Explore topic-wise InterviewSolutions in .

option 2 is the correct answer

option 4 is the correct answer

iska answer 2N hoga thik

answer is option 2) 4N

option 2 is the correct answer

Power = 4KW = 4000 W Volt = 220 Electric power , P=VI (I)After putting values, I = 18.18 A (II)R denotes resistance here ,V= IR R= V/ I= 220 V/ 18. 18 A= 12. 1012 ohm. (III) Power= 4000 W= 4000 J/ s So, in 2 hours energy in kWh is = 4000J/ s * 3600 * 2/( 3600000)= 8 kWh

1. Physical quantity coulomb/second is called Electric Current.2. Flow of charge is called Electric Current.

suchalak kise kahte h

don't know the answer

hope this is helpful

(a) initial velocity,u = 0time,t = 4 sacceleration,a= 5m/sdistance ,s= ?

putting these value in the second equ. of motion= s=ut +½ at²s= 0×4 +½ ×5× 4²s= ½× 5 × 16s= 40 ans

similarly (b) and (c)

thanks

1. Ans.Nephrons are the filtration units of kidney. Each kidney has a large no. of nephrons. The process starts with filteration of urine.

2. Ans.Plants get rid of:1. of water by transpiration.2. waste products may be stored in vacuoles or may be stored in leaves which fall off.3. resine and gums are stored in xylem.4. some waste substance may be excreted in the soil.5. as by products move out of the plants by diffusion through stomata.

Ans 3. The amount of urine produced depends on the amount of excess water and dissolved wastes present in the body.

m= 100kgg= 10 m/s²t = 25swork done = mghW = 100 X 10 X 19Work done = 19000 JP = Work done/time takenPower = 19000/25Therefore, power = 760 W

Power = (mg*S)/t= (100*10*19)/25= 760 W

Please hit the like button

f=mg=10×10=100NA=2 (lb+bh+lh) = 2 (0.3×0.2+0.2×0.1+0.3×0.1) =2(0.06+0.02+0.03 = 2×0.11 = 0.22m^2p=f/a = 100/0.22 = 5N approximately

Since int=2, distance covereds=2mwe have ,

s= ut+1/2at^22= 2*u+1/2a*(2^2)or u +a= 1

Please like the solution 👍 ✔️👍

When Magnesium burns air it reacts with oxygen present in air to form magnesium oxide.2Mg + O2→2MgO2.

option d subrahmanyam chandrasekhar

Instantaneous velocityis thevelocityof an object in motion at a specific point in time. This is determined similarly to averagevelocity, but we narrow the period of time so that it approaches zero. If an object has a standardvelocityover a period of time, its average andinstantaneous velocitiesmay be the same.

The answer is With an initial velocity and moves with uniform acceleration.

Freely suspended magnetalways points in the North-South direction even in the absence of any othermagnet.

Mass of the wooden block = m= 5 kgdimensions = 40 cm × 20 cm × 15cmthe weight of the wooden block applies a thrust on the table top.That is,Thrust = F = mg= 5 kg × 9.8 m/s²= 49 N

Area of a side = length × breadth= 20 cm × 15 cm= 300 cm²= 0.03 m²

Pressure = thrust/ areaPressure = 49 /0.03= 1633.3N/m²

The same thrust in implied when it lies on the given dimension.Area= length × breadth= 40 × 20= 800= 0.08 m²

Pressure = 49/0.08= 612.5

The distance covered in 'Tth' second will be given as

s = u + (f/2).(2T - 1)

and

the distance covered in '(T+1)th' second will be given as

s' = u + (f/2).[2(T+1) - 1]

and we are given

if the sum of the distances travelled in Tth& ( T+1)thsec is 80m

so,

s + s' = 80m

or

u + (f/2).(2T - 1) +u + (f/2).[2(T+1) - 1] = 80m

or

2u + (f/2).[(2T - 1) + (2T + 2 - 1)] = 80m

or

2u + (f/2).[4T] = 80

or

2u + 2fT = 80

or

u + fT = 40

now, we know that

final velocity is given as

v = u + at

or in this case

v = u + fT

so,

we get the final velocity as

v = 40 m/s

By using law of conservation of momentumm₁u₁ = (m₁ + m₂)v

v = m₁u₁ / (m₁ + m₂)= (10 × 10^-3 kg × 400 m/s) / [(10 + 900) × 10^-3 kg]= 4.395 m/s

Velocity acquired by the wooden block is 4.395 m/s

A converging mirror is a concave mirror. Concave mirror produces enlarged, virtual and erect image when the object is placed between Principal Focus(F) and Pole (P). The image is formed in the backside of the mirror.This property is taken as an advantage to make shaving mirrors and makeup mirrors which can produce enlarged and erect image of the object.

option c is write answer

Three changes that a force can bring about on a body:

1) Force can change the shape of a body.

Example: While kneading the dough, the shape of the dough changes as we apply force with our fists.

2) Force can change the state of motion of an object.

Example: A pushing force can put any object into motion which is initially at rest.

3) Force can change the direction of motion of an object.

Example: While playing tennis, players hit the ball with his racket to change the direction of the ball to put into opponent's court.

Force can change the state of the object. Example :kicking a ball change its state of rest or of motion Force can change speed Example :kicking a ball change its speed Force can change the direction Example :when we kick a ball, it's direction also change

Gravitychanges with altitude. The gravitational force is proportional to 1/R2, where R is your distance from the center of the Earth. Here is an example: The radius of the Earth at the equator is 6400 kilometers. Let's say you were in a jet at the equator that was 40 kilometers high above the earth's surface.

for small heights g does not change .

h = 11.4m is the answer of this question

O -ans

a = 2f - f /2m, For left block Nsin30 - f=ma, N/2-f =mf/2m, N/2 =f+f/2, N=3f.

Since, the body is moving with constant velocity therefore, the acceleration of the body is zero. Hence, the force acting on the body is zero.

Hence, option (a) is correct.

As for the variables: ti = 0 s tf = 2 s xi = 0 m xf = 0.8 m vi = ? vf = ?

vi = 0 m/s xf - xi = 1/2(vi + v)t 0.8 = 1/2(2)v v = 0.8 m/s

Then v = vi + at 0.8 = 2a

a = 0.4 m/s^2

Then F = ma F = 3(0.4) = 12 N

Then W = Fd W = 12(0.8) = 0.96 J

Like my answer if you find it useful!

1)72,60=72/60=divided by 2=36/30=divided by 6=6/5

Things you need to know before we begin:

1. Equations of Kinematicsv = u + ats = ut + 1/2 at^2v^2 - u^2 = 2aswhere,t - timev - velocity at time tu - velocity at time t = 0a - acceleration of the objects - distance traveled in t time

2. Value of Acceleration due to gravity ( 'g' )g = 9.8 m/s^2where,g - acceleration due to gravity

Now,Distance covered in nth second = Distance traveled in n seconds - Distance traveled in (n-1) seconds

so,Distance covered in nth second (Sn) comes to be,Sn = u + a/2(2n-1)

also,a = - gnegative sign represents that the acceleration is opposite to the direction of motion of the object or the velocity of the object.

As distance covered in 5th second is twice the distance covered in 6th second we have,S5 = 2(S6)i.e,( u - 9g/2) = 2(u - 11g/2)

solving which results in,u = 13g/2

as, g = 9.8 m/s^2

we have,u = 63.7 m/s

Comparing y = 10x-x² = 10x(1-x/10)

with the standard equation of trajectory y = xtan∅(1-x/R) , we get than

tan∅ = 10 and R = 10m

so, option B should be correct.