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F = ma..mv dv/dx = -k/x = -0.5/x

vdv = -0.5 dx/x

v2 / 2 - (2) 2/ 2 = 0.5 ( -1n . 2.01/0.1) = -1.5

v2 = 2 ( 2- 1.5) = 1

v = 1 m/s .

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the acceleration of combined of both bodies will be 2

acceleration. of combination of two bodies is 2

The magnitude of the magnetic force on acharg particle isF =|q| v B sinθ

Here, q = charge on a proton = 1.602 x 10−19Cv = 2.5 x 10⁶m/sθ = 30°B = 4 TSubstituting all these values in the expression for F, we get:-F =1.602 x 10−19C x2.5 x 10⁶m/s x 4 T× sin30° = 8×10⁻¹³ N

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mass of the block= 10 kgacceleration due to gravity= 10 m/s^2force acting on the block, F =100Ncoefficient of friction, µ= 0.5

the normal force, N= mg=10*10=100 NFriction force, f= µN=0.5*100=50N

the frictional force is acts opposite to the direction of applied force.

let the acceleration of the block be "a"

therefore, F-f=ma=>100-50=10*a=>a=5m/s^2 (answer)

Velocityof a body is defined as the time rate of displacement, where as acceleration is defined as the time rate of change of velocity.Acceleration is a vector quantity. The motion may be uniformly accelerated motion or it may be non-uniformly accelerated, depending on how the velocity changes with time.

Uniform Acceleration

The acceleration of a body is said to be uniform if its velocity changes by equal amounts in equal intervals.

The slope of velocity - time graph sives acceleration. acc. along OA =10/2 =5msec^-2acc .along AB = (10-10)/(8-2)= 0 acc.along BC = (0-10)/(10-8)=-5msec^-2

so only first law of reflection is an extension of principle of conservation of energy.

F=mg×sinθ

10=m×10×sin30°

m=2kg

thanks Buddy

plz solve another questions also which I have posted

The friction force causing the deceleration = f = m.a

Where m = mass of the body,

and a = deceleration of the body = 4.0 m/s²

So f = 4m N

Normal force on the body = weight of the body = mg N

So coefficient of kinetic friction = 4m/mg =4/g = 4/9.8= 0.4

Net retarding force = {mg*(sin 45) + 0.5*mg*(cos 45)} orretardation = [{mg*(sin 45) + 0.5*mg*(cos 45)}/m]= (g/√2)*[1+0.5] = {3/(2√2)}*g = 1.06*g = 10.405 m/s²

A bio machine, nanite, or nanomachine, refers to any discrete number of molecular components that produce quasi-mechanical movements (output) in response to specific stimuli (input).

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Given Distance from Fort D = 7km = 7000 mSpeed of sound S = 350 m/sec

So time taken to reach the siren sound to security guardT = D / S = 7000/350 = 20T = 20 sec

Therefore, guard watch be slow by 20 sec

(c) is correct option

0 to50 minTime = 50 min=50/60 = 5/6 hNet displacement = 0Total distance = 2.5 + 2.5 = 5 kmAverage velocity = Displacement / Time = 0Average speed = Distance / Time = 5/(5/6) = 6 km/h

ans in m/sec

((NH4)3Po4) = H3Po4+3NH3

CV^2 has the dimensions of energy of capacitorand LI^2 has the dimensions of energy of magnetic fieldhence option c

A); is the correct answer

a) is the right answer of the following

B) is correct answer

306.456cm^3sec^-1

One is for variable resistanceand one is for taking a path from any branch or can say over any path

Rc indicate radius of curvature of a circular path..

Given, power of pump = 2kW =2000WTime (t)= 60secHeight (h) = 10mg = 10m/s²As you know, power =work done per unit time.Work done = mgh = m ×10×10 =100mTherefore, 2000W = 100m/60sTherefore, m = 1200kgSo, the pump can raise 1200kg of water in one minute.

Heat generated by heater = 8500 kJ/h = 8.5 x 10^6 J/h Specific heat of water = S = 4.18 J/g/0C Let mass of water that can be heated from 10 to 60 deg Cel = m (in grams) Heat required in 1hr = 8.5×10^6 J Using Q = m S (T2 – T1) 8.5×10^6 = m * 4.18 * (60 – 10) 8.5 x 10^6= m * 4.18 * 50 m = 8.5x 10^6 / 209 = 1776.5 g 1.77 kg

option B. is correct.

first part.

in rectangle, opposite sides are equalso, AD=BC & AB=CDso, x-y=14....... (1) & x+y=30....... (2) on adding 1 &2 equationwe get, 2x=44 x=22putting the value of 'x' in equation (1) we get, 22-y=14 y=22-14 y=8answers: x = 22 & y = ________________________

Option A) is correct.

acceleration is F/m = 20/5 = 4m/s²

now , after 1 sec the velocity will be

V = u +at => V = 10+4*1 = 14m/s.

please provide proper information related to this question.

Let m = mass , M1 & M2 are the molecular masses .. and Na1 and Na2 = moles of different substances ( no. of molecules)

we know that masses are equal.., som = M1*Na1

and m = M2*Na2

so, M1*Na1 = M2*Na2

so ratio of no. of molecules are Na1/Na2 = M2/M1.

the answer is 2v1v2/(v1+v2)

let x/2 distance cover in time t1 & another x/2 distance cover in time t2t1 = (x/2)/40t2 = (x/2)/60t1+t2 = x/48average speed = x/(t1+t2) = x/(x/48) = 48Km/hr

The force of attraction or repulsion acting along a straight line between two electric charges is directly proportional to the product of the charges and inversely to the square of the distance between them.

the force of attraction or repulsion between pair of charges is directly proportional to the product of two charges and inversely proportional to square of distance between two charges.this force acts along line joining two charges

h=1/2g(t1+t2)2

2h/g=(t1+t2)2------(1)

h/2=1/2gt12

t12=h/g---------(2)

From 1st and 2nd

t12=(t1+t2)2/2

t1=(t1+t2)/1.41

1.41t1=t1+t2

t1=t2/.41

So

t1=2.414t2

Coulomb's lawis valid, if the average number of solvent molecules between the two interesting charge particles should be large.

Coulomb's lawis valid, if the point charges are at rest. It is difficult to apply theCoulomb's lawwhen the charges are in arbitrary shape

coulomb's law not applicable on continuous charges ,it only applicable only on point charges

charges should be on rest