InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 12851. |
Write a program to print the number upto 50 ? |
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| 12852. |
What is heat capacity? What is specific heat? |
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Answer» Heat capacity: The amount of heat required per unit rise of temperature is called heat capacity. Heat capacity = Qt∆∆ Specific heat: “As the quantity of heat required by unit mass of the material to rise its temperature by one degree” is called specific heat. Specific heat s = Qm t |
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| 12853. |
A How are electromagnetic waves produced? What is the source of energy carried by a prrgy carried by a propagating electromagneticWvesidentify the electromagnetic radiations undera.) In remote switches of household electronic devicesb.) as diagnostic tool in medicine. |
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Answer» The creation of all electromagnetic waves begins with a charged particle. This charged particle creates an electric field (which can exert aforce on other nearby charged particles). When it accelerates as part of an oscillatory motion, the charged particle creates ripples, or oscillations, in its electric field, and also produces a magnetic field. Once in motion, the electric and magnetic fields created by a charged particle are self-perpetuating—time-dependent changes in one field (electric or magnetic) produce the other. This means that an electric field that oscillates as a function of time will produce a magnetic field, and a magnetic field that changes as a function of time will produce an electric field. Both electric and magnetic fields in an electromagnetic wave will fluctuate in time, one causing the other to change.All the above sources of electromagnetic waves use the simple principle of moving charge |
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| 12854. |
Who propounded the theory of electromagnetic waves? |
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Answer» About 150 years ago,James Clerk Maxwell, an English scientist, developed a scientific theory to explain electromagnetic waves. He noticed that electrical fields and magnetic fields can couple together to form electromagnetic waves. |
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4) Match the columnsColumn 'Ai) Latent heatin) Specific heat capacityColumn 'B'a) callg cb) kcal |
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Answer» latent heat =option cspecific heat capacity =option d |
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8. What oscillates in e.m. waves? Give twoexamples of e.m. waves. |
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Answer» Electric and magnetic fields oscillates in e.m waves.eg: Radio waves, Light |
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| 12857. |
Do electromagnetic wavescarryenergyandmomentum |
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Answer» Yes electromagnetic waves carry both energy and momentum because The energy carried by an electromagnetic wave is inversely proportional to its wavelength: E=hλ. The momentum carried by an electromagnetic wave is proportional to its energy: p=Ec. Like my answer if you find it useful! |
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| 12858. |
18) What should come in the place of questionin the given series?Th C, DE, EG, FI, GK, ?e series is BA. CA) DOB) LMC) HMD) IK |
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Answer» BA, CC, DE, EG, FI, GK,? Ans is (c) HM |
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| 12859. |
P.S.S.C.E. 20025. Write any four characteristics of electromagnetic wavesGive two uses of (1) radiowaves and (ii) microwaves |
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Answer» Objects in space, such as planets and comets, giant clouds of gas and dust, and stars and galaxies, emit light at many different wavelengths. ... Becauseradio wavesare larger than opticalwaves,radiotelescopes work differently than telescopes thatwe usefor visible > light (optical telescopes). |
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| 12860. |
age of an object formed by a lens is ofItmagnification -1. If the distance betweenthe object and its image is 60 cm, what isthe focal length of the lens? If the object ismoved 20 cm towards the lens, wherewould the image be formed? State reasonand also draw a ray diagram in support ofCBSE 2016your answer |
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Answer» Magnification,m= -1Distance between object and image, u + v = 60 cm Magnification (m) is given bym=vu⇒−1=vu⇒v=−u Now, we have,−u+v= 60⇒−u−u=60⇒−2u=60⇒u=−30cmSo,v=−(−30)=30cmUsing lens formula1v−1u=1f⇒1f=130−1−30=230⇒1f=115⇒f=15cm |
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| 12861. |
ind the Squivaleat capจ์ก,,ou, 4acity belunu'n.hr6 |
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Answer» this is another representation of wheat-stone-brige. type circuit... in which we can remove the middle 6μF capacitor. and the remaining 4 will make pair between them in parallel.. so, the parallel equivalent C = 6+6 = 12μF for both pairs now theses are connected in series..therfor Ceq = 12*12/(12+12) = 144/24 = 6μF. |
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| 12862. |
8 कोई अवतल दर्पण अपने सामने 10 cm दूरी पर रखे किसी बिंब का तीनगुणा आवर्धित (बड़ा) वास्तविक प्रतिबिंब बनाता है। प्रतिबिंब दर्पण से कितनीदूरी पर है।A concave mirror produces three times magnified real image of anobject placed at 10 cm in front of it. Where is the image located? |
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Answer» v=-30cm will be right answer |
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42. In the human eye, the eye lens forms animage of the object on the retina. The imageIS(a) Real and erect(b) Real and inverted(c) Virtual and erect(d) Virtual and inverted |
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Answer» Answer: b) Real and invertedexplanation :The real and inverted image formed on the retina is carried to the brain by the optic nerve in the form of electrical signals. The brain interprest these signals and processes the information such that we see the objects erect. |
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| 12864. |
following1.object at infinity in concave mirror2. object beyond C in concave mirror3. object at Cin concave mirmor4. object between F & C in concave mirror d. highly diminished imagea. enlarged imageb. highly enlarged imagec. diminished imagee. highly enlarged imagef. image is same size as objectg. point sized image |
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Answer» 5 object between f and p 6 object on c7 object is placed on infinity |
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| 12865. |
A lens of focal length 20 cmis used to produce a tentimes magnified image of afilm slide on a screen. Howfar must the slide be placedfrom the lens |
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| 12866. |
(a)Ăź)Draw a labeled diagram of human eye. |
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Answer» CorneaThe clear outer part of the eye's focusing system located at the front of the eye. FoveaThe center of the macula; gives the sharpest vision. IrisThe colored part of the eye that regulates the amount of light entering the eye. LensA clear part of the eye behind the iris that helps to focus light, or an image, on the retina. MaculaThe small sensitive area of the retina that gives central vision. It is located in the center of the retina and contains the fovea. Optic NerveA bundle of more than one million nerve fibers that carries visual messages from the retina to the brain. PupilThe opening at the center of the iris. The iris adjusts the size of the pupil and controls the amount of light that can enter the eye. RetinaThe light-sensitive tissue lining at the back of the eye. The retina converts light into electrical impulses that are sent to the brain through the optic nerve. Vitreous GelA clear gel that fills the inside of the eye. please like the solution 👍 ✔️👍 very very thank you |
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| 12867. |
Eaeminesor nfow. Reason out whetherwat st tie aurtvtiss nisserd belne itn tdie ligit oi your wnedierstanding of the teruSumar is swinning in a pondA dinkey is carrying a load on its back.wind-mill is lifting water from a well.Agreen plant is carrying out photosynthesisAn engine is pulling a train.. Food grains are getting dried in the sunA sailboat is moving due to wind energy |
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6. Name three things a green plante7. What is the juice secreted by the liver called? What does it do?ito that lives in our intestine |
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Answer» bile juice is secreted by the liver.bileincreases the absorption of fats, it is an important part of the absorption of the fat-soluble substances, such as the vitamins A, D, E, and K. Besides its digestive function,bileserves also as the route of excretion for bilirubin, a byproduct of red blood cells recycled by the liver. juice is secreted by the liver =bilebile increase the absorption of fats.it is an important part of the absorption of the fat-soluble substances Bile juice is secreated by the liver it helps to digest food bile juice is secreted by the liver it increase absorption of fat bile juice is screted by liver |
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9.(B) 30 J(C) 40 Jenter (who is stationary relative to box) finds that when anwith an acceleration of 10 m/sInside a horizontally moving box, anobject is placed on a smooth horizontal tableIn this box if 1 kg body suspen(w.r.t. experimenter) will be. (Take g -10 m/s(A) 10 Nis sand is released, it movesls suspended with a light string, the tension in the string in equilibrium position.(B) 10/2 N(D) zero(C) 20 Nth nulley mass of pulley is |
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| 12870. |
We wish to obtain an equal sized inverted image of a candle flame on a screen kept atdistance of 4 m from the candle flame.(a) Name the type of lens that should be used(b) What should be the focal length of the lens and at what distance from the candleflame the lens be placed.Draw a labelled diagram to show the image formation in this case.(c) |
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Answer» When experimenting the reflexive properties of light using a convex lens we observe that the nature of the image formed depends entirely on the distance of the object which in this case is the candle When the focal length is longer then the image formed is real and equal sized and inverted. |
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e wish to obtain an equal sized inverted image of a candle flame on a screen kept atdistance of 4 m from the candle flame.(a) Name the type of lens that should be used.(b) What should be the focal length of the lens and at what distance from the candleflame the lens be placedDraw a labelled diagram to show the image formation in this case.(c) |
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Answer» (a) To obtain a real and inverted image of same size we must use CONVEX LENS.In a convex lens when object is held at 2f than the image is formed real and inverted. (b) Focal length of the lens is 2 m.Distance of candle flame from the lens is 4 m. (c) Ray Diagram |
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15.Astudent has to project a three times magnified image of a candle flame on a wall. Name thetype of lens (converging/diverging ) required for the purpose. If the candle flame is at adistance of 6 m from the wall, find the focal length of the lens.3 |
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Answer» Converging lens or Convex lens should be used by the user to project the image of candle on the wall as he wants it to be three times magnified. Reason:In Convex lens, when object is placed between F and C , the image will be formed beyond C .Nature of Image :--> magnified, real and inverted.hi=3hoImage distance= object distance + 6v=6+uwe know that magnification=m=v/um=v/u-3=v/u[since image is magnifed three times ]-3=6+u/u-3u=6+u4u=-6u=-6/4u=-1.5 mv=6-(-1.5)v=7.5mby using lens formula,1/f =1/v-1/u1/7.5 +1/1.5=1/f10/75+10/15=1/f10+50/ 75=1/f∴ f=75/60=1.25mThus, Focal length of a given convex lens is 1.25m |
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37. A28. An NCC parade is going at a uniform speed of 6 km/hthrough a place under a berry tree on which a bird issitting at a height of 12-1 m. At a particular instant thebird drops a berry. Which cadet (give the distance fromthe tree at the instant) will receive the berry on hisuniform?38. |
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| 12874. |
Find the force acting on the1.The motion of a particle of mass m is described by yparticle.(F-mg)i t + ¡ g t |
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| 12875. |
(c)The motion of a particle of mass m is given by yt ←g,Find the force ontheparticle.2 |
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The velocity of a particle is v=G+2-2k.The component of the veločity of a particleparallel to vector a-i+j+k in vector formIS. |
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Q.17. An object is kept at a distance of 5 cm in front of acopvex mirror of focal length 10 cm. Calculate theosition and nature of the image formed. |
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16. The image of a candle flame placed at a distance of 30 cm from amirror is formed on a screen placed in front of the mirror at a distanceof 60 cm from its pole. What is the nature of the mirror? Find its focallength. If the height of the flame is 2.4 cm, find the height of its image.State whether the image formed is erect or inverted. |
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| 12879. |
Q. 17. An object is kept at a distance of 5 cm in front of acopvex mirror of focal length 10 cm. Calculate theAns. Here, uosition and nature of the image formed. |
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Answer» how u =-5 |
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| 12880. |
Calculate focal length of a spherical mirror from the following observations, ObjectExampledistance u (50.1 t0.5) cm ond image distance v- (20.1+02) cm |
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Answer» we know that the focal length is given as1/f = 1/v + 1/uso,1/f = 1/50.1 + 1/20.1or1/f = 1/0.0697thus, the focal length will bef = 14.34 cmthus, the corresponding error equation would beΔf/f = Δu/u + Δv/vso,Δf = f.(Δu/u + Δv/v)orΔf = 14.34 [(0.1/20.1) + (0.2/50.1)] orΔf = 14.34 [0.00497 + 0.00399] thus, Δf = 0.13so, the final value is f +- Δf = 14.34 +- 0.13 cm |
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| 12881. |
where the symbols have their usual meaning. Let us now solve ble iuon convex mirror.Sample Problem. An object 5 cm high is placed at a distance of 10 cm from a convex mirradius of curvature 30 cm. Find the nature, position and size of the image.(To left of mirror)ulatedoh ect distance, u =-10 cmbiact distance, 1110 c |
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| 12882. |
6. An object 5 cm high is placed at a distancefocal60 cm in front of a concave mirror oflength 10 cm. Find (i) the position and (ii) size,of the image. |
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Answer» Object distance , u= -60cm Focal lenght , f =-10cm Object size = 5 cm v =? Mirror formula, 1/v + 1/u = 1/f 1/v = 1/u - 1/f 1/v= 1/-(60) +1/-(10) 1/v = -1+6/60 1/v = -5/60 1/v = -1/12 v = -12 Image position = -12 Size of the image, Magnification , m= -v/u m = -(-12)/-60 m = 12/-60 m = 1/-5 m= -0.2 Then , m = h'/h -0.2= h'/5 -0.2 × 5 = h' h' = -1 |
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ly llts aiameter.13. The moment of inertia of a flywheel havingkinetic energy 360 J and angular speed of 20rad/s is(a) 18 kg m2(c) 2.5 kg m2(b) 1.8 kg m2(d) 9 kg m2 |
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Answer» Kinectic Energy = I(w^2) /2 Where, I = moment of inertiaw = angular speed I(w^2) = 360*2 I = 720/20*20 I = 1.8 kg m2 (b) is correct option |
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A 2 cm high object is placed on theprincipal axis of a concave mirror at adistance of 12 cm from the pole. If theimage is inverted, real and 5 cm high,then the focal length of the mirror is(A) 30 cm(B) 25 cm(C) 8.6 cm(D) 20 cm |
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Answer» answer of this question is b B is the right answer |
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IV. Answer the following Question08.Explain the formation of the depletion region for a p-n junction. How does the widthof this region change when the junction is (G)Forward biased (ii) reverse biasedregion.(iii)How does an increase doping concentration affect the width of the depletion |
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216. What is meant by directional characterstics of a p-n junction? Give its one applicationbased on this characteristic. |
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Answer» A PN-junction diode is formed when a p-type semiconductor is fused to an n-type semiconductor creating a potential barrier voltage across the diode junction. APN Junction Diodeis one of the simplest semiconductor devices around, and which has the characteristic of passing current in only one direction only. However, unlike a resistor, a diode does not behave linearly with respect to the applied voltage as the diode has an exponential current-voltage (I-V) relationship and therefore we can not described its operation by simply using an equation such as Ohm’s law. If a suitable positive voltage (forward bias) is applied between the two ends of the PN junction, it can supply free electrons and holes with the extra energy they require to cross the junction as the width of the depletion layer around the PN junction is decreased. By applying a negative voltage (reverse bias) results in the free charges being pulled away from the junction resulting in the depletion layer width being increased. This has the effect of increasing or decreasing the effective resistance of the junction itself allowing or blocking current flow through the diode. Then the depletion layer widens with an increase in the application of a reverse voltage and narrows with an increase in the application of a forward voltage. This is due to the differences in the electrical properties on the two sides of the PN junction resulting in physical changes taking place. One of the results produces rectification as seen in the PN junction diodes static I-V (current-voltage) characteristics. |
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. If the doping concentrations of emitter andbase junction of n-p-n transistor are same. Howit will affect the base and collector current? |
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(c) in which circuit shown below p-n diode is inforward bias?(1) Ove0 +2V(11) ove tw(iii) 2Votoo20ov00V3+1+1=5 |
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Answer» A pn junction diode is said to be in forward bias when the anode is at higher potential than that of cathode. A pn junction diode is said to be in forward bias when the anode is at higher potential than that of cathode. The p side is anode, and n side is cathode. So, (ii) is in forward bias. (2) right answer s%%%%% 2) is the correct answer |
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| 12889. |
9.An object is 4cm high. It is desired to form a real image 2cm high at 60cm from the mirror. What type of mirroris needed and what should be its focal length?{Ans: - 40 cm) |
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Answer» Height of object ho = 4 cm Focal lenght of convex mirror = ? cm Object distance u = ? cm Image distance v = 60 cm Image height hi = 2 cm Magnification m = hi/ho = 2/4=1/2 v/u = 1/2 60cm/u = 1/2 u = 120 cm mirror formula: 1/v + 1/u = 1/-f 1/-f = 1/v + 1/u = 1/60 + 1/120 = 3/120 = 1/40 ⇒ f= -40 cm |
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| 12890. |
A projectile is fired with a speed u at an angle θ with thehorizontal. Its speed when its direction of motion makesan angle" α, with the horizontal is(A) u secθ cosa(C) u cosθ seca(B) u secθ sinaD) u sino seca |
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When a body is thrown with a velocity u making an angle θ with the horizontal plane, the maximumdistance covered by it in horizontal direction is -u2 sin 6u sin 292gUssin 26(C)u2 sin 28 |
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2x15ZNName the type of biasing of p-n junction diode so, that the junction offers very high resistance |
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Answer» reverse baising of pn junction offers very high resistance |
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7.A ball rolls off the top of a staircase with a horizontalvelocity u m/s. If the steps are h metre high and betre wide, the ball willhit the edge of the nth step.2hua)n2(b) n Lu (c)n- 2hugb2hu2gb(a) n - z-, (d) n= n-hu?gb? |
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Answer» the correct option is (a) |
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stone is projected from point A with speed u making an angle 60 with horizontal as shown. The fixedsurface makes an angle 30 with horizontal. The stone lands at B after time t Then the1. Ainclineddistance AB is equal tout(c) 3ut(D) 2 ut |
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Answer» How you eddited that photo |
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| 12895. |
startA jet 'airplane travelling at the speed of 500 kmat the speed of 1500 km hrelative to the jet plane. What is the speed of thlatter with respect to an observer on the ground?3.h ejects its products of combustiout hiihuro with sneed of 126 km h1 is brought to |
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Answer» Velocity of jet plane with respect to ground, vJ= 500 km/h Velocity of exhaust with respect to jet plane, vEJ= −1500 km/h Using the equation of relative velocity, vEJ= vE- vJ -1500 = vE- (500) vE= -1000 km/h Hence,Speed of Exhaust w.r.t. ground = 1000 km/h |
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Which of these is an example of underground stems?a. Sugar canec. CarrotPotatod. Cabbage |
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Answer» Potato Many plants have underground modified stems that may be mistaken for roots. Examples of underground stems include corms, such as taro (left); rhizomes, such as ginger (center); and tubers, such as potatoes (right).Thus iloption b is correct. |
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Q. 7. What are various methods which help in Managing and conserving the recomarvation of resources. Our survival quality of te |
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Answer» 1. Use of alternative sources of power such as solar and wind energy. 2.Plant trees to prevent soil erosion. 3.Practicing of judicious ways to conserve water in our homes. 4.Use pipelines to transport oil. 5.Growing of vegetation in catchment areas. |
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22. A jet air plane travelling at a speed of 500 km/hejects its products of combustion at a speed of1500km/h relative to the jet plane. The speed of thelatter with respect to an observer on the ground is :-(1) 1500 km/h(3) 1000 km/h(2) 2000 km/h(4) 500 km/h |
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| 12899. |
whatwillbetheperiodofoscillation of A.G 0180 asort Answer Type QuestionsDefine intensity of magnetic field and write its unit. |
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Answer» -The magnetic field intensity at any point is defined as the force experienced by the point when placed under the influence of an external magnetic field. -Tesla is the SI unit |
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dyQ.14y=x2 + x+8find dy/dx(B) 3x +1(C) 2x-1(D) 2x(A) 2r+1ds |
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Answer» thank you |
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