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Sum of OA and OB = √R²+R² = √2R in the direction of OC

so, sum of all the vectors = (sum of OA +OB )+OC = √2R+R

option d

can u explain how L ad / L db= 8/12

if kinetic energies are samethen momentum will.be same.tooas momentum is directly proportional. to kinetic energy

work done in force vs displacement graph is area under the graph so from x=1 to x=2 area is 10×1=10

from x=2 to x=3 area is 20×1=20

from x=3 to x=4 area is -20×1=-20

from x=4 to x=5 area is 10×1=10

total=10+20-20+10=20erg

Correct answer is 20 erg as 10+20-20+10 is 20 hope this will help you

1]20 ergs.......................

min. wavelength =violetmax. wavelength =red

min. frequency = redmax. frequency = violet

min. wavelengths =violet max. wavelengths =red

surface area of sphere=4πr^2=4*3.14*3.06*3.06=

The answer is option c. Replace a by alpha.

option c is the correct answer

please let me know if you have any query in any steps

option c is the right answer

a) in 3 significant figure the value is 20.7b) the value is 0.000312. in 3 significant figures

this is related to the concept of impulse(I).I = F*t

hence , greater the time taken to apply force, lower will be its impulse on our body and therefore, we will hurt less.

Conservation of energy states that the total energy of an isolated system remains constant irrespective of whatever internal changes may take place with energy disappearing in one form reappearing in another.

It may be shown that in the absence of externalfrictional force the total mechanicalenergy of a body remains constant.Let a body of mass m falls from a point A,which is at a height h from the ground as shown in fig.

At A,

Kinetic energykE = 0Potential energyEp = mghTotal energyE = Ep + Ek= mgh + 0= mgh

During the fall, the body is at a position B. Thebody has moved a distance x from A.

At B,

velocityv2= u2+ 2as

applying,v2= 0 + 2ax = 2ax

Kinetic energy Ek=1/2 mv2= 1/2m x 2gx= mgxPotential energyEp = mg (h – x)Total energy E= Ep + Ek =mg (h-x) + mgx= mgh – mgx + mgx= mgh

If the body reaches the position C.

At C,

Potential energyEp = 0Velocity of the body C isv2= u2+ 2asu = 0, a = g, s = happlyingv2= 0 + 2gh = 2gh

kinetic energyEk =1/2mv2=1/2m x 2gh= mgh

Total energy at C E = Ep + Ek E = 0 + mgh E = mghThus we have seen that sum ofpotential and kinetic energy of freelyfalling body at all points remains same.Under the force of gravity, themechanical energy of a body remainsconstant.

The total amount ofmechanical energy, in a closed system in the absence of dissipative forces (e.g. friction, air resistance), remains constantAt Point A:At point A, the ball is stationary; therefore, its velocity is zero.Therefore, kinetic energy, T = 0 and potential energy, U = mghHence, total mechanical energy at point A isE = T + U = 0 + mgh = mgh... (i)At Point B :Suppose the ball covers a distance x when it moves from A to B. Let v be the velocity of the ball point B. Then by the equation of motion v^2-u^2 = 2aS, we havev^2 - 0 = 2gx or v^2 = 2gx Therefore,Kinetic energy, T = 1/2 mv^2 = 1/2 x m x (2gx)= mgxAnd Potential energy, U = mg (h - x)Hence, total energy at point B isE = T + U = mgx + mg(h-x) = mgh ...(ii)At Point C :Suppose the ball covers a distance h when it moves from A to C. Let V be the velocity of the ball at point C just before it touches the ground. Then by the equation of motion v^2 - u^2 = 2aS, we have V^2 - 0 = 2gh or V^2 = 2gh.Therefore,Kinetic energy,T = 1/2 mV^2 = 1/2 x m x (2gh) = mghand Potential energy, U = 0Hence, total energy at point E = T + U= mgh + 0 = mgh... (iii)Thus, it is clear from equations (i), (ii) and (iii), that the total mechanical energy of a freely falling ball remains constant.

mechanical energy is the sum of potential energy and kinetic energy. It is the energy associated with the motion and position of an object.

option 3 is correct

Given:

a = +3.2 m/s2

t = 32.8 s

vi = 0 m/s

Find:

d = ??d = vi*t + 0.5*a*t2d = (0 m/s)*(32.8 s)+ 0.5*(3.20 m/s2)*(32.8 s)2

d = 1720 m is the required answer.

(i) For reflected light, the light is in the same medium of incidence so the speed is 3 x 10^8ms-2itself.

Wavelength also remains the same, that is 589 nm

Frequency = Velocity/Wavelength = 3 x 10^8/ 589 x 10^-9= 5.093 x 10^14Hz

(ii) Speed of light in glass = Speed of light in air / refractive index of glass = 3 x 10^8/ 1.5 = 2 x 10^8ms^-2

Wavelength of light in glass = Wavelength of light in air / refractive index of glass = 589 / 1.5 = 392.67nm

​ Frequency of light remains constant so it is ​5.093 x 10^14Hz itself.

tube light gives us light

so, light energy is the answer.

The phenomenon that causes stars to twinkle is atmospheric refraction. That is, the air above us is a big ocean of not very dense fluid that has a small bending effect on light that passes through it. If it were perfectly still, the light from a star would follow a path that stays put, and the star's image would appear stable.But the atmosphere is always moving; winds in every level of it cause slight density differences to move around, and different densities bend light by different amounts. And so the light rays from a star zig and zag as they head toward your eyes. That makes them appear totwinkle.hence option d

The standard venue for the long jump includes a runway at least40 metres(131 feet) in length with no outer limit, a takeoff board planted level with the surface at least 1 metre (3.3 feet) from the end of the runway, and a sand-filled landing area at least2.75 metres(9 feet) and no more than3 metres

The primary physical difference is that thermoplastics can be remelted back into a liquid, whereas thermoset plastics always remain in a permanent solid state. Think of thermoplastics as butter – butter can be melted and cooled multiple times toformvarious shapes.

thanks

The triple point of any substance is that temperature and pressure at which the material can coexist in all three phases (solid, liquid and gas) in equilibrium. Specifically the triple point of water is 273.16 K at 611.2 Pa

2+2+2+2+2+2+2+2+2=18^

0.5oscillation =3sthen 3.5 =7 times 0.5then 7*2=14secmultiplier is 2 as oscillations are to and fro

supposeelectric field linesare notperpendicularto the localsurface of the conductor. Thenelectric fieldwill have some component parallel to thesurface. ... So, forsurfaceto be equipotentialsurfacefor static charge distribution thefield linesat thesurfaceareperpendicular to the surface.

Is it 600 V?

(a) Electric flux is defined as the number of electric field lines passing through anareanormal to the surface. Alternatively. The surface integral of the electric field is defined as the electric flux through a closed surface.(b)

एकपरमाणुकिसी भी साधारण से पदार्थ की सबसे छोटी घटक इकाई है जिसमे एक रासायनिक तत्व के गुणहोतेहैं। हर ठोस, तरल, गैस, और प्लाज्मा तटस्थ या आयनन परमाणुओं से बना है। ...परमाणुके द्रव्यमान का 99.94% से अधिक भाग नाभिक में होता है।

i). B2. , because the wire having L will be treated as broken , at t = 0

ii) yes

Electric Potential - Electric potential energy is defined as the total potential energy a unit charge will possess if located at any in the outer space.

Electric Potential Difference - In an electric circuit the potential between two point (E) is defined as the amount of work done (W) by an external agent in moving a unit charge(Q)from one point to another. Mathematically we can say that, E = W/QWhere, E =Electric potential difference between two points W = Work done moving a change from one point to another, Q = Quantity of charge in Coulombs.

E = qVq = eso,E = 200eV

Actually, thwre is no figure attached,

But I have solved a same problem with the diagram

So I am answering this based on that diagram.

Impulse = Pf- Pi(where P = momentum = mv)Pi= m*(d/t) = 1*(20/4) = 5 kg m/sPf= m*(d/t) = 1*(-20/4) = -5 kg m/s

I = Pf- Pi= -5 -5 = -10 kg m/s