InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 11801. |
A body of mass 40 gm is moving with a constant velocity of 2 cm/sec on a horizontal frictionlessforce on the table is-(1)39200 dyne(3) 80 dyne(4) zero dyne(2) 160 dyne |
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Answer» Force on the table is given by F =mg=40 x 980=39200 dynes Zero dyne because in ques. they mentioned that it moving with const.velocity therefore acc. is zero so force = 0 dyne |
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| 11802. |
Q.9A body of mass 40 gm is moving with a constantvelocity of 2 cm/sec on a horizontal frictionless table.The force on the table is -(1) 39200 dyne (2) 160 dyne(3) 80 dyne(4) zero dyne |
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Answer» 80 dyne ( F=ma, so 40* 2= 80 dyne ) f= m * a =mv/t for one second is t so f= 40*2 gm cm per second f= 40*10 gm cm person ie 80 |
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| 11803. |
17Find the current drawn from the battery by network offour resistors shown in the figure. CBSE 2015N410221022102 NSionDK3 V |
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Answer» 1/R=1/20+1/20R=10I=3/RI=3/10I=0.3amp A proton,deutron,and alpha particle are infinity uniform magnetic field with same speed and perpendicular to magnetic field.which particle circulate in the field with more frequency and more radius?? |
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| 11804. |
7.A rain drop of radius 0.3 mm has a terminal velocity in air - 1 ms-1, The viscous force on it is(1) 101.73 x 10-4 dyne (2) 101.73 x 10-5 dyne (3) 16.95 x 10-4 dyne (4)16.95 x 103 dyne |
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Answer» how u got coefficient of dynamic viscosity formula means value of that |
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| 11805. |
A metal ball falls from a height 1 m onto a steelplate and jumps up to a height of 0.81 m. Find thecoefficient of restitution.(Ans: 0.9) |
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Answer» tx |
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| 11806. |
13. A metallice sphere of volume V falls through glycerine with aterminal velocity 2 ms. If we drop a ball of volume 8V of samemetal into a column of glycerine, the terminal velocity of the ballwill bea. 2 ms b. 2 ms'd. 2 ms&msWinter in flowing through a horizontal tube. The pressure of the |
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Answer» v'=4vhencev'=2*4=8m/s (c) is a correct answer (c) is a correct answer |
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| 11807. |
A metal ball falls from a height of 32 metre on a steel plate. If the coefficient of restitution is 0 5. to what heighwill the ball rise after second bounce(A) 2 m(B) 4 m(C) 8 m(D) 16 m |
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| 11808. |
163. A capacitor is made of a flat plate of area A andasecond plate having a stair like structure as shownin Fig. 1(d).65. The width of each stair is a andthe height is b. Find the capacitance of theassembly. |
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| 11809. |
दी...” .... ८... “ 2ot drond 3Py Ho 3 |
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Answer» The Maxwell right hand thumb rule indicates the direction of the magnetic field in a direction of current. If the thumb of the right hand points along the direction of current, then the remaining curled fingers of the same hand gives the direction of the magnetic field due to the current. When the position of the thumb will be upward, the curled fingers will be anti-clockwise and the magnetic field will be anti-clockwise too and vise versa. |
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| 11810. |
12]) The speed of light is 3 x 108 m/s. Calculate the frequency of yellow light of wavelength12)6 x 107 m. |
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| 11811. |
A glass prism deviates the red and the blue rays through 10°and 12°, respectively. A second prism of equal angle deviatesthem through 8° and 10° respectively. Find the ratio of theirdispersive powers.Ans. 9: 1]I gass nrism shows |
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| 11812. |
8. A milk mari adds a very small amount of baking soda to fresh milk.a) Why does he shift the pH of the fresh milk from 6 to slightly alkaline ?b) Why does this milk take a long time to set as curd ? |
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| 11813. |
Newton's rings |
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Answer» Newton's ringsis a phenomenon in which an interference pattern is created by the reflection of light between two surfaces—a spherical surface and an adjacent touching flat surface. It is named for IsaacNewton, who first studied the effect in 1717. Go through the text |
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| 11814. |
7Figure shows two blocks A and B of same mby a light string passing over a massless smooth puliley The block isattached to a spring of spring constant 40 N/m whosafixed to a support 04 m above the horizontal surface Initiallyspring is unstretched and vertical when the system is released tomove. The velocity of the block A at the instant it breaks of from thesurface is (lerigth of the spring in unstretched state 40cm,g 10m/s?)(A) 0 5 m/sec0 32 kg connected40 om(D) 2 m/sec(C) 1.5 m/secSpace for Rough Worko(B) 1 m/sec |
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Answer» sir please solution dijiyega |
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| 11815. |
10. A block of mass M is hanging over a smooth and lightpulley through a light string. The other end of the stringis pulled by a constant force F. The kinetic energy ofthe block increases by 20 J in 1 s.(a) The tension in the string is Mg.(b) The tension in the string is F.(c) The work done by the tension on the block is 20in the above 1 s.id) The work done by the force of gravity is -20 J in theabove 1 s. |
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| 11816. |
Two bodies of masses m and 3m are connected bya light string passing over a smooth pulley. Duringthe ensuing motion the acceleration of the centreof mass is(2) g/3(4) g(3) g/4 |
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Answer» (2) is the correct answer of this question Option 2 is correct because acceleration is proportional to g / difference between the two masses. |
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| 11817. |
Distinguish between Renewable and Non-Renewable sources of energy ? |
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Answer» Renewable resources are the resources which can be revived, through the natural process, over time. On the other hand, non-renewable resources are the natural resources which are not going to be replenished, shortly. Renewable resources do not become extinct easily, and so they are sustainable in nature. |
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| 11818. |
32. Write two advantages of classifying energy source as Renewableand Non-Renewable |
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Answer» Like if you find it useful |
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| 11819. |
LAUNCHPADA 100 m long train is moving with a uniformelocity of 45 km/hr. The time taken by thain to cross a bridge of length 1 km is58 s (b) 68 s (c) 78 s ) 88 s |
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Answer» The formula for velocity is distance ÷ time taken. In symbols: V=S÷t. Where: V = velocity S = distance t = time taken. To solve your question: You need to convert each unit to its standard form, so: V = 45Km/hr = 12.5m/s S = 1km = 1000m t = ? Solution V = S÷t 12.5 = 1000÷t Making t subject of formula: t = 1000÷ 12.5 t = 80 seconds. So it will take 80 seconds for a train moving at 12.5 meters every second to cross a kilometer long bridge. However, The question states the train is 100 meters long. This means the last point on the train has an extra 100 meters to cover. So it becomes: t = 1100 ÷12.5 t = 88 seconds. So the time it takes a train 100m long, moving at 12.5km/hr to cover 1km is 88 seconds or 1 minute, 28 seconds |
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| 11820. |
a simple Atwood machine, two unequal massesand ma are connected by a string going over a clampedlight smooth pulley. In a typical arrangement(figure 5-E7) m, 300 g and m 600 g. The system isreleased from rest. (a) Find the distance travelled bvthe first block in the first two seconds. (b) Find thetension in the string. (c) Find the force exerted by the22.Inclamp on the pulley. |
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| 11821. |
1. An object has moved through adistance. Can it have zerodisplacement? If yes, supportyour answer with an example. |
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Answer» Yes, zero displacement is possible if an object has moved through a distance. Suppose a ball starts moving from point A and it returns back at same point A, then the distance will be equal to 20 meters while displacement will be zero. Yes, zero displacement. Can be the answer because when car moves from point A and comes to again point A the distance is equal to 30 meters and displacement 0 |
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| 11822. |
An object has moved through adistance. Can it have zerodisplacement? If yes, supportyour answer with an example,along the |
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Answer» yes if the starting position and final po yes if the initial position and final position of the object is same |
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| 11823. |
2.From the following graph calculate thedistance travelled by the body between 2 and3 seconds.10+-(s/u) a271 25€3 4T(Sec.) →(b) 2 m(d) 9m(a) 10 m(c) 7 m |
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| 11824. |
Ansa y etat Velocity - und7. Calculate the acceleration of a body which starts from rest and travels 87.5m 5sec? |
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Answer» a =acceleration u =initial velocity v =final velocity s =displacement t =time according to question u =0 m/sec t=5 sec s =87.5 m we will apply equation 2 s =ut +1/2 at ^2 87.5 =0×5 +1/2 a (5^2 )87.5 =1/2 a (25 )87.5 =a 12.587.5 /12.5 =a 7 =a so ,7 m /sec^2 is acceleration |
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| 11825. |
The rate constant of a Reaction at 500k and 700k are 0.02sec-1 and 0.07sec-1 calculate Ea and A. |
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| 11826. |
ced alongExample 12. A thin rod of lengthoptic axis of a concave mirror of focalimage which is real and elongated.What will be the magnification ?length f/3 is placed alomof focal length f such thiongated, just touches the |
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Answer» Since the image touches the rod, one end of the rod must be at C of the mirror.Since the image is real and elongated, the other end of the rod must be between C and F of the mirror.The distance of this latter ( A) end from the optic center of the mirror is (R-f/3) = 2f-f/3= 5f/ 3(u –f)= 5f/ 3-f = 2f/3m = f/ (u-f) = 3/2 = 1.5 Magnification of the A end of the rod is 1.5 where as the magnification of the joint of image and rod is 1. |
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| 11827. |
. A bus starts from rest and picks up a velocity of 90 km/h in minute. Calculate the uniform[0.83 m/s]lo un n nrrd nf 144 km/h in 40 s, before taking off. Calculate2acceleration of the bus in m/s2 |
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| 11828. |
A car accelerate from 18 km/h to 36km/h in 5 sec Calculate 1)Acceleration 2)Distance covered |
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Answer» 18 km/hr =18*5/18 m/s =5m/sso, 36km/hr =10m/sacceleration=change in velocity /time=1m/s^2s=ut+0.5at2=25+25/2=37.5m |
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| 11829. |
A shell on ground explodes suddenly, withfragments flying in all directions upto aspeed of 20 m/s. The area in danger is(g- 10m/s)(A) 400 π m?(B) 1600mm2(D) 3600 π m2π㎡ |
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| 11830. |
Find the position of image formed by a lens combination u1= 30 cm, frequency f1= +10 cm, V1= ? |
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Answer» 1 |
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| 11831. |
xerer9udoes the force of gravitation between two objects changeHowwhenthe distance between them is reduced to half? |
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| 11832. |
The waterdrops are falling at regular intervals from the tap which is h m above the groundThe third drop is about to leave the tap when first drop touches the ground. If the distancebetween second drop and first drop is 3.75m, then what is the height h. (take g 10ms)3.75m, then what is the height h. (ake g 10m-) |
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| 11833. |
An oil drop of 12 excess electrons is held stationary under a constantelectric field of 2.55 x 104 NC-1 in Millikan's oil drop experiment. Thedensity of the oil is 1.26 g cm3. Estimate the radius of the dropg 9.81 m s e 1.60 x 10-19 C).1.25 |
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| 11834. |
The length of a given cylindrical wire is increased by 100 %.Due to the consequent decrease in diameter the change inthe resistance of the wire will be |
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Answer» The total volume remains the same before and after stretching. Therefore A xl = A’ x l’ Here l’ = 2 l A’ = A x l / l’ = A x l / 2 l = A/2 Percentage change in resistance = Rf– Ri/ Rlx 100 = ? l’/A’ - l/A / l ? l/A x 100 = [ (l’/A’ X A/l) – 1 ] x 100 [(2 l/A/2 x A / l)-1 ] x 100 = 300% |
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| 11835. |
apabrc 0n 14. How many natural numbers not exceedingnl4321 can be formed with digits 1,2, 3 and 4 ifthe digits can repeat?4So |
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| 11836. |
A thin semicircular conducting ring (PQR) ofradius ‘r' is falling with its plane vertical in ahorizontal magnetic field B, as shown in figure.The potential difference developed across thering when its speed is v, is(a) Zerob) Bvu- 2 and P is at higher potnetial(c) π1Bv and R is athigh er pomenal(d) 21Bv and R is at higher potential |
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Answer» Since the falling object is a ring the projection of length of the ring along right angle is equal toPR= 2R emf=Blvemf=Blv=B2RV and induced current in anti clock wise direction. So,R will be with higher potential 2RBv Hence d is the correct answer |
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| 11837. |
Define the unit of force using the second law of motion A force of SN produces an acceleration ofm's' on a mass m, What hcceleration would the same._force provide ithththemasses are tend togethers on ama sm, Whataccelerationwouldthesame8m/s on a mass m, and an acceleration of 24 |
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Answer» F = 5N a = 8m/s²m = F/a = 5/8 kg a2 = 24 m/s²m2 = 5/24 kg m+m2 = 5/8 + 5/24 = (15+5)/24 = 20/24 = 5/6 kgacceleration of mass tied together = F/(m+m2) = 5/(5/6) = (5×6)/5 =6 m/s² Suppose an object of mass, m is moving along a straight line with an initial velocity, u.It is uniformly accelerated to velocity, v in time, t by the application of a constant force, Fthroughout the time, t. The initial and final momentum of the object will be,p1 = mu and p2 = mv respectively. The change in momentum ∝ p2 – p1The change in momentum∝ mv – muThe change in momentum∝ m × (v – u).The rate of change of momentum ∝ m × (v −u)/tOr, the applied force,F ∝m × (v −u)/tF = km (v - u)/t F = kma Here a [a = (v – u)/t ] is the acceleration, which is the rate of change of velocity. The quantity, k is a constant of proportionality.The SI units of mass and acceleration are kg and m s-2 respectively. The unit of force is so chosen that the value of the constant, k becomes one. For this, one unit of force isdefined as the amount that produces an acceleration of 1 m s-2 in an object of 1 kg mass.That is, 1 unit of force = k × (1 kg) × (1 m s-2).Thus, the value of k becomes 1. and F = ma which is the mathematical expression on the Newton's second law of motion. |
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| 11838. |
Distinguish between metals and non-metals. What are metalloids? Giveany two examples of metalloids |
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Answer» A metalloid is a chemical element that exhibits some properties of metals and some of nonmetals. ... Definition for metalloids: elements with properties intermediate between metals and nonmetals. Boron, silicon, germanium, arsenic, antimony, tellurium, and polonium are metalloids Difference between metals and non-metals The metals are generally present in the solid form at room temperature except mercury which is liquid at room temperature. Whereas non-metals may be solid, liquid and gaseous at room temperature. Metals are good conductors of heat and electricity but non-metals are poor conductors of heat and electricity. Metals are ductile in nature i.e. it can be drawn into thin wires. But non-metals are not ductile. Metals are malleable but non-metals are not malleable. Malleable means the property through which metals can be hammered into thin sheets. Metals are lustrous i.e. having shinning appearance but non-metals are dull in appearance. Metals contain 1 to 3 electrons in their outermost shell whereas non-metals contain 4 to 8 electrons in their outermost shell. Metal loses electrons to form electropositive ions but non-metals accept electrons to form electronegative ions. Metals have low ionization enthalpy and non-metals have high ionization enthalpy. Metals react with oxygen to form basic oxides whereas non-metals usually react with oxygen to form acidic oxides. Metals are good reducing agent as it loses electrons easily from its valance shell. But non-metals are good oxidizing agent as it accepts electrons in its outermost shell. Metals are sonorous in nature i.e. produces sound when hit by an object. but non-metals does not produces any sound. thanks😁😁😂 |
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| 11839. |
The current flowing through a resistor connected in a circuit and thepotential difference developed across its ends are as shown in thediagram by milliammeter and voltmeter readings respectively(a) What are the least counts of these meters?(b) What is the resistance of the resistor?200300100mA |
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Answer» Least count = 200-100/10= 100/10= 10 for ameeterand for Voltmeterits2-1/10= 0.1nowb) resistance= v/i= 2.4/250*10^-3= 9.6 ohm |
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| 11840. |
The current flowing through a resistor connected in a circuit and thepotential difference developed across its ends are as shown in thediagram by milliammeter and voltmeter readings respectively:(a) What are the least counts of these meters?(b) What is the resistance of the resistor ?2002100 H300mA |
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Answer» Least count = 200-100/10= 100/10 = 10 for ameterand 2-1/10= 0.1 for voltmeter |
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| 11841. |
Name any two metals which do not reactwith sodium hydroxide. |
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Answer» Noble metals like gold or platinum will not react with sodium hydroxide. Their oxidization potentials are simply to high to sustain the reaction. |
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| 11842. |
Three resistors R R and R, each of 24022 areconnected across a 120 V supply, as shown inFig. 3.139. Find (i) the potential difference acrosseach resistor and (ii) the total heat developed acrossthe three resistorsRin 1 minute.[Ans. O V = 80 V,(i) V2 =V, = 40 V(ii) 2400 ]Fig. 3.139 |
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Answer» V1=80V BECAUSE V=RI V= 240÷30= 80 JUST AS V2AND V3ALSO WE CAN FIND |
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| 11843. |
(4) 20 cm/s15. A particle starts from rests and travels a distance S with uniform acceleration, then it travels a distance 2S with unifonmspeed, finally it travels a distance 3S with uniform retardation and comes to rest. If the compelte motion of the particlea straight line then the ratio of its average velocity to maximum velocity is-45327 |
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| 11844. |
2.6 A hydrogen atom initially in the ground level absorbs a photon,which excites it to the n- 4 level. Determine the wavelength andfrequency of photon. |
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| 11845. |
[2015: 2 Marks, Set-2]2.37 A balanced (positive sequence) three-phaseAC voltage source is connected to abalanced, star connected load through a star-delta transformer as shown in figure. The line-to-line voltage rating is 230 V on the starside, and 115 V on the delta side. If themagnetizing current is neglected andIs = 10020° A, then what is the value onTp in Ampere?WwMa) 502300(c) 503230°(b) 502-30(d) 200230°on 15.2 Marks. Set-21 |
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Answer» Is= 100<0so230/115*25= 50<30 |
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| 11846. |
35. A copper wire is stretched l0.1% longer, the percentagechange in its resistance is(a) 02% (b) 0.1% (c) 05% (d) 04%36. A current of 3A flows through awire shown in figure. Thepotential difference betweenpoints A and Bis3 28 V6 V(a) 26.5 V(c) 58 V(b) 14.5 V37. Five resistances of10Q, 20Q, 20 Ω, 40Ω, and 50Ω areconnected as shown in figure. Theequivalent resistance betweenpoints A and Bis10Ω20Ω50220Ω40 2(a) 40 s2 (b) 60 S2 (c) 2092 (d) 30 |
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Answer» the given circuit is a wheat stone bridge as 10/20 = 20/40 so remove the middle resistance of 60Ω ( because they are in between equipotential points so, 10 and 20 are in series , adding up to 30Ω and 20 and 40 are in series , adding up to 60Ω now this 30Ω and 60Ω are in parallel... the equivalent resistance is = 30*60/(30+60) = 20Ω option C 20free |
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| 11847. |
In the figure shown the velocity of lift is 2 m/s while string is winding on the motor shaft with velocity2 m/s and block A is moving downwards with a velocity of 2 m/s, then find out the velocity of block B.D-7.2m/s回函 A2m/s(A) 2 m/s?(C) 4 m/sT(d) 8 m/s? |
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Answer» The options could have missed the right answer. |
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| 11848. |
6.Why is the heavy wheel attached to the shaft of engines? |
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Answer» Flywheel is aHeavy wheel attachedto a rotatingshaftto smooth out delivery of power from amotorto a machine. The inertia of the flywheel opposes and moderates fluctuations in the speed of theengineand stores the excess energy for intermittent use. Heavy wheel attachedto a rotatingshaftto smooth out delivery of power from a motor to a machine. The inertia of the flywheel opposes and moderates fluctuations in the speed of theengineand stores the excess energy for intermittent use. |
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| 11849. |
(a) 20 m(b) 64 m(c) 32 m(d) 36 m15. A lift performs the first part of its ascent with uniform acceleration a and the remaining wituniform retardation 2a. If t is the time of ascent, find the depth of the shaft.at2atat4328 |
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Answer» thank you |
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| 11850. |
20 m/sC-4.In the figure shown the velocity of ift is 2 m/s while string is winding onthe motor shaft with velocity 2 m/s and block A is moving downwardswith a velocity of 2 m/s, then find out the velocity of block B.2mis(A) 2 m/s(B) 2 m/s2misC) 4 m/s(D) 8 m/s |
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