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repeat the question please

the distance is 49m and the displacement is 24.5m

The answer is.-0 m displacement....

can you explain it

12 hours is the correct answer

Eachsatellitein theGPSconstellation orbits at an altitude of about 20,000 km from the ground, and has an orbital speed of about 14,000 km/hour (the orbitalperiodis roughly 12 hours - contrary to popular belief,GPS satellitesare not in geosynchronous or geostationary orbits).

12 hours is the right answer

Correct answer is. 12 hours

12 hours is the correct answer

Option (2) is correct.

96mA is the right answer..

tqq

thnk u so much plz give sol. of my other physics questions that the request

The initial velocity is v =8√2 m/s.

and we know that Velocity at max. point is Vcosθ so Vcosθ = 8 => 8√2cosθ = 8 => cosθ = 8/8√2 = 1/√2 therefore θ = 45° now. range is u²sin2θ/g = (8√2)²sin(2*45)/10 = 8*8*2/10 = 128/10 = 12.8m

I = neAVV=I/neAV= (6.25)/(8.5x10^28xπ(2x10^3)^2x1.6x 10^(-19))solve and get the answer

Puretungstenhas some amazing properties including the highest melting point (3695 K), lowest vapor pressure, and greatest tensile strength out of all the metals.Because of these properties it is the most commonlyusedmaterial for light bulb filaments

thanks😀😁😂

option a is the correct answer of the given question

answer of this question is (c)

This is just a formulatotal energy of a particle executing shm is TE = 1/2 M(ω)^2 A^2

it also be look like a curve

SINCE 484J ENERGY IS SUPPLIED TO IT. THEN CHANGE IN ROTATIONAL KINETIC ENERGY IS EQUAL TO ENERGY SUPPLIED TO IT.SOLUTION: (1/2)IWF2 – (1/2)IWi2 = 484 (WHERE WF AND WI ARE INITIAL AND FINAL ANGULAR VELOCITIES)WI = 6 RAD/SWF = 37 RAD/SHENCE PUTTING THE VALUES(1/2)I(37*37)-(1/2)I(6*6)= 484684.5I-18I = 484HENCE MOMENT OF INERTIA= 0.72

Newton's third law:If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.

This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself. We sometimes refer to this law loosely as action-reaction, where the force exerted is the action and the force experienced as a consequence is the reaction.The swimmer pushes against the pool wall with her feet and accelerates in the direction opposite to that of her push. The wall has exerted an equal and opposite force back on the swimmer. You might think that two equal and opposite forces would cancel, but they do not because they act on different systems. In this case, there are two systems that we could investigate: the swimmer or the wall. If we select the swimmer to be the system of interest, as in the image below, thenF_{t{wall on feet}}Fwallonfeet​F, start subscript, w, a, l, l, space, o, n, space, f, e, e, t, end subscriptis an external force on this system and affects its motion. The swimmer moves in the direction ofF_{wall on feet}}Fwallonfeet​F, start subscript, w, a, l, l, space, o, n, space, f, e, e, t, end subscript. In contrast, the forceF_{{feet on wall}}Ffeetonwall​F, start subscript, f, e, e, t, space, o, n, space, w, a, l, l, end subscriptacts on the wall and not on our system of interest. ThusF_{feet on wall}}Ffeetonwall​F, start subscript, f, e, e, t, space, o, n, space, w, a, l, l, end subscriptdoes not directly affect the motion of the system and does not cancelF_{{wall on feet}}Fwallonfeet​F, start subscript, w, a, l, l, space, o, n, space, f, e, e, t, end subscript. Note that the swimmer pushes in the direction opposite to that in which she wishes to move. The reaction to her push is thus in the desired direction.

1 velocity constant therefore acceleration is zero 2acceleration is constant3 acceleration is decreasing with time 4 acceleration is constant 5 acceleration is increasing with time

the slope of the graph gives acceleration of the object

5 cows ke total leg h 29and 2 dogs ke total 8 hand 1 cat ke 4 h total mila ke hote h 32

given impulse at t = 2sec is -10 kgm/s

also impulse = mv = 2*v

so velocity is = 10/2 = 5 m/s

now x° = v*t = 5*2 = 10m

option A

option C is correct..

magnetic lines.. will always start from N and end to S. and it won't intersect with each other.

Right hand thumb rule: When holding thecurrent-carrying straight conductor inyourright handsuch that thethumbpoints towards thedirectionof thecurrent, the finger of theright handwrapsaroundtheconductor inthedirection of the field linesof themagnetic field.

Answer:3)Closed loops

Magnetic field lines are continuous, forming closed loops without beginning or end. They go from the north pole to the south pole

answer no (3) closed loops

Magnetic field always Closed loops

closed loop ..........................

The roof of the movie theater as well as the conference hall are intentionally made curved . This is done so that the sound produced can be reflect from the roof parts and also from the walls so that the sound produced can be reached in all part of the theater or the conference hall.

here a particle start from rest so initial velocity=0 and travel a distance x time=2seconds and a distance y in=?

can u send this pic clearly to my whatsapp num...8610381447

The angles of two bullets from horizontal is 60 and 20 degrees and their velocity is also same. So, the height of two bullets is inthe ratio of their angles.Therefore,Height for the two bullet is in ratio 60 :30 = 2 : 1

Given :m = 3 kg

u = 0h = 100 mg = 9.8 m/s²

Using 3rd equation of motion :v² - u² = 2gh

v² - 0² = 2 (9.8) 100v = 2√490

v = 14√10 m/s

Now, during penetration :u = 14√10 m/sv = 0S = 2 ma = ?t = ?

Using 3rd equation of motion; v² - u² = 2aS

0² - (14√10)² = (2) a (2)4a = -1960a = -490 m/s²

Now, using 1st equation is motion ;v = u+at0 = 14√10 + (-490)tt = 14√10/490t = 0.0903 sec

(1) is correct option

Here,Mass Of Machine Gun(m)= 20kg

Mass of each Bullet, (M)=35g=0.035kg

Velocity Of Bullet(v)=400m/s

No.Of Bullets/sec=4

Force required = rate of change of linear momentum of bullets=n(mv)/t

=4×(0.035×400)/1=56N

Given the perihelion = r2 = shortest distance of a planet from Sun aphelion = r1 = longest distance of planet from Sun mass of planet = m. mass of Sun = M

So the length of the major axis of the Elliptical orbit of the planet = r1 + r2.

Semimajor axis = R = (r1 + r2)/2.

According to Kepler's laws:

The square of time period T of a planet revolving around Sun is proportional to the cube of semi major axis R of the elliptical orbit of the planet.

T² ∞ R³ T∞R³/² T ∞ [r1 + r2] ³/² Answer.

Actual value of the time period is given by:

Option b)FrequencySound is propagated in the form of longitudinal waves. When sound travels from one medium to another medium the wavelength and velocity remains changed and the frequency remains unchanged.The velocity of sound in the given medium is obtained byv=nW, where "n" is the frequency of sound and "W" is its wavelength in that medium. Velocity of sound is directly proportional to the wavelength.Thus, if the velocity of sound wave doubles when travelled from one medium to another medium then its wavelength also doubles.The frequency of sound depends on the source of the sound, not the medium of propagation .Hence the frequency does not change when travelled from air to water.

Recoil velocity = - mass of the bullet*Velocity of the bullet/Mass of the gun=-10*50/1000=-0.5m/s

Power = force × velocity = mnv × v = mnv^2 Substitute the values = 0.04× 240/60 ×80 ×80 =1024Watt

Momentum of the bullet equals the momentum of the gun.

Momentum equals to :

Mass × Velocity

We substitute into the formulae and get :

0.03 × 330 = 10 × V

9.9 = 10V

V = 0.99 m/s

Momentum before firing is zero since both the gun and the bullet are at rest and their velocities are zero.

Momentum after firing is equal to momentum of the gun plus the momentum of the bullet which are equal and opposite.

This is therefore :

330 × 0.03 × 2 = 19.8Kgm/s

you copy pasted it from brainy website

Newton's third lawis: For every action, there is an equal and opposite reaction.

Agun recoilswhen a bullet isfiredfrom it: When a bullet isfiredfrom agun, thegunexerts a force on the bullet in the forward direction. This is the action force. The bullet also exerts an equal force on thegunin the backward direction. This is the reaction force.