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S=10^-3/0.0075*12=5*10^-3ohm

hence R=3988ohm

TheChittagong armoury raid,also known as theChittagong uprising, was an attempt on 18 April 1930 to raid the armoury of police and auxiliary forces from theChittagongarmoury in theBengal PresidencyofBritish India(now inBangladesh) byarmed Indian independence fightersled bySurya Sen.

The history of the Chittagong Armoury Raids, showed the extreme bravery of the Bengali race as pioneers of the armedIndian revolutionary movementuntil it moved to the north in the U P and Punjab During 1912-1947, the Sikh population of India was only 1.1 per cent, but 75 per cent of the revolutionaries serving in prison wereSikhs.

The Chittagong Armoury Raids of 1930 were carried bymany men and two women, who were enthused with patriotism. The revolutionaries, four Bengalis and one domiciled northern Indian and sixty-one students between16-18, titled themselves Indian Republican Army (IRA) based on theIrish Republican Army (IRA).

The uprising was a simulation of the Irish “Easter Uprising” in Dublin. They even chose the Easter week of 1930 on the night of April 18, to strike at the British Armoury; Telephone exchange and Telegraph office; and the European Club inChittagong.

Another group severed the rail connections. They planned to hold the town for a week, like the Irish Republican Army that heldDublinfor one week. Theirs was “do and die” and “not to do and die”.

This incredibly brave volunteer Army though small in number, were armed and trained, willing to go down fighting like the Dubliners did. Their leaflet proclaimingIndia’s freedom was a carbon copy of the Proclamation of Independence, declared on behalf of the Provisional of theIrishRepublicby Patrick Pearse on the steps ofDublin’s General Post Office, fourteen years before the Armoury raids.

shaft c moves very fast then b shaft and then the last shaft c

Shaft C will turn slowly as it has to turn shaft A and B also.

shaft c will turn most slowly compares to shaft a and b

shaft C will turn slowly as compared to shaft A & B

increasing shunt resistance is the correct answer

Range of ammeter can be increased by increase or decreasing shunt resistance mcq

increasing the shunt resistance

Thecontact angleis theangle, conventionally measured through the liquid, where aliquid–vaporinterfacemeets asolidsurface. It quantifies thewettabilityof a solid surface by a liquid via the Young equation. A given system of solid, liquid, and vapor at a given temperature and pressure has a unique equilibrium contact angle. However, in practice a dynamic phenomenon ofcontact angle hysteresisis often observed, ranging from the advancing (maximal) contact angle to the receding (minimal) contact angle The equilibrium contact is within those values, and can becalculated from them.

Bhai full answer do

1

Option (4) is correct.

thank u

Voltage in resistance will be π/2 times.. ahead to capacitor.

but in series the current should be in same phase..

so, option A.

F=q1q2/r2Force is measure in dyn = g · cm/s^2,ris measured in cm, and the units of the two charges (called esu or statcoulombs [statC]) must be the same. In order for the units to manipulate algebraically correctly, the unit of electric charge must becm3/2g1/2s−1cm3/2g1/2s−1. This use of Coulomb’s law is exactly what one branch of CGS users did, resulting in a system called the electrostatic CGS units.

Ans :- Themoon'sorbit carries it around Earth's sky once a month, because themoontakes about a month to orbit Earth. So themoonmoves – with respect to the fixed stars – by about 12 to 13 degreeseach day. The moon'sorbital motion carries it eastward in Earth's sky.

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option 3 is the answer

Total length discovered by train=850m+150m=1000m

Velocity=Dispacement/time

t=s/v

t=1000m / (12.5m/s)

t=80s

Time taken to cross the bridge is 80s

Total distance covered= Length of the bridge + length of train =100+200= 300m Speed of train = 72 km/hr= 72*5/18= 20 m/s

Time taken = 300/20= 15 seconds.

Using,v = u + at

v = 15 m/su = 5 m/st = 5 s

15 = 5 + a*510 = 5aa = 10/5 = 2 m/s^2

Now, using s = ut + 1/2 at^2 = 5*5 + 1/2 * 2 * 5*5 = 25 + 25 = 50 m

Therefore,Displacement = 50 m

(a) is correct option

akhil , because there is no. change in direction of Velocity in 100m

option c

option c

thanku

sin20 = sin(90-70) = cos70 cos20 = cos(90-70) = sin70

(sin20*sin20+sin70*sin70)/(cos20*cos20+cos70*cos70) + (sin(90-t)sint)/tant + (cos(90-t)cost)/cott

= (sin20*sin20+cos20*cos20)/(cos20*cos20+sin20*sin20) + (costsint)/(sint/cost) + (sintcost)/(cost/sint)

= 1/1 + cost*cost + sint*sint = 1 + 1 = 2

Using, v = u + at

v = final velocity u = initial velocity t = time taken a = acceleration

v = 54 km/hr = 54*5/18 = 3*5 = 15 m/su = 0a = 0.5 m/s^2

15 = 0 + 0.5*tt = 15/0.5t = 150/5 = 30 s

Therefore, Cycle reaches foot of the hill in 30 s

(a) is correct option

Theconservation of energy principlestates that energy can neither be destroyed nor created. Instead, energy just transforms from one form into another. So what exactly is energy transformation? Well, as you might guess,energy transformationis defined as the process of changing energy from one form to another.

There are so many different kinds of energy that can transform from one form to another. There is energy from chemical reactions calledchemical energy, energy from thermal processes calledheat energy, and energy from charged particles calledelectrical energy. The processes offission, which is splitting atoms, andfusion, which is combining atoms, give us another type of energy callednuclear energy. And finally, the energy of motion, kinetic energy, and the energy associated with position, potential energy, are collectively calledmechanical energy.

That sounds like quite a lot, doesn't it? Well it is, but don't worry, it's actually all pretty easy to remember. Next, we'll explore all of these kinds of possible transformations in more detail.

Different Types of Energy TransformationsChemical energyis the energy stored within a substance through the bonds of chemical compounds. The energy stored in these chemical bonds can be released and transformed during any type of chemical reaction.

Think of when you're hungry. When you eat a piece of bread to satisfy this hunger, your body breaks down the chemical bonds of the bread and uses it to supply energy to your body. In this process, the chemical energy is transformed into mechanical energy, which you use to move, and which we'll cover in more detail in a moment. It also transforms it intothermal energy, which is created through the metabolic processes in your body to generate heat. Most of the time, chemical energy is released in the form of heat, and this transformation from chemical energy to heat, or thermal energy, is called anexothermic reaction.

Next, there are two main types ofmechanical energy: kinetic energy and potential energy.Kinetic energyis the energy associated with the motion of an object. Therefore, any object that moves has kinetic energy. Likewise, there are two types ofpotential energy: gravitational potential energy and elastic potential energy.Gravitational potential energyis associated with the energy stored by an object because of its location above the ground.Elastic potential energyis the energy stored by any object that can stretch or compress. Potential energy can be converted to kinetic energy and vice versa.

For example, when you do a death-defying bungee jump off of a bridge, you are executing a variety of energy transformations. First, as you prepare to jump, you have gravitational potential energy - the bungee cord is slack so there is no elastic potential energy. Once you jump, you convert this gravitational potential energy into kinetic energy as you fall down. At the same time, the bungee cord begins to stretch out. As the cord stretches, it begins to store elastic potential energy. You stop at the very bottom when the cord is fully stretched out, so at this point, you have elastic potential energy. The cord then whips you back up, thereby converting the stored elastic potential energy into kinetic energy and gravitational potential energy. The process then repeats.

Electrical energyis the energy carried by charged particles as they move around a conductor. A perfect example of electrical energy being released is during a lightning storm. A lightning strike on a tree is an example of electrical energy being transformed into heat or thermal energy. The tree becomes hot and may even burn as a result of the electrical discharge.

Chemical energy can also be converted into electrical energy. For example, the chemical energy in a battery is converted into electrical energy. The electrical energy, which involves the motion of electrical charges or currents, can be used to power everyday devices like computers and flashlights.

power is said to be of 1 kilowatt 1000 joule of work performed in 1 hour.1 kWh= 1 kW × 1 hr = 1000 watt × 3600 s(1 kW=1000 watt, 1 hr=3600) =3600×1000 joule =3.6×10^6 jouleHence Proved

Power is the rate of work done.Power = 2984 J s-¹= 4 horsepower. [1 horse power= 746W]

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acceleration is f = at

=> v is integration of f = at²/2

so, V -u = at²/2=> V = u+at²/2

option 2

the (2) option is correct as it simply signifies that acceleration is change of velocity.

answer us 4

4) is the corrected answer.

hence, option (b) is correct.

We know that the acceleration due to gravity can be described asg = GM/R^2Mass of the planets: M1 = density*volume = d*(4/3*pi*r1^3)M2 = d*(4/3*pi*r2^3)Now, g1 = 4(G*d*pi*r1^3)/(3r1^2) = 4/3*G*d*r1And g2 = 4(G*d*pi*r2^3)/(3r2^2) = 4/3*G*d*r2Now the ratio of acceleration due to gravityWe get, g1/g2 = 4/3*G*d*r1/4/3*G*d*r2 = r1/r2=1/2

hence, acceleration due to gravity on the planet are in the ratio of 1:2 option (a)

Gravitational potential energy , U = GMm / r.For calculating the weight at distance 2r from centre of earth , we need to get m*g.But here acceleration due to gravity , g is not equal to 9.8 m/s^-2.Calculation of g can be done using the formula :-g = GM / r^2Therefore, the value of g at a distance of R= GM / R^2Thus , weight of the body at a distance R from the body = mg = GMm / R=- Ur/R

B) is correct answer

from where did u find this ans

thanks

thanks

Let the force due to buoyancy be B.

In the first case the equation will be

Mg - B = Ma

In the second case the equation will be

B - (M-m)g = (M-m)a

Since the volume is unchanged, the force of Buoyancy remains unchanged as same amount of air is displaced even now and the new mass is (M-m)

Adding the two equations we get,

mg = (2M-m)a

or m(g+s)=2Ms

or m=2Ma/(g+a)

Let the force due to buoyancy be B.

In the first case the equation will be

Mg - B = Ma

In the second case the equation will be

B - (M-m)g = (M-m)a

Since the volume is unchanged, the force of Buoyancy remains unchanged as same amount of air is displaced even now and the new mass is (M-m)

Adding the two equations we get,

mg = (2M-m)a

or m(g+a)=2Ma

or m=2Ma/(g+a)