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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 2701. |
\begin{array} { l } { \text { The angle between vectors } \overline { \mathrm { A } } = 4 \hat { \mathrm { i } } + 3 \hat { \mathrm { j } } \text { and } } \\ { \overline { \mathrm { B } } = 3 \hat { \mathrm { i } } - 4 \hat { \mathrm { j } } \text { is } } \end{array} |
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Answer» The dot product between A and B gives 12-12=0. Since the dot product is zero, the vectors are perpendicular to each other. Hence, angle between A and B is 90°. |
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| 2702. |
25.A lead sphere of mass m falls in viscous liquidwith terminal velocity Vor Another lead sphere ofmass M falls through the same viscous liquid withterminal velocity 4vo. the ratiois(2) 4(3) 8(4) 162 |
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| 2703. |
48. The speed of light in a medium of (absolute)refractive index of 2 is(a) 6 x 108 ms-1 (b) 3 × 108 ms-1(c) 2 × 108 ms-I . (d) 1.5 × 10"ms-1 |
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Answer» n=c/vv=c/nv=3×10^8/2v=1.5×10^8m/sYour answer is (d). |
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| 2704. |
7. The refractive index of glass is 3and water has refractive index 3.If the speed of light in glass is2 * 108 m/s, the speed of light inwater in m/s is(a) 1.50 x 108(b) 1.78 x 108(c) 2.25 x 108(d) 2.67 x 108 |
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Answer» d right answer bhai please like |
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| 2705. |
44. The refractive index of kerosene is 1.1 times of therefractive index of water. The velocity of light inkerosene is 2 x 108 m/sec then the velocity of lightin water will be(1) 2 x 108 m/sec(2) 2.1 x 108 m/sec(3) 2.2 x 108 m/sec (4) 2.2 x 108 m/sec |
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Answer» refractive.index of kerosene/refractive index of water=doped of light in kerosene/speed of light in waterhence as it is 1.1 times hencespeed of light in water will be 1.1*2*10^8=2.2*10^8m/s |
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| 2706. |
6. A metal ring of initial radius r and cross-section A is fitted on a wooden disc ofradius R (R > r). If Young's modulus ofthe metal is Y, then the tension in thering is |
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Answer» Young's modulus of elasticity is given by,Y = Fl / AxF = YAx / l But, l = 2πrAnd x = 2πR - 2πr = 2π(R-r) Hence, force of expansion is-F = YA × 2π(R-r) / 2πrF = YA(R-r) / r Force acting on expanding ring is YA(R-r)/r. |
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| 2707. |
A particle of mass m is executing a uniform motion along a circular path of radius r. if the magnitude ofits linear momentum is p, the radial force acting on the particle will be(A) pmr20.radius r.the(B) rm/p(C) mp?/r(D) p Imr |
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Answer» given P =mv so v=P/m so radial force is = mv^2/r = m ^2P^2/mr = mP2/r |
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| 2708. |
what is chemistry,physics,biology. |
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Answer» Ans :- Chemistry - Chemistry is the scientific discipline involved with elements and compounds composed of atoms, molecules and ions: their composition, structure, properties, behavior and the changes they undergo during a reaction with other substances. Physics - Physics is the natural science that studies matter and its motion and behavior through space and time and that studies the related entities of energy and force. Physics is one of the most fundamental scientific disciplines, and its main goal is to understand how the universe behaves. Biology - Biology is the natural science that studies life and living organisms, including their physical structure, chemical processes, molecular interactions, physiological mechanisms, development and evolution. unlimited thanks nro |
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| 2709. |
28.A girl pushes her physics book up against the horizontal ceiling of her room as shown in the figure.Physics bookGirl's pushThe book weighs 20 N and she pushes upwards with a force of 25 N. The choices below list the magnitudes of the contactforce Fce between the ceiling and the book, and FBH between the book and her hand. Select the correct pair.(1) FCE 20 N and BH 25 N(3) Fc 5 25 N(2) FG 25 N and FH45 N(4) FCB 5 N and FH 45 N |
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| 2710. |
Observe the correlation in the first pair and complete the following:Future shoot : Plumule : Future root: _____ Plasmodium : Multiple fission : Planaria: _____ |
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Answer» a)radicleb)regeneration |
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| 2711. |
\left. \begin{array} { r } { = 9 \times 10 ^ { 9 } \times 0.2 \times 10 ^ { - 6 } \times 0.01 \times 10 ^ { - 6 } } \\ { \times [ \frac { 1 } { 0.05 } - \frac { 1 } { 0.10 } ] } \end{array} \right. |
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| 2712. |
\left. \begin{array} { l } { 1.728 \times 10 ^ { 6 } cm ^ { 3 } } \\ { 1.7 \times 10 ^ { 6 } cm ^ { 3 } } \\ { 1.8 \times 10 ^ { 6 } cm ^ { 3 } } \end{array} \right. |
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Answer» 5) ampere second is a unit of charge 4) option 1 is the correct answer |
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| 2713. |
40) Which substance obtained oncooling the vapor produced on heatingammonium chloride? |
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Answer» Ammonium chloride because there is no change is property of ammonium chloride after heating |
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| 2714. |
ol 4Uys 214 का१ भप : 3’ IKN0Y QIR\‘» i giyY75 60}‘7:_ 4o :0P Wy g wsfi??q e=t Uty amu g०५10जल |
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Answer» Salma takes time from house to school = 15 m = 15*60 = 900 sec Speed of bicycle = 2 m/s Distance between her house and school= speed*time= 900*2= 1800 m= 1.8 km |
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| 2715. |
HClCH_3COOH |
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Answer» HCl- Hydrochloric acidCH3COOH is the acetic acid thank u |
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| 2716. |
A projectile is thrown with a velocity of 20 m/sat an angle of 60° with the horizontal. After howmuch time the velocity vector will make an angleof 45° with the horizontal: (take g 10 m/s?)(1) v3 sec(2) 1/3 sec3) (v3 + 1) sec (4) (3 -1) sec |
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Answer» For velocity to make 45° the vertical and horizontal velocity should be equal horizontal component of velocity is always constant as it is 20cos(60°) =10m/s and initial velocity in vertical direction = 20sin(60) = 10√3 so, for vertical component to change to 10m/s use V = u-gt => 10 = 10√3 -10t=> 10t = 10(√3-1)=> t = √3-1 sec option 4 |
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| 2717. |
16. The range R of projectile is same when its maximum heights are hi and h2. What is the relation between Rand hi and h2(A) K=4Mh2(B) R 2h, h2(C) R = 2./h,h2(D) R = 4M112Efaront ngles with horizontal |
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| 2718. |
7 A body of weight 72 N moves from the surface ofearth at a height half of the radius of earth, thengravitational force exerted on it will be |
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Answer» answer is already given by a student |
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| 2719. |
91. Ifa body loses half of its velocity on penetrating3 em in a wooden blcok, then how much will itpenetrate more before coming to rest? |
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| 2720. |
P1. If a body loses half of its velocity on penetrating3 cm in a wooden block, then how much will itpenetrate more before coming to rest? |
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| 2721. |
91. If a body loses half of its velocity on penetrating3 cm in a wooden blcok, then how much will itpenetrate more before coming to rest? |
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| 2722. |
If a body loses half of its velocity on penetrating 3 cm in awooden block, then how much will itpenetrate more before coming to rest?A 1 cmBO 2 cmCL 3 cmD.O 74 N |
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Answer» option A |
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| 2723. |
5.Explain why a charged body loses its charge if we touch it with our hand. |
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Answer» Because the body passes the charge A charged body loses its charge if we touch it with our hand this is because when we touch the body which is charged with our hand the charge gets transferred to our hand does the body loses its charge |
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| 2724. |
A bullet fired into a fixed target loses half of itsvelocity after penetrating 3 cm. How thuch furtheritwill penetrate before coming to rest assuming thatiffaces constant resistance to motion IEEE 2005) |
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| 2725. |
(i) 12 m/sec and 3600 N(3) 16 m/sec and 6400 NA body of mass 2 kg is thrown up vertically with a kinetic energy of 490 J. If the acceleration due to gravity(2) 14 m/sec and 4900 N(4) 18 m/sec and 8100 N55.is 9.8 ms2, the height at which the kinetic energy of the body becomes half of the original value is(1) 50 mA pendulum of length 2 m is left at A. When it reaches B, it loses 10% of its total energy due to air resistance.(2) 25 m(3) 12.5 m(4) 10 m56,The velocity at B is(1) 6 m/s(2) 1 m/s(3) 2 m/s(4) 8 m/s |
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| 2726. |
nsider a heavenly body whose mass is 3 x 104 kg (half that of the earth) and radius is 3,200 km(half thatQ.of the earth). What is the acceleration due to gravity at the surface of thisheavenly body? |
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| 2727. |
A parachutist after bailing out falls 50 m withoutfriction. When parachute opens, it decelerates at2 m/s2. He reaches the ground with a speed of 3 m/s.At what height did he bail out? [JEE mains 2005](1) 293 m(3) 91 m9.(2) 111 m(4) 182 m |
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Answer» option 1 is the nearest answer so that's the correct answer. |
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| 2728. |
A car moving with a speed of 50 km/hr, can bestopped by brakes after at least 6 m. If the same car ismoving at a speed of 100 km/hr, the minimumstopping distance is7.[JEE mains 2003](1) 12 mm(3) 24 m(2) 18 m(4) 6 m |
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| 2729. |
Two forces are such that the sum of their magnitudesis 18 N and their resultant is 12 N which isperpendicular to the smaller force. Then themagnitudes of the forces are JEE mains 20(1) 12 N, 6N 2) 13 N, 5 N(3) 10N,8N02](4)16 N, 2 N |
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| 2730. |
14) The co-ordinates of a moving particle at any time 't'are given by x - at and y Bt'. The speed of thecle at time t is given by JEE mains 2003]\begin{array}{l}{\text { (1) } 3 t \sqrt{\alpha^{2}+\beta^{2}}} \\ {\text { (3) } t^{2} \sqrt{\alpha^{2}+\beta^{2}}}\end{array} |
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| 2731. |
A body weighs 63N on the surface of the earthWhat is the gravitational force on it at a heightequal to the half of the radius of the earth |
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| 2732. |
A wire of resistance 5Ω is drawn out so that its length is increased to twice its original length.Calculate it's new resistance2,4) 10Ω1) 2022) 5Ω3) 8Ω |
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| 2733. |
pressure of a constant volume gasthermometer is 4 atm at ice point and 5 atmt steam point. When the pressure is 5.5 atmthe temperature is1) 300°C 2) 1500C 3) 1250C 4) 66,. C2. The |
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Answer» To find stream point: x / [p(x) - p(0)] = 100 / [p(100) - p(0)] x is the temperature you want to calculate. p(x) is the thermometric property at x Kelvin. x / [5.5 - 4] = 100 / [5 - 4] x = 150C |
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| 2734. |
One mole of an ideal gas expands at a constanttemperature of 300 K from an initial volumeof 10 litres to a final volume of 20 litres. Thework done in expanding the gas is (R-8.31 J/mole-K)( in joules) |
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| 2735. |
Calculatethe resistance2-AAAA.Laima LamM |
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| 2736. |
is some water in a penker plaged on the pan of a spring balance. If we dip our finger in thisater without touching the bottom ofthe beaker, then what would be the effect on the reading ofthe balance? |
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Answer» When we dip our finger in the water, the water exerts upward thrust on the finger (Archimedes’s principle). Due to Newton’s thirdlaw of motion, the finger will exert an equal and opposite force on the water in downward direction resulting in increase of the weight of water. Thus the reading of the spring balance will increase. |
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| 2737. |
One mole of an ideal gas expands isothermallyto double its volume at 27°C. Then the workdone by the gas is nearly |
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Answer» P=nRT=1*8.314*300=2492Atm |
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| 2738. |
Problem - 13.29: An ideal gas expands isothermallyfrom a volume V, to V, and then compressed to originalvolume V, adiabatically. Initial pressure is P, and finalpressure is P the total work done is W. Then what is itsvalue and its conditions. |
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| 2739. |
One mole of O2 gas having a volume equal to22.4 litres at 0°C and 1 atmospheric pressurein compressed isothermally so that its volumereduces to 11.2 litres. The work done in thisprocess is |
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Answer» work done = nRTln(Vf/vi) = 1*0.08*273*ln(1/2) = -15.13 L-atm |
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| 2740. |
1.A body of mass 5 kg is suspended by a springbalance on an inclined plane as shown. The springbalance measure30°(1) 50 N(3) 500 N(2) 25 N(4) 10 N |
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Answer» As downward force moves along the inclined plane mgsinθ=5×10×sin30°= 25N thank you |
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| 2741. |
A spring balance has a scale that reads from 0 to 50 kg. The length of the scale is 20em. A body suspended from this balance, when displaced and released, oscillateswith a period of 0.6 s. What is the weight of the body? |
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Answer» I don't. no. hat I don't know ok. hat. . ... . |
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| 2742. |
2. What is a spring balance? |
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Answer» a balance that measures weight by the tension of a spring. A spring scale or spring balance or newton meter is a type of weighing scale. It works by Hooke's Law, which states that the force needed to extend a spring is proportional to the distance that spring is extended from its rest position. Therefore, the scale markings on the spring balance are equally spaced. |
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| 2743. |
Figure shows a 5 kg ladder hanging from a string that is connected with a ceiling andis having a spring balance connected in between. A boy of mass 25 kg is climbing upthe ladderataccelenation 1 m. Assuming the spring balance and the string to bemassless and the spring to show a constant reading, the reading of the spring balanceis : Take g 10 m/s2)(A) 30 kg10.IllustrationWithof m(B) 32.5 kg(D) 37.5kg(C) 35 kg |
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| 2744. |
24. A steam engine delivers 5.4 X 108 J of work per minute and absorbs 3.6 X 10J of heat per minute from its boiler (i) What is the efficiency of the engine ? (ii)How much heat is wasted per minute? |
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| 2745. |
A Carnot's engine working between 27°c and127°c takes up 800 J of heat from thereservoir in one cycle. What is the work doneby the enginea、2001A) 4001 |
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Answer» As we knowEfficiency (n) = 1 - T2/T1= 1 -300/400= ¼Nown = W/Q1HenceWork done = efficiency (n) * heat absorbed(Q1)= ¼ * 800= 200 Joules |
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| 2746. |
23. A metal block absorbs 4500 cal of heat when heated from 30째C to 80째C. Iits thermal capacity is3) 9 gm4) 9 cal l째C1) 90gm2) 90cal l째C |
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Answer» Thermal capacity is energy required to raise the temp of a substance by 1 degree kelvin/celcius. 4500/(80-30)= 90cal/kelvin |
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| 2747. |
Derive ideal gas equation, PV = nRT |
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| 2748. |
Two trains A and B of length 400 m each are moving on two parallel tracks withuniform speed of 72 km h-1 in the same direction, with A ahead of B. The driveB decides to overtake A and accelerates by 1 m s2. If after 50 s, the guard of Bjisbrushes past the driver of A, what was the original distance between them |
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Answer» from where you got answer plz name the appor yourself |
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| 2749. |
Applying the first law of thermodynamics, obtain the relation between the two specific heats of a gas. |
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Answer» Accordingto first law of thermodynamic quantity of heat energy of heat energy absorbed by the system is equal to the sum of increases in the internal energy of the system and the external work done by it.From first lawΔQ =ΔU + pdV where,ΔQ = heat transition between system and surroundingΔU = change in internal energy of the system |
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| 2750. |
78. A proton, a deuteron and an alpha particle of the same momentum are moving inVoevo.constant magnetic field. Their radii are respectively ro. Pa and ra. Then fordiralssame momentum are moving in circular trajectories in a(a) 1:1:2(b) 2:2:1(c) 1:1:1(d) 2:1:2 |
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Answer» C is the right answer |
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