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13201.

Four holes of radius R are cut from a thin squareplate of side 4R and mass M. The moment of inertiaof the remaining portion about z-axis is:(Ar)3 4(2)MR2(1)夜MR28 10π3 16ntal culinder of

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13202.

AI. with marked price䚏11.500 is sold at 10% discount Due to festivalseason, the shop keeper allows a further discount of 5%. Find the net selingprice of the T.V9.

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Marked Price = Rs 11,500

Find the 10% discount:

10% Discount = 10% x Rs 11,500 = 0.1 x 11500 = Rs 1150

Find the selling price after the 10% discount:

Price after discount = Rs 11,500 - 1150 = Rs 10,350

Find the 5% discount:

5% Discount = 5% of Rs 10,350 = 0.05 x 10350 = Rs 517.50

Find the selling price after the 5% discount:

Price after discount = Rs 10350 - Rs 517.50 = Rs 9832.50

Answer: The net selling price is Rs 9832.50

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13203.

23. A ball is projected vertically upward with a speed of50 m/s. Find (a) the maximum height, (b) the time torach the maximum height, (o) the speed at halfmaximum height. Take g = 10 m/seed at half the24. A ball is drannod f

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13204.

5. One light year -(a) Speed of light x time taken(c) 9.46 x 1075 meters

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c 9.46×105

One light year is equal to 9.46×10^15meters One light year is equal to distance traversed by the light in one year.

13205.

Find the ue of one light year in giga metre

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13206.

value of 1 light year in SI unit is

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1 light-yearis about 9.461 × 10 power 15 metres

thanks😀😁😂

13207.

A fundamental SI unit named after a scientists is .....(1)..

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A fundamental SI unit named after a scientist is ampere.

13208.

13. The velocity-time graph of a body moving in a straight line is shownin the figure. The displacement and distance travelled by the body 4in 6 sec. are respectively2#8 m, 16 m(B) 16 m, 8 m(C) 16 m, 16 m(D) 8 m, 8 m2 3 4 5 623t(sec)

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13209.

1 sI unit of energy is

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Joule is the SI unit of energy...

SI unit of energy is Joule.

joule is the si unit of energy

The SI unit of energy/work is the joule (J), named for English physicist James Prescott Joule (1818 - 1889)

Joule is the SI unit of Energy

SI unit of energy is joule

like plz 😀 is

13210.

32. Underline the correct alternative:(a) When a conservative force doespositive work on a body, the potentialenergy of the body increases/decreases/remains unaltered.(b) Work done by a body against frictionalways results in a loss of its kineticpotential energy.(c) The rate of change of total momentunmof a many-particle system isproportional to the external force/sum of the internal forces on thesystem.(d) In an inelastic collision of twobodies, the quantities which donot change after the collision arethe total kinetic energy/total linearmomentum/total energy of the systemINCERTof two bodies.

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13211.

1+1+1What does the magnetic field pattern insidethe solenoid indicate 7 State how this field beutilised to make an electromagnet. List twoways by which strength of this magnet can beincreased.

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13212.

1. Obtain the unit of work in SI unit system and write itsdefinition

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TheSIunitofworkisthejoule (J), which is defined asthe workexpended by a force of one newton through a displacement of one metre

In physics, a force is said to do work if, when acting, there is a displacement of the point of application in the direction of the force

13213.

53.Considertheprocessonasystemshowninfigure.Duringtheprocess,theworkdonebythesystem(I) continuously increases(3) first increases then decreases(2) continuously decreases4 first decreases then increases

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13214.

An electric iron draws a current of 4 A from 220 V supply line. When voltage of supply is changedthen iron draws a current of 2 A, what is the new voltage applied?Ans. 1101

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110 v can be the answer of question

13215.

The ratio of the kinetic energy to the total energy of an electron in a Bohr orbit is(a) 120.(b) 2(d) of these

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13216.

46, Let AAcos0+ JA sin0, be any vector. Anothervector B which is normal to A is:-(1) iBcose +jBsin θ(2) iB sin θ+jBcosesin θ--(B cos

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we have to check manually for the DOT product to be zero..

so, in option 3.

A•B = (Acos∅i+Asin∅j)•(Bsin∅i-Bsin∅j) = ABcos∅.sin∅ -ABsin∅cos∅ = 0

so, option 3 is correct.

13217.

A nichrome wire 1 m long and 1 mm2in cross-section area draws 4 ampere at 2 volt. The resistivity of nichrome is

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R=2/4=0.50.5= r1/(10^-6)= r = 5×10^-7

13218.

52.4 J of work is required to stretch a spring through10 cm beyond its unstretched length. The extrawork required to stretch it through additional10 cm shall be(1) 4 J(3) 12 J(2) 8 J(4) 16 J

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The potential energy in string stored is = 1/2*(k)(10)²

=> 4 = 1/2*(k)*100=> K = 4/50

now when string is stretched to further 10cm

the equation is

W = 1/2*(k)*(20²-10²)W = 1/2*(4/50)*(400-100)W = 300/25 = 12J.

option 3.

13219.

loss section area of a steel wire (Y-2.0x101 N/m2is 0.1 cm2. The required force, to make its lengthdouble will be

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13220.

EXERCISESsteel wire of length 4.7 m and cross-sectional area 3.0 x 10-5 m2 stretme amount as a copper wire of length 3.5 m and cross-sectional area of 4.0der a given load. What is the ratio of the Young's modulus of steel to that ofchesure 9.11 shows the strain-stress curve for a given material. What are (a)dulus and (b) approximate yield strength for this material?

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1

2

13221.

A relaxed biceps muscle requires a force of 25 N for anelongation of 5 em, and the same muscle undermaximum tension requires a force of 500 N for the sameelongation. Regarding the muscle as a uniform cylinderof length 0.2 m and cross-sectional area 50 cm2, findYoung's modulus for the muscle tissue under each ofthese conditions.lAns. 2 x 10 Pa, 4 x 105 Pal

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13222.

If the difference in the temperature of twoliquids in degree centrigrade scale in 10°Cthen what will be the difference in theirtemperature in fahrenheit scale ?

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If the difference inthe temperature of two liquids in degree centigrade scale in 10 degree celcious , then the temperature in Fahrenheit scale is 32 degree celcious

13223.

Two liquids of masses M1 and M2 and specificheats S1 and S2 respectively are mixed. Thespecific heat of the mixture is

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((M1*S1)+(M2*S2))/(M1+M2)

solution pls...

13224.

Paper IPa6) An electromagnet is aA) Permanent magnet B) Temporary magnetc) Permanent magnet or D) of theseonlyonlytemporary magnetdepending upon thetype of material

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Unlike a permanent magnet, the strength of anelectromagnetcan easily be changed by changing the amount of electric current that flows through it. The poles of anelectromagnetcan even be reversed by reversing the flow of electricity. Anelectromagnet worksbecause an electric current produces a magnetic field.

13225.

A particle moves along a circle of radius R with a constant angular speed ω·Its displacement (onlymagnitude) in time t will be(A) ot(B) 2 R cos ot(C) 2 R sin ot(D) 2R sin of

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13226.

U SVPA survey was conducted by a group of students as a part of their environmentawareness programme, in which they collected the following data regarding the numberof plants in 20 houses in a locality. Find the mean number of plants per house,0-2 2-4 4-6 6-8Number os plants:8-10 10-12 12-141Number of houses:2 1 5 6 2Which method did you use for finding the mean, and why?

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13227.

muck-oynnewo/U00.fy, mauinさーat-.q-Speed-oA

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Mass of the truck = 1,000 kg Initial velocity (u) = 20 m/s Final velocity (v) = 0 m/s Displacement (S) =? Force acting (F) = - 5000 N Solution: We know that F = ma -5000 = 1000*aa = - 5000/1000 = - 5 m/s^2

Now, using 2as = v^2 - u^2 2 × (-5) x s = 0^2 - 20^2-10s = - 400s = -400/-10 = 40 m

Therefore, distance travelled by truck before stopping is 40 m

13228.

1) 1.2JD16, n identical cubes each of mass 'm' and sideare on the horizontal surface. Then theminimum amount of work done to arrangethem one on the other is

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Work done in placing a 2ndcube on the first one, W2​ mglSimilarly W3= 2 mgl W4= 3 mgl Wn= (n -1) mglTotal work done WN= W1+ W2+ W3...+WnWN​ = [ mgl+2mgl+3mgl....(n - 1) mgl ]WN​ =mgl [ 1+2+3+......(n - 1) ]

13229.

17. The friction of the air causes a vertical retardationequal to 10% of the acceleration due to gravityThe maximum height will be changed by (g 10 m/s')(1) 9%(3) 10%(2)(4)11%12%

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Time of flight T=2u sinθ/gθ

T1/T2 =g2/g1 = (g+g/10) /g

=11/10

Fractional decrease in time of flight=(T1−T2) /T1

=[ (T1/T2)−1 ] / (T1/T2)

= [ (11/10−1) ] / 11/10= 1/11

So the % decrease in flight time will be =9%

13230.

160 x10-*1.62 × 10-82.63 × 10-85.20x10-8684 × 10-810x10-8129 x10-940 × 10-81.84 × 10-6ㄛㄒㄛ1010 x10-141013 x10-161015 x10-171012x10-1312雨 (70 )20 18-07-30:49 : 234673|××0-0 3 52112561191|44例(でMr

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Post the question that required to be answered.

13231.

. A concrete wall of thickness one metre of a dam can withstand a side pressureof 105 N m2. Find the thickness of sidewall at the bottom of the water dam ata depth of 100 m. I g: 10ms-2 and density of water 103 kg/m3F

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13232.

A 242 x 104kg freight car moving along ahorizontal rail road spur track at 7.2 km/hourstrikes a bumper whose coil springsexperiences a maximum compression of 30cm in stopping the car. The elastic potentialenergy of the springs at the instant whenthey are compressed 15 cm is210(A) 12.1 x 104 joules (B) 121 x 104 joules(C) 1.21 x 104 joules (D) 1.21 x 106 joules

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thanku

13233.

An engine can pump 30,000 litres of water to a vertical height of 45 metre in 10 minutes.Calculate the work done by the machine and the power.(Density of water 103 kg/m3, 1000 litre 1 m3, g 9.8 m s-2)

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Mass of water which pumping by machine = 30000 x 10^-3 x 1000 kg =30000 kg

now, potential energy of water =- mgh =-30000 × 9.8 ×45 joule= -13230000 Joule

workdone by water =- potential energy =13230000 Joule=13230 kilojoule

power of machine =energy of machine/time =13230000 /10x 60=132300/6 =22050w=22.05 kw

13234.

3. A piece of iron of mass 2-0 kg has a heat capacityof 966 J K-1. Find : (i) heat energy needed to warmit by 15°C, and (ii) its specific heat capacity in S.I.Ans. (i) 14490 J, (ii) 483 J kg-1 K-1.unit.

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ii part

13235.

A rocket with a lift-off mass 3.5 x 104 kg is blastedupwards with an intial acceleration of 10 m/s2. Thenthe initial thrust of the blast is:(A) 3.5 x 105 N(C) 14.0 x 105 N(B) 7.0 x 105 N(D) 1.75 x 105 N

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13236.

2kg of water is converted into steam by boilingat atmospheric pressure. The volume changesfrom 2 x 103 m3 to 3.34 m3. The work done bythe system is about) 1770 kI

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13237.

2) 4/5An elevator is designed to lifta load of 1000 kg through 6 floors of a building averaging 3.5 m per floor in 6 sec.Power of the elevator, neglecting other losses, will be(1) 3-43 x104 wart(2) 4.33 x 104 watt (3) 2.21 x10t watt(4) 5.65 x 104 watt

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13238.

List four forms of energy that you use from morning, when ywake up, till you reach the school.

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Four forms of energy and from where they come are as follows ==>(1). Muscular energy: from the food we eat.(2). Kinetic or Mechanical Energy: by moving , our limbs move and our body accelerates(3). Thermal Energy: Metabolic processes in your body produce it as byproduct and your body consumes chemical energy specifically to produce heat. (4). Potential Energy: by having mass, and efforts vary acc. to situations.Eg. Less energy and effort is consumed when we run down a stair than up.

13239.

10. A toy cart of mass /3 kg is pulled by a force of 20 N at an angle of 30° with the frictionless horizontal surface onwhich the cart is placed. The cart shall move on the surface with an acceleration :(A) 0 ms-2(B) 1 ms2(C) 10 ms-2(D) 10-/3 ms2mass 5 kg is observed to accelerate up at the rate ofWhat mass of sand should be put inside the box so that it may accelerate down at the rate of 6?when placed deep inside water,(A) 1 kg(B) 1.5 kg(C) 2 kg(D) 2.5 kg

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13240.

A sphere of mass 5 kg and volume 2.2 x 104 m3 is completely immersed in water. Findthe buoyant force exerted by water on the sphere. Density of water 1000 ke/m2water. Find0 kg/m3

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13241.

4. A body of mass 5 kg has momentum of 10 kg m/s. When a force of 0.2 N is applied on it for 10 seconds, whatis the change in its kinetic energy(2) 2.2J(3) 3.3J(4) 4.4J

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13242.

Write two differencesin speed & velocity

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The speed of an object is defined as the distance it has traveled divided by the amount of time elapsed. The velocity of the object is similar to speed but has one main difference: velocity takes into account the direction of an object.

13243.

Arope of mass 5 kg is movingvertically in vertical positionwith an upwards force of 100 N acting at the upper endand a downwards force of 70 N acting at the lower end.The tension at midpoint of the rope is3.27

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when you give one upward and one downward force on a rope of mass,and you have to find the tension at midpoint then simply average the two forces,100N+70N/2=85N

13244.

1. List the three factors required for communicating through sound

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Locution--the semantic or literal significance of the utterance;

Illocution--the intention of the speaker; and.

Perlocution--how it was received by the listener.

wrong answer

13245.

WritetheexpressionforLorentz'sforceactingonachargedparticleandexplaintheterinins

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13246.

2. Write two factors on which the Buoyant force exerted by a liquid depends?

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Thebuoyant force dependson the mass of the object. Thebuoyant force dependson the weight of the object. Thebuoyant forceis independent of the density of the liquid. Thebuoyant force dependson the volume of the liquid displaced.

13247.

16. Whenever an object moves, or, tends to move over the surface of anotherobject, there is a force of friction. List two factors on which this force of friction2depends

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the force of friction depends on following factors1 . Roghness of the surface.2. Irregularities on the surface of object.3 . Force Applied4. Mass of object

Area of contact with surfaceroughness of surfaceforce appliedmass of object

13248.

(A) 2/3 sec(B) 1/6 sec(C) 1/2 secThe kinetic energy K of a particle movingalong a cirde of radius R depends on the distance covered sa is a positive constant. The total force acting on the particle isAU (Eng. 1w7 11/2R2

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Given K.E = 1/2 mv² = as²

= mv² = 2as²

now differenciating with respect to t

2mv = dv/dt = 4as ds/dt = 4asv

mat = 2 as

Hence Ft = 2 as here (Ft = tangential force) ..... 1>

centripetal force = Fc = mac = mv²/R = 2 mas²/ mR = 2as²/R ..... 2>

now net force of particle is =√Ft² + F² c =√(2as)² + (2as²/R)²

= 2 as(√1 + s²/R² or 2as(1 + s²/R²) raise to power 1/2

13249.

2]Iftheforceactingonabodyinuniforncircularmotiondependsuponthemassmofbody, itsspeed v and the tadits of h h t

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13250.

A ball is thrown upward with a kinetic energy of 20 J.maximum height of 2 m.Findthemassofthehailfitgoestoa2oCColculate the kinetic cnergy of the body

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potential energy = kinetic energy = 20 Jouleso,PE = mgh = 20m = 20/ghm = 20/(10X2)thus, the mss of the body will be = 1 kg.

awesome thanks