3x and 5x√3x^2+5x^2+2*3x*5x*cos60=28√9x^2+25x^2+15x^2=28√49x^2=28X=28/7=4hence each force will be3x=3*4=125x=5*4=20

The resultant force is given by

Fr = √[5²+5² +2(5)(5)cos(π/3) ] = √25+25+25 = √75N

Becauseour bodiesneed to disperse heat, and they can't do that effectively when the airtemperatureis close toour body temperature.Ourmuscles and metabolism generate heat continuously.

correct

let me know if you get stuck somewhere..

I think 8 is the correct answer pls inform me whether i am right or not

yes it is right

=9.375×100×100÷2(lb+bh+hl)=9.375×100×100÷2(22.5×10+10×7.5+7.5×22.5)=100

wrong answer answer is 16.8 Newton

Temperature in Fahrenheit= [9(30)+160]/5= 86°F

dont know this is not an important question

Here A = πr^2 Differentiating both sides w.r.t x dA/dr = 2πr Now dA/dr = (dA/dt)/(dr/dt) = 2πr So dA/dt = 2πr (dr/dt)

Suppose that the radius r and surface area S = 4r2 of a sphere are differentiable functions of t. Write anequation that relates dtds to dtdr .

H-1. If function is given y = 1 – x2 then find out maximum value of this function.

. If function is given y = 1 – x2 then find out maximum value of this function.

If function is given y = 1 – x2 then find out maximum value of this function

273+27=300k300 Kelvin is the answer

Radius of curvature = 40cm

focal length = 40cm- 20cm= 20cm

Distance between mirror and object = 10cm

Position is between focus and pole

Nature is virtual and erect.

Magnification is greater than 1.

mass-----kg------measure of inertia

weight-----N------zero at centre

acceleration due to gravity-------m/s^2------depends on height

Gravitational constant--------Nm^2/kg^2------same in the intire universe....

144J is the answer of your question

According to 1st law of thermodynamicsdU = q + W

8.4 kJ = (20 × 4.2 kJ) + WW = 8.4 kJ - 84 kJW = -75.6 kJW = -75.6/4.2 = -18 kcal

Work done by system is 18 kcal

The focal length of the lens is the distance between the lens and the image sensor when the subject is in focus, usually stated in millimeters (e.g., 28 mm, 50 mm, or 100 mm). In the case of zoom lenses, both the minimum and maximum focal lengths are stated, for example 18–55 mm.

we know,2f = c

Where, f = focal length c = radius of curvature

f = c/2

f = 40/2

f = 20 cm

thank uu so much g

-0.5D will right answer

-0.5 dioptre is the correct answer of the given question

when the system is at rest tension= weight of the body=mg

so, t1=5*10=50,likewise t2=20 and t3=30(unit=N)

when the system is acclerated upwards a pseudo force acts on the body downwards so,tension=mg+ma

t1=5*10+5*2=60N,likewise t2=24N and t3=36N

0.25 meter is the right answer

Let it accelerates with say ‘a’ in time ‘x’ then it reaches a velocity ‘v’ and continues motion for time ‘8x’ abd finally then retards with ‘b’ in time ‘x’.

v = 0 + ax

=> v = ax

=> 60 = ax

=> a = 60/x

And,

0 = v – bx

=> b = 60/x

Distance covered in time of acceleration,

S1= 0 + ½ at2

=> S1= ½ ax2= ½ × 60/x × x2= 30x

Distance covered while moving with constant velocity is,

S2= vt = 60 × 8x = 480x

Distance covered in time of retardation,

02= v2- 2bS3

=> S3= 602/(2 × 60/x)

=> S3= 30x

So, total distance = 30x + 480x + 30x = 540x

Total time = x + 8x + x = 10x

average velocity = 540x/10x = 54 km/h

very complicated method

100/80 - 100/50 dioptres i.e. -0.75

radius of curvature = 2×focal length of convex mirror= 2×15= 30

15 m is correct answer

radius of curvature =2*focal length of convex mirror =2*15=30cm.

30 is the correct answer

Apply Archimedes principle when system is at rest,

weight of the block = Buoyant force by liquid

pb V g =pLV/2 g

so

pb/pL =1/2

Now, when system accelerates upward with g/3 draw FBD of the block, Buoyant force upwards and weight downwards

Being part of the system block also goes up with g/3,

making equation from 2ndlaw of motion

Fb- Mg = Mg/3

Fb= 4Mg/3

pliquidVvolume of block immersedg = 4/3p blockVtotal volume of the block g

hence

Vvolume of block immersed /Vtotal volume of the block = 2/3

C=20cmF=C/2 =20/2F=10cmV=8cm

1/F =1/V +1/U1/10 =1/8 +1/U1/10 - 1/8 = 1/U5-4/40 =1/U1/40 =1/UhenceU =40cmthe distance of object from mirror is 40cm

G:The gravitational constant, also known as the universal gravitational constant, or as Newton's constant, denoted by the letter G, Its measured value isapproximately 6.674×10−11 m3⋅kg−1⋅s−2.

Atransformerthat increases voltage from primary to secondary (more secondary winding turns than primary winding turns) is called astep-up transformer.