InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 13101. |
A young man of mass 60 kg stands on the floor of a lift which is accelerating downwards at 1m/s then bhereaction of the floor of the lift on the man is(1) 528 N15.(Take g 9.8m/s)(4) none(2) 540 N(3) 546N |
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Answer» 1]When lift is moving upwardsWeight = m(g + a)= 60 kg × (10 + 2) m/s²= 720 N [2]When lift is moving downwardsWeight = m(g - a)= 60 kg × (10 - 2) m/s²= 480 N AS IT MOVE DOWNARDS SO THE Tension in a string is equal to reaction forcetherefore reaction = m(g-a) = 60(9.8-1) = 528N |
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| 13102. |
14.How many images of a candle will be formed if it is placed between twoparallel plane mirrors separated by 40 cm? |
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| 13103. |
PRACTICE PROBLEMSin a vertical circle with a string making 2 revolutions per second. If the radiusle is 1.2 m. Find the tension (a) at the top of the circle, (b) at the bottom of the circleGiven g 10 m s2 and 3.14. |
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Answer» thanksbut till the question is not completed |
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| 13104. |
commercial unit and S.l. unit ofènergy(c) An electricbulb of 60 W is used for 6 h per day Calculate the units of work benergy consumed in one day by the bulb. |
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Answer» Power=60 WTime=6 hr=6×3600 secs=21600 secs Energy consumed per day=60×21600 Joules=1.296 MJ |
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| 13105. |
give reason. The leaves of an electroscope are placed inside an insulated glass jar. |
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Answer» The electroscope can also be charged without touching it to a charged object, by electrostatic induction. If a charged object is brought near the electroscope terminal, the leaves also diverge, because the electric field of the objectcausescharges in the electroscope rod to separate the leaves. |
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| 13106. |
4. Explain how an electroscope can be used to detect the nature ofof charges present ina body. |
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| 13107. |
What do you mean by uniform circular motion? Show that in a uniform circular motion of a particle of mass'm" the centripetal force is Fowhere v is the magnitude of velocity and r is the radius of the circular path1+4-5 |
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| 13108. |
+25the third equation of motion. It has been derived byof motion. It has been derived by the graphicUNIFORM CIRCULAR MOTIONa circle, it is called circular motion. In other wtion, we will discuss hoan alatan memicircle it is called circun |
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Answer» Uniform circular motioncan be described as themotionof an object in acircleat a constant speed. As an object moves in acircle, it is constantly changing its direction. At all instances, the object is moving tangent to thecircle. |
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| 13109. |
A boy of mass 25 kg stands on a board of mass 10 kg which in turn is kept on a frictionless horizontalice surface. The boy makes a jump with a velocity component 5 m/s in horizontal direction with respectto the ice. With what velocity does the board recoil? With what rate are the boy and the board separatingfrom each other ? |
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Answer» Initial momentum of the system is 0 as , no one is moving Let the boy jumps with velocity 5 w.r.t ground and board moves with -V with respect to groud in opposite direction now, on conserving linear momentum 0 = 25*(5) + 10*(-V) => 10v = 25*5=> 10v = 25*(5)=> V = 12.5 m/s and V relative of boy w.r.t board = 5-(-12.5) = 17.5 m/s |
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| 13110. |
A boy of mass 25 kg stands on a board of mass 10 kg which in turn is kept on a frictionless horizontalice surface. The boy makes a jump with a velocity component 5 m's in horizontal direction with respectto the ice. With what velocity does the board recoil? With what rate are the boy and the board separatingfrom each other ? |
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Answer» thx |
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| 13111. |
Q6 A particle moves along the x- axis from x 0 tox 5m under the influence of aforce given by Fa(7-2x+3x). Find the work done in the process. |
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| 13112. |
Q6. A particle moves along the x-axis from x-0 to x=5 m under the influence of a force given by7-2x + 3x2 Calculate the work done in doing so.f 135 J ) |
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| 13113. |
30A particle moves in a circle of radius 25 cm at tworevolutions per second. The acceleration of theparticle in m/s isMNR 1991; UPSEAT 2000; |
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| 13114. |
An electric bulb of 60w is used for 6hours per day. Calcu-late the units of energy consumed in one day by the bulb.2 |
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Answer» Power of the bulb,P=60W=60/1000 KW=0.06 KW time, t = 6 h energy consumed by bulb per day=P×t=0.06 KW× 6 h =0.36 KWh =0.36 units |
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| 13115. |
(c) An electricbulb of 60 W is used for 6 h per day. Calculate the units ofenergy consumed in one day by the bulb |
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Answer» Power=60 WTime=6 hr=6×3600 secs=21600 secs Energy consumed per day=60×21600 Joules=1.296 MJ |
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| 13116. |
Short AllJIITo the uniform circular motion accelerated ? Give reasons for your answercircular11.1 |
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| 13117. |
11. Figure given shown the distance-time graph of the motion of a car. It following from the graph that the cariS(A) At rest(B) In uniform motion(C) In non-uniform accelerationx = 1.2 t2Uniformly accelerated |
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| 13118. |
129. A toy car with charge q moves on a frictionlesshorizontal plane surface under the influence of auniform electric field E. Due to the force q Eits velocity increases from 0 to 6 m/s in onesecond duration. At that instant the direction ofthe field is reversed. The car continues to movefor two more seconds under the influence of thisfield. The average velocity and the average speedof the toy car between 0 to 3 seconds arerespectively(2)(3)(4)1 m/s, 3 m/s1 m/s, 3.5 m/s2 m/s, 4 m/s1.5 m/s, 3 m/s |
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| 13119. |
4.A particle moves along x-axis asx 4(t 2)(A) The initial velocity of particle is 4(C) The particle is at origin at t 0+a(t 2)2. Which of the following is true?(B) The acceleration of particle is 2a(D) of these |
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| 13120. |
A particle completes 3 revolutions per second on acircular path of radius 8 cm. Find the values ofangular velocity and centripetal acceleration of theparticle -radcm(A) 6; 28872 2radcm(B) π.s(C) 6π rad(D) cm; 288 2 |
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| 13121. |
In a ripple tank 10 ripples are produced persecond. The distance between alterrate crestsin 10 cm. Find the velocity of ripples. |
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Answer» don't know answer........ |
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| 13122. |
. An object of mass 10 kg is projected from groundwith speed 40 m/s at an angle 600 with horizontalThe rate of change of momentum of object onesecond after projection in SI unit is[Take g 9.8 m/s2](1) 73(3) 176(2) 98(4) 140 |
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Answer» 98 is the correct answer Rate of change of momentum = force = weight of the object = 98 Newtons.There is only one force acting that is gravity. We can find also this way:v = v cos60i + (v sin60 – g t) j p = mv = mvcos60 i + m (v sin60 – gt) j dp/dt = F =m a = m g j = -10 * 9.8 j N = 98j Newtons vertically downwards. |
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| 13123. |
Explain Snell's law. |
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Answer» Snell's law (also known as Snell–Descartes law and the law of refraction) is a formula used to describe the relationship between the angles of incidence and refraction, when referring to light or other waves passing through a boundary between two different isotropic media, such as water, glass, or air. |
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| 13124. |
A particle moves along x-axis with speed6 m/s for the first half distance of a journey and thesecond half distance with a speed 3 m/s. Theaverage speed in the total journey is(1) 5 m/s(3) 4 m/s(2) 4.5 m/s(4) 2 m/s |
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| 13125. |
state and explain Newton law of cooling |
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Answer» Newton's Law of Cooling statesthat the rate of change of the temperature of an object is proportional to the difference between its own temperature and the ambient temperature (i.e. the temperature of its surroundings). |
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| 13126. |
Section B Motion under Gravity11. A body is dropped from a height h under accelerationdue to gravity g. If t, and t, are time intervals for itsfall for first half and the second half distance, therelation between them is(A) tl = t2(B) t, 2t,(D) t, 4t,(C) t, 2.414 t, |
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Answer» h=1/2g(t1+t2)^2 2h/g=(t1+t2)^2------(1) h/2=1/2gt1^2 t1^2=h/g---------(2) From 1st and 2nd t1^2=(t1+t2)^2/2 t1=(t1+t2)/1.41 1.41t1=t1+t2 t1=t2/.41 So t1=2.414t2 Hansika you look intelligent, because you solved an uneasy question. Can you answer 26 no. question and also that starts from 'A bullet. . |
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| 13127. |
13. Write equation for the distance covered by uniform accelerated body in nth sccond. A body travels halfof its total path in last second of its fall from rest. Calculate its time of fall. |
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| 13128. |
19. Find the change in the internal energy of 2 kg of wateras it is heated from 0°C to 4°C. The specific heat capacityof water is 4200 J kg-1 K-1 and its densities at 0°C and4°C are 999-9 kg m and 1000 kg m respectively.Atmospheric pressure 105 Pa. |
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| 13129. |
An engine of 150 kW power is drawing a train of totalmass 150,000 kg up an inclination of 1 in 5. The frictionalresistance is 4 kg wt/1000 kg. Find its maximum speed.Given : g 10 m s-2.[Ans. 0.5 m s-1] |
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| 13130. |
2. Does coulombs law obey Newton's third law of motion. |
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Answer» Yes it does obey Newton's laws of motion as it deals with force . |
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| 13131. |
6. A car travels along a straight line for the first halftime with speed 50 kmh and the second half timewith speed 60 kmh. Find the average speed of thecar.(Ans. 55 kmh-1) |
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Answer» AVERAGE SPEED = (50+60)/2 = 110/2 = 55 Km/ph AV =(50+60)/2=110/2=55Km/Ph |
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| 13132. |
want to come to rest.A truck starts from rest and rolls down a hill with a constantacceleration. It travels a distance of 400 m in 20 s. Find itsacceleration. Find the force acting on it if its mass is7 tonnes (Hint: 1 tonne 1000 kg.) |
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| 13133. |
6. How many mega coulombs of positive (ornegative) charge are present in 2.0 mole of neutralhydrogen (H2) gas ? |
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Answer» it will contain 2.00 mol of hydrogen nuclei/electron/proton 1 mol electron/proton has 1farad charge=96500coulomb=9.65×10e-2 MCoulomb hence 2.00 mol will have 0.193MCoulomb charge |
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| 13134. |
A car travels from Chennai to Bengaluruwith a speed of 60 km/hr and returns backalong the same path with a speed of40 km/hr. The average speed of the car isgiven by:(1) 50 km/hr (2) 13.8 m/s(3)48 km/hr (4) 172.8 m/s |
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| 13135. |
10. A car travels along a straight line for first half time with speed 40 km/h and the second half tine withspeed 60 km/h. Find the average speed of the car |
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Answer» Definition of development: The systematic use of scientific and technical knowledge to meet specific objectives or requirements. |
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| 13136. |
(5x11a. A car travels first half of journey with 30 km/hr speed and next half with 60 km/hr. Find theaverage speed of the car for entire journeyb. The diameter of a sphere is 2.486 cm Find theunluo uf u |
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Answer» Let the total distance be 2x therefore the car travel s first half distance I.e. x with 30 km/hr time = x/30 hrthe car travel s second half of the distance I.e x with 50km/hrtime = x/50 hrnow,average speed= total distance travelled/total time taken= 2x/x/30+ x/60= 2x/6x+3x/180= 2x/9x*180= 40 km/hr |
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| 13137. |
A car of mass 1000 kg travels up anincline of 1 in 25 at a constant velocityof 50 km/h. What power does the carengine have to develop if there is aresistive force of 300 N opposing themotion? |
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| 13138. |
Іоа9. Zara's toy car uses battery power to move from one end of the track to the other.Where on the track will gravity make the car go faster?а. Аb. BCCd.D |
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Answer» C is the right answer C is the right answer c is the right answer. c is the eight answer c) is the right answer of the following C is the right answer |
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| 13139. |
Sample Problem A river 500 m wide flows at a rate of 4 km hº. A swimmer who can swimat 8 km h-in still water, wishes to cross the river straight. (1) Along what direction must he strike?(ü) What should be his resultant velocity. (ii) What is the time of crossing the river ? |
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| 13140. |
In a hostel 20 bulb of 1000 220v, glow everyday for 10 hour. The electricity charge inmonth of April at rate of 2.50 rupees per unitwill be- |
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| 13141. |
A man crosses a 320 tn wide river perpen-dicular to the current in 4 min. If in stillwater he can swim with a speed 5/3 timesthat of the current, then the speed of thcurrent in m/min is43.t 4 |
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Answer» Let the velocity of swimmer = V(s) Let the velocity of current = V(w) width of river = 320 m time taken to cover the river = 4 minute the swimmer swims in -ve direction so that the resultant velocity would be perpendicular to the river velocity . so the resultant velocity or V(sw) has two components V(sw) sinФ in the perpendicular V(sw) cosФ in the base direction As we know V(sw) sinФ = V(w) Also V(sw) cosФ = V(s) And t = 320 / V(sw)cosФ 4 = 320 / V(sw)cosФ In the question it is given that the 5/3V(w) = V(sw) So , we can write 4 = 320 / (5/3) V(w) x 4/ 5 V(w) = 320 x 3 / 4 x 4 V(w) = 20 x 3 V(w) = 60 m/min hit like if you find it useful |
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| 13142. |
The alkali metal having highest reducing property is(1) Li(2) K(3) Na4) Cs |
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Answer» Li has highest reducing property. |
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| 13143. |
how is bio diversity effected by the excessive use of fossil fuels |
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Answer» Biodiversity effected by the excessive use of fossil fuels because fossil fuel are limited so when we use it its amount decreases along with its use. also after some years it exhausts Biodiversity loss is accelerating, and the risks to biodiversity are increasing .We in the midst of a global biodiversity crisisThe biggest threats to biodiversity are Human activities.These act across a range of scales.Even local biodiversity lose can have knock-on large scale impacts on ecosystem function and productivity. |
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| 13144. |
If the particle is moving along a straight linegiven by the relation x 2-3t +40 where s isin cms., and t in sec. Its average velocityduring the third sec is |
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Answer» wrong ans |
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| 13145. |
A block of weight 100 N is pushed by a force F on a horimoves with an acceleration 1 m/s", when force is doubled itbecomes 10 m/s2. The coefficient of friction isInteger Answer Type:rough plane1S10- (g 10 ms |
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| 13146. |
15 When do we say that work is done? Write anobjot in the direction of its displacement. A pair of bullocks exerts a foraebeing ploughed is 15n long. How much work is done in ploughing the length of the field?expression for thework done when a force is cÇtgonnof 140s on a plough. The SeldorDefine power. What are the various energy transfomations that occur when you are riding a bicyclie 7 Azelectric :eater is rated 1500w. How much energy does it use in 10 hours? |
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Answer» Power is the ability or capacity to do something or act in a particular way. |
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| 13147. |
61. A particle of mass 2 kg is moving in circular path with constant speed 20 m/s. The magnitude of change in velocitywhen particle travels from A to P will be |
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Answer» From the figure , The initial velocity is 20i and the final velocity is 20jso the change will be ∆v = 20j-20i and |∆V| =√20²+20² = 20√2 |
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| 13148. |
(b)A bock of mass 2 kg moving on a horizontal surface with speed of 3 ms enters roughpatch ranging from x-0.20 m to 1.50 m. The retarding force F, on the block in this range isgiven by Fr=-kx2 0.20<x<1.50F, = 0x 0.20 m and x> 1.50 m . Calculate work done by retarding forcewhere k is constant equals to 50 J m.(3M) |
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| 13149. |
a fan of 60w runs for 75 hours in a month.how much electric energy is consumed? |
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Answer» Electrical energy=Power×time =60×75 =4500 |
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| 13150. |
The wettability of a surface by a liquid dependsprimarily on -(1) viscosity(2) surface tension(3) density(4) angle of contact between the surface and theQ.3INEET-2013]liquid |
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Answer» option 4 (4)angle of contact between the surface and the liquid |
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